A soup can has a radius of 4.3 cm and a height of 11.6 cm. What is the volume of the soup can to the nearest tenth of a cubic centimeter​

The most appropriate measure of center is Median. As the data has a large value (290) at the end, it is the better choice to choose the median for finding the center because the mean or average is appropriate to represent the general level if there are not too large or too small values in the set. The median for the given bowling scores for 6 people is 117.5.

Since the standard deviation and range gives the variability of the given data, the mean and median are used for calculating the center.

Given data values are,

112, 114, 115, 120, 122, 290

Mean of the given data values,

Mean = Sum of all values / number of values

Sum of values = 112 + 114 + 115 + 120 + 122 + 290 = 873

Number of values = 6

∴ Mean = [tex]\frac{873}{6}[/tex]

             = 145.5

Median of the given data values,

Arranging the data values in the ascending order - 112, 114, 115, 120, 122, 290

Number of values = 6 (even)

So, the median is the average between the two centers

∴ Median = [tex]\frac{115+120}{2}[/tex]

                = 117.5

Since the last value in the set is larger than all the values (a sudden change or rise in the value), the most appropriate measure of center is the median and it is 117.5.

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Answer:

Option b

Step-by-step explanation:

By definition we know that:

[tex]cos ^ 2(\theta) = 1- sin ^ 2(\theta)[/tex]

We know that for this case:

[tex]sin(\theta) = \frac{1}{4}[/tex]

Then:

[tex]cos ^ 2(\theta) = 1- (\frac{1}{4})^2\\\\cos ^ 2(\theta) = 1- (\frac{1}{16})\\\\cos ^ 2(\theta) = \frac{15}{16}\\\\[/tex]

Apply square root on both sides of the equation

[tex]\sqrt{cos ^ 2(\theta)} = \sqrt{\frac{15}{16}}\\\\cos(\theta) = \sqrt{\frac{15}{16}}\\\\cos(\theta) = \frac{\sqrt{15}}{4}[/tex]

Answer:

A) 0.123; B) 0.8078; C) Because the population is normally distributed.

Step-by-step explanation:

For part A,

We first calculate the z-score, which tells us how many standard deviations from the mean our score is.

Since we are finding the z-score of an individual score and not a sample, we use the formula

[tex]z=\frac{X-\mu}{\sigma}[/tex]

Our score, X, is 209.3; our mean, μ, is 200; and our standard deviation, σ, is σ.  This gives us

[tex]z=\frac{209.3-200}{8}=\frac{9.3}{8}=1.1625[/tex]

We look this value up in a z-table.  However, we must round it to the nearest hundredth first; this is 1.16.  From a z-table, we get that the area under the curve to the left of, or less than or equal to, this score is 0.8770.

However we want the probability that the value is greater than this; this means we subtract our found probability from 1:

1-0.8770 = 0.123

For part B,

Again we first calculate the z-score.  However this time we are finding the probability of a mean of a sample rather than an individual score; this means we use the formula

[tex]z=\frac{\bar{X}-\mu}{\sigma\div \sqrt{n}}[/tex]

Our X is 198.20; our μ is still 200, and our σ is still 8; our value of n is our sample size, 15:

[tex]z=\frac{198.20-200}{8\div \sqrt{15}}=\frac{-1.8}{2.0656}=-0.87[/tex]

Looking up this value in a z-table, we get 0.1922.

However, we want the probability that the area, or probability, is greater than this; so we subtract from 1:

1-0.1922 = 0.8078

For part C,

When a population is normally distributed, this means that a sample taken from this population will also be normal; this means we can use the normal distribution.

sides of right angle triangle follows Pythagoras theroem

which states

a^2 +b^2 = c^2

where a , b and c are sides of right angle triangle.

here none of options do not follow this.

so answer is option D

Answer:

D

Step-by-step explanation:

Which of the following are measurements of the sides of a right triangle?

Check c^2 = a^2 + b^2 where c is the largest of the 3 sides.

If c^2 = a^2+b^2 you have a right triangle. If it doesn't, you don't.

Answer:

30

Step-by-step explanation:

Answer:

C(1,99) and E(5,8)

Step-by-step explanation:

Discrete data are numerical values that are distinct and outstanding mostly assigned from surveys by counting e.t.c

Thus, these numerical values cannot be negative as we can not count negative  values.

the data can only take known exact values so it is not continuous. From the given sets of data the sets that satisfy the given guidelines are C(1,99) and E(5,8)

a.

3x = 30

x = 30/3

x = 10

b.

12x = 12

x = 12/12

x = 1

c.

1 = x-3

x = 1+3

x = 4

d.

-24 = 4x

x = -24/4

x = -6

HOPE THIS WILL HELP YOU

Answer:

The answer is -6.

Step-by-step explanation:

To find the value of y in (3, y), plug in 3 for x in y = -(2x) and solve for y.

y = -(2(3))

y = -6

y = -6, so the answer is -6.

Answer:

-8

Step-by-step explanation:

I think the equation you want is y=-(2^x) because if you meant what you put originally the first guy is right.

What you do is take 2^3 which equals 8 and then you have the negative left which gets you to -8. I probably explained this terribly and I am sorry.

Answer:

[tex]x = 150 * 3^{y}[/tex]

Step-by-step explanation:

Let's start by creating the beginning of the data sample, knowing the population of bees triples each year.

Year 0 = 150

Year 1 = 450

Year 2 = 1350

Year 3 = 4050

Year 4 = 12150

If we look at the numbers, we see they are all divided by 150:

Year 0 = 150 / 150 = 1

Year 1 = 450 / 150 = 3

Year 2 = 1350 / 150 = 9

Year 3 = 4050 / 150 = 27

Year 4 = 12150 / 150 = 81

We then see the result of the division by 150 is in fact the table of multiplication by 3.

So, by inverting the operation, we can see the number of bees (x) for any given year starting from now is 150 times 3 at the power of the year (y).

Answer:

y=150(3)^x

Step-by-step explanation:

I had to do an assignment with the same question, this is the answer :)

Answer:

42,000 dollars was the value of the plot last year

Step-by-step explanation:

[tex]x*\frac{110}{100}=46200\\110x=4620000\\x=\frac{4620000}{110} \\x=42000[/tex]

Answer: 20 pounds.

Step-by-step explanation:

We know the weight of each flower arrangement (each one weighs 6 2/3 pounds) and the total number of flower arrangaments Isabelle ordered (3 flower arrangements).

To make the calculus easier, we can rewrite the mixed number 6 2/3 as a decimal number:

Divide the numerator 2 by the denominator 3 and add the result to the whole number 6:

[tex](6+0.666)lb=6.666lb[/tex]

If 1 arrangement weighs 6.666 pounds, the total weigth of 3 arrangements can be calculated by multiplying 6.666 pounds by 3:

[tex]weight_{(total)}=(6.666lb)(3)\\weight_{(total)}=20lb[/tex]

Answer:

Step-by-step explanation:

Area = 7.6 × 3.7

Area = 28.12 cm²

I hope I helped you.

Answer:

[tex]28.12cm^2[/tex]

Step-by-step explanation:

The figure shown in the diagram  is  a parallelogram.

The area of a parallelogram is [tex]base \times height.[/tex].

The base of the parallelogram is 3.7cm

The height of the parallelogram is 7.6cm.

The area of the parallelogram

[tex]3.7\times 7.6=28.12cm^2[/tex]

The first choice is the correct answer

There are no compound periods given, so use the simple interest formula:

A = P(1+rt) where P is the principal, r is the rate and t is the time.

A = 5000(1+0.0975(6))

A = 5000(1+0.585)

A = 5000(1.585)

A = $7,925

Interest = 7925 - 5000 = $2,925

Total paid back = $7,925

Answer:

The Interest is 2,925.00 and now you owe 7,925.00. I hope this helps

Step-by-step explanation:

Answer:

2 2/3 lbs

Step-by-step explanation:

Convert Alya's mixed number to an improper fraction

   3*1+1 = 4/3

multiply 4/3 times 2/1

    4*2 = 8

    3*1 = 3

8/3 - convert back to mixed number

    8/3 = 2 2/3

12,500-11,625=875

1%=125

10%=1250

5%=625

625+125=750=6%

750+125=875=7%

so the percentage is 7%

Answer:

200 smaller lots

Step-by-step explanation:

10 ÷ 1/20 = 200

The number of smaller lots should be 200

Ms.Beard bought 10 acres of land she plans to divide the land into smaller slots that are each 1/20 of an acre

= 10 ÷ 1/20

= 200

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Answer:

Multiply both sides of the equation by -2

Distribute -1/2 over (x+4)

Step-by-step explanation:

we have

[tex]-\frac{1}{2}(x+4)=6[/tex]

Method 1

Multiply both sides of the equation by -2 ------> Step 1

[tex](x+4)=6*(-2)[/tex]

[tex](x+4)=-12[/tex]

Subtract 4 from both sides of the equation

[tex]x=-12-4=-16[/tex]

Method 2

Distribute -1/2 over (x+4)-------> Step 1

[tex]-\frac{1}{2}x-2=6[/tex]

Multiply both sides of the equation by -2

[tex]x+4=6(-2)[/tex]

[tex]x+4=-12[/tex]

Subtract 4 from both sides of the equation

[tex]x=-12-4=-16[/tex]

Answer:

⇒ Multiply both sides of the equation by -2

⇒ Distribute -1/2 over (x+4)

Those are the 2 answers.

Answer:

79.5688 < µ < 83.1646

Step-by-step explanation:

Sample mean is the sum of all scores, divided the the total number of test takers.  In this case, the sample mean is:

(87.4 + 86.9 + 89.9 + 78.3 + 75.1 + 70.6)/6 =  488.2/2 = 81.3667

The sample standard deviation is the square root of the sample variance.  See attached photo 1 for calculation of these values...

The sample standard deviation is 3.1856

We need to make a 90% confidence interval for this data.  Since n < 30, we will use a t-value.  The degrees of freedom is always one less than the sample size so on the t-distribution chart, look under the column for Area under the curve = 0.10, and the row for 5.  The t-value you should see is t = 2.015

See attached photo 2 for the construction of the confidence interval

The graph of the equation y − 2 = 2⁄3(x + 4) is a blue line that passes through the points (0, 2) and (3, 4).

To graph the equation `y − 2 = 2⁄3(x + 4)` using the Line Tool and selecting two points, we can use the following steps:

1. Find the slope and y-intercept of the line.

The equation is already in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept. In this case, the slope is 2⁄3 and the y-intercept is 2.

2. Find a point on the line.

The y-intercept is always a point on the line, so we can use the point (0, 2) as our first point.

3. Use the slope to find another point on the line.

The slope tells us how much to move up or down and how much to move to the right to find another point on the line. In this case, the slope is 2⁄3, so we need to move up 2 units and to the right 3 units from our first point. This gives us the point (3, 4).

4. Select the two points in the Line Tool and draw the line.

Once we have selected the two points, we can draw the line by clicking and dragging the mouse.

Step 1: Find the slope and y-intercept of the line.

The equation `y − 2 = 2⁄3(x + 4)` is already in slope-intercept form, y = mx + b, where m is the slope and b is the y-intercept. In this case, the slope is 2⁄3 and the y-intercept is 2.

Step 2: Find a point on the line.

The y-intercept is always a point on the line, so we can use the point (0, 2) as our first point.

Step 3: Use the slope to find another point on the line.

The slope tells us how much to move up or down and how much to move to the right to find another point on the line. In this case, the slope is 2⁄3, so we need to move up 2 units and to the right 3 units from our first point. This gives us the point (3, 4).

Step 4: Select the two points in the Line Tool and draw the line.

Once we have selected the two points, we can draw the line by clicking and dragging the mouse.

Here is a diagram of the graph:

[Image of a graph of the equation y − 2 = 2⁄3(x + 4)]

The blue line is the graph of the equation. The red point is the point (0, 2) and the green point is the point (3, 4).

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The Y intercept is the same for both -3/11

The slope is the fraction with the letter x.

For P the slope is 5/8, which is less than 1

For q the slope is 8/5 which is greater than 1

Because the slope of p is less than  the slope of q, the slope would be less steep.

The answer is the second one.

Answer:

B

Step-by-step explanation:

Answer:

1. The Pythagoras theorem

Hypotenuse^2 = base^2 + perpendicular^2

2. Formula for calculating speed

Speed = Distance  Time

3. Areas

Rectangle = length * width

Square = side^2

4. Profit and loss formulas

Step-by-step explanation:

Final answer:

Einstein's second postulate on the constant speed of light in a vacuum led to the famous equation [tex]E = mc^2,[/tex] demonstrating mass-energy equivalence. Although not commonly used in everyday life, other practical formulas impact daily activities such as finance, medicine, and cooking.

Explanation:

The second postulate upon which Albert Einstein based his theory of special relativity is related to the speed of light. This principle states that light travels at a constant speed of [tex]c = 3.00 imes 10^8 m/s[/tex] in a vacuum and does not depend on the frame of reference from which it is observed. This postulate led to one of the most renowned equations in physics, [tex]E = mc^2[/tex], which describes the relationship between energy (E), mass (m), and the speed of light (c). In this equation, E represents the energy equivalent of a certain mass (m) when it is converted into energy, revealing the profound concept that mass and energy are interchangeable.

While [tex]E = mc^2[/tex] is a groundbreaking equation in theoretical physics, it is not commonly applied in everyday situations. However, there are many other formulas that are routinely used in daily life. Examples include calculations for simple interest in finance, dose calculations in medicine, and recipes in cooking that require proportional adjustments. These formulas help us to navigate various practical aspects of our day-to-day activities.

The answer has to be A) r(n) = 15n +55, as when n=0, r(n)=55 so the equation must end with +55.

Answer:

A. [tex]r(n)=15*n+55[/tex]

Step-by-step explanation

Since the value of n is given in the table as 0,5,15,30 and 35.So we will put the value of n in the given option starting from A.

Now putting the value of n as 0 in option A

we get [tex]r(n)=15*n+55[/tex]

[tex]r(0)=15*0+55\\r(0)=55[/tex]

Now putting the value of n as 5 in option A

we get [tex]r(n)=15*n+55[/tex]

[tex]r(5)=15*5+55\\r(0)=130[/tex]

Now putting the value of n as 15 in option A

we get [tex]r(n)=15*n+55[/tex]

[tex]r(15)=15*15+55\\r(0)=280[/tex]

Now putting the value of n as 30 in option A

we get [tex]r(n)=15*n+55[/tex]

[tex]r(30)=15*30+55\\r(0)=505[/tex]

Now putting the value of n as 35 in option A

we get [tex]r(n)=15*n+55[/tex]

[tex]r(35)=15*35+55\\r(0)=580[/tex]

After seeing the results of each value we see that option A is matching with all the given values. So the correct answer is A.

25. Step-by-step explanation:

[tex]\text{The general form of an ellipse is:}\dfrac{(x-h)^2}{a^2}+\dfrac{(y-k)^2}{b^2}=1\\\\\bullet \text{(h, k) is the Center}\\\bullet \text{a is the radius of x}\\\bullet \text{b is the radius of y}\\\bullet \text{the largest value between a and b is the major}\\\bullet \text{the smallest value between a and b is the minor}\\\bullet \text{the vertices are the (h, k) value plus the major (a or b) value}\\\bullet \text{the co-vertices are the (h, k) value plus the minor (a or b) value}\\\bullet \text{Length is the diameter}=2r\\[/tex]

[tex]\dfrac{x^2}{16}+\dfrac{y^2}{25}=1\quad \text{can be rewritten as}\ \dfrac{(x-0)^2}{4^2}+\dfrac{(y-0)^2}{5^2}=1\\\\\bullet (h, k)=(0,0)\\\bullet a=4\\\bullet b=5\\\bullet \text{b is the largest value so: b is the major and a is the minor}\\\bullet \text{Vertices are }(0, 0+5)\ and\ (0, 0-5)\implies (0, 5)\ and\ (0, -5)\\\bullet \text{Co-vertices are }(0+4, 0)\ and\ (0-4, 0)\implies (4,0)\ and\ (-4,0)\\\bullet \text{Length of major is }2b:2(5)=10\\\bullet \text{Length of minor is }2a:2(4)=8[/tex]

To find the foci, first we must find the length of the foci using the formula:

[tex](r_{major})^2-(r_{minor})^2=c^2[/tex]

Then add the c-value to the h (or k)-value that represents the major.

b² - a² = c²

25 - 16 = c²

        9 = c²

       ±3 = c

The center is (0, 0) and the major is the y-value so the foci is:

(0, 0+3) and (0, 0-3) ⇒ (0, 3) and (0, -3)

26. Answers

Follow the same steps as #25:

Center: (0, 0)

Vertices (7, 0) and (-7, 0)

Co-vertices: (0, 3) and (0, -3)

foci: (2√10, 0) and (-2√10, 0)

length of major: 14

length of minor: 6

Answer:

[tex]\large\boxed{Q1.\ A_{\triangle PQR}=90\ cm^2}\\\\\boxed{Q2.\ V\approx321\ m^3}[/tex]

Step-by-step explanation:

[tex]Q1.\\\\\text{If}\ \triangle ABC\sim\triangle PQR\ \text{then the quotient of the areas is equal}\\\text{the square of the similarity scale}\ k.\\\\\text{The sides}\ AB\ \text{and}\ QP\ \text{are corresponding}.\ \text{Calculate the scale:}\\\\k=\dfrac{4}{6}=\dfrac{4:2}{6:2}=\dfrac{2}{3}\\\\\text{The area of }\ \triangle ABC=40\ cm^2.\\\\\text{Let the area of}\ \triangle PQR=x,\ \text{then}\\\\\dfrac{40}{x}=\left(\dfrac{2}{3}\right)^2\\\\\dfrac{40}{x}=\dfrac{4}{9}\qquad\text{cross multiply}\\\\4x=(9)(40)\qquad\text{divide both sides by 4}\\\\x=(9)(10)\\\\x=90\ cm^2[/tex]

[tex]Q2.\\\\\text{The formula of a volume of a sphere:}\\\\V=\dfrac{4}{3}\pi R^3\\\\R-radius\\\\\text{We have the diameter}\ 2R=8.5\ m\to R=\dfrac{8.5}{2}\ m=4.25\ m.\\\\\text{Substitute:}\\\\V=\dfrac{4}{3}\pi(4.25)^3=\dfrac{4}{3}\pi(76.765625)=(4)(25.588541)\pi=102.354164\pi\\\\\pi\approx3.14\\\\V=(102.354164)(3.14)\approx321\ m^3[/tex]

Answer: The answers are

(1) 90 cm²   and (2) 321 m³.

Step-by-step explanation:  The calculations are as follows:

(1) The triangles ABC and PQR are similar. And the area of ΔABC is 40 cm².

Also, AB = 4 cm  and PQ = 6 cm.

We are to find the area of triangle PQR.

Similarity ratio of two similar triangles is equal to the ratio of any two corresponding sides of the triangles.

So, the similarity ratio of ΔABC and ΔPQR is given by

[tex]\dfrac{AB}{PQ}=\dfrac{4}{6}=\dfrac{2}{3} =2:3\\\\\\\Rightarrow AB:PQ=2:3.[/tex]

Now, let the area of ΔPQR be denoted by [tex]A_{PQR}.[/tex]

We know that the ratios of the area of two similar triangles is equal to the ratios of the squares of any two corresponding sides of the triangles.

Therefore, we must have

[tex]\dfrac{\textup{area of triangle ABC}}{\textup{area of triangle PQR}}=\dfrac{AB^2}{PQ^2}\\\\\\\Rightarrow \dfrac{40}{A_{PQR}}=\left(\dfrac{AB}{PQ}\right)^2\\\\\\\Rightarrow \dfrac{40}{A_{PQR}}=\left(\dfrac{2}{3}\right)^2\\\\\\\Rightarrow \dfrac{40}{A_{PQR}}=\dfrac{4}{9}\\\\\\\Rightarrow 4\times A_{PQR}=40\times 9\\\\\\\Rightarrow A_{PQR}=90~\textup{cm}^2.[/tex]

Thus, the area of triangle PQR is 90 cm².

(2) Given that a science museum has a spherical model of the earth with a diameter of 8.5 m.

We are to find the volume of the model.

Since the model is spherical in shape, so will be using the following formula:

the volume of a sphere with radius 'r' units is given by

[tex]V=\dfrac{4}{3}\pi r^3.[/tex]

The diameter of the model is 8.5 cm, so the radius of the model will be

[tex]r=\dfrac{8.5}{2}=4.25~\textup{m}.[/tex]

Therefore, the volume of the model is given by

[tex]V\\\\\\=\dfrac{4}{3}\pi r^3\\\\\\=\dfrac{4}{3}\times3.14\times(4.25)^3\\\\\\=\dfrac{964.17625}{3}\\\\\\=321.39\sim 321~\textup{m}^3.[/tex]

Thus, the volume of the model is 321 m³.

Hence, the answers are

(1) 90 cm²   and (2) 321 m³.

Answer:   a) 36x + 3

                b) 36x + 27

                c) 16x + 15

                d) 81x

Step-by-step explanation:

f(x) = 4x + 3         g(x) = 9x

a) f(g(x)) = 4(9x) + 3       replaced x in f(x) equation with 9x

             = 36x + 3

b) g(f(x)) = 9(4x + 3)      replaced x in g(x) with 4x + 3

             = 36x + 27

c) f(f(x)) = 4(4x + 3) + 3     replaced x in f(x) with 4x + 3

           = 16x + 12   + 3

           = 16x + 15

d) g(g(x)) = 9(9x)            replaced x in g(x) with 9x

              = 81x

Answer:

solution given:

f(x) = 4x + 3

g(x) = 9x

answer:

a.fog(x)=f(9x)=4×9x+3=36x+3

domain=real number

b.gof (x)=g(4x+3)=9(4x+3)=36x+26

domain=real number

c.fof(x)=f(4x+3)=4(4x+3)+3=16x+12+3

=16x+15

domain: real number

d.

gog(x)=g(9x)=9×9x=81x

domain: real number.

Answer:

32 units²

Step-by-step explanation:

From point 1 to point 2, the y values change by 8 units while the x values stay the same.  This side of the rectangle has a length of 8

From point 1 to point 3, the x values change by 4 units while the y values stay the same.  This side of the polygon has a length of 4

The area of the rectangle is 8x4 = 32 units²

Answer:

32 square units

Step-by-step explanation:

A rectangle has vertices at (-1, 6), (-1, -2), (3, 6), and (3,-2)

Area of a rectangle = length times width

LEts find the distance between  (-1, 6) and  (3, 6)

Apply distance formula

[tex]D= \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

[tex]D= \sqrt{(3+1)^2+(6-6)^2}=\sqrt(16)= 4[/tex]

LEts find the distance between   (-1, 6), (-1, -2)

[tex]D= \sqrt{(-1+1)^2+(-2-6)^2}=\sqrt(64)= 8[/tex]

Area of the rectangle = 4 times 8= 32 square units

10

6/3 =n/5

times n by 2 basically

answer is 10

it’s basically ratios

I think the answer is 5

The answer should be B: $1,785.25

Answer:

$1785.245

Step-by-step explanation:

Cost of truck = $32,459

We are given that Bobby gets 5.5% commission on the cost of each vehicle he sells.

So, Commission = [tex]\frac{5.5}{100} \times 32459[/tex]

Commission = [tex]1785.245[/tex]

Hence his commission if he sells a truck for $32,459 is $1785.245

I. If the linear correlation coefficient for two variables is zero, then there is no relationship between the variables.

True.

II. If the slope of the regression line is negative, then the linear correlation coefficient is negative.

False.

III. The value of the linear correlation coefficient always lies between -1 and 1.

True.

IV. A linear correlation coefficient of 0.62 suggests a stronger linear relationship than a linear correlation coefficient of -0.82.

False.

So, the correct statements are I and III.

Therefore, the correct answer is:

OB. I and II

Let's evaluate each statement:

I. If the linear correlation coefficient for two variables is zero, then there is no relationship between the variables.

True. A correlation coefficient of zero indicates no linear relationship between the variables. However, it's important to note that there could still be a nonlinear relationship.

II. If the slope of the regression line is negative, then the linear correlation coefficient is negative.

False. The linear correlation coefficient (Pearson correlation coefficient) measures the strength and direction of a linear relationship between two variables. It ranges from -1 to 1. The sign of the correlation coefficient indicates the direction of the relationship (positive or negative), not the slope of the regression line. So, this statement is not necessarily true.

III. The value of the linear correlation coefficient always lies between -1 and 1.

True. The linear correlation coefficient, also known as Pearson's correlation coefficient, ranges from -1 to 1. A correlation coefficient of -1 indicates a perfect negative linear relationship, 0 indicates no linear relationship, and 1 indicates a perfect positive linear relationship.

IV. A linear correlation coefficient of 0.62 suggests a stronger linear relationship than a linear correlation coefficient of -0.82.

False. The magnitude (absolute value) of the correlation coefficient indicates the strength of the linear relationship, regardless of the sign. Therefore, a correlation coefficient of -0.82 suggests a stronger linear relationship compared to a correlation coefficient of 0.62.

So, the correct statements are I and III.

Therefore, the correct answer is:

OB. I and IV

The complete question is here:

Which of the following statements concerning the linear correlation coefficient are true? 1: If the linear correlation coefficient for two variables is zero, then there is no relationship between the variables. II: If the slope of the regression line is negative, then the linear correlation coefficient is negative. III: The value of the linear correlation coefficient always lies between - 1 and 1. IV: A linear correlation coefficient of 0.62 suggests a stronger linear relationship than a linear correlation coefficient of -0.82. A. III and IV

B. I and IV

C. I and II

D. II and III

The true statements for the given information are:

I: If the linear correlation coefficient for two variables is zero, then there is no relationship between the variables.

III: The value of the linear correlation coefficient always lies betweenminus1 and 1.

The correct options are I and III.

I: If the linear correlation coefficient for two variables is zero, then there is no relationship between the variables. This statement is true. The linear correlation coefficient, also known as Pearson's correlation coefficient (r), measures the strength and direction of the linear relationship between two variables. When r = 0, it indicates that there is no linear relationship between the variables.

II: If the slope of the regression line is negative, then the linear correlation coefficient is negative. This statement is not necessarily true. The slope of the regression line indicates the direction and steepness of the relationship between the variables, while the correlation coefficient indicates the strength and direction of the linear relationship. The correlation coefficient can be negative even if the slope of the regression line is positive, and vice versa.

III: The value of the linear correlation coefficient always lies between -1 and 1. This statement is true. The correlation coefficient ranges from -1 to 1, where -1 indicates a perfect negative linear relationship, 0 indicates no linear relationship, and 1 indicates a perfect positive linear relationship. Therefore, the correlation coefficient always falls within this range.

IV: A linear correlation coefficient of 0.62 suggests a stronger linear relationship than a linear correlation coefficient of -0.82. This statement is false. The magnitude of the correlation coefficient indicates the strength of the linear relationship, regardless of whether it is positive or negative. Therefore, in this case, the correlation coefficient of -0.82 suggests a stronger linear relationship compared to 0.62 because the magnitude of -0.82 is larger than that of 0.62.

In summary, statements I and III are true, while statements II and IV are false.

Complete question

Which of the following statements concerning the linear correlation coefficient are true?

I: If the linear correlation coefficient for two variables is zero, then there is no relationship between the variables.

II: If the slope of the regression line is negative, then the linear correlation coefficient is negative. III: The value of the linear correlation coefficient always lies betweenminus1 and 1.

IV: A linear correlation coefficient of 0.62 suggests a stronger linear relationship than a linear correlation coefficient of minus 0.82.

Answer:

The answer is hyperbola; with angle of rotation = 45° ⇒ answer (b)

Step-by-step explanation:

* At first lets talk about the general form of the conic equation

- Ax² + Bxy + Cy²  + Dx + Ey + F = 0

∵ B² - 4AC < 0 , if a conic exists, it will be either a circle or an ellipse.

∵ B² - 4AC = 0 , if a conic exists, it will be a parabola.

∵ B² - 4AC > 0 , if a conic exists, it will be a hyperbola.

* Now we will study our equation:

- xy = -2.5

∵ A = 0 , B = 1 , C = 0

∴ B² - 4 AC = (1)² - 4(0)(0) = 1 > 0

∴ B² - 4AC > 0

∴ The graph is hyperbola

* To find the angle of rotation use the rule:

- cot(2Ф) = (A - C)/B

∵ A = 0 , B = 1 , C = 0

∴ cot(2Ф) = 0/1 = 0

∴ 2Ф = 90°

∴ Ф = 45°

* The answer is hyperbola; with angle of rotation = 45°