Are the polygons similar? If they are, choose the correct similarity statement and scale factor.

Answer:

The answer is d = √[(p - m)² + (q - n)²] ⇒ first answer

Step-by-step explanation:

* The distance between any to points (x1 , y1) , (x2 , y2) is

- d = √[square the difference of x- coordinates plus

        square the difference of y-coordinates]

∴ d = √[(x2 - x1)² + (y2 - y1)²] or

∴ d² = (x2 - x1)² + (y2 - y1)²

* x2 - x1 is the horizontal distance (h) and y2 - y1

 is the vertical distance (v)

- By using Pythagoras theorem

∴ d = √[h² + v²]

∵ The two points are (p , q) and (m , n)

- Put x1 = m and y1 = n

- Put x2 = p and y2 = q

∴ d² = (p - m)² + (q - n)²

∴ d = √[(p - m)² + (q - n)²]

∴ The answer is d = √[(p - m)² + (q - n)²] ⇒ first answer

Answer:

The answer is d = √[(p - m)² + (q - n)²] ⇒ first answer

Step-by-step explanation:

Answer:

Step-by-step explanation:

15 less than twice a number g is 19

2g - 15 = 19      add 15 to both sides

2g - 15 + 15 = 19 + 15

2g = 34       divdie both sides by 2

2g : 2 = 34 : 2

g = 17

20% as a fraction is 1/5

25% is 1/4

40% is 2/5

and 70% is 7/10

Depending on what your fraction is, you can find the answer in the fraction itself-

20%, you can take 20, 5 times to get to 100. Hence 1/5.

25 can go into 100 4 times (1/4)

40 is just 20 twice, so its 2/5.

Take 10 7 times and get 7/10.

Hope this helps a bit :)

Answer:

= 32√3 ft²

Step-by-step explanation:

Area of the trapezoid will be equal to the area of the square and that of the triangle.

Considering the triangle part;

Cos 60 = x/8

x = 8 × sin  60

   = 4

Base of the triangle part = 4 ft

Therefore, top of the trapezoid = 6 ft

Height = 8 × sin 60

            = 8 × √3/2

           = 4 √3

Area of the trapezoid

Area = ((a+b)/2) × h

        = ((6 + 10 )/2 )× 4√3

        = 16/2 × 4√3

        = 32√3 ft²

Answer:

4th option is correct

Step-by-step explanation:

Here in the triangle we have angle = 60

hypotenuse= 8

opposite and adjacent can be solved using trigonometric ratios

cos 60  = [tex]\frac{adjacent}{hupotenuse} \\\frac{adjacent}{8} \\\frac{1}{2}=\frac{adjacent}{8}[/tex]

which gives adjacent = 4  on solving

likewise using sine we can find opposite side to the angle which is height of

trapezium.

sin60[tex]\frac{opposite}{hypotenuse}=\frac{x}{8} \\\frac{\sqrt{3} }{2}=\frac{x}{8}\\x=4\sqrt{3}[/tex]

therefore height =[tex]4\sqrt{3}[/tex] and adjacent = 4  ft

therefore opposite sides of Trapezium are 10 ft and 6 ft  

Formula for area of Trapezium =[tex]\frac{1}{2}[/tex](sum of parallel sides)x height

=      [tex]\frac{1}{2}[/tex](10+6)x [tex]4\sqrt{3}[/tex]

on solving it ,we get  [tex]32\sqrt{3}[/tex]

Answer:

  x = 11.5

Step-by-step explanation:

Taking the logarithm base 2 will transform this to a linear equation.

  2(2x+7) = 3(2x -3)

  0 = 3(2x -3) -2(2x +7) . . . . subtract the left side

  0 = 2x -23 . . . . . . . . . . . . . simplify

  0 = x - 23/2 . . . . . . . . . . . . divide by 2

  11.5 = x . . . . . . . . . . . . . . . . add 11.5

The solution is x = 23/2 = 11.5.

_____

Check

This value of x makes the equation become ...

  4^(2·23/2 +7) = 8^(2·23/2 -3)

  4^30 = 8^20 . . . . . true

Since an 100% chance is all possibilities, then it must add up to 100. If we take away that 14 from 100 by subtracting, you just get 86. Therefore, there is an 86% chance that it will not rain tomorrow.

Answer:

  f(x) = -4/3x² -2/3x +10

Step-by-step explanation:

The quadratic regression function of a graphing calculator or spreadsheet can determine the equation for you.

___

Or, you can determine it yourself.

The equation can be written in the form ...

   f(x) = a(x +3)(x -5/2) . . . . . . . using the given x-intercepts

for some value of "a"

For x = 0, this must match the y-intercept.

  f(0) = a(0 +3)(0 -5/2) = 10

  -15/2·a = 10

  a = -20/15 = -4/3

So, the function can be written as ...

  f(x) = (-4/3)(x +3)(x -5/2)

or

  f(x) = -4/3x² -2/3x +10

-2/3( 2x^2 + x - 15) is the answer.

From the given x-intercepts, 2 factors of the equation will be (x + 3) and

(2x - 5):- So we can write:

At the y-intercept x = 0 so we have the equation a(0+3)(2(0) - 5) = 10  where a is a constant.

a * -15 = 10

a = -2/3  so the function is  (-2/3)(x  + 3)(2x - 5)

= -2/3( 2x^2 + x - 15).

Answer:   [tex]\bold{\dfrac{11}{18}}[/tex]

Step-by-step explanation:

Think of the products row by row:

11  12  13  14  15  16  - 0 products greater than 6

21 22 23 24 25 26  - 3 products greater than 6

31 32 33 34 35 36  - 4 products greater than 6

41 42 43 44 45 46   - 5 products greater than 6

51 52 53 54 55 56  - 5 products greater than 6

61 62 63 64 65 66  - 5 products greater than 6

[tex]\dfrac{\text{number greater than 6}}{\text{total possible outcomes}}=\dfrac{22}{36}=\dfrac{11}{18}\ when\ reduced[/tex]

Answer:

11/18.

Step by.step explanation:

There are 36 possible outcomes when 2 dice are rolled.

Outcomes for a product greater than six are:

2,4  2,5  2,6  3,3  3,4  3,5  3,6  4,2  4,3  4,4  4,5  4,6  5.2 ......5.6 , 6.2 .......6.6.

=  22 ways.

required Probability is 22/36 = 11/18 (answer).

Answer:

Based off of the given information I believe the answer is 8,000,000 hydrogen atoms because it appears that the ratio between hydrogen and oxygen atoms in 2:1.

Step-by-step explanation:

Using the 2:1 ratio of hydrogen to oxygen atoms in water (H2O), a volume of water with 4,000,000 oxygen atoms would contain 8,000,000 hydrogen atoms.

We know that water, with the chemical formula H2O, consists of two hydrogen atoms for every oxygen atom. Using this information, for every oxygen atom in water, we need to account for two hydrogen atoms.

Given that a certain volume of water contains 100,000 hydrogen atoms and 50,000 oxygen atoms, we have a 2:1 ratio of hydrogen to oxygen atoms. If we want to determine how many hydrogen atoms are in a volume of water containing 4,000,000 oxygen atoms, we must apply the same 2:1 ratio.

To do so, we multiply the number of oxygen atoms by 2 (since there are two hydrogen atoms for every one oxygen atom), obtaining: 4,000,000 oxygen atoms  times 2 = 8,000,000 hydrogen atoms.

Answer:

The draw in the attached figure

Step-by-step explanation:

Let

L-----> the length of the rectangle

W----> the width of the rectangle

we know that

The perimeter of a rectangle is equal to

[tex]P=2(L+W)[/tex]

we have

[tex]W=23\ ft[/tex]

so

[tex]P=2L+46[/tex] -----> equation A

[tex]P\leq 236\ ft[/tex]  ----> inequality B

substitute equation A in the inequality B and solve for L

[tex]2L+46\leq 236[/tex]

[tex]2L\leq 236-46[/tex]

[tex]2L\leq 190[/tex]

[tex]L\leq 95\ ft[/tex]

The maximum possible  value of L is 95 ft

therefore

The rectangle could be

Length 95 ft

Width 23 ft

see the attached figure to see the draw

Answer:

Area of Large Circle = 380.13

Area of Small Circle = 254.47

Area of Sidewalk = 125.66

Step-by-step explanation:

The side walk is just subtracting the smaller number from the bigger one.

The area is just Pi*r^2

Answer:

A  379.94 m^2

B 254.34 m^2

C 125.6 m^2

Step-by-step explanation:

A  Area of a circle is given by

A = pi r^2

We know the radius is 11

A = pi 11^2

A = 3.14 (121)

A = 379.94 m^2

B The Area of the orange circle

A = pi r^2

The radius is 9 m

A = pi 9^2

A = 3.14 (81)

A = 254.34 m^2

C  The Area between the circles is the difference between the large circle and the small circle

Ablue-Aorange

379.94-254.34

125.6 m^2

Answer:

Step-by-step explanation:

Line passes through (0,0) and (-1,4) .

Slope = -4

Equation of line is : y - 0 = - 4(x - 0)

                                 y = - 4x

Answer:

  your choices are correct

Step-by-step explanation:

sin(x +π/2) is a translation of the sine function to the left by π/2 units, which makes it look exactly like the cosine function that you want.

cos(-x) is the same as cos(x), since the cosine function is an even function.

___

sin(x -π/2) will look like -cos(x), not what you want.

The third choice is a reflection across the x-axis of the function you started with. It is not equivalent.

Answer:

(4,10) is the solution

Step-by-step explanation:

2x + y = 18

x – y = –6

Using elimination

2x + y = 18

x – y = –6

----------------------

3x    = 12

Dividing each side by 3

3x/3 = 12/3

x =4

Now we can find y

2x+y = 18

2(4) +y =18

8+y = 18

Subtracting 8 from each side

8-8+y = 18-8

y=10

(4,10) is the solution

Answer:

25%

Step-by-step explanation:

Just did test

[tex] \frac{27 \: miles \div 2}{2 \: hours \div 2} = \frac{13.5 \: miles}{1 \: hour} [/tex]

[tex] \frac{13.5 \: miles \div 2}{1 \: hour \div 2} = \frac{6.75 \: miles}{0.5 \: hour} [/tex]

The boat will travel 6.75 or

[tex]6 \frac{3}{4} [/tex]

miles in 1/2 hour.

Answer:

Geometric

Step-by-step explanation:

Does multiplying the same number with each term give the next term?

If so, then it is Geometric Sequence.

Does adding the same number with each term give the next term?

If so, then it is Arithmetic Sequence.

We see that multiplying by 3 gives us each successive term. 2 times 3 is 6 and 6 times 3 is 18. So it is geometric sequence.

It is NOT arithmetic sequence since we add 4 to 2 to get next number 6, but we have 12 to get next number, which is 18. So not an arithmetic sequence.

Answer is "Geometric"

Answer:

Step-by-step explanation:

________

Good evening ,

________________

“”There are 9 pages in the album ,Farah puts the same number of photos on each page ,for a total of 63 photos “”

We can explain the last sentence this way : “ 9p = 63” then p=7

__

:)

Answer: Your answer is option D. In each family of function,the Parent function is the most basic function in the family

The family function has same highest degree, same shape for graph and consequently.

The correct option is D.

Given:

Identify the function is the most basic function in the family.

Below are the few example of family function.

[tex]y=x^2[/tex]

[tex]y=3x^2[/tex]

The graph for the both the function has same highest degree, same shape for graph and consequently. The parent function is the simplest from a family of function.

Thus, the correct option is D.

Learn more about parent function here:

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the answer is A :)))))))))))))))))

Answer:

I am pretty sure it is Rhombus or a sideway rectangle but since they dont say more than givin I would say Rhombus

Step-by-step explanation:

Answer:

1/2 or 0.5

Step-by-step explanation:

First think: How many numbers are there between 5 and ten that are odd?

5,7 and 9 are all odd (that makes 3 numbers)

Then you take that and divide it by the total number of numbers between 5 and 10

5,6,7,8,9,10 (that makes 6 numbers)

You then get 3/6, simplified to 1/2 or 0.5

$10.75 x 8 = $86 x 4(weeks) = $344

Multiply his hourly rate by the number of hours per week:

$10.75 x 8 hours = $86.00 per week.

An average month has 4 weeks, so in a 4 week month, multiply his weekly pay by the number of weeks in a month. ( Some months have 5 weeks, so you would need to multiply the weekly amount by 5 weeks).

$86 x 4 weeks = $344

Answer:

True

Step-by-step explanation:

The given inequality is

[tex]5\le x\le 8[/tex]

The boundaries of the inequality are inclusive.

We use the square brackets to indicate closed interval.

[tex]5\le x\le 8[/tex] is therefore written in interval notation as;

[5,8]

The correct choice is true

Answer:

if i don't doubt then 1/4

Step-by-step explanation:

Answer:

2700

Step-by-step explanation:

Answer:

Step-by-step explanation:

-4x∧2  -1

-4x squared minus one

The pumping stations will deliver approximately 8.188 gallons of oil during the 4-hour period from t = 0 to t = 4.

To find the amount of oil delivered by the pumping stations during the 4-hour period from t = 0 to t = 4, we need to evaluate the definite integral of the function D(t) over that interval. The function D(t) is given by D(t) = 5t / (1 + 3t). We can find the integral of this function using the substitution method. Let u = 1 + 3t, then du = 3dt. Rearranging this equation, we have dt = du / 3.

Substituting this in the integral, we get:

∫ D(t) dt = ∫ (5t / u) * (1/3) du = (5/3) * ∫ (t / u) du

Integrating the above expression, we get:

∫ D(t) dt = (5/3) * ∫ (t / u) du = (5/3) * ∫ (t / (1 + 3t)) du

To evaluate this integral, we can use the natural logarithm function. We know that ∫ (1/u) du = ln|u| + C, where C is the constant of integration. Substituting back for u, we have:

(5/3) * ∫ (t / (1 + 3t)) du = (5/3) * ∫ (t / u) du = (5/3) * ln|1 + 3t| + C

Now, we can use the definite integral to find the amount of oil delivered during the 4-hour period:

∫04 D(t) dt = (5/3) * ∫04 (t / (1 + 3t)) dt = (5/3) * [ln|1 + 3(4)| - ln|1 + 3(0)|] = (5/3) * [ln|13| - ln|1|] = (5/3) * ln|13| = 8.188

Therefore, the pumping stations will deliver approximately 8.188 gallons of oil during the 4-hour period from t = 0 to t = 4.

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Answer I think it is c I hope that right I am sorry for late responds

Answer:

A) 0.5564; B) 0.8962; C) Choice D. Part​ (a) because the seat performance for a single pilot is more important.

Step-by-step explanation:

For part A,

We will find the z score for each value and then subtract the probabilities for each to give us the area between them.  We use the z score for an individual value:

[tex]z=\frac{X-\mu}{\sigma}[/tex]

Our first X is 130 and our second X is 191.  Our mean, μ, is 136 and our standard deviation, σ, is 28.5:

[tex]z=\frac{130-136}{28.5}=\frac{-6}{28.5}\approx -0.21\\\\z=\frac{191-136}{28.5}=\frac{55}{28.5}\approx 1.93[/tex]

Using a z table, we can see that the area under the curve to the left of z = -0.21 is 0.4168; the area under the curve to the left of z = 1.93 is 0.9732.  This means the area between them is

0.9732-0.4168 = 0.5564.

For part B,

We will find the z score for each value again and subtract them; however, since we have a sample we will use the z score for the mean of a sample:

[tex]z=\frac{\bar{X}-\mu}{\sigma \div \sqrt{n}}[/tex]

Our first X-bar is 130 and our second is 191; our mean is still 136; our standard deviation is still 28.5; and our sample size, n, is 36:

[tex]z=\frac{130-136}{28.5\div \sqrt{36}}=\frac{-6}{28.5\div 6}\approx -1.26\\\\z=\frac{191-136}{28.5\div \sqrt{36}}=\frac{55}{28.5\div 6}\approx 11.58[/tex]

The area under the curve to the left of -1.26 is 0.1038; the area under the curve to the left of 11.58 is 1.00:

1.00-0.1038 = 0.8962

For part C,

We want the probability that each individual pilot will be safe in these seats, so the value in part A is more important.

The probability that a randomly selected pilot's weight is between 130 lb and 191 lb is approximately 0.558 or 55.8%. The probability that the mean weight of 36 randomly selected pilots is between 130 lb and 191 lb is approximately 0.1056 or 10.56%. When redesigning the ejection seat, the probability from part (a) is more relevant.

To find the probability that a randomly selected pilot's weight is between 130 lb and 191 lb, we need to calculate the z-scores for both weights and find the area under the curve between those two z-scores. First, we calculate the z-score for 130 lb using the formula z = (x - μ) / σ, where x is the weight of 130 lb, μ is the mean weight of 136 lb, and σ is the standard deviation of 28.5 lb. Solving for z, we get z = (130 - 136) / 28.5 = -0.21. Using a z-table or calculator, we find that the area to the left of -0.21 is approximately 0.415. Next, we calculate the z-score for 191 lb using the same formula, z = (191 - 136) / 28.5 = 1.93. Again using a z-table or calculator, we find that the area to the left of 1.93 is approximately 0.973. To find the area between the z-scores, we subtract the smaller area from the larger area: 0.973 - 0.415 = 0.558. Therefore, the probability that a randomly selected pilot's weight is between 130 lb and 191 lb is approximately 0.558 or 55.8%.

To find the probability that the mean weight of 36 randomly selected pilots is between 130 lb and 191 lb, we need to use the Central Limit Theorem. The sample mean follows a normal distribution with a mean equal to the population mean and a standard deviation equal to the population standard deviation divided by the square root of the sample size. In this case, the mean is still 136 lb and the standard deviation is 28.5 lb divided by the square root of 36, which is 4.75 lb. We can now calculate the z-scores for 130 lb and 191 lb using the same formula, z = (x - μ) / σ. The z-score for 130 lb is (130 - 136) / 4.75 = -1.26, and the z-score for 191 lb is (191 - 136) / 4.75 = 11.58. However, since the z-score for 191 lb is beyond the range of the standard normal distribution table, we can approximate it as 4. This means that we need to find the area under the curve to the left of -1.26 and subtract the area to the left of -4. Using a z-table or calculator, we find that the area to the left of -1.26 is approximately 0.1056, and the area to the left of -4 is approximately 0.000032. Subtracting the smaller area from the larger area, we get 0.1056 - 0.000032 = 0.1056. Therefore, the probability that the mean weight of 36 randomly selected pilots is between 130 lb and 191 lb is approximately 0.1056 or 10.56%.

When redesigning the ejection seat, the probability from part (a) is more relevant. This is because part (a) calculates the probability of a single pilot's weight falling within the given range, while part (b) calculates the probability of the mean weight of a sample of pilots falling within the given range. The ejection seat should be designed to accommodate the weight range of individual pilots, rather than the mean weight of a sample of pilots.

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