At the player's maximum height, their velocity is 0. Recall that
[tex]{v_f}^2-{v_i}^2=2a\Delta y[/tex]
which tells us the player's initial velocity [tex]v_i[/tex] is
[tex]0^2-{v_i}^2=-2g(0.65\,\mathrm m)\implies v_i=3.6\dfrac{\rm m}{\rm s}[/tex]
The player's height at time [tex]t[/tex] is given by
[tex]y=v_it-\dfrac g2t^2[/tex]
so we find their airtime to be
[tex]0.65\,\mathrm m=\left(3.6\dfrac{\rm m}{\rm s}\right)t-\dfrac g2t^2\implies t=0.36\,\mathrm s[/tex]
During a skydiving landing, a parachute deploys from the back of the diver as it taxis back down to the Earth. The parachute helps the diver slow down before landing. How does the parachute help during this process? * 1 point It increases the weight of the shuttle. It increases the potential energy of the shuttle. It increases heat transfer by radiation. It increases friction by air resistance.
Your answer would be - It increases friction by air resistance.
Hope this helps you:)
Feel free if you want me to clarify something!
A parachute slows a skydiver's descent by increasing air resistance, acting against the skydiver's downward momentum. The parachute's increased surface area amplifies this resistance, significantly reducing speed for a safer landing.
Explanation:A parachute assists a skydiver during landing by increasing air resistance, which slows the skydiver's descent by increasing the upwards force of air pushing against the diver. The open canopy of the parachute expands the surface area against which the air pushes, thereby increasing the air resistance. Initially, the skydiver is in free fall, attaining a maximum or 'terminal' velocity depending on body position. For instance, terminal velocity can be as high as 350 km/h in a headfirst position. The deployment of the parachute dramatically reduces this speed due to the increased air resistance.
It's like dropping a baseball and a tennis ball from the same height at the same time; the baseball will hit the ground first due to less air resistance compared to the lighter tennis ball.
The parachute's role is essential to slow a skydiver's fall, reducing the risk of injury upon landing by decreasing the skydiver's change in momentum on impact.
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A 10.0g piece of copper wire, sitting in the sun reaches a temperature of 80.0 C. how many Joules are released when the copper cools to 40.0 C? The specific heat capacity of copper is 0.377 j/(g.C)
Answer:
150.8 J
Explanation:
The heat released by the copper wire is given by:
[tex]Q=mC_s \Delta T[/tex]
where:
m = 10.0 g is the mass of the wire
Cs = 0.377 j/(g.C) is the specific heat capacity of copper
[tex]\Delta T=40.0 C - 80.0 C=-40.0 C[/tex] is the change in temperature of the wire
Substituting into the equation, we find
[tex]Q=(10.0 g)(0.377 J/gC)(-40.0^{\circ})=-150.8 J[/tex]
And the sign is negative because the heat is released by the wire.
which of the following objects can you use to roughly visualize a length of 1 meter? the length of an ant on a sidewalk? the length of a 2 liter bottle of soda pop? the height of a kitchen counter? the length of a football field?
Which of the following is smaller than a single atom?
Proton
Molecule
Element
Solution
proton boisssssssssssssssssssssssssssssss
A transformer only works with which type of current?
split
direct
alternating
magnetic
Answer would be: alternating.There is no electrical connection between the two coils. These only work if alternating current is supplied to the main coil. If DC was supplied, there would be no flow of current in the minor coil.
Answer:
alternating
Explanation:
The transformer works on the principle of electromagnetic induction.
When a changing magnetic flux is linked with the coil, then an induced emf is produced.
When an alternating current is give to the primary coil, the magnetic flux linked with the coil changes, which linked to the secondary coil of the transformer and hence an induced emf is developed.
Which is the best example of the law of conservation of energy
Water is a good example of the law of conservation because, water when not moving has potential energy, and when moving like for example tap water, it turns kinetic.
The best example of the law of conservation of energy is the rolling skateboard that slows down because its kinetic energy changes to heat. This illustrates that energy is not created or destroyed but simply changes forms.
The law of conservation of energy states that energy cannot be created or destroyed, but it can be transferred or transformed from one form to another.
Option A is incorrect because the energy of the basketball does not disappear when it stops bouncing. Instead, the kinetic energy of the basketball is transformed into other forms of energy, such as sound and heat, when it hits the ground.
Option C is incorrect because the energy of the book is not destroyed when it falls to the ground. Instead, the potential energy of the book is converted into kinetic energy as it falls, and then some of that kinetic energy is transformed into sound and heat when it hits the ground.
Option D is incorrect because the ramp does not create energy for the toy car. Instead, the ramp converts some of the potential energy of the toy car into kinetic energy as it moves down the ramp.
Therefore, the best example of the law of conservation of energy is option B, where some of the kinetic energy of the skateboard is transformed into heat as it slows down. This illustrates the principle that energy cannot be destroyed, but can be transformed from one form to another.
Complete Question - Which is the best example of the law of conservation of energy?
A) A basketball stops bouncing because its energy disappears.
B) A rolling skateboard slows down because some of its kinetic energy changes to heat.
C) A falling book hits the ground and all of its energy is destroyed.
D) A toy car gains speed as it moves down a ramp because the ramp creates energy.
A conductor wire with length of 0.20 m and weight of 1.47 N is oriented perpendicularly to a magnetic field. If the current of 1.75A flows to the north, the net force on the wire is measured using a balance and found to be zero. What is the magnitude and direction of the magnetic field?
1. Magnitude: 4.4 T
The net force on the wire is zero, therefore the magnetic force must be equal to the weight of the wire:
[tex]F_M = W = 1.47 N[/tex]
Where the magnetic force is
[tex]F_M = IBL sin \theta[/tex]
where
I = 1.75 A is the current
B is the magnetic field
L = 0.20 m is the length of the wire
[tex]\theta=90^{\circ}[/tex] is the angle between the direction of L and B
Solving the formula for B, we find the magnitude of the magnetic field:
[tex]B=\frac{F_M}{ILsin \theta}=\frac{1.47 N}{(1.75 A)(0.20 m)(sin 90^{\circ})}=4.2 T[/tex]
2. Direction: westward
The direction is given by the right's hand rule. We know that:
- thumb --> magnetic force (upward)
- index finger --> current (north)
- middle finger --> direction of magnetic field: so, it must be westward.
- middle
How do you answer this. Need help ASAP. Offering 20 points !!!
in this since your volume remains at a constant you'll need to use Gay-Lussacs law, p1/t1=p2/t2.
your temp should be converted in kelvin
variables:
p1=3.0×10^6 n/m^2
t1= 270k
just add 273 to your celcius
p2= ? your solving for this
t2= 315k
then you set up the equation
(3.0×10^6)/270= (x)(315)
you then cross multiply
(3.0×10^6)315=270x
distribute the 315 to the pressure.
9.45×10^8=270x then you divide 270 o both sides to get
answer
3.5×10^6 n/m^2
what will not affect strength of a electromagnet?
Making the nail longer does not affect the strength of the electromagnet unless more coil is added to it.
What is electromagnet?Electromagnet is a form of magnet which has a magnetic field that is produced by an electric current. Electromagnets usually consist of wire wound into a coil.
Therefore, Making the nail longer does not affect the strength of the electromagnet unless more coil is added to it.
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Making the nail longer does not affect the strength of the electromagnet unless more coil is added to it.
What is electromagnet?Electromagnet is a form of magnet which has a magnetic field that is produced by an electric current. Electromagnets usually consist of wire wound into a coil.
The wire turns are often wound around a magnetic core made from a ferromagnetic or ferrimagnetic material such as iron; the magnetic core concentrates the magnetic flux and makes a more powerful magnet.
Electromagnets are widely used as components of other electrical devices, such as motors, generators, electromechanical solenoids, relays, loudspeakers, hard disks, MRI machines, scientific instruments
Therefore, Making the nail longer does not affect the strength of the electromagnet unless more coil is added to it.
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which of the following is true of a mechanical wave
- They require a physical medium to propagate.
- They can be described in terms of frequency, wavelength, and amplitude.
- They can be refracted, reflected, and diffracted.
- They can transfer energy from one point to another.
A coin placed at a focal point of a converging lens. is an image is formed? what is its nature?
A converging lens is a type of optical lens that is thicker at the center than at its edges; this type of lens concentrate or converge (that is why its name) at a point the rays of light that pass through it.
If we talk about the formation of the image, its location and nature will depend on where the object is located with respect to the focal length of the lens. So, in general:
- If the object is considerable away from the focal point, a real image (which can be projected on a screen) will be formed, inverted and smaller than the object.
-If the object is very close to the focal point, a virtual image will be observed (it is given this name because the image can not be projected on a screen) upright and bigger than the object.
Now, if the object is placed right at the focal point, the image would be formed at infinity (therefore, we would not see it) and its nature would be virtual.
According to this, the image of the coin will not be seen.
If the object is positioned at the focal point, the image is formed at infinity and its nature is virtual.
What is a lens?The term lens refers to any refracting surface. Recall that refraction is the bending of the light ray at the interval between two media.
The nature of the image formed by a lens depends on the position of the object. If the object is positioned at the focal point, the image is formed at infinity and its nature is virtual.
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The frequency of a wave is the inverse of the wave's _______?
period
velocity
amplitude
wavelength.
The frequency of a wave is the inverse of the wave's period.
(Instead of "inverse", the word "reciprocal" is more appropriate.
It means that [ frequency = 1/period ], and [ period = 1/frequency ].
The easiest way to remember both of these is to just remember that (frequency) x (period) = 1 .)
Answer:
period
Explanation:
the mass of the sled 329 kg, V=34m/s. What is the magnitude of the centripetal force that acts on the sled during the turn with radius of 33.0m?
Hello
The formula for centripetal force is:
Fc = m*[(V^2)/r]
Where
m = 329000 g
V = 34 m/s
r = 33 m
Then
Fc = (329000)*[(34^2)/33]
Fc = 11.524.969,7
Best regards
Lindsay has placed on object to the left of the lens, indicated by the bold line to project its image onto a screen. What actions would provide a clear image that is larger?
A)Move the object and image to the left.B)Move the object and image to the right.C)Move the object to the left and the screen to the right.D)Move the object to the right and the screen to the left.
b.Move the object and image to the right.
To obtain a clear image that is larger, Lindsay should move the object to the left and the screen to the right. Option C is correct.
What is the lens?A lens is a clear object made of glass or plastic that can bend (refract) and focus light.
When an object is placed to the left of a converging lens, a real and inverted image is produced on the other side of the lens. The size and position of the image are determined by the distance between the object and the lens, as well as the distance between the lens and the image.
To obtain a larger image, move the object closer to the lens or move the screen further away from the lens.. Moving the object and image to the right would make the image smaller, and moving the object and image to the left would not necessarily make the image larger or clearer.
Therefore, option C) Move the object to the left and the screen to the right is the correct answer to obtain a clear image that is larger.
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What is the difference between mass and weight? In at least three sentences, explain the difference and give an example.
Mass and weight are different. Mass is the measurement of how much matter an object has, while weight deals with the pull of gravity. For example, an astronaut floating in space is weightless, due to the limited influence of gravity. But he will still have mass, that is because mass and weight are different :)
Mass is entirely a property of the object. So the conditions and environment surrounding the object have no effect on it, and it doesn't change.
Weight is a measurement of the interaction between the object and its environment, so its weight changes as it moves from place to place.
Example:
A standard brass cylinder in a laboratory set of calibrated masses is marked "1 kilogram".
When you weigh it on Earth, the scale says "9.8 Newtons" or "2.2 pounds".
If you take the set of calibrated masses to the Moon with you, and weigh the same "1 kilogram" piece, it weighs "1.62 Newtons" or "5.8 ounces" up there.
if an object looks blue , it reflects_____ light
blue
Because, That object absorbs all colors light waves but does not absorbs Blue. So The blue light is reflected because it is not absorbed.
The molar mass of a gas
Answer:
dependent on the type of gas and the mass of a mole of the gas
Explanation:
_______ measures an object's change in position per unit time.
A) Distance
B)Force
C) Speed
I believe your answer should be C. Speed.
Answer:
C) Speed
Why?
Think of it like when youre on the road. Your speed is determined by miles per hour. Thats your speed. Hope this helps! Let me know if you don't understand.
A particle of mass 13 g and charge 45 μC is released from rest when it is 77 cm from a second particle of charge −11 μC. Determine the magnitude of the initial ac- celeration of the 13 g particle.
Answer:
[tex]577.7 m/s^2[/tex]
Explanation:
First of all, we need to calculate the electric force exerted on the particle. This is given by:
[tex]F=k\frac{q_1 q_2}{r^2}[/tex]
where:
k is the Coulomb's constant
[tex]q_1 = 45 \mu C=45 \cdot 10^{-6}C[/tex] is the charge of the particle
[tex]q_2 = -11 \mu C = -11 \cdot 10^{-6}C[/tex] is the charge of the second particle
[tex]r=77 cm=0.77 m[/tex] is the initial separation between the particles
Substituting,
[tex]F=(9\cdot 9 Nm^2C^{-2})\frac{(45\cdot 10^{-6}C)(-11 \cdot 10^{-6}C)}{(0.77 m)^2}=-7.51 N[/tex]
where the negative sign tells us that it is an attractive force. We can ignore it since we are only interested in the magnitude of the acceleration, which is given by
[tex]a=\frac{F}{m}[/tex]
where
m = 13 g = 0.013 kg is the mass of the particle
Substituting, we find
[tex]a=\frac{7.51 N}{0.013 kg}=577.7 m/s^2[/tex]
A box of mass 50 kg is pushed hard enough to set it in motion across a flat surface. Then a 99-N pushing force is needed to keep the box moving at a constant velocity. What is the coefficient of kinetic friction between the box and the floor?
0.23
0.20
0.18
0.17
Answer:
0.20
Explanation:
The box is moving at constant velocity, which means that its acceleration is zero; so, the net force acting on the box is zero as well.
There are two forces acting in the horizontal direction:
- The pushing force: F = 99 N, forward
- The frictional force: [tex]F_f=\mu mg[/tex], backward, with
[tex]\mu[/tex] coefficient of kinetic friction
m = 50 kg mass of the box
g = 9.8 m/s^2 gravitational acceleration
The net force must be zero, so we have
[tex]F-F_f = 0[/tex]
which we can solve to find the coefficient of kinetic friction:
[tex]F-\mu mg=0\\\mu = \frac{F}{mg}=\frac{99 N}{(50 kg)(9.8 m/s^2)}=0.20[/tex]
How is data not actually obtained from the experiment represented in a line graph?
with a double line
with only dots
with a colored line
with a broken line
20 POINTS!
With a broken line????????
Answer:
broken line
Explanation:
Suppose that two pith balls, each with a charge of 1 Coulomb, are hanging in the lab room, seperated by a distance of 1 meter, and applying a force on eachother. What will be the magnitude of the electrostatic force between them?
Using Coulomb's Law, the electrostatic force between two 1 Coulomb charges separated by 1 meter is calculated to be [tex]8.99 \times 10^9[/tex] Newtons. This significant repulsive force illustrates the power of electrostatic forces at even relatively large distances.
Calculating Electrostatic Force Between Two Charges
To determine the electrostatic force between two pith balls, each with a charge of 1 Coulomb, separated by a distance of 1 meter, we use Coulomb's Law. Coulomb's Law is given by the formula:
[tex]F = k \times (|q_1 \times q_2|) / r^2[/tex]
where:
F is the magnitude of the force between the chargesk is Coulomb's constant, approximately [tex]8.99 \times 10^9 N.m^2/C^2[/tex][tex]q_1[/tex] and [tex]q_2[/tex] are the charges (1 C each in this case)r is the distance between the charges (1 meter in this case)Substituting the given values:
[tex]F = 8.99 \times 10^9 N.m^2/C^2 \times (1C \times 1 C) / (1 m)^2[/tex]
This simplifies to:
[tex]F = 8.99 \times 10^9 N[/tex]
Air pressure is caused by the density of gas molecules in the air. Please select the best answer from the choices provided T F
Answer: The given statement is true.
Explanation:
Density is defined as mass per unit volume.
Mathematically, Density = [tex]\frac{mass}{volume}[/tex]
So, when more is the density of air molecules then it means there will be more mass per unit volume. This will lead to more number of collisions between the molecules. Hence, more will be the air pressure.
Thus, we can conclude that the statement air pressure is caused by the density of gas molecules in the air, is true.
Answer:
TRUE!
Explanation:
:)
When an object is lifted 12 meters off the ground, it gains a certain amount of potential energy. If the same object is lifted 36 meters off the ground, its potential energy is
Final answer:
Lifting an object to a greater height increases its gravitational potential energy. The potential energy is calculated as the product of the object's mass, gravitational acceleration, and height. Tripling the height triples the potential energy.
Explanation:
When an object is lifted higher off the ground, it gains gravitational potential energy proportional to its height above the ground. This potential energy (PE) depends on the mass of the object (m), the acceleration due to gravity (g), and the height (h) above the ground. For the given 1360 kg automobile, the potential energy can be calculated using the equation PE = mgh. If we know the car gains a certain amount of potential energy at a height of 12 meters, lifting it to 36 meters, or three times that height, will result in three times the potential energy. To demonstrate, let's say the car is lifted to 36.6 m, the potential energy will be PE = 1360 kg × 9.81 m/s² × 36.6 m.
If a boy (m = 25 kg) at rest on skates is pushed by another boy who exerts a force of 500 N on him and if the first boy's final velocity is 20 m/s, what was the contact time?
Answer:
1 second
Explanation:
The impulse exerted on the boy is equal to its change of momentum:
[tex]I = \Delta p\\F \Delta t = m \Delta v[/tex]
where
F = 500 N is the push on the boy
[tex]\Delta t[/tex] is the contact time
m = 25 kg is the mass of the boy
[tex]\Delta v = 20 m/s[/tex] is the change in velocity of the boy
Solving the formula for the contact time, we find
[tex]\Delta t=\frac{m\Delta v}{F}=\frac{(25 kg)(20 m/s)}{500 N}=1 s[/tex]
What causes the phases of our moon
sunlight, and the position of the earth
A ball is dropped from the roof of a building. If it takes 2.6s to reach the ground how tall is the building
To find the height of the building, we use the free-fall equation s = ut + ½ at² with the time of fall (2.6s), resulting in a height of approximately 33.18 meters.
To calculate the height of the building given that a ball is dropped and takes 2.6 seconds to reach the ground, we can use the equations of motion for an object in free fall. Assuming the initial velocity (u) is 0 m/s (since the ball is dropped) and acceleration (a) is due to gravity (g = 9.81 m/s²), the equation we use is:
s = ut + ½ at²
Where:
Plugging in the values, we have:
s = 0 m/s (2.6 s) + ½ (9.81 m/s²)(2.6 s)²
s = ½ (9.81 m/s²)(6.76 s²)
s = 4.905 m/s² × 6.76 s²
s = 33.1763 m
Therefore, the height of the building is approximately 33.18 meters.
15. A girl pushes a box that has a mass of 85 kg up an incline. If the giri exerts a force
of 200 N along the incline what is the mechanical advantage of the incline?
M.A = 4.25
Explanation;Mechanical advantage is the ratio of the force required to do something in comparison to the actual force required using a simple machine.
It is the ratio of output force to the input force.
M.A = Output Force/ Input Force
Out put force 85 Kg = 850 N
Input force = 200 N
Therefore;
M.A = 850 N/200 N
= 4.25
a 60 kg gila monster on a merry go round is travelling in a circle with a radius of 3 m at a speed of 2m/s
What is acceleration and net force and compare this with monster weight
Apply the equation for objects that move in circles:
[tex]a = \dfrac{v^2}{r}[/tex],
where
[tex]a[/tex] is the acceleration of the object, [tex]v[/tex] is the tangential speed of the object, and[tex]r[/tex] is the radius of the circular path.For this monster:
[tex]a[/tex] is to be found, [tex]v = 2\;m\cdot s^{-1}[/tex], and[tex]r = 3\;\text{m}[/tex].[tex]\displaystyle a = \frac{({2\;\text{m}\cdot\text{s}^{-1}})^{2}}{3\;\text{m}} = \frac{2^2}{3}\;\text{m}\cdot\text{s}^{-2}= 1.3\;\text{m}\cdot\text{s}^{-2}[/tex].
By Newton's Second Law,
[tex]\Sigma F = m\cdot a[/tex],
where
[tex]\Sigma F[/tex] is the net force on an object,[tex]m[/tex] is the mass of the object, and[tex]a[/tex] is the acceleration of the object.[tex]\Sigma F[/tex] is to be found,[tex]m = 60\;\text{kg}[/tex] for this monster, and[tex]a = 1.33333\;\text{m}\cdot\text{s}^{-2}[/tex] from previous calculations.[tex]\Sigma F = m\cdot a = 60\;\text{kg} \times 1.33333\;\text{m}\cdot\text{s}^{-2} = 80\;\text{N}[/tex].
Weight of an object near the surface of the earth:
[tex]W = m\cdot g[/tex],
where
[tex]m[/tex] is the mass of the object, and[tex]g[/tex] is the gravitational acceleration "constant" (a.k.a. gravitational field strength.) [tex]g \approx 9.81\;\text{N}\cdot\text{kg}^{-1}[/tex] near the surface of the earth.[tex]W = 60\;\text{kg} \times 9.81\;\text{N}\cdot\text{kg}^{-1}=5.9\times 10^{2} \;\text{N}[/tex].
think about something that has happened to you physically—a fall, a jump, an accident, or something you may have done hundreds of times in your favorite sport. Analyze the action and describe it in terms of Newton’s laws. Identify the initial conditions and the forces involved.
My best hobby is driving. Driving has something to do with Newton's first law of motion, which states that an object will continue to be in its state of rest or in uniform motion in a straight line unless it is acted upon by an external force. This law means that an object will continue to be in motion in the same direction unless it is acted upon by a force. Newton's first law of motion is also called the law of inertia.
I usually experience the law of inertia when I am driving my car.
Every morning, for me to move the car from its state of rest to a state of uniform motion, I have to switch on the ignition, which represent an unbalanced force that move the car out of its states of rest. When I am driving, the car continue in motion and in the same direction, unless I apply the brake. The application of the brake is an example of applying an unbalanced force to stop a body in motion.