A bunch of 6 bananas costs $3.54. What is the unit rate?

we have

[tex] y = -6x^{2} + 3x + 2 [/tex]

we know that

the vertex form of the vertical parabola equation is equal to

[tex] y=a(x-h)^{2} +k [/tex]

where

(h,k) is the vertex of the parabola

To find the equation rewritten in vertex form let's factor the equation

Factor the leading coefficient

[tex] y = -6(x^{2} - 0.5x) + 2 [/tex]

Complete the square. Remember to balance the equation by adding the same constants to each side

[tex] y = -6(x^{2} - 0.5x+0.0625-0.0625) + 2 [/tex]

[tex] y = -6(x^{2} - 0.5x+0.0625) + 2 +0.375 [/tex]

[tex] y = -6(x^{2} - 0.5x+0.0625) + 2.375 [/tex]

Rewrite as perfect squares

[tex] y = -6(x-0.25)^{2} + 2.375 [/tex]

therefore

the answer is

[tex] y = -6(x-0.25)^{2} + 2.375 [/tex]

Yes because

15/15 equals 1 whole

While 9/15 is not equal to one

Meaning 1 whole is bigger than 9 out of 15 of something

72.6 is 82.5 percent of 88. To find what percent 72.6 is of 88, divide 72.6 by 88 and then multiply by 100%. This gives you 82.5%, which means 72.6 is 82.5 percent of 88.

To find what percent 72.6 is of 88, you can use the formula:

Percentage = (Part / Whole) × 100%

In this case, the 'Part' is 72.6 and the 'Whole' is 88. Plugging these numbers into the formula:

Percentage = (72.6 / 88) × 100%

Percentage = 0.825 × 100%

Percentage = 82.5%

So, 72.6 is 82.5 percent of 88.

The degree of the function is one. Then function y = x will be a linear function.

A function is an assertion, concept, or principle that establishes an association between two variables. Functions may be found throughout mathematics and are essential for the development of significant links.

If the degree of the equation is one. Then the function will be a linear function.

The function is given below.

y = 1x

y = x

The power of the variables 'x' and 'y' will be one. Then the function is a linear equation.

The degree of the function is one. Then function y = x will be a linear function.

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Answer:

Option A is correct.

Step-by-step explanation:

In this figure we have to find the measurement of angle C.

As it clear from the picture the angle c is an acute angle which is less than 90° angle. We always measure the angles from the given point A. Therefore this is 50° angle.

So the answer would be option A. 50°.

Answer:

coincides with

Step-by-step explanation:

just got it right on edg

Vertical asymptotes at   x = {-2π, -π, 0, π, 2π}

Given:  [tex]y=csc(x)[/tex]

To find : For what values of x , it has vertical asymptotes.

Explanation:

A given function will have vertical asymptotes when its denominator becomes equal to zero.

We know that,    [tex]csc(x)=\frac{1}{sin x}[/tex]

So,  [tex]Sin(x)=0[/tex]  will give vertical asymptotes

       x = {-2π, -π, 0, π, 2π}

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Answer: it is false :)

Answer:

The correct option is 4. The average rate of change from x = −1 to x = −3 is -1.

Step-by-step explanation:

It is given that the graph of parabola going through (-1,7) and (-3,9).

It means the value of at x=-1 is 7.

[tex]f(-1)=7[/tex]

The value of at x=-3 is 9.

[tex]f(-3)=9[/tex]

The slope of a function f(x) for the interval [a,b] is

[tex]m=\frac{f(b)-f(a)}{b-a}[/tex]

We have to find the average rate of change from x = −1 to x = −3. Here a=-1 and b=-3. So the average rate of change from x = −1 to x = −3 is

[tex]m=\frac{f(-3)-f(-1)}{-3-(-1)}[/tex]

[tex]m=\frac{9-7}{-3+1}[/tex]

[tex]m=\frac{2}{-2}[/tex]

[tex]m=-1[/tex]

The average rate of change from x = −1 to x = −3 is -1. Therefore the correct option is 4.

To solve for t in the equation rt-2n=y, add 2n to both sides to get rt=y+2n, and then divide by r to find t=(y+2n)/r.

To solve the equation rt-2n=y for t, we need to isolate t on one side of the equation. Here's a step-by-step solution:

Thus, the value of t in terms of y, n, and r is t = (y + 2n) / r.

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Answer:

16

Step-by-step explanation:

The solution is, the practical domain is all real numbers from 5 to 7, inclusive. and the practical range is all real numbers from 58 to 81.2.

The domain of a function is the set of values that we are allowed to plug into our function. This set is the x values in a function such as f(x). The range of a function is the set of values that the function assumes. This set is the values that the function shoots out after we plug an x value in.

Here, we have,

Clarence works more than 5 hours and less than 7 so the practical domain is all real numbers from 5 to 7, inclusive.

Function: f(t) = 11.6 t

Restrictions: 5 ≤ t ≤ 7

Domain: possible values of t: all real values between 5 and 7 inclusive

Range: possible values of f(t): from 11.6 * 5 to 11.6 *7 = from 58 to 81.2, inclusive.

Using this domain, the practical range is:

From f(5) = 11.6(5) = 58

To f(7) = 11.6(7) = 81.2

inclusive.

Answer:

the practical domain is all real numbers from 5 to 7, inclusive. and the practical range is all real numbers from 58 to 81.2

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Calculating S'(5) and S'(25) involves estimating the slope of the tangent to the temperature-speed graph of Coho salmon at those temperatures. The provided data is insufficient for an exact calculation and more information or a graph is needed.

The influence of temperature on the maximum sustainable swimming speed (S) of Coho salmon can be analyzed using calculus to find the rate of change of speed with respect to temperature, commonly represented as S'(T). To estimate the values of S'(5) and S'(25), one would typically use a graph of S versus T and look for the slope of the tangent to the curve at T=5 and T=25.

However, the given data is insubstantial for such an analysis. More context or a graph is needed to provide a specific estimate. Generally, one might use the values given for S at temperatures nearby T=5 and T=25 to calculate the approximate rates of change at these points through the use of difference quotients or other numerical methods if a graph or formula is not available.

The maximum error in the area of a circle with an estimated radius of 14 inches and a measurement error of "+/-0.08 inches" can be calculated using differentials as approximately 7.03 inches².

To estimate the maximum error in calculating the area of a circle with a radius of approximately 14 inches (with a measurement error of "+/-0.08 inches"), we can use differentials. The formula for the area of a circle is A =
^(2), where π is a constant (approximately 3.14159). The differential dA, which represents the change in area, is given by dA = 2πr * dr, where dr is the change in radius.

With an error in radius measurement of"+/-0.08 inches", we have dr = 0.08 inches. Therefore, the error in the area, referenced as dA, can be calculated as:

dA = 2 * π * 14 inches * 0.08 inches

This gives dA ≈ 2 * 3.14159 * 14 * 0.08 inches², which can be calculated to determine the maximum error in the area.

After performing the calculation, we find that the maximum error in the area of the circle is about 7.03 inches².

The solution for the given equation is square root of 7. Therefore, option B is the correct answer.

In mathematics, an equation is a formula that expresses the equality of two expressions, by connecting them with the equals sign =.

The given equation is x²=7.

The solution of an equation is the set of all values that, when substituted for unknowns, make an equation true.

For the given equation x²=7, square root on both the sides.

That is, x=±√7

Therefore, the solution of the equation is x=±√7.

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A single six-sided die has specific outcomes for events: at most 2 consists of {1, 2}, rolling a 3 consists of {3}, and rolling an even number includes {2, 4, 6}.

When a single die is rolled, the possible outcomes for different events are as follows:

The event where the die comes up at most 2 includes the outcomes {1, 2}.

The event where the die comes up 3 includes the single outcome {3}.

The event where the die comes up even includes the outcomes {2, 4, 6}.

It is important to list all possible outcomes clearly to understand the probabilities for each event. For instance, the probability of each of these events can be calculated by counting the favorable outcomes and dividing by the total number of possible outcomes, which is 6 in the case of a single six-sided die roll.