To make lemonade, kate uses 1 cup of lemon juice and 2 cups sugar. if she makes a larger amount of lemonade with 10 cups of sugar, how many cups of lemon juice does she need?
Kate uses 1 cup of lemon juice and 2 cups of sugar to make lemonade. She requires 5 cups of lemon juice if she uses 5 cups of sugar to produce a larger batch of lemonade.
What is the ratio?It is defined as the comparison of two quantities to ascertain how many times one yields the other. The ratio can be written as a fraction or as a sign: between two numbers.
It is given that, Kate uses 2 cups of sugar and 1 cup of lemon juice to make lemonade. If she uses 10 cups of sugar to create more lemonade.
The ratio of lemon juice to sugar is 1:2.
For 10 cups of sugar, the number of cups of lemon juice needed as,
We have to maintain the ratio as 1:2.So for 10 cups of sugar, the ratio is maintained as,
=5:10
=1:2
Thus, she needs 5 cups of juice to make lemonade.
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Carrots sell for $2.10 per pound, and crackers sell for $2.90 per pound. Glen bought some carrots and some crackers. The total weight was 2.3 pounds and cost $6.03.
How many pounds of carrots and how many pounds of crackers did Glen buy?
Note: Please give a direct answer
Which test point holds true for y − 2x ≤ 1?
(0, 2)
(-2, 4)
(1, 4)
(5, 0)
Answer:idek tbh
Step-by-step explanation:
A retailer charges a flat handling fee of $5.00, plus $0.75 per quarter pound, to ship an item. Bailey pays $9.50 to have an item shipped from the retailer. What is the weight of the item? 1.50 pounds
Answer:
1.50 pounds
Step-by-step explanation:
Given : A retailer charges a flat handling fee of $5.00, plus $0.75 per quarter pound, to ship an item.
Bailey pays $9.50 to have an item shipped from the retailer.
To Find: What is the weight of the item?
Solution:
He paid total amount = $9.50
A flat handling fee = $5.00
Amount he paid without handling fee = $9.50-$5.00
=$4.50
Now we are supposed to find what is the weight of an item that costs $4.50
So, we are given that it costs $0.75 per quarter pound, to ship an item.
So, cost of 1 pound = [tex]\frac{0.75}{\frac{1}{4}}=3[/tex]
So, it cost $3 for 1 pound
So, weight of an item that costs $1 = [tex]\frac{1}{3}[/tex]
So, weight of an item that costs $4.50=[tex]\frac{1}{3}\times 4.50[/tex]
=1.50 pounds
Hence the weight of the item is 1.50 pounds.
Answer:
1.50 pounds
Step-by-step explanation:
el de arriba lo dijo
When you see a traffic light turn red, you apply the brakes until you come to a stop. Suppose your initial speed was 11.2 m/s, and you come to rest in 34.7 m. How much time does this take? Assume constant deceleration.
...?
What is the value of p in the equation y2=-4x? p=?
Answer:
the value of p=-1
Step-by-step explanation:
General equation of a parabola is
[tex]y^2= 4p(x)[/tex] where vertex is at (0,0)
now we compare the given equation with general form
[tex]y^2=-4x[/tex]
We have -4 in the place of 4p
[tex]4p=-4[/tex]
Divide both sides by 4
so p = -1
the value of p = -1
Find the product for 7 x 2/3
The word product is the answer to a multiplication problem.
7 x 2/3
7/1 x 2/3
(7 x 2)/(1 x 3)
Answer: 14/3
Sheila deposited $1,050.00 into a saving account at her local bank. if the interest rate is 1.5%, then how much will he have after 18 months (round your answer to the nearest cent)?
You are serving bratwurst and hamburgers at your annual picnic. You want at least three bratwursts or hamburgers for each of your 40 guests. Bratwursts cost $1.35 each and hamburgers $1.2 each. Your budget is $175.
Let x be the number of bratwursts and y the number of hamburgers. whiichs system of inequalities represents this situation?
Options:
x+y<=40 1.35x+1.2y>=175
x+y<=40 1.35x+1.2y<=175
x+y>=120 1.35x+1.2>=175
x+y>=120 1.35x+1.2<=175
...?
Answer:
Option D -[tex]x+y\geq 120[/tex] , [tex]1.35x + 1.2y \leq 175[/tex]
Step-by-step explanation:
Given : You want at least three bratwursts or hamburgers for each of your 40 guests. Bratwursts cost $1.35 each and hamburgers $1.2 each. Your budget is $175.
To find : Which system of inequalities represents this situation?
Solution :
Let x be the number of bratwursts and y the number of hamburgers.
You want at least three bratwursts or hamburgers for each of your 40 guests.
i.e, you want at least [tex]3\times(40)=120[/tex] bratwursts or hamburgers.
We can write the equation as,
Number of bratwursts + number of hamburgers at least 120
[tex]x+y\geq 120[/tex]
Bratwursts cost $1.35 each and hamburgers cost $1.2 each. Your budget is $175.
We can write equations as ,
Cost of bratwursts + cost of hamburgers at most 175
[tex]1.35x + 1.2y \leq 175[/tex]
Therefore, The system of linear equation form is [tex]x+y\geq 120[/tex], [tex]1.35x + 1.2y \leq 175[/tex]
Hence, Option D is correct.
Franko's pizza is selling their pizzas 35% cheaper than usual. if a pizza normally costs $12.00, how much is it now?
Find the radius of a circle with circumference of 55.3 yd^2. Round to the nearest tenth.
How many permutations of the letters ABCDEFG contain:
a.) the string BCD?
b.) the string CFGA?
c.) the strings BA and GF?
The number of permutations of ABCDEFG containing BCD, CFGA, and BA & GF are 120, 24, and 120, respectively.
Explanation:In permutations, the order of the items is important. For all these problems, we're asked how many permutations of the letters ABCDEFG contain a specific string. To solve this, we can initially treat the required string as a single item.
For BCD, we consider 'BCD' as one letter, so now we have 5 letters (A,E,F,G,BCD). The number of permutations for 5 items is 5P5 = 5! = 120. For CFGA, we consider 'CFGA' as one letter, so now we have 4 letters (B,D,E,CFGA). The number of permutations for 4 items is 4P4 = 4! = 24. For BA and GF, we consider 'BA' and 'GF' as one letter each, so now we have 5 letters (C,D,E,BA,GF). The number of permutations for 5 items is 5P5 = 5! = 120. Learn more about Permutations here:https://brainly.com/question/23283166
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15 less than 4 times a number is 9 find the number
A company has tow electric motors consume varying amounts of power. The power consumed by each motor is a function of the time (t in minutes) for which it runs. The cost of power (in $) to run one motor is given by the function Ca(t)=t^2-2t+5. The cost of running the second motor is given by Cb(t)=3t+2. Which gives the total cost of running both motors?
C(t)=3t^3-6t^2+15t
C(t)=2t^2-4t+10
C(t)=t^2+t+7
C(t)=3t^3+6t^2-15t
Answer:
Option (c) is correct.
The total cost of running both motors is [tex]t^2+t+7[/tex]
Step-by-step explanation:
Given : The cost of power (in $) to run one motor is given by the function [tex]C_a(t)=t^2-2t+5[/tex] and The cost of running the second motor is given by [tex]C_b(t)=3t+2[/tex]
We have to find the total cost of running both motors.
Since we are given the cost to run each motors so, total cost will be the sum of running both motors.
Let C(t) be the total cost of running both motors.
[tex]C(t)=C_a(t)+C_b(t)[/tex]
Substitute,
[tex]C_a(t)=t^2-2t+5[/tex]
and [tex]C_b(t)=3t+2[/tex]
We get,
[tex]C(t)=t^2-2t+5+3t+2[/tex]
Simplify, we get,
[tex]C(t)=t^2+t+7[/tex]
Thus, The total cost of running both motors is [tex]t^2+t+7[/tex]
If there is a ratio of 3 to 2 what is the ratio of 3if the total is 30
The revenue from selling x shirts is r(x) = 11x.
The cost of buying x shirts is c(x) = 6x + 20.
The profit from selling x shirts is p(x) = r(x) – c(x).
What is p(x)?
A. p(x) = 5x + 20
B. p(x) = 17x + 20
C. p(x) = 17x – 20
D. p(x) = 5x – 20
HELP!!give me the correct answer!! thank you
Answer:
Correct answer is: D p(x)=5x-20: Apex
Step-by-step explanation:
The value of the profit function is equal to 5x - 20. The correct option is D.
Given that:
Revenue function: r(x) = 11x
Cost function: c(x) = 6x + 20
To find the profit function, we need to subtract the cost function from the revenue function:
p(x) = r(x) - c(x)
Substituting the given revenue and cost functions and calculated as:
p(x) = 11x - (6x + 20)
Simplifying above expression as:
p(x) = 11x - 6x - 20
Combining like terms as:
p(x) = 5x - 20
Therefore, the value of the profit function is equal to 5x - 20. The correct option is D.
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some one factor 5x^2+23x+26
5*x^2-23*x-(-26)=0
1. x = 2
2. x = 13/5 = 2.600The temperature, in degrees fahrenheit (°
f., decreased at a constant rate from 0°f to -25 °f in 5 hours. by how many degrees did the temperature decrease per hour?
The temperature decreased at a constant rate of 5 degrees Fahrenheit per hour.
Explanation:The question is asking for the rate at which the temperature is decreasing per hour. The temperature started at 0oF and decreased to -25oF. That's a total change in temperature of 25oF (since we're counting how much it dropped below 0o). This change happened over the course of 5 hours. Therefore, to find the rate of change, we divide the total change (25 degrees) by the total time (5 hours). This gives us 5oF per hour. So, the temperature decreased at a rate of 5oF per hour.
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What is the factored form of the expression?
s^4 – 16
A. (s - 2)^2(s + 2)^2
B. (s - 2)(s + 2)
C. (s - i)(s + i)(s - 2)(s + 2)
D. (s - 2i)(s + 2i)(s - 2)(s + 2)
Solve for x.
log6(2x + 3) = 3 ...?
The value of x that satisfies the original equation is 106.5. To solve the given logarithmic equation, convert it to its exponential form and simplify. Subtract 3 from both sides, and finally divide by 2 to find that x equals 106.5.
Explanation:To solve for x in the equation log6(2x + 3) = 3, we can convert the logarithmic equation into its exponential form. This means that we interpret the equation as 6 raised to the power of 3 equals 2x + 3:
63 = 2x + 3
The next step is to simplify. 6 to the power of 3 is 216:
216 = 2x + 3
We can now solve for x by first subtracting 3 from both sides:
216 - 3 = 2x
213 = 2x
And then dividing by 2:
x = 213 / 2
x = 106.5
Thus, the value of x that satisfies the original equation is 106.5.
Why do we use decimals in everyday life
Twice a number decreased by 44 is 6 times the sum of the number and 3 times the number. find the number
from 5x^2-6x+8, subtract 3x^2-2x-4?
Solve -2.5n + 8.7 > 5.45.
n < 1.3
n > 1.3
n < -5.66
n > -5.66
Answer:
N < 1.3
Step-by-step explanation:
Go thank the answer above! :)
PLZZZZZ HELP
Which answer best describes the system of equations shown in the graph?
not enough information
consistent and independent
coincident
inconsistent
Answer:
Option (2) is correct.
The given system of equation is Consistent and independent.
Step-by-step explanation:
coincident : When two lines overlap each other. then they are coincident lines.Inconsistent: When there is no solution for the given system of equations then the system is called "inconsistent". Consistent : When there is one or infinitely many solutions for the given system of equations is called "consistent".Independent : When each equation of the system gives new information Otherwise they are called Dependent. like x + y = 2 and 2x + 2y =4 this shows one equation is multiple of other hence, dependent.Now consider the given graph,
Since, they intersect at a unique point. Hence, they are consistent.
Also the two given equations are independent of each other .Thus, independent also.
Thus, the given system of equation is Consistent and independent.
Thus, option (2) is correct.
A souvenir maker wants to create a scale model of the Empire State Building. The Empire State Building is 1,472 feet tall and has a base with dimensions 286 ft by 286 ft. If the model is 6 in. tall, what are the approximate dimensions of its base in inches? (Round your answer to the nearest tenth of an inch.)
A) 1.2 in. by 1.2 in.
B) 1 in. by 1 in.
C) 0.2 in. by 0.2 in.
D) 2.3 in. by 2.3 in.
Polygon ABCD is reflected and dilated to give polygon PQRS. The coordinates of the preimage are (2, 2), (6, 8), (12, 8), and (16, 2). The coordinates of the image are (11, 15),
(9, 12), (6, 12), and (4, 15). What is the scale factor of the dilation?
Answer: The scale factor of the dilation is 0.5.
Explanation:
It is given that ABCD is polygon which is reflected and dilated , then we get PQRS.
The vertices of ABCD are (2, 2), (6, 8), (12, 8), and (16, 2) respectively. The vertices of image PQRS are (11, 15),(9, 12), (6, 12), and (4, 15) respectively.
The reflection affects the coordinates but does not affect the length of the sides.
But when we talk about dilation it affects the length of sides according to the scale factor or a constant factor.
If a line segment AB is dilated by scale factor k then length of A'B' is k times length of AB.
[tex]|A'B'|=k\times |AB|[/tex] .... (1)
So we have to find any side length of preimage and the side length of that side in image. it means we have to find AB and PQ.
Use distance formula to find the side length.
[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
[tex]AB=\sqrt{(8-2)^2+(6-2)^2}=\sqrt{36+16}=2\sqrt{13}[/tex]
[tex]PQ=\sqrt{(9-11)^2+(12-15)^2}=\sqrt{4+9}=\sqrt{13}[/tex]
It is noticed that the size of side in preimage is [tex]2\sqrt{13}[/tex] and the size of same side in image is [tex]\sqrt{13}[/tex].
Using equation (1), we get
[tex]\sqrt{13}=k \times 2\sqrt{13}[/tex]
[tex]k=\frac{1}{2}[/tex]
[tex]k=0.5[/tex]
Hence, the value of scale factor is 0.5.
(URGENT-15 Points) Can someone help me/check my answers for this? Thank you! For the first screenshot, my answers for 1-5 are: (1) 79.2 (2) 12.4 (3) 78 and 82 (4) 76 and 84 (5) 74 and 86. I am stuck on questions 6-8 (#8 is on the second screenshot at the top...). On the second screenshot, I'm not sure how to answer question (9) based on the dot-plot on the first screenshot. For (10), if it's asking for the mean of these numbers, I got 23.8. If it's just asking for the sum, I got 119. For 11-12, the means aren't the same because this mean (#10) is based on the random sample generated from the original number of grades, while the first mean (#2) was based on the total population of grades for the entire class. It would make sense that the second mean would be smaller than the first. I'm giving away 15 points to the person who can help me with this and check my answers! I'd really appreciate it! :)
A building casts a 50-foot shadow. Alex is 5 feet tall and casts a 6-foot shadow. Approximately how tall is the building?
A.24 ft
B.42 ft
C.60 ft
D.50 ft
Answer:
Option B: 42 feet is the answer.
Step-by-step explanation:
The length of the shadow of the building is = 50 feet
Let the height of the building be = L
Height of Alex = 5 feet
Length of Alex's shadow = 6 feet
Now we will equate the ratios.
[tex]\frac{5}{6}= \frac{L}{50}[/tex]
[tex]6L=250[/tex]
[tex]L=250/6[/tex]
L = 41.67 ≈ 42 feet
So, the height of the building is approx 42 feet.
The diagonal of a square is x units. What is the area of the square in terms of x?
square units
square units
2x square units
square units
Let
b------> the length side of a square
we know that
the area of a square is equal to
[tex]A=b^{2}[/tex]
Find the length side of the diagonal applying the Pythagoras Theorem
[tex]d^{2}=b^{2}+b^{2}[/tex]
[tex]d^{2}=2b^{2}[/tex]
[tex]d=b\sqrt{2}\ units[/tex]
Remember that
[tex]d=x\ units[/tex] -----> given problem
substitute
[tex]d=b\sqrt{2}\ units[/tex]
[tex]x=b\sqrt{2}\ units[/tex]
Solve for b
[tex]b=\frac{x\sqrt{2}}{2}\ units[/tex]
Substitute in the formula of area
[tex]A=(\frac{x\sqrt{2}}{2})^{2}[/tex]
[tex]A=\frac{x^{2}}{2}\ units^{2}[/tex]
therefore
the answer is
[tex]\frac{x^{2}}{2}\ units^{2}[/tex]
The area of the square in terms of x is [tex]\( \frac{x^2}{2} \),[/tex] obtained by using the Pythagorean theorem and the formula for the area of a square.
To find the area of the square in terms of [tex]\(x\),[/tex] we need to first understand the relationship between the diagonal and the side length of a square.
In a square, each diagonal divides the square into two congruent right triangles. Using the Pythagorean theorem, we can find the relationship between the diagonal [tex](\(x\))[/tex] and the side length of the square [tex](\(s\)).[/tex]
The Pythagorean theorem states:
[tex]\[ \text{Hypotenuse}^2 = \text{Adjacent side}^2 + \text{Opposite side}^2 \][/tex]
For a square:
[tex]\[ x^2 = s^2 + s^2 \][/tex]
[tex]\[ x^2 = 2s^2 \][/tex]
Now, we can solve for [tex]\(s\)[/tex] in terms of [tex]\(x\):[/tex]
[tex]\[ s^2 = \frac{x^2}{2} \][/tex]
[tex]\[ s = \sqrt{\frac{x^2}{2}} \][/tex]
[tex]\[ s = \frac{x}{\sqrt{2}} \][/tex]
The area [tex](\(A\))[/tex] of a square is given by:
[tex]\[ A = s^2 \][/tex]
Substituting the expression for s in terms of x :
[tex]\[ A = \left(\frac{x}{\sqrt{2}}\right)^2 \][/tex]
[tex]\[ A = \frac{x^2}{2} \][/tex]
Therefore, the area of the square in terms of x is [tex]\( \frac{x^2}{2} \).[/tex]
The question probable may be:
The diagonal of a square is x units. What is the area of the square in terms of x?