Answer:
Explanation:
Given
Charge of [tex]Q=0.8\ nC[/tex]
Length of side of cube [tex]a=4\ m[/tex]
Total Flux through the cube [tex]\phi =\frac{Q}{\epsilon _0}[/tex]
[tex]\epsilon _0=8.854\times 10^{-12}\ C^2/N-m^2[/tex]
total Flux [tex]\phi=\frac{0.8\times 10^{-9}}{8.854\times 10^{-12}}[/tex]
[tex]\phi =90.35\ N-m^2/C[/tex]
As cube has 6 faces , so flux through each face will be similar
thus flux through each face [tex]\phi'=\frac{\phi }{6}[/tex]
[tex]\phi '=\frac{90.35}{6}=15\ N-m^2/C[/tex]
A particle beam is made up of many protons, each with a kinetic energy of 3.25times 10-15 J. A proton has a mass of 1.673 times 10-27 kg and a charge of 1.602 times 10-19 C. What is the magnitude of a uniform electric field that will stop these protons in a distance of 2 m?
Answer:
E = 1.024 x 10⁴ V/m
Explanation:
given,
KE of the particle = 3.25 x 10⁻¹⁵ J
mass of the proton = 1.673 x 10⁻²⁷ Kg
charge of the proton = 1.602 x 10⁻¹⁹ C
distance = 2 m
Electric field = ?
we know
work done = KE, and also
W = q V
now,
[tex]V = \dfrac{W}{q}[/tex]
[tex]V = \dfrac{3.25\times 10^{-15}}{1.602\times 10^{-19}}[/tex]
V = 2.028 x 10⁴ V
now, using equation of electric field
[tex]E = \dfrac{V}{d}[/tex]
[tex]E = \dfrac{2.028\times 10^4}{2}[/tex]
E = 1.024 x 10⁴ V/m
hence, the magnitude of the electric field is equal to E = 1.024 x 10⁴ V/m
Answer:
E = 1.024 x 10⁴ V/m
Explanation:
given,
KE of the particle = 3.25 x 10⁻¹⁵ J
mass of the proton = 1.673 x 10⁻²⁷ Kg
charge of the proton = 1.602 x 10⁻¹⁹ C
distance = 2 m
Electric field = ?
we know
work done = KE, and also
W = q V
now,
V = 2.028 x 10⁴ V
now, using equation of electric field
E = 1.024 x 10⁴ V/m
hence, the magnitude of the electric field is equal to E = 1.024 x 10⁴ V/m
During practice, a baseball player hits a very high fly ball, and then runs in a straight line and catches it. Which had the greatest displacement during the time period from the hitting of the ball to its catching
Answer:
The player and the ball have the same displacement
Explanation:
Displacement is the distance between the final position and initial position, When the ball is hit upwards, it is caught at the same height. The vertical displacement of the ball is zero. The horizontal displacement of the ball would be equal to the displacement of the player because the player runs in a straight line to catch the ball.
When we see Saturn going through a period of apparent retrograde motion, it means (a) Saturn is
temporarily moving backward in its orbit of the Sun. (b) Earth is passing Saturn in its orbit, with both
planets on the same side of the Sun. (c) Saturn and Earth must be on opposite sides of the Sun.
Answer:
b) Earth is passing Saturn in its orbit, with both planets on the same side of the Sun.
Explanation:
Retrograde motion is an optical effect due to the fact that Earth rotates more quickly than the planet that apparently has a retrograde motion in the sky.
For this particular case, Saturn has a slower speed in its orbit around the sun. That means that the Earth will pass it, and that will give the effect that the planet is moving backward. That same scenario can be seen between two cars on a highway, the faster car will see the slower car when it passes going in backward for a short fragment of time.
Remember that all the object in the night sky moves from east to west (since the Earth rotates counterclockwise in its daily movement), in the case of a planet with retrograde motion, it will move from west to east for a couple of months.
Apparent retrograde motion of Saturn occurs when Earth overtakes Saturn in their respective orbits around the Sun, creating the illusion that Saturn is moving backward (westward) against the star's background. This is a result of our perspective from Earth and not an actual reversal of Saturn's orbit.
Explanation:When we observe Saturn going through a period of apparent retrograde motion, it is not because Saturn is actually moving backwards in its orbit. Instead, this phenomenon occurs because Earth is passing Saturn in its orbit, with both planets on the same side of the Sun. As Earth, which moves faster in its orbit due to being closer to the Sun, overtakes Saturn, Saturn appears to move westward against the background stars. This westward motion is temporary and is perceived from Earth due to our vantage point.
As Earth continues in its orbit, reaching a point where the direct line of sight aligns with Saturn once more, Saturn will resume its normal prograde motion (eastward relative to the stars) in the night sky. This retrograde motion is much simpler to understand now with our knowledge of Earth and other planets orbiting the Sun, rather than from the historically held geocentric view which placed Earth at the center of the universe.
The water mass having both high salinity and warm temperature and found at about 1,000 meters water depth in the central north Atlantic has been formed
Answer:
In the Mediterranean sea
Explanation:
The water present in the deeper part of the North Atlantic ocean is warm and comprised of high salinity, and abundance in oxygen as well as rich in terms of nutrient ones. On the other hand, the opposite occurs in the southern part of the Atlantic ocean. This warm water is typically found up to a depth of about 1000 meters below the mean sea level.
This Atlantic ocean is directly connected to the Mediterranean sea through the Gibraltar Strait.
Therefore, this mass of water that is comprised of higher salinity and higher temperature that is found at a depth of 1000 meters in the northern part of the Atlantic ocean has been formed in the Mediterranean sea.
A boy and his dog are out for a morning excursion to the river, whichis located 4.0 km away. The boy walks briskly at 2.0 m/s in a straight line. The dog isunleashed and runs back and forth at 4.5 m/s between the boy and the river, until bothreach the river. What is the distance run by the dog?
Answer:
9 Km
Explanation:
given,
distance of the river = 4 Km = 4000 m
speed of the boy = 2 m/s
speed of the dog back and forth = 4.5 m/s
distance ran by the dog = ?
time taken by the boy to cover the distance
we know,
distance = speed x time
[tex]t = \dfrac{4000}{2}[/tex]
t = 2000 s.
now, distance travel by the dog.
d= 4.5 x 2000
d = 9000 m
d = 9 Km
distance covered by the dog is equal to 9 Km.
Krystal is exploring the properties of iron. She takes a large iron nail and finds that the nail does not attract other metal objects. Next, she uses a battery and copper wire to transform the nail into an electromagnet. When she connects the circuit, the nail becomes magnetic and can pick up small metal objects like paper clips. This is shown in the illustration below.
What best describes what has happened to the iron in the nail that causes it to become magnetic?
Explanation:
Iron has tiny magnetic domains inside it. Each domain acts like a tiny magnet with its own magnetic field. These domains are randomly distributed thus resulting in zero magnetic field and iron doesn't behave like a magnet.
When a copper wire is wound around the nail and current is passed through the coil, magnetic field is generated. This magnetic field penetrates through the nail. Due to this the magnetic domains of the nail align in the same direction thus having a net magnetic field. The nail behaves like a magnet till the time current flows through the coil.
The subfield of anthropology that describes, analyzes, interprets, and explains social and cultural similarities and differences is ______ anthropology.
Answer:
cultural
Explanation:
Cultural anthropology studies the characteristics of the behavior learned in human societies, that is, science of human culture. In general, it is the science that studies the origin, development, structure, characteristics and variations of human culture in both past and present societies. Ethnography, ethnology, archeology, linguistics and physical anthropology are the disciplines on which cultural anthropology is founded.
a square solar collector measures 6.00 m by 6.00 m and another solar collector measures 8.000 m by 8.000 m. using the correct number of significant figures what is the combined area of both collectors?
a) 1.00×10^2
b) 1.0 ×10^2
c)1×10^2
d) 1.000x10^2
e) 1.0000x10^2
Answer: [tex]1.000\times 10^2m^2[/tex]
Explanation:
Significant figures : The figures in a number which express the value -the magnitude of a quantity to a specific degree of accuracy is known as significant digits.
The rule apply for the multiplication and division is :
The least precise number present determines the number of significant figures in the answer.
The rule apply for the addition and subtraction is :
The least precise number present after the decimal point determines the number of significant figures in the answer.
Area of square collector 1 =
Area of square collector 1 =[tex]6.00m\times 6.00m=36.0m^2[/tex]
Area of square collector 2 =[tex]length\times breadth[/tex]
Area of square collector 2 =[tex]8.000m\times 8.000m=64.00m^2[/tex]
Combined area of both collectors = Area of square collector 1 + Area of square collector 2 = [tex]36.0m^2+64.00m^2=100.0m^2=1.0\times 10^2m^2[/tex]
The combined area of both collectors is [tex]1.000\times 10^2m^2[/tex]
The combined area of both solar collectors is 1.0 × 10² m².
Explanation:To find the combined area of both solar collectors, simply add the areas of the two squares. The formula for the area of a square is length multiplied by width. For the first solar collector measuring 6.00 m by 6.00 m, the area is 6.00 m x 6.00 m = 36.00 m². To find the combined area of both solar collectors, simply add the areas of the two squares. The formula for the area of a square is length multiplied by width. For the first solar collector measuring 6.00 m by 6.00 m, the area is 6.00 m x 6.00 m = 36.00 m². For the second solar collector measuring 8.000 m by 8.000 m, the area is 8.000 m x 8.000 m = 64.00 m². Adding the areas, we get 36.00 m² + 64.00 m² = 100.00 m².The correct answer, using the correct number of significant figures, is therefore 1.0 × 10² m². This answer is represented by option b.For the second solar collector measuring 8.000 m by 8.000 m, the area is 8.000 m x 8.000 m = 64.00 m². Adding the areas, we get 36.00 m² + 64.00 m² = 100.00 m².
The correct answer, using the correct number of significant figures, is therefore 1.0 × 10² m². This answer is represented by option b.
Why is it inaccurate to use mgy to calculate the potential energy of a satellite orbiting earth at a height one earth radius above the earth's surface
The formula U = mgy is not accurate for calculating the gravitational potential energy of a satellite orbiting at a significant height because g is not constant at such distances. Instead, the formula U = -GMm/r should be used. This reflects the gravitational potential becoming more negative at larger distances, which means orbits at those distances are bound due to the total energy remaining negative.
Explanation:It's inaccurate to use the simple formula U = mgy to calculate the gravitational potential energy of a satellite orbiting Earth at a significant height because this formula assumes that the gravitational acceleration (g) is constant. However, g varies with altitude and is less at higher altitudes. For satellites in orbit, especially at a height of one Earth radius above the surface, we need to use a more general expression that accounts for the change in g with distance from the center of Earth.
The correct formula for calculating the gravitational potential energy (GPE) of a satellite at a distance r from the center of Earth (where r is significantly greater than the Earth's radius) is derived from the law of universal gravitation and is U = -GMm/r, where G is the gravitational constant, M is the mass of Earth, and m is the mass of the satellite.
This more general expression shows that at large distances, GPE becomes increasingly negative, approaching zero as r becomes infinitely large. A satellite with negative total energy is in a bound orbit because the kinetic energy (which is always positive) is not enough to overcome the magnitude of the negative GPE, hence the satellite remains gravitationally bound to Earth. As for the trend in the ratio of kinetic energy to the change in potential energy as the size of the orbit increases, it generally decreases, indicating that for larger orbits, the kinetic energy constitutes a larger fraction of the total energy needed to maintain the orbit.
The assumption made in this derivation is that the satellite orbits around the center of the astronomical body (such as Earth), and not around a common center of mass, which is not exact but works well since Earth is much more massive compared to the satellite, as in the case of the Moon orbiting the Earth.
A red train traveling at 72 km/h and a green train traveling at 144 km/h are headed toward each other along a straight, level track. When they are 920 m apart, each engineer sees the other's train and applies the brakes. The brakes slow each train at the rate of 1.0 m/s2. Is there a collision? If so, give (a) the speed of the red train, (b) the speed of the green train, and (c) the separation between the trains when they collide (0 m). If not, give (a) the speed of the red train (0 m/s), (b) the speed of the green train (0 m/s), and (c) the separation between the trains when they stop.
Final answer:
The red and green trains apply brakes with a deceleration of 1.0 m/s^2 when 920 m apart, and will stop without colliding, leaving a separation of 80 m.
Explanation:
When the red train traveling at 72 km/h and the green train traveling at 144 km/h are 920 meters apart and both apply brakes with a deceleration of 1.0 m/s2, we can calculate whether a collision will happen.
First, convert the speeds from km/h to m/s: the red train's speed is 20 m/s (72 km/h) and the green train's speed is 40 m/s (144 km/h).
Next, calculate the stopping distance for both trains using the formula s = v2 / (2a), where v is the initial speed and a is the deceleration. For the red train: s = (20 m/s)2 / (2 x 1 m/s2) = 200 m. For the green train: s = (40 m/s)2 / (2 x 1 m/s2) = 800 m.
The total stopping distance for both trains is 200 m + 800 m = 1000 m. Since they start 920 m apart, they will not collide because their combined stopping distance is greater than the initial separation.
Thus, (a) the speed of the red train when they stop will be 0 m/s, (b) the speed of the green train will be 0 m/s, and (c) the separation between the trains when they stop will be 80 meters.
When opening a door, you push on it perpendicularly with a force of 46.0 N at a distance of 0.740 m from the hinges. 1. What torque (in N·m) are you exerting relative to the hinges?2. Does it matter if you push at the same height as the hinges? There is only one pair of hinges.
Answer:
given,
Force acting perpendicularly to the door = 46 N
distance from the hinge = 0.740 m
we know,
torque = Force x distance
τ = F x r
τ = 46 x 0.740
τ = 34.04 N.m
b) No it does not matter if we push at the same height as the hinges.
now, From the expression we can clearly see that what matters is the perpendicular distance from the point of force application.
A pot of water on the stove has a temperature increase of 45 C. How much is that temperature increase in degrees Fahrenheit?
1. 25 degrees F increase2. 113 degrees F increase3. 57 degrees F increase4. 77 degrees F increase5. 81 degrees F increase
Answer:
2. 113 degrees F increase
Explanation:
Formula for converting °C to °F is
(°C × 9/5)+32
Where °C is the temperature value in degree Celsius. Given temperature to be 45°C, converting to °F we have;
(45°C × 9/5) + 32
= 81+32
= 113°F
If your volume measurement is only good to two significant figures, will your results be more precise if you use mass measurements that have six significant figures. Is it true?
Using mass measurements with six significant figures does not increase the precision of your results if your volume measurement is only accurate to two significant figures, due to the rule that in multiplication or division, the result must be reported with the same number of significant figures as the measurement with the least number of significant figures.
Explanation:If your volume measurement is only good to two significant figures, will your results be more precise if you use mass measurements that have six significant figures? The answer is no. When determining the precision of your results in chemistry, particularly in calculations involving volume and mass, it is vital to understand the rules governing significant figures. According to these rules, when performing multiplication or division, the result should be reported with the same number of significant figures as the measurement with the least number of significant figures. For instance, if a calculation involving the density formula (density = mass/volume) uses a mass with six significant figures and a volume with only two, the final density value should be expressed with two significant figures.
This principle ensures that the precision of your results reflects the precision of the least precise measurement. It prevents the false impression of greater accuracy than the measurements allow. Therefore, even if your mass measurements are incredibly precise, having six significant figures, the precision of your results will still be limited by the two significant figures in your volume measurement. This rule highlights the importance of consistency in measurement precision for enabling accurate and reliable scientific work. The concept of significant figures serves as a fundamental aspect of data analysis and reporting in chemistry, ensuring that reported results accurately reflect the uncertainties inherent in experimental measurements.
A wave on a string is described by
D(x,t)=
(2.00cm)sin[(12.57rad/m)x?(638rad/s)t],
1. where x is in m and t is in s. The linear density of the string is 5.00g/m.
2. What is the string tension?
3. What is the maximum displacement of a point on the string?
4. What is the maximum speed of a point on the string?
Explanation:
A wave on a string is described is given by :
[tex]D(x,t)=2\ cm\ sin[(12.57\ rad/m)-(638\ rad/s)t][/tex]
The linear density of the string is 5 g/m.
Where
x is in meters and t is in seconds
The general equation of a wave is given by :
[tex]y=A\ sin(kx-\omega t)[/tex]
(2) The speed of the wave in terms of tension is given by :
[tex]v=\sqrt{\dfrac{T}{\mu}}[/tex]
Also, [tex]v=\dfrac{\omega}{k}[/tex]
So, [tex]\dfrac{\omega}{k}=\sqrt{\dfrac{T}{\mu}}[/tex]
[tex]T=\dfrac{\mu \omega^2}{k^2}[/tex]
[tex]T=\dfrac{5\times 10^{-3}\times (638)^2}{(12.57)^2}[/tex]
T = 12.88 N
(3) The maximum displacement of a point on the string is equal to the amplitude of the wave. So, the maximum displacement is 2 cm.
(4) The maximum speed of a point on the string is given by :
[tex]v=A\omega[/tex]
[tex]v=0.02\times 638[/tex]
v = 12.76 m/s
Hence, this is the required solution.
Old Faithful geyser in Yellowstone National Park shoots water every hour to a height of 40.0 m. With what velocity does the water leave the ground? (Disregard air resistance. g 9.81 m/s) a. 7.00 m/s c. 28.0 m/s d. 14.0 m/s b. 19.8 m/s 30.) A moderate force will break an egg. However, an egg dropped on the road usually breaks, while one dropped on the grass usually does not break because for the egg dropped on the grass, a. the b. the change in momentum is greater. time interval for stopping is greater. the change in momentum is less the time interval for stopping is less. . c. d.
Answer:
a) [tex]v \approx 28.010\,\frac{m}{s}[/tex], b) B. Time interval for stopping is greater.
Explanation:
a) The initial velocity is found with the help of the Principle of Energy Conservation:
[tex]K = U_{g}[/tex]
[tex]m\cdot g \cdot h = \frac{1}{2}\cdot m \cdot v^{2}[/tex]
[tex]v = \sqrt{2\cdot g \cdot h}[/tex]
[tex]v = \sqrt{2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (40\,m)}[/tex]
[tex]v \approx 28.010\,\frac{m}{s}[/tex]
b) According to the Impact Theorem, the egg does not break on the grass since contact force is significantly lower and time interval is greater. Hence, the right answer is option B.
1) The water leaves the ground at a velocity of 28 m/sec. Therefore the correct option is B).
2) An egg dropped on the road usually breaks, while one dropped on the grass usually does not break because contact force is significantly lower and time interval is greater.
Given :
Yellowstone National Park shoots water every hour to a height of 40 m.
Solution :
1) From conservation of momentum -
KE = PE
[tex]\rm \dfrac{1}{2}mv^2 = mgh[/tex]
[tex]\rm v = \sqrt{2gh}[/tex] --- (1)
where,
[tex]\rm g = 9.8\;m/sec^2[/tex]
h = 40 m
Now put the values of g and h in equation (1) we get,
[tex]\rm v = \sqrt{2\times 9.8\times 40}[/tex]
v = 28 m/sec
2) According to the impact theorem, the egg does not break on the grass since contact force is significantly lower and time interval is greater. Therefore, the correct option is B).
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If three of 3 ohms, 5 ohms, and 22 ohms are connected in series in a 28-volt circuit, how much current will flow through the 3-ohm resistor?A - 9.3 amperesB - 1.05 amperesC - 0.93 amperes
Explanation:
We know that in series connection current in all the resistors are same.
Effective resistance is sum of individual resistances.
Here three of 3 ohms, 5 ohms, and 22 ohms are connected in series in a 28-volt circuit
Effective resistance = 3 + 5 + 22 = 30 ohms
Voltage = 28 V
We know
Voltage = Current x Resistance
V = IR
28 = 30 x I
I = 0.93 A
Current in each resistor is 0.93 A
Option C is the correct answer.
In a study, the data you collect is Habits on a Always/Sometimes/Never scale. What is the level of measurement? nominal ordinal interval ratio
Answer:
It's an ORDINAL Level of measurement.
The level of measurement for data collected on a Always/Sometimes/Never scale is ordinal.
Explanation:The level of measurement for data collected on a Always/Sometimes/Never scale is ordinal. In an ordinal scale, data can be categorized and ordered, but the intervals between data points may not necessarily be equal or meaningful. In this case, the habit categories would have a natural order (Always, Sometimes, Never), but the difference between Always and Sometimes may not be the same as the difference between Sometimes and Never.
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An observer sees a lightning flash from a distant thunder-storm and 12 seconds later hears the sound. if the temperature of the air is 20 c, how far from the storm is the observer?
Answer:
The answer is 3597501.48 km
Explanation:
The speed of light is 299792 km/s.
The speed of sound is 0.343 km/s
The difference is 299791.76 km/s
and of there is 12 second difference between sound and the light. The distance will be:
[tex]299791.76*12=3597501.48[/tex]
It should be far from the storm is the observer is 3597501.48 km.
Air Temperature:It measured how hot or cold the air should be. It explained the kinetic energy, or energy of motion, of the gases that make up air. Since gas molecules move faster due to which there is an increment in the air temperature
Since the temperature of the air is 20c and there is 12 seconds.
Also,
The speed of light is 299792 km/s.
The speed of sound is 0.343 km/s
The difference is 299791.76 km/s
Now it is
[tex]= 299791.76 km/s \times 12[/tex]
= 3597501.48 km
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When a cold alcohol-in-glass thermometer is first placed in a hot tub of water, the alcohol initially descends a bit and then rises. Explain.
Answer:
Wen we place a cold alcohol in glass in a hot tub of water then the glass will be warmed first so it will expand a little due to which the level of alcohal decreases. After some time when thermal equilibrium is achevied then the alcohol will expand more then glass as the alcohol has the greater coeficient of expansion then glass so there will be an incerease in the level of alcohol which will indicate how much high the temperature is.
Explanation:
The alcohol level in a thermometer initially drops when placed in hot water because the glass expands first, temporarily increasing the volume before the alcohol heats up and rises. This illustrates the principle of thermal expansion.
When a cold alcohol-in-glass thermometer is initially placed in a hot tub of water, the column of alcohol first descends slightly before rising. This phenomenon can be explained by the principles of thermal expansion.
Initially, the cold glass of the thermometer comes into contact with the hot water. Because the glass directly touches the hot water, it heats up faster than the alcohol inside. Glass has a lower thermal conductivity compared to alcohol, so it responds quicker to the temperature change. As the glass heats up, it expands slightly. This initial expansion of the glass causes a temporary increase in the volume inside the thermometer, making the alcohol level drop slightly.After a brief moment, the alcohol begins to heat up and expand. The alcohol expands much more than the glass due to its higher coefficient of thermal expansion. As the alcohol expands, it rises up the narrow tube, indicating an increase in temperature.This behavior demonstrates the concept of thermal expansion where different materials expand at different rates when subjected to temperature changes. Understanding this concept helps explain the movement of the alcohol column within the thermometer.A man 6 feet tall walks at a rate of 5 feet per second away from a light that is 15 feet above the ground. When he is 10 feet from the base of the light, a) at what rate is the tip of his shadow moving?
Answer:
[tex]\frac{25}{3}ft/s[/tex]
Explanation:
Height of man= 6ft
Height of light=1 5ft
Let BC=x and CD=y
BD=x+y
Triangle ABD and ECD are similar
When two triangles are similar then the ratio of their corresponding sides are equal
[tex]\frac{AB}{EC}=\frac{BD}{CD}[/tex]
[tex]\frac{15}{6}=\frac{x+y}{y}[/tex]
[tex]\frac{5}{2}=\frac{x+y}{y}[/tex]
[tex]5y=2x+2y[/tex]
[tex]5y-2y=2x[/tex]
[tex]3y=2x[/tex]
Differentiate w.r.t t
[tex]2\frac{dx}{dt}=3\frac{dy}{dt}[/tex]
We have [tex]\frac{dx}{dt}=5ft/s[/tex]
Substitute the value then we get
[tex]2\times 5=3\frac{dy}{dt}[/tex]
[tex]\frac{dy}{dt}=\frac{2\times 5}{3}=10/3ft/s[/tex]
Rate at which the tip of shadow is moving=[tex]\frac{dx}{dt}+\frac{dy}{dt}[/tex]
Rate at which the tip of shadow is moving=[tex]5+\frac{10}{3}=\frac{15+10}{3}ft/s[/tex]
Rate at which the tip of shadow is moving=[tex]\frac{25}{3}ft/s[/tex]
A pumper is supplying a 400-foot hoseline with 120 gpm flowing. The hoseline is composed of 250 feet of 2½-inch hose reduced to 150 feet of 1½-inch hose. If the fire is located in sub-basement level 3, what is the total pressure loss in the hose assembly?
Answer:
It's answer : 44 atm
Explanation:
A fly wheel with a diameter of 1.20m is rotating at an angular speed of 200 Rev/min
(a) what is the angular speed of the flywheel in radians per second be
(b)what is the linear speed of a point in the rim of the flywheel
(c) what constant angular acceleration
Answer:a) 20.944rad/s (b) 12.57m/s (c) 800rev/min²
Explanation:
Final answer:
The angular speed of the flywheel in radians per second is 20π/3 radians/s. The linear speed of a point in the rim of the flywheel is 40π/9 m/s. The constant angular acceleration of the flywheel cannot be determined without additional information.
Explanation:
(a) To convert the angular speed from revolutions per minute (rpm) to radians per second, we need to multiply by a conversion factor of
2π radians = 1 revolution
First, convert the angular speed from rpm to revolutions per second:
200 rev/min × (1 min/60 s) = 200/60 rev/s
Next, convert the revolutions per second to radians per second:
200/60 rev/s × (2π radians/1 rev) = 20π/3 radians/s
So, the angular speed of the flywheel in radians per second is 20π/3 radians/s.
(b) The linear speed of a point on the rim of the flywheel can be calculated using the formula:
Linear speed = angular speed × radius
Given that the diameter of the flywheel is 1.20 m, the radius is 0.60 m.
Linear speed = (20π/3 radians/s) × (0.60 m) = 40π/9 m/s
So, the linear speed of a point in the rim of the flywheel is 40π/9 m/s.
(c) The flywheel has a constant angular acceleration if its angular velocity changes at a constant rate over time. The formula for angular acceleration is:
Angular acceleration = change in angular velocity / change in time
Since the question does not provide information about the change in angular velocity or time, we cannot determine the constant angular acceleration of the flywheel.
If we want to find the height of an object like a flagpole, we can use triangles. In the graphic above, triangle ABE is similar to triangle ACD. In the graphic line segment DC is the height of the . Using the length of BE (your height), AB (your shadow), and AC (the shadow of flagpole), we can use a proportion to determine the height of the .
Answer:
[tex]\displaystyle CD=BE\ \frac{CA}{BA}[/tex]
Explanation:
Thales Theorem
It applies when a line is drawn parallel to one side of a triangle and it intersects the other two sides. The theorem states that line divides the two sides in the same ratio or proportion.
We have drawn the triangle that describes the situation stated in the question, where we want to know the value of CD, knowing the values of BE, BA, and CA. The red line BE is parallel to the line CD, so the Tales theorem must stand meaning that the sides AC and AB are proportionally divided at the same ratio as CD and BA, thus
[tex]\displaystyle \frac{CD}{BE}=\frac{CA}{BA}[/tex]
We can solve for CD (the height of the flagpole)
[tex]\boxed{\displaystyle CD=BE\ \frac{CA}{BA}}[/tex]
Answer:If we want to find the height of an object like a flagpole, we can use right triangles. In the graphic above, triangle ABE is similar to triangle ACD. In the graphic line segment DC is the height of the flagpole. Using the length of BE (your height), AB (your shadow), and AC (the shadow of flagpole), we can use a proportion to determine the height of the flagpole.
Explanation: fill in the blank
Objects 1 has half the mass of object 2 and the objects move toward each other and experience an inelastic collision. If both objects do not move after the collision compare the velocity of both objects before the collision.
Answer:
Explanation:
Given
Object 1 is of mass [tex]\frac{m}{2}[/tex]
Object 2 has mass of [tex]m[/tex]
They undergone inelastic collision and do not move after collision i.e. the collision is perfectly inelastic
Final momentum of both the object is zero
suppose [tex]v_1[/tex] and [tex]v_2[/tex] are the velocities of object 1 and 2 respectively then
[tex]m_1v_1+m_2v_2=0[/tex]
[tex]\frac{v_1}{v_2}=-\frac{m_2}{m_1}[/tex]
[tex]\frac{v_1}{v_2}=-2[/tex]
[tex]v_1=-2v_2[/tex]
i.e. velocity of object 1 is twice the velocity of object 2 but opposite to the direction of object 2
The comparison of the velocity of both objects before the collision is [tex]u_1=-2u_2[/tex]
According to the law of conservation of momentum, the momentum of a body before collision is equal to the momentum after collision. Mathematically;
[tex]m_1v_1 + m_2u_2=m_1v_1+m_2v_2[/tex]
Since both objects do not move after the collision, the equation becomes:
[tex]m_1v_1 + m_2u_2=0[/tex]
Also if Objects 1 has half the mass of object 2, then [tex]m_1=0.5m_2[/tex]
Substitute into the formula above:
[tex]0.5m_2u_1 + m_2u_2=0\\0.5m_2u_1 =-m_2u_2\\0.5u_1=-u_2\\u_1=-2u_2[/tex]
The comparison of the velocity of both objects before the collision is [tex]u_1=-2u_2[/tex]
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Suppose wave pulses in an aquarium are produced by a mechanical motor that moves a bob up and down at the surface. The setup uses a 10-W motor and has a period of 1.9 s between bobs. How much kinetic energy is in each pulse.
Answer:
kinetic energy in each pulse = 9.5J
Explanation:
The concept used here is that of work, energy and power.Power P = Work /TimeWork = energy in this caseE = Power x time = Ptbut Power = 10W and t = 1.9sEnergy E = 10W x 1.9s = 19JConventionally, overall energy = kinetic + potential
Hence kinetic energy in each pulse = half of the total energy = 0.5 x 19
energy = 9.5J
The kinetic energy is in each pulse is 19J.
The Power delivered is defined at the rate of work done, if P be the power, W be the work done and t be the time for which the work is done then:
P = W/t
W = Pt
given that P = 10w and t = 1.9s
W = 10×1.9 J
W = 19J
Now, the work done is equal to the change in Kinetic energy (KE)
ΔKE = W = 19J
Hence, the kinetic energy is 19J.
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A plastic rod is charged up by rubbing a wool cloth, and brought to an initially neutral metallic sphere that is insulated from ground. It is allowed to touch the sphere for a few seconds, and then is separated from the sphere by a small distance. After the rod is separated, the rod:A) is repelled by the sphere.B) is attracted to the sphere.C) feels no force due to the sphere.I know the answer is A, but I don't understand why. how do we know that the sphere and the rod have the same charge? What does it mean to be insulated from the ground?
Answer:
You are right. The answer to this question is option A. The metallic sphere is a conductor and can allow electric charges flow through it from one region to another. The reason the sphere is insulted from the ground is to block out the transfer of charges from the sphere to the ground or from the ground to the sphere. The ground itself can serve as infinitely large sink or source for electric charges.
The act of touching the sphere with the charged rod deposits some electric charge on the sphere. These charges in the absence of an insulator between the sphere and the ground will flow straight into the ground. But because there is an insulator connected to the sphere the charges remain on the sphere with no way of getting out of the sphere.
These charges are the same with that on the rod as they were conducted and not induced by polarization (in general if the shepre became charged by polarization, it would have a charge opposite that on the rod). Since like charges repeatedly and unlike charges attract. The sphere would always repel the rod.
Thank you for reading and I hope this was helpful to you.
When the plastic rod is charged and brought close to the neutral metallic sphere, charges are redistributed. After touching and separating, the rod is repelled by the sphere due to the imbalance of charges. Insulating the sphere from the ground prevents charge redistribution.
Explanation:When the plastic rod is rubbed with a wool cloth, it becomes charged and gains electrons. The charged rod is brought close to the initially neutral metallic sphere, which causes a redistribution of charges on the sphere's surface. Electrons in the sphere are attracted to the positively charged rod, causing an imbalance of charges.
When the rod touches the sphere, electrons from the sphere are transferred to the rod, neutralizing the rod's charge. The sphere gains a negative charge due to the excess electrons it lost to the rod. When the rod is separated from the sphere, it is now negatively charged and repelled by the negatively charged sphere.
Insulating the sphere from the ground means that the sphere is not in contact with any conductive material that can provide or receive charge. This ensures that the charge on the sphere remains constant and does not redistribute to the ground, allowing for the charge redistribution between the rod and the sphere.
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10. A worker uses a pulley system to raise a 24.0 kg carton 16.5 m. A force of 129 N is exerted and the rope is pulled 33.0 m. a. What is the mechanical advantage of the pulley system?
Answer: Machanical advantage of the machine is 1.86
Explanation: Machanical advantage of a machine is the ratio of the Force to overcome which is the load in this case 24kg * 10= 240N to the force exerted(Effort) to overcome the load in this case 129N.
So, we have
MA = load/effort
= 240N/129N
= 1.86.
The mechanical advantage of the pulley system is equal to 1.82.
Given the following data:
Mass of carton = 24 kgLoad distance = 16.5 mEffort = 129 NewtonEffort distance = 33 mScientific data:
Acceleration due to gravity = 9.8 [tex]m/s^2[/tex]To determine the mechanical advantage of the pulley system:
First of all, we would calculate the force acting on the load as follows;
[tex]Force = mg\\\\Force = 24 \times 9.8[/tex]
Force = 235.2 Newton
Now, we can solve for mechanical advantage:
[tex]M.A = \frac{Load}{Effort} \\\\M.A=\frac{235.2}{129}[/tex]
Mechanical advantage = 1.82.
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A cart is pushed to the right with a force of 15 N while being pulled to the left with a force of 20 N. The net force on the cart is?
The net force of the cart when it is pushed to the right with a force of 15N.
Explanation:
To find the force of net, which is calculated by the formula.
The Net Force= Addition of the force applied on the respective direction.
The Net Force here is given by
The Net Force = 15-20 (A force towards the right and a force towards left, two opposite so subtraction).
Hence
Thus the Net Force = -5(The force towards left, so it gets a negative value).
The net force on the cart is -5 N, which means the cart is experiencing a force of 5 N in the opposite direction of its motion.
Explanation:The net force on the cart can be found by subtracting the force pulling the cart to the left from the force pushing the cart to the right. In this case, the force pushing the cart to the right is 15 N and the force pulling the cart to the left is 20 N. So, the net force on the cart is:
Net force = Force pushing to the right - Force pulling to the left
Net force = 15 N - 20 N
Net force = -5 N
The net force on the cart is -5 N, which means the cart is experiencing a force of 5 N in the opposite direction of its motion.
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When energy from the Sun reaches the air above land, the air warms and rises. Along a coastline, cooler air above the ocean flows towards land to replace this rising air. What types of heat transfer are taking place during this process?
Answer:
convection
Explanation:
Convective heat transfer, often referred to simply as convection, is the transfer of heat from one place to another by the movement of fluids. this time fluid is out atmosphere.
If the pressure acting on a given sample of an ideal gas at constant temperature is tripled, what happens to the volume of the gas?
Answer:
Explanation:
According to Boyle's law for constant temperature of gas Pressure is inversely proportional to the volume of gas.
[tex]PV=nRT[/tex]
[tex]PV=constant[/tex]
[tex]P\propto \frac{1}{V}[/tex]
if Pressure is tripled then
[tex]P\times V_1=3P\times V_2[/tex]
[tex]V_2=\frac{V_1}{3}[/tex]
Volume becomes one-third of original volume
Final answer:
According to Boyle's Law, tripling the pressure on a gas at constant temperature will reduce its volume to one third of the original volume.
Explanation:
The question is based on Boyle's Law which states that for a given mass of an ideal gas at constant temperature, the volume of the gas is inversely proportional to its pressure. Therefore, if the pressure acting on a gas is tripled (pressure is proportional to 3), the volume will be reduced to one third of its original value (volume is proportional to 1/3), assuming that the temperature and the amount of gas remain constant.