A girl and a boy are riding on a merry-go-round that is turning at a constant rate. The girl is near the outer edge, and the boy is closer to the center. For a given elapsed time interval, which rider has greater angular displacement?

Both the girl and the boy have the same nonzero angular displacement.
Both the girl and the boy have zero angular displacement.
The boy has greater angular displacement.
The girl has greater angular displacement.
Part B

A girl and a boy are riding on a merry-go-round that is turning at a constant rate. The girl is near the outer edge, and the boy is closer to the center. Who has greater linear speed?

Both the girl and the boy have zero linear speed.
The girl has greater linear speed.
Both the girl and the boy have the same nonzero linear speed.
The boy has greater linear speed.

Answer: [tex]90\°[/tex]

Explanation:

The Compton Shift [tex]\Delta \lambda[/tex] in wavelength when the photons are scattered is given by the following equation:

[tex]\Delta \lambda=\lambda_{c}(1-cos\theta)[/tex]     (1)

Where:

[tex]\lambda_{c}=2.43(10)^{-12} m[/tex] is a constant whose value is given by [tex]\frac{h}{m_{e}c}[/tex], being [tex]h[/tex] the Planck constant, [tex]m_{e}[/tex] the mass of the electron and [tex]c[/tex] the speed of light in vacuum.

[tex]\theta)[/tex] the angle between incident phhoton and the scatered photon.

We are told the maximum Compton shift in wavelength occurs when a photon isscattered through [tex]180\°[/tex]:

[tex]\Delta \lambda_{max}=\lambda_{c}(1-cos(180\°))[/tex]     (2)

[tex]\Delta \lambda_{max}=\lambda_{c}(1-(-1))[/tex]    

[tex]\Delta \lambda_{max}=2\lambda_{c}[/tex]     (3)

Now, let's find the angle that will produce a fourth of this maximum value found in (3):

[tex]\frac{1}{4}\Delta \lambda_{max}=\frac{1}{4}2\lambda_{c}(1-cos\theta)[/tex]      (4)

[tex]\frac{1}{4}\Delta \lambda_{max}=\frac{1}{2}\lambda_{c}(1-cos\theta)[/tex]      (5)

If we want [tex]\frac{1}{4}\Delta \lambda_{max}=\frac{1}{2}\lambda_{c}[/tex], [tex]1-cos\theta[/tex]   must be equal to 1:

[tex]1-cos\theta=1[/tex]   (6)

Finding [tex]\theta[/tex]:

[tex]1-1=cos\theta[/tex]

[tex]0=cos\theta[/tex]  

[tex]\theta=cos^{-1} (0)[/tex]  

Finally:

[tex]\theta=90\°[/tex]    This is the scattering angle that will produce [tex]\frac{1}{4}\Delta \lambda_{max}[/tex]      

Answer:

decrease by a factor 10

Explanation:

The parallax angle of a close star is given by

[tex]p=\frac{1}{d}[/tex]

where

p is the parallax angle

d is the distance of the star from Earth, in parsecs

From the formula we see that the parallax angle is inversely proportional to the distance.

In this problem, the distance of the star is increased by a factor 10:

d' = 10 d

so the new parallax angle would be

[tex]p'=\frac{1}{10 d}=\frac{1}{10}\frac{1}{d}=\frac{p}{10}[/tex]

So, the parallax angle would decrease by a factor 10.

If the star Alpha Centauri were moved to a distance 10 times farther than its current position, its parallax angle would become 10 times smaller due to the inverse relationship between parallax and distance.

The concept in question is related to the parallax method in astronomy, a way to measure the distances to nearby stars relative to distant ones. This method works because of Earth's annual motion around the Sun, essentially creating a large baseline and a triangle. Parallax is defined as the one-half angle that a star appears to shift when observed from different sides of the Earth's orbit, and this shift decreases with distance.

If the star Alpha Centauri were moved to a distance 10 times farther than it is now, it’s parallax angle would become 10 times smaller. This is because parallax and distance have an inverse relationship: as distance increases, parallax decreases, and vice versa. This rule applies to any interstellar object observed from Earth, including Alpha Centauri. Therefore, the parallax angle of Alpha Centauri would be one tenth of what it is now if it were 10 times farther away.

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Answer:

A the distance between the positive charge and the electron

B the charge on the electron

D the charge of the positive charge

Explanation:

The electric field produced by the positive charge Q at the location of the electron is given by

[tex]E=k\frac{Q}{r^2}[/tex]

where

k is the Coulomb constant

Q is the charge

r is the distance between the charge Q and the electron

The force exerted on a charged particle by an electric field is given by

[tex]F=qE[/tex]

where q is the magnitude of the charged particle. So, the force exerted on the electron in this problem is

[tex]F=eE = k\frac{eQ}{r^2}[/tex]

where e is the charge of the electron. As we see from the equation, the force depends only the following quantities:

A the distance between the positive charge and the electron (r)

B the charge on the electron (e)

D the charge of the positive charge (Q)

Final answer:

The force on an electron in an electric field depends on the distance between the positive charge and the electron, the charge on the electron, and the charge of the positive charge. Factors such as the masses and radii of the charges do not directly affect the electrostatic force.

Explanation:

An electric field is created by electric charges and can exert a force on other charges within the field. The force on an electron in an electric field created by a positive point charge depends on several factors. Let's identify these dependencies.

A. The distance between the positive charge and the electron: The force is inversely proportional to the square of the distance between the charges (r2).

B. The charge on the electron: The electrostatic force exerted on the electron is proportional to the magnitude of its charge.

D. The charge of the positive charge: The magnitude of the electric field, and therefore the force on the electron, is proportional to the charge of the positive point charge (Q).

The mass of the electron (C), the mass of the positive charge (E), the radius of the positive charge (F), and the radius of the electron (G) do not affect the electrostatic force the electron experiences.

Answer:

d) 182 mm Hg

Explanation:

The ratio of partial pressure to total pressure is equal to the molar ratio.

P / 870 mm Hg = 0.21

P = 182 mm Hg

Answer is D.

Final answer:

At  an atmospheric pressure of 870 mm Hg with 21 percent oxygen, the partial pressure of oxygen is D) 182mm

Explanation:

The question is asking to calculate the partial pressure of oxygen in the atmosphere when the total atmospheric pressure is 870 mm Hg, given that oxygen constitutes 21% of the atmosphere. The partial pressure of oxygen (Po₂) is found by multiplying the total pressure by the percent content of oxygen in the mixture. This can be calculated as follows:

Po₂ = (870 mm Hg) × (0.21)

Therefore, the partial pressure of oxygen is:

Po₂ = 182.7 mm Hg

Since we only have whole numbers in the options provided, we round this to the nearest whole number, which is 183 mm Hg. This is not exactly one of the options given, so it seems there might be a typo in the choices; the closest correct answer would be 182 mm Hg.

The term is “ISOTOPES” These describe atoms with different atomic masses.

The term which describes different atomic masses of similar atom because of varying numbers of neutrons are Isotopes.

Explanation:

The isotopes are the chemical element which has different atomic masses due to the fact that number of neutrons are not same but it has same number of proton.

When the number of neutron increases in a nucleus, with the same electronic configuration and same number of proton, element is said to have isotopes. There are may be variants of isotopes of an element. For example, hydrogen has 3 isotopes.

Answer: 5 units

Let's begin by stating clear that movement is the change of position of a body at a certain time. So, during this movement, the body will have a trajectory and a displacement, being both different:

The trajectory is the path followed by the body (is a scalar magnitude).

The displacement is the distance in a straight line between the initial and final position (is a vector magnitude).

According to this, in the description of the object (figure attached) placed at 0 on a number line and moving some units to the left and some oter units to the right, we are talking about the path followed by the object, hence its trajectory. So, 13 units is its trajectory.

But, if we talk about displacement, we have to draw a straight line between the initial position of the object (point 0) to its final position (point 5).

Now, being this an unidimensional problem, the displacement vector for this object is 5 units.

Answer: It seems i am made for this since, i LOVE eclipses, so basically it's when the moon goes in front of the moon, and is kinda hidden, making an eclipse

Hello There!

A partial solar eclipse is when the moon comes between the sun and our planet "Earth" but they do not align in a perfect straight line. Because of this, the moon only covers around half of the suns disc

Answer:

Mercury

Explanation:

Answer:

Amygdala, Frontal cortex

Explanation:

The amygdala is part of the brain responsible for aggressive behavior, fear and immediate reactions associated with high risks. The frontal cortex, on the other hand, is the part of the brain responsible for reasoning. Because the former matures faster than the latter in adolescents, then teens' behavior is generally associated with high risks and little reasoning before acting.

Answer:

[tex]2.68\cdot 10^8 MJ[/tex]

Explanation:

The power is related to the energy by

[tex]P=\frac{E}{t}[/tex]

where

P is the power

E is the energy

t is the time elapsed

The power of this nuclear power planet is

[tex]P=3100 MW = 3.1\cdot 10^9 W[/tex]

The time we are considering is 1 day, which is

[tex]t = 1 d = 86400 s[/tex]

So we can re-arrange the previous equation to find the energy produced by the power plant in one day:

[tex]E=Pt =(3.1\cdot 10^9 W)(86400 s)=2.68\cdot 10^{14} J=2.68\cdot 10^8 MJ[/tex]

The path difference between the two waves is the path difference between the two waves should be one and one-quarter of a wavelengths.

Wavelength is the distance between two identical or similar positions it means that it is the distance between crests or trough in the adjacent cycle of the waveform.

Wavelength is denoted by (lambda).

It is measured in meter, or centimeter, or millimeters.

Mathematically,

Wavelength is equal to velocity divided by frequency,

So,

Wavelength (lambda) = Velocity/frequency.

Velocity is in meter per second.

Frequency is in 1/second.

Prism is a transparent object in which if  sunlight is passed then it will be split in a VIBGYOR

where V = vilot, I = indigo, B = blue, G = green, Y = Yellow, O = orange, R = red.

In this series wavelength of red is higher and vilot is smaller and frequency of violet is higher and red is smaller.

Therefore, The path difference between the two waves is the path difference between the two waves should be one and one-quarter of a wavelengths.

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Answer:

Tundra Biome

Explanation:

Permafrost is a type of soil that is frozen all year round. It consists of rocks, soils and ice. The ice or frost holds the earth materials together.

The tundra biome lies below the arctic circle close to the north pole. Most of the earth here is predominantly frozen all year round. A layer of glacier covers  the surface and a deep lying layer of permafrost follows suit.

Some mountain tops capped with ice shows this tundra features.

Most tundras are termed cold deserts as they have little to no precipitation all year round. There is absence of vegetation cover as a result of low growing season of the plants.  

Answer:

800 kg/m³

Explanation:

I assume you want to find the density of the sphere?

Start with a free body diagram.  There are three forces acting on the sphere: gravity pulling the sphere down, buoyancy pushing the sphere up, and tension pulling the sphere down.

Applying Newton's second law:

∑F = ma

B - W - T = ma

Since the sphere isn't accelerating, a = 0.

B - W - T = 0

B = W + T

We know that the tension is one-fourth the weight:

B = W + W/4

B = 5/4 W

B = 5/4 mg

Buoyant force is defined as:

B = ρVg,

where ρ is the density of the fluid, V is the displaced volume, and g is acceleration of gravity.

ρVg = 5/4 mg

ρV = 5/4 m

The mass of the sphere is equal to its density times its volume.  Since the sphere is fully submerged, it's volume is the same as the volume of the displaced water.

ρV = 5/4 ρₓV

ρ = 5/4 ρₓ

ρₓ = 4/5 ρ

So the density of the sphere is 4/5 the density of the water.  Water's density is 1000 kg/m³, so:

ρₓ = 4/5 (1000 kg/m³)

ρₓ = 800 kg/m³

The submerged sphere experiences a gravitational force (its weight) and a counteracting buoyant force. The tension in the string tethering it is one-fourth of the sphere's weight. This situation could occur if the buoyant force on the sphere is three-fourths of the sphere's weight.

The subject of this question is about the physics of forces in a fluid medium - specifically, the interaction between buoyancy, weight, and tension. In this case, a sphere is fully submerged in water and secured with a string. Despite being underwater, the object still experiences the force of gravity, which pulls it downward. This weight is represented by the mass of the sphere times the acceleration due to gravity (we use 9.8 m/s² for Earth).

However, while submerged, the sphere also experiences a buoyant force due to the displacement of the water. This force is equal to the weight of the water displaced by the sphere, which acts in the opposite direction of the weight, or upward. The string provides a tension force that prevents the sphere from moving.

In this scenario, the tension force in the string is one-fourth the weight of the sphere. This could happen if the buoyant force acting on the sphere is equal to three-fourths of the sphere’s weight, leaving one-fourth of the sphere's weight to be balanced by the string.

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super nova is named for such explosion

Answer:

supernova

Explanation:

gradpoint

Answer:

c) ability to store charge

Explanation:

The capacity of an object gives a measure of the ability of the object to store electric charge. In formula, it is defined as the ratio between the charge stored on the object and the electric potential on the object:

[tex]C=\frac{Q}{V}[/tex]

where

Q is the charge

V is the voltage

Therefore, an object with a larger capacity than another object means that if the two objects are at same voltage V, the first object can store more charge than the second object.

Capacitance measures an object's ability to store charge, and is dependent on the geometry of conductor arrangement and the dielectric properties between conductors. It is measured in farads, with one farad being equivalent to one coulomb of charge per one volt.

The property of objects that is best measured by their capacitance is their ability to store charge. A capacitor, which is an arrangement of objects that can store electrical energy due to their geometry, has a capacitance that is directly proportional to the electric potential energy it can store per unit electric potential. The capacitance of a system depends only on the geometry of the conductor arrangement and the physical properties of the dielectric between the conductors.

It is important to note that capacitance is not related to a material's ability to conduct electric current nor is it primarily about distorting an external electrostatic field. Instead, it defines how much charge can be separated for a given electric potential, that is, how much electric energy is stored or held in potential. The SI unit of capacitance is the farad (F), where 1 farad equals 1 coulomb (C) per 1 volt (V).

(A) 3.9

When a dielectric is inserted between the plates of a capacitor, the capacitance of the capacitor increases according to the equation:

[tex]C' = k C[/tex] (1)

where

C' is the final capacitance

k is the dielectric constant

C is the original capacitance

The capacitance is inversely proportional to the to voltage across the plates:

[tex]C=\frac{Q}{V}[/tex] (2a)

where Q is the charge stored and V the potential difference across the plates. We can rewrite C' (the capacitance of the capacitor filled with dielectric) as

[tex]C'=\frac{Q}{V'}[/tex] (2b)

Substituting (2a) and (2b) into (1), we find

[tex]V'=\frac{V}{k}[/tex] (3)

where

V = 45.0 V is the original voltage across the capacitor

V' = 11.5 V is the voltage across the capacitor filled with dielectric

Solving for k,

[tex]k=\frac{V}{V'}=\frac{45.0 V}{11.5 V}=3.9[/tex]

(B) 22.8 V

When the dielectric is partially pulled away, the system can be assimilated to a system of 2 capacitors in parallel, of which one of them is filled with dielectric and the other one is not.

Keeping in mind that the capacitance of a parallel-plate capacitor is proportional to the area of the plates:

[tex]C \propto A[/tex]

and in this case, the area of the capacitor filled with dielectric is just 1/3 of the total, we can write:

[tex]C_1 = \frac{2}{3}C\\C_2 = \frac{1}{3}kC[/tex]

where C1 is the capacitance of the part non-filled with dielectric, and C2 is the capacitance of the part filled with dielectric. The total capacitance of the system in parallel is

[tex]C'=C_1 + C_2 = \frac{2}{3}C+\frac{1}{3}kC=(\frac{2}{3}+\frac{1}{3}k)C[/tex]

Substituting,

[tex]C'=(\frac{2}{3}+\frac{1}{3}(3.9))C=1.97 C[/tex]

This is equivalent to a capacitor completely filled with a dielectric with dielectric constant k=1.97. Therefore, using again eq.(3), we find the new voltage:

[tex]V'=\frac{V}{k}=\frac{45.0 V}{1.97}=22.8 V[/tex]

Ultraviolet light, whose wavelength is approximately between 100 nm and 380 nm; is a type of electromagnetic radiation that is not visible to the human eye.

This light is used for many purposes, among which is the identification of fluerescent minerals.

In this sense, fluorescence is a property that certain materials have in which they absorb energy in the form of short wavelength not visible electromagnetic radiation (the ultraviolet, for example) and then emit some of that energy in the form of longer wavelength electromagnetic radiation (in the visible spectrum). This is also called luminiscence.

Hence, the correct option is a.

Answer:

4 seconds

Explanation:

Average acceleration is change in velocity over change in time:

a = Δv / Δt

Δt = Δv / a

Δt = (15 m/s - 5 m/s) / 2.5 m/s²

Δt = 4 s

Answer: The time taken by the bicycle rider is 4 seconds.

Explanation:

To calculate the time taken by the rider, we use first equation of motion:

[tex]v=u+at[/tex]

where,

v = final velocity of the rider = 15 m/s

u = initial velocity of the rider = 5 m/s

a = acceleration of the car = [tex]2.5m/s^2[/tex]

t = time taken = ?

Putting values in above equation, we get:

[tex]15=5+(2.5\times t)\\\\t=\frac{15-5}{2.5}\\\\t=4s[/tex]

Hence, the time taken by the bicycle rider is 4 seconds.

Answer:

4.71 eV

Explanation:

For an electromagnetic wave with wavelength

[tex]\lambda=264 nm = 2.64\cdot 10^{-7} m[/tex]

the energy of the photons in the wave is given by

[tex]E=\frac{hc}{\lambda}=\frac{(6.63\cdot 10^{-34}Js)(3\cdot 10^8 m/s)}{2.64\cdot 10^{-7}m}=7.53\cdot 10^{-19} J[/tex]

where h is the Planck constant and c the speed of light. Therefore, this is the minimum energy that a photon should have in order to extract a photoelectron from the copper surface.

The work function of a metal is the minimum energy required by the incident light in order to extract photoelectrons from the metal's surface. Therefore, the work function corresponds to the energy we found previously. By converting it into electronvolts, we find:

[tex]E=\frac{7.53\cdot 10^{-19} J}{1.6\cdot 10^{-19} J/eV}=4.71 eV[/tex]

Answer:

Peaks

Explanation:

- A transverse wave is a wave in which the oscillation occurs in a direction perpendicular to the direction of propagation of the wave

- A longitudinal wave is a wave in which the oscillation occurs in a direction parallel to the direction of propagation of the wave

In a transverse wave, the highest and the lowest points of the wave are determined by the presence of crests (peaks) and troughs. On the contrary, in a longitudinal wave, the wave consists of alternating regions of higher particle density (called compressions) and of lower particle density (called rarefactions).

Therefore, the correct answer is

peaks

Answer:

Peaks, Dips

Explanation:

I got the question right

A nuclear reaction will not be affected with the use of a catalyst.

The incorrect statement is that the rate of a nuclear reaction is increased by the addition of a catalyst. Nuclear reactions result in significant energy changes and the transformation of elements or isotopes, but they are not influenced by catalysts or the chemical state of atoms.

One of the statements about nuclear reactions provided in the student's question is not true. In fact, the statement that the rate of a nuclear reaction is increased by the addition of a catalyst is incorrect. Unlike chemical reactions, the rate of a nuclear reaction is not affected by catalysts because nuclear reactions involve changes within the nucleus of an atom, and catalysts do not have the ability to affect the nuclear forces that govern these reactions.

Nuclear reactions are significant because they involve much larger energy changes compared to ordinary chemical reactions. The energy released or absorbed during nuclear reactions can result in a measurable change in mass, according to the principle of mass-energy equivalence. Also, these reactions often lead to the formation of different isotopes or even different elements, depending on the changes within the atomic nucleus.

Furthermore, nuclear reactions are not influenced by the chemical state of the atoms involved or by the presence of a catalyst. They depend primarily on factors related to the nuclei themselves, such as neutron flux in a fission reactor or temperature and pressure in a fusion reaction.

Answer:

Is the equation for Ec=1/2 m(Dv)^2 where Dv is the difference between the angular speed & the areolar speed?

In convex mirrors the focus is virtual and the focal distance is negative. This is how the reflected rays diverge and only their extensions are cut at a point on the main axis, resulting in a virtual image of the real object .

The Mirror equation is:  

[tex]\frac{1}{f}=\frac{1}{u}+\frac{1}{v}[/tex]    (1)  

Where:  

[tex]f=-6cm[/tex] is the focal distance  

[tex]u=12cm[/tex] is the distance between the object and the mirror  

[tex]v[/tex] is the distance between the image and the mirror

We already know the values of [tex]f[/tex] and [tex]u[/tex], let's find [tex]v[/tex] from (1):  

[tex]v=\frac{u.f}{u-f}[/tex]    (2)  

[tex]v=\frac{(12cm)(-6cm)}{12cm-(-6cm)}[/tex]

[tex]v=-4cm[/tex]   (3)

On the other hand, the magnification [tex]m[/tex] of the image is given by the following equations:  

[tex]m=-\frac{v}{u}[/tex]   (4)

[tex]m=\frac{h_{i}}{h_{o}}[/tex]   (5)

Where:

[tex]h_{i}[/tex] is the image height  

[tex]h_{o}=15cm[/tex] is the object height

Now, if we want to find the image height, we firstlu have to find [tex]m[/tex] from (4), substitute it on (5) and find [tex]h_{i}[/tex]:

Substituting  (3) in (4):

[tex]m=-\frac{-4cm}{12cm}[/tex]  

[tex]m=\frac{1}{3}[/tex]    (6)

Substituting  (6) in (5):

[tex]\frac{1}{3}=\frac{h_{i}}{15cm}[/tex]

[tex]h_{i}=\frac{15cm}{3}[/tex]

Finally we obtain the value of the height of the image produced by the mirror:

[tex]h_{i}=5cm[/tex]

Answer:

The answer is D. on edgen

Explanation:

D. 5.0

The 30-gram bullet fired and 50-gram bullet dropped from the same height, ignoring air resistance, will hit the ground at the same time. The reason is that the acceleration due to gravity is a constant and act only vertically downward. If air resistance were present, the fired bullet would hit the ground first due to deceleration caused by air resistive force.

The subject of this question is Physics, and it deals with the concept of free fall and projectile motion. Free fall is a type of motion in which an object falls downward due to gravitational force only, with no other forces having an impact. Projectile motion is the motion of an object that is launched into the air and subject to gravity and air resistance.

In this case, we are asked which of the two objects, a bullet fired horizontally and another dropped directly downward from the same height, will hit the ground first, ignoring air resistance. The surprising answer is that they hit the ground at the same time. While the fired bullet travels a further horizontal distance, the vertical component of its motion behaves just like that of the dropped bullet. Therefore, both bullets hit the ground simultaneously.

However, if air resistance is taken into account, the bullet will decelerate quicker due to its higher speed resulting in a greater air resistive force. This would cause the fired bullet to hit the ground first. This is derived from the fundamental laws of Physics that describe the effect of gravity on an object's motion. The acceleration due to gravity is a constant and acts only vertically downward, therefore, it affects both scenarios the same, making both bullets hit the ground at the same time in vacuum.

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-- turbulence

-- well mixed, non layered atmosphere

-- tornados

-- cumulonimbus clouds

-- thunderstorms

-- a lot of heavy clouds

Answer:

Red light has longer wavelength, while blue light has higher frequency

Explanation:

Red light and blue light corresponds to two different portion of the visible part of the electromagnetic spectrum.

The two colors have different wavelengths - more precisely:

Blue: 450 - 500 nm

Red: 620 - 750 nm

So, we see that red light has a longer wavelength than blue light.

Moreover, the frequency of an electromagnetic wave, f, is inversely proportional to the wavelength, [tex]\lambda[/tex]:

[tex]f=\frac{c}{\lambda}[/tex]

where c is the speed of light. This means that blue light, which has a shorter wavelength, has a higher frequency than red light.

Answer:

Explanation:

The atmosphere is the gaseous portion of the earth. It consists of different molecules of gas.

The geosphere is the solid portion of the earth which include the crusts, mantle and the core.

Earth is a dynamic planet. Our planet is dynamic in the sense that it is constantly changing and all its parts interacts with one another.

The gases in the atmosphere such a CO₂, H₂O, Nitrogen oxides originates from volcanic processes from deep within the earth. Hydrothermal vents and black smokers constantly release gases into the atmosphere.

The atmosphere plays a lot of roles in determining weather and climatic conditions. Agents of denudation like wind, water and glaciers are connected to the movement of gaseous portion of the earth. As new rocks forms on the crust, wind, water and glaciers acts on them. This process plays a central role in the rock cycle. The rock cycle would not be complete without agents of denudation which are strongly connected to the workings of atmospheric gases and materials like dusts.  

Therefore we see that the geosphere and atmosphere are linked.

Answer:

I'm not sure if I have the right words for it, but it is most likely that all three rays will form a larger inverted image after they pass through the lens because the arrow is outside the focal point. The image will be outside of F2, like the arrow is outside of F1.

Explanation:

Due to the shape of the lens in the diagram, you can imagine 3 lines branching out from point Q. I've made a digital sketch about what will happen as they pass through. It's a little crude, but it still works. I hope this was helpful.

The three principal rays intersect at the right side of the convergent lens.

To find the answer, we need to know about the trace of the principal rays.

The three principal rays are as follows

All the above rays are drawn from the tip of the pointed arrow.

Thus, we can conclude that the three principal rays intersect at the right side of the convergent lens.

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Answer:

B) 2 times what it now is

Explanation:

The acceleration due to gravity at the surface of the Earth is given by

[tex]g=\frac{GM}{R^2}[/tex]

where

G is the gravitational constant

M is the mass of the Earth

R is the Earth's radius

In this problem, the mass of the Earth is doubled:

M' = 2M

while the radius remains the same:

R' = R

so the new acceleration due to gravity would be

[tex]g'=\frac{GM'}{R'^2}=\frac{G(2M)}{R^2}=2\frac{GM}{R^2}=2g[/tex]

so, the acceleration due to gravity would become twice the current value.

Note also that the value of g does not depend on the mass of the objects involved.

Answer:

A

Explanation:

First of all the answer is less than the smallest resistor, so it is less than 18 ohms.

1 / r1 + 1/ r2 = 1/r

1/18 + 1/23.5 = 1/r

1/18 = 0.05555555

1/23.5 = 0.0422532

1/18 + 1/23.5 = 0.0555555 + 0.0422532

1/r = 0.0981087  

r = 1/0.0981087

r = 10.193

A

Final answer:

The equivalent resistance for two resistors in parallel, one with 18.0 ohms and the other with 23.5 ohms, is approximately 10.2 ohms, which is answer choice A.

Explanation:

When calculating the equivalent resistance for resistors in parallel, you use the formula 1/Req = 1/R1 + 1/R2 where Req is the equivalent resistance, and R1 and R2 are the resistances of the individual resistors. For the two resistors with resistances of 18.0 ohms and 23.5 ohms, the calculation would be:

1/Req = 1/18.0 + 1/23.5

1/Req = 0.0556 + 0.0426

1/Req = 0.0982

Req = 1 / 0.0982

Req ≈ 10.18 ohms

Therefore, the correct answer is A. 10.2 ohms.