A 1000-kg car is slowly picking up speed as it goes around a horizontal curve whose radius is 100 m. The coefficient of static friction between the tires and the road is 0.350. At what speed will the car begin to skid sideways?

Answer:

the distance between interference fringes increases

Explanation:

For double-slit interference, the distance of the m-order maximum from the centre of the distant screen is

[tex]y=\frac{m \lambda D}{d}[/tex]

where [tex]\lambda[/tex] is the wavelength, D is the distance of the screen, and d the distance between the slits. The distance between two consecutive fringes (m and m+1) will be therefore

[tex]\Delta y = \frac{(m+1) \lambda D}{d}-\frac{m \lambda D}{d}=\frac{\lambda D}{d}[/tex]

and we see that it inversely proportional to the distance between the slits, d. Therefore, when the separation between the slits decreases, the distance between the interference fringes increases.

The difference between visible light and gamma rays is their frequency, energy and wavelength. All electromagnetic waves travel at the same speed, which is called the speed of light. ... Visible light has much lower energy and longer wavelengths than gamma radiation.

If you are using PLATO, which I'm sure you are cause I've had the same question, the answer it the following:

Transformers increase and decrease voltage as needed.

The alternating current more effective at long–distance travel than direct current because transformers increase and decrease voltage as needed.

Alternating current is an electric current which periodically reverses direction and changes its magnitude continuously with time.

The voltage difference developed through transmission lines is very high,. This reduces the current and minimizes the energy lost through transmission. So, alternating current is chosen over direct current for transmitting electricity.  It is much cheaper to change the voltage of an alternating current.

Thus, the alternating current more effective at long–distance travel than direct current because transformers increase and decrease voltage as needed

Learn more about alternating current.

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Answer:

[tex]8.1\cdot 10^{-4} C^{-1}[/tex]

Explanation:

The volumetric expansion of the liquid is given by

[tex]\Delta V=\alpha V_0 \Delta T[/tex]

where

[tex]\alpha[/tex] is the coefficient of volume expansion

[tex]V_0[/tex] is the initial volume

[tex]\Delta T[/tex] is the change in temperature

For the liquid in this problem,

[tex]V_0 = 2.35 m^3\\\Delta T=48.5^{\circ}C\\\Delta V=0.0920 m^3[/tex]

So we can solve the equation to find [tex]\alpha[/tex]:

[tex]\alpha=\frac{\Delta V}{V_0 \Delta T}=\frac{(0.0920 m^3)}{(2.35 m^3)(48.5^{\circ}C)}=8.1\cdot 10^{-4} C^{-1}[/tex]

The intensity of sound is just like the force of gravity, the force between electric charges, and the intensity of light . . . they all DEcrease at the same rate that the SQUARE of the distance INcreases.

So if two people are watching or listening to the same source, and one intensity is 1/10 as intense as the other intensity, then the farther person must be  √10  times as far from the source as the nearer person is.

√10 = 3.1622 ...

So the second guy is about 3.16 miles from the fire truck.  

Final answer:

The intensity of sound follows the inverse square law, so if a fire truck's sound is heard 10 times less intensely compared to a person 1 mile away, the other person is approximately 3.16 miles away.

Explanation:

When considering the intensity of a sound and how it decreases with distance, we are dealing with a concept in physics known as the inverse square law. The intensity of a sound is inversely proportional to the square of the distance from the source. So, if a person hears a fire truck with an intensity that is 10 times less than the intensity heard by another person 1 mile away, we apply the inverse square law: Intensity Ratio = (Distance1/Distance2)². Accordingly, the other person would be √10, which is approximately 3.16 times farther away, meaning they are roughly 3.16 miles from the fire truck.

(a) 0.456 m/s

The maximum speed of the oscillating mass can be found by using the conservation of energy. In fact:

- At the point of maximum displacement, the mechanical energy of the system is just elastic potential energy:

[tex]E=U=\frac{1}{2}kA^2[/tex] (1)

where

k = 34.9 N/m is the spring constant

A = 5.0 cm = 0.05 m is the amplitude of the oscillation

- At the point of equilibrium, the displacement is zero, so all the mechanical energy of the system is just kinetic energy:

[tex]E=K=\frac{1}{2}mv_{max}^2[/tex] (2)

where

m = 0.42 kg is the mass

vmax is the maximum speed, which is maximum when the mass passes the equilibrium position

Since the mechanical energy is conserved, we can write (1) = (2):

[tex]\frac{1}{2}kA^2=\frac{1}{2}mv_{max}^2\\v_{max}=\sqrt{\frac{kA^2}{m}}=\sqrt{\frac{(34.9 N/m)(0.05 m)^2}{0.42 kg}}=0.456 m/s[/tex]

(b) 0.437 m/s

When the spring is compressed by x = 1.5 cm = 0.015 m, the equation for the conservation of energy becomes:

[tex]E=\frac{1}{2}kx^2+\frac{1}{2}mv^2[/tex] (3)

where the total mechanical energy can be calculated at the point where the displacement is maximum (x = A = 0.05 m):

[tex]E=\frac{1}{2}kA^2=\frac{1}{2}(34.9 N/m)(0.05 m)^2=0.044 J[/tex]

So, solving (3) for v, we find the speed when x=1.5 cm:

[tex]v=\sqrt{\frac{2E-kx^2}{m}}=\sqrt{\frac{2(0.044 J)-(34.9 N/m)(0.015 m)^2}{0.42 kg}}=0.437 m/s[/tex]

(c) 0.437 m/s

This part of the problem is exactly identical to part b), since the displacement of the mass is still

x = 1.5 cm = 0.015 m

So, the speed when this is the displacement is

[tex]v=\sqrt{\frac{2E-kx^2}{m}}=\sqrt{\frac{2(0.044 J)-(34.9 N/m)(0.015 m)^2}{0.42 kg}}=0.437 m/s[/tex]

(d) 4.4 cm

In this case, we have that the speed of the mass is 1/2 of the maximum value, so:

[tex]v=\frac{v_{max}}{2}=\frac{0.456 m/s}{2}=0.228 m/s[/tex]

And by using the conservation of energy again, we can find the corresponding value of the displacement x:

[tex]E=\frac{1}{2}kx^2+\frac{1}{2}mv^2\\x=\sqrt{\frac{2E-mv^2}{k}}=\sqrt{\frac{2(0.044 J)-(0.42 kg)(0.228 m/s)^2}{34.9 N/m}}=0.044 m=4.4 cm[/tex]

The correct answer for part (d) is: [tex]\[ x = \pm\frac{A}{\sqrt{2}} \][/tex] where [tex]\( A \)[/tex] is the amplitude of the motion.

To determine the value of [tex]\( x \)[/tex] at which the speed of the oscillating mass is equal to one-half the maximum value, we first need to establish the relationship between the speed of the mass and its position in the oscillation.

The total mechanical energy [tex]\( E \)[/tex] of a mass-spring system in simple harmonic motion (SHM) is conserved and is given by the sum of its potential energy [tex]\( U \)[/tex] and kinetic energy [tex]\( K \)[/tex]. At the maximum displacement (amplitude [tex]\( A \)[/tex]), all the energy is potential, and the kinetic energy is zero. Conversely, at the equilibrium position, all the energy is kinetic, and the potential energy is zero.

The maximum potential energy [tex]\( U_{\text{max}} \)[/tex] occurs at the amplitude [tex]\( A \)[/tex] and is given by:

[tex]\[ U_{\text{max}} = \frac{1}{2}kA^2 \][/tex]

where [tex]\( k \)[/tex] is the spring constant.

The maximum kinetic energy [tex]\( K_{\text{max}} \)[/tex] occurs at the equilibrium position and is equal to the total mechanical energy [tex]\( E \)[/tex]:

[tex]\[ K_{\text{max}} = \frac{1}{2}mv_{\text{max}}^2 = E \][/tex]

Since energy is conserved:

[tex]\[ E = U_{\text{max}} + K_{\text{max}} = \frac{1}{2}kA^2 + \frac{1}{2}mv_{\text{max}}^2 \][/tex]

At any point in the oscillation, the total mechanical energy is:

[tex]\[ E = U + K = \frac{1}{2}kx^2 + \frac{1}{2}mv^2 \][/tex]

We are given that the speed [tex]\( v \)[/tex] is half the maximum speed [tex]\( v_{\text{max}} \)[/tex], so we can write:

[tex]\[ \frac{1}{2}mv^2 = \frac{1}{2}m\left(\frac{v_{\text{max}}}{2}\right)^2 \][/tex]

Substituting [tex]\( v_{\text{max}} \)[/tex] from the energy conservation equation:

[tex]\[ \frac{1}{2}m\left(\frac{v_{\text{max}}}{2}\right)^2 = \frac{1}{2}m\left(\frac{\sqrt{\frac{2E}{m}}}{2}\right)^2 = \frac{1}{2}m\left(\frac{1}{2}\sqrt{\frac{2E}{m}}\right)^2 = \frac{1}{2}m\left(\frac{1}{2}\right)^2\frac{2E}{m} = \frac{1}{2}E \][/tex]

Now, we can equate the total mechanical energy at this point to the potential energy, since the kinetic energy is half the total energy:

[tex]\[ \frac{1}{2}kx^2 = \frac{1}{2}E \][/tex]

Substituting [tex]\( E \)[/tex] from the energy conservation equation:

[tex]\[ \frac{1}{2}kx^2 = \frac{1}{2}\left(\frac{1}{2}kA^2\right) \][/tex]

Solving for [tex]\( x \)[/tex]:

[tex]\[ kx^2 = \frac{1}{2}kA^2 \][/tex]

[tex]\[ x^2 = \frac{1}{2}A^2 \][/tex]

[tex]\[ x = \pm\sqrt{\frac{1}{2}A^2} \][/tex]

[tex]\[ x = \pm\frac{A}{\sqrt{2}} \][/tex]

Therefore, the value of [tex]\( x \)[/tex] at which the speed of the oscillating mass is equal to one-half the maximum value is [tex]\( \pm\frac{A}{\sqrt{2}} \)[/tex]. Since the amplitude [tex]\( A \)[/tex] is given as 5.0 cm (0.05 m), the specific values of [tex]\( x \)[/tex] are:

[tex]\[ x = \pm\frac{0.05 \text{ m}}{\sqrt{2}} \approx \pm 0.0354 \text{ m} \][/tex]

The gravitational force between Earth and the Moon is dominant over electrical forces because Earth and the Moon are nearly electrically neutral, making Coulomb forces almost cancel out. Gravitational force is always attractive and more substantial between objects with large masses, unlike electrostatic forces which are negligible for large bodies.

The gravitational force between the Earth and the Moon predominates over electrical forces primarily because most objects, including the Earth and Moon, are nearly electrically neutral. Hence, the attractive and repulsive Coulomb forces nearly cancel each other out. Secondly, the gravitational force is always attractive, becoming significant on a large scale and making it the dominating force in interactions between large objects such as Earth and Moon. While the gravitational and electrostatic forces are both inverse square forces, meaning they both diminish with the square of the distance, gravitational force depends on the mass and is stronger between objects with large masses. In contrast, the electrostatic force, being much greater than the gravitational force between charged particles, becomes negligible when considering large, nearly neutral bodies.

Doubles and Remains the same

D - 1,960 J, 3,720 J

At a height of 50 m from the ground, the potential energy will be;

= 4 × 9.8 × 50

= 1960 Joules

This means that some of the energy possessed by the stone at a height of 145 m was converted to kinetic energy.

Therefore; the energy that was converted to kinetic energy will be;

= 5,680 J - 1960 J

= 3,724 Joules

Approximately kinetic energy is 3,720 Joules

Therefore;

The Potential energy is 1960 Joules and Kinetic energy is 3,720 Joules

After 9 years of spectacular findings, NASA shut down the Kepler space telescope at the end of last October (2018).

From 2009 to 2018, the Kepler mission found more than 2,600 planets in other "solar systems" ... in orbit around other stars besides our Sun.  AND, at the time the mission ended, (5 months before the night I'm writing this), there were still more than 2,000 sets of data still to be analyzed.

The results suggest that having a family of planets is really not an unusual thing for a star.  Indeed, the rare, unusual stars may be the few that don't have planets orbiting them.

Planets around other stars are probably so common that they are the rule, and not the exception to the rule.

Answer:

 Electric field E = kQ/r^2  

Distance between charges = 6.30 - (-4.40) = 10.70m  

Say the neutral point, P, is a distance d from q1. This means it is a distance (10.70 - d) from q2.  

Field from q1 at P = k(-9.50x^10^-6) / d^2  

Field from q2 at P = k(-8.40x^10^-6) / (10.70-d)^2  

These fields are in opposite directions and are equal magnitudes if the resultant field = 0  

k(-9.50x^10^-6) / d^2 = k(-8.40x^10^-6) / (10.70-d)^2  

9.50 / d^2 =8.40 / (10.70-d)^2  

d^2 / (10.70-d)^2 = 9.50/8.40 = 1.131  

d/(10.70-d) = sqrt(1.1331) = 1.063  

d = 1.063 ((10.70-d)  

= 10.63 - 1.063d  

2.063d = 10.63  

d = 5.15m  

The y coordinate where field is zero is 6.30 - 5.15 = 1.15m

Explanation:

Less than

For the parallel circuit in the previous part (with the switch closed), the current through the 20-ω resistor is less than the current through 10-ω resistor.

According to Ohm's Law, the current through a conductor is directly proportional to the potential difference at constant pressure and temperature.

Therefore; V α I

Mathematically;  V = IR ; Where R is the resistance of a device or a conductor.

From the relationship; I = V/R ; which means current and resistance have inverse relationship such that an increase in resistance causes a decrease in electric current.

Therefore; the current through the 20-ω resistor is less than the current through 10-ω resistor.

In a parallel circuit, the current through a 20-ω resistor is half of the current through a 10-ω resistor. This is because in a parallel circuit, resistors with lower resistance will have more current flowing through them, which is a consequence of Ohm's Law.

For a parallel circuit with a closed switch, the current through the resistors is influenced by their resistances.

According to Ohm's law, the current is inversely proportional to the resistance. Therefore, for the resistors of 20-ω and 10-ω, the current through the 20-ω resistor is half the current through the 10-ω resistor.

It is important to understand that in a parallel circuit, the voltage across each component is the same, and the total current in the circuit is the sum of the currents through each component. This implies that lower resistance components will draw more current from the circuit. The reason for this is represented mathematically in Ohm's law, which states that I = V/R.

Thus, when we speak about the 20-ω and 10-ω resistors, since they are assumed to have the same voltage across them, the current in the 20-ω resistor would be V/20, and the current in the 10-ω resistor would be V/10. This essentially means the current through the 20-ω resistor is half of the current through the 10-ω resistor given the same voltage.

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Electric energy??? there isn't much information from the question but I can infer it's electricity.

Photovoltaic is the term that describes the process of transforming light energy into electrical energy. This often occurs in solar cells which absorb sunlight and produce electricity. Another instance of light energy conversion is in photosynthesis, where plants convert sunlight into chemical energy.

In the context of the question, the term you're looking for is Photovoltaic. This is a form of energy transformation where light energy is converted into electrical energy. This often happens in devices known as solar cells that are designed to capture sunlight and generate electricity from it.

Consider the example of a solar cell. When sunlight (radiant energy) hits the surface of the cell, the materials within the cell absorb the light and transform it into electrical energy. This process is often used to power electrical devices or store energy for later use.

Another instance is in photosynthesis performed by plants. Plants convert light energy (from the sun) into chemical energy that they can use to grow and reproduce. The energy transformation in this case is from light to chemical.

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Answer:

+e

Explanation:

The charge of an up quark is:

[tex]q_u = +\frac{2}{3}e[/tex]

The charge of a down quark, instead, is:

[tex]q_d = -\frac{1}{3}e[/tex]

In this problem, we have a particle consisting of 1 down quark and 2 up quarks, Therefore, the net charge of the particle will be

[tex]q=1(q_d)+2(q_u)=1(-\frac{1}{3}e)+2(\frac{2}{3}e)=-\frac{1}{3}e+\frac{4}{3}e=\frac{3}{3}e=+e[/tex]

So, the particle has a charge of +e.

Answer:

.012

Explanation:

Take the mass of the fish and divide it by the mass of the water:

65/.30=216.667

Divide the given speed by the value we found above:

2.5/216.667=.0115

Answer can be rounded up to .012

The speed of the archerfish immediately after it expels the drop of water is about (b) 0.012 m/s

[tex]\texttt{ }[/tex]

Newton's second law of motion states that the resultant force applied to an object is directly proportional to the mass and acceleration of the object.

[tex]\large {\boxed {F = ma }[/tex]

F = Force ( Newton )

m = Object's Mass ( kg )

a = Acceleration ( m )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

The Question:

What is the speed of the archerfish immediately after it expels the drop of water?

(a) 0.0025 m/s; (b) 0.012 m/s; (c) 0.75 m/s; (d) 2.5 m/s.

Given:

mass of fish = m₁ = 65 g

mass of drop of water = m₂ = 0.30 g

speed of water = v₂ = 2.5 m/s

initial speed of water = initial speed of archerfish = u₁ = u₂ = 0 m/s

Asked:

the speed of the archerfish = v₁ = ?

Solution:

We will use Conservation of Momentum Law as follows:

[tex]m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2[/tex]

[tex]65(0) + 0.30(0) = 65v_1 + 0.30(2.5)[/tex]

[tex]0 + 0 = 65v_1 + 0.75[/tex]

[tex]65v_1 = -0.75[/tex]

[tex]v_1 = -0.75 \div 65[/tex]

[tex]\boxed{v_1 \approx -0.012 \texttt{ m/s}}[/tex]

[tex]\texttt{ }[/tex]

The speed of the archerfish immediately after it expels the drop of water is about 0.012 m/s

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: High School

Subject: Physics

Chapter: Dynamics

(a) 138.2 J

Since the applied force is parallel to the displacement of the block, the work done by the force is given by:

[tex]W=Fd[/tex]

where

F = 46.7 N is the magnitude of the force

d = 2.96 m is the displacement of the block

Substituting the numbers into the equation, we find

[tex]W=(46.7 N)(2.96 m)=138.2 J[/tex]

(b) 45.1 J

In order to calculate the total energy dissipated among the floor and the block as thermal energy, we have to calculate the work done by the frictional force, which is

[tex]W_f = F_f d = (-\mu mg)d[/tex]

where[tex]\mu=0.635[/tex] is the coefficient of friction

m = 4.35 kg is the mass of the block

g = 9.8 m/s^2

d = 2.96 m is the displacement

and the negative sign is due to the fact that the frictional force has opposite direction to the displacement.

Substituting, we find

[tex]W_f =-(0.635)(4.35 kg)(9.8 m/s^2)(2.96 m)=-80.1 J[/tex]

The magnitude of this work is equal to the sum of the thermal energy dissipated between the floor and the block:

[tex]W_f = E_{floor}+E_{block}[/tex]

And since we know

[tex]W_f = 80.1 J\\E_{floor}=35.0 J[/tex]

we find

[tex]E_{floor}=W_f-E_{block}=80.1 J-35.0 J=45.1 J[/tex]

(c) 58.1 J

According to the work-energy theorem, the increase in kinetic energy of the block must be equal to the work done by the applied force minus the work done by friction (which becomes wasted thermal energy):

[tex]\Delta K=W-W_f[/tex]

Substituting

[tex]W=138.2 J\\W_f = 80.1 J[/tex]

We find

[tex]\Delta K=138.2 J-80.1 J=58.1 J[/tex]

The higher the frequency, the more energy the photon has. Of course, a beam of light has many photons. This means that really intense red light (lots of photons, with slightly lower energy)

When the cart arrives at any place that's 1.0 meter higher than where it started, its potential energy will be

(9.8) · (its mass on kilograms)  Joules .  

Potential Energy is given by the formula mass x gravity x height. The starting height is irrelevant in its calculation. The potential energy depends on the mass of the object, gravity and the elevated height.

The potential energy of an object is calculated by the formula Potential Energy = mass x gravity x height. Whenever the height of an object increases, its potential energy will increase as well provided mass and the  gravitational field (g) remain constant. Here, the starting height being 0.0 m is irrelevant to the calculation of potential energy at 1.0 m height. If the mass of the cart and the value of gravity (usually taken as 9.8 m/s2 on Earth's surface) are known, you can substitute those values into the formula to find the potential energy.

e.g. If the mass of the cart was 2 kg, the potential energy at a height of 1.0 m would be 2 kg x 9.8 m/s

2

x 1.0 m = 19.6 joules.

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Answer:

Yes

Explanation:

When a sound wave moves through the air, a point in the air undergoes alternative changes in density called compressions and rarefactions.

A sound wave is a longitudinal waves, which means that the vibrations of the particles in the medium occur in a direction parallel to the direction of motion of the wave. Longitudinal waves creates two different regions in the medium:

- Compressions: these are regions where the density of the particles of the medium (in this case, air particles) are higher

- Rarefactions: these are regions where the density of the particles of the medium (in this case, air particles) are lower

Speed = (distance covered) / (time to cover the distance)

Speed = (60 km) / (3.5 hr)

Speed = (60 / 3.5) (km/hr)

Speed = 17.14 km/hr

The only way of telling about dark energy is our observation of how the universe has been expanding. It basically works the opposite as gravity, pushing things away from it. Thus, the closest answer would be D. The shape of galaxies in cluster galaxies.

Answer:

D. The shape of galaxies in cluster galaxies

Explanation:

When the Universe began to expand, everything present in Universe began to move at a very high rate. This was concluded that some external force is working on it in order to pull these things. It was known  as the dark energy.

Thus the size and shape of galaxies is increasing because of this  dark energy, hence the study of change in shape and size of galaxy gives information about dark energy as it is constantly applying  force thus increasing the size.

Answer:

5.33 cm

Explanation:

The lens equation states that:

[tex]\frac{1}{f}=\frac{1}{p}+\frac{1}{q}[/tex]

where

f is the focal length

p is the distance of the object from the lens

q is the distance of the image from the lens

In this problem,

p = 8 cm

q = 16 cm ( the sign is positive since the image is real, which means it is formed on the other side of the lens)

Substituting into the equation,

[tex]\frac{1}{f}=\frac{1}{8 cm}+\frac{1}{16 cm}=\frac{3}{16 cm}[/tex]

[tex]f=\frac{16}{3}cm=5.33 cm[/tex]

Final answer:

Observational characteristics that could indicate a white dwarf or neutron star include being surrounded by a planetary nebula, emitting most strongly in visible and ultraviolet, and being in a binary system that undergoes nova explosions.

Explanation:

The observational characteristics that could indicate that an object is either a white dwarf or a neutron star are:

May be surrounded by a planetary nebula: A white dwarf can be surrounded by a planetary nebula, which is a glowing shell of gas and dust expelled by the dying star.

Emits most strongly in visible and ultraviolet: Both white dwarfs and neutron stars emit most of their energy in the visible and ultraviolet parts of the electromagnetic spectrum.

May be in a binary system that undergoes nova explosions: Some white dwarfs can be in a binary system where the companion star transfers material to the white dwarf, causing periodic nova explosions.

Answer:

C. red main-sequence star

Explanation:

Which of these stars has the hottest core?A)a blue main-sequence star. B)a red supergiant. C)a red main-sequence star.

Stars are basically exploding gases usually hydrogen and helium gases, held together by gravity. The closest to us is the sun. which contains gases

a blue main-sequence star temperature is between 10,000 Kelvin to 40000kelvin

red main-sequence star. can about 10million kelvin

while

B)a red supergiant is 3500-4500 K

Blue stars are generally the hottest, so a blue main-sequence star likely has the hottest core. The star's color provides insight into its core temperature.

The temperature of a star is typically indicated by its color, which can be used to infer information about its core. In general, blue stars are the hottest and red stars are the coolest. Therefore, of the options given, a blue main-sequence star likely has the hottest core. It's interesting to note that a star's core temperature can alter its life cycle stages, hence why we classify stars into different categories like main-sequence, supergiant and so on.

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Answer:

chlorine gas

Explanation:

Answer:

The gas is chlorine gas.

Explanation:

[tex]NaClO + 2 HCl \rightarrow Cl_2 + H_2O + NaCl[/tex]

Chlorine gas is a toxic gas and very reactive inside the human body. Also an irritant to eyes and skin. Exposure to high concentration leads to lung damage or death.

Where as the byproduct formed are water and sodium chloride which an aqueous solution of sodium chloride harmless to humans.

Substitute your values into the formula:

W = Work done = 288

[tex]Q_{in}[/tex] = 360

Solve to find e:

e = 288 ÷ 360 = 0.8

Convert e to a percentage by multiplying by 100.

0.8 × 100 = 80

Answer:Force on -7 uC charge due to charge placed at x = - 10cm

now we will have

towards left

similarly force due to -5 uC charge placed at x = 6 cm

now we will have

towards left

Now net force on 7 uC charge is given as

towards left

Explanation:

Using the equation E = hc/λ we can find out how much energy a single photon of wavelength 193 nm has. E = Planck Constant * Speed of Light/193 nm

Answer:

The number of photons is 4.8x10^14

Explanation:

The frequency of wave is equal to:

[tex]f=\frac{c}{l}[/tex]

where c is the speed of light, l is the wavelength of wave. Replacing values:

[tex]f=\frac{3x10^{8} }{193x10^{9} } =1.5x10^{15} Hz[/tex]

The energy of the proton is:

[tex]E=hf[/tex]

where h is the Planck´s constant. Replacing

[tex]E=6.626x10^{-34}*1.5x10^{5}=1.03x10^{-18} J[/tex]

The number of photons is:

[tex]n=\frac{E1}{E}[/tex]

where E1 is the energy of photon. Replacing:

[tex]n=\frac{0.5x10^{-3} }{1.03x10^{-18} }=4.8x10^{14}[/tex]

Explanation:

The law of repulsion is given by Coulomb. The mathematical form of Coulomb law is given by :

[tex]F=\dfrac{kq_1q_2}{r^2}[/tex]...............(1)

Where

F is the force

k is the electrostatic constant

[tex]q_1\ and\ q_2[/tex] are electric charges

r is the distance between charges

The Newton's law of universal gravitation is given by :

[tex]F=\dfrac{Gm_1m_2}{r^2}[/tex]..............(2)

G is the universal gravitational constant

From equation (1) and (2) it is clear that both law obeys inverse square law and both are of same type. So, the law of repulsion by Coulomb agrees with the Newton's law of universal gravitation.

The Law of Coulomb agrees with the inverse-square law and Newton's law of universal gravitation. It doesn't directly correspond with Newton's laws of motion or the findings of Gilbert on magnetism.

The Law of Coulomb is closely related to and agrees with the inverse-square law, which states that a specified physical quantity or intensity is inversely proportional to the square of the distance from the source of that physical property. This rule is also employed in Newton's law of universal gravitation.

However, the Law of Coulomb does not directly correspond or agree with Newton's laws of motion or the findings of Gilbert. Newton's laws of motion govern the relationship between the motion of an object and the forces acting upon it, while Gilbert's findings primarily concern magnetism.

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