The given sequence is not geometric because they don't have a common ratio.
What is geometeric sequence?
A geometric sequence is set of numbers which have a common ratio. The next number in a geometirc sequence is the multiple of the previous number.
Ratios of the numbers in the sequence-1/1 = -1
4/1 = 4
8/4 = 2
The numbers don't have a common ratio.
Thus, we can conclude that the given sequence is not geometric because they don't have a common ratio.
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The common ratio is not the same for all pairs of consecutive terms, so the sequence is not geometric.
To determine if a sequence is geometric, we need to check if there is a common ratio between consecutive terms.
In a geometric sequence, each term is obtained by multiplying the previous term by a constant value called the common ratio.
Let's check the given sequence: -1, 1, 4, 8.
To find out if it is geometric, we need to check if the ratio of consecutive terms is constant:
Common Ratio (r) = (Second Term) / (First Term)
= 1 / (-1)
= -1
Now, let's check if the common ratio is the same for the other pairs:
1st and 2nd terms: 1 / (-1) = -1
2nd and 3rd terms: 4 / 1 = 4
3rd and 4th terms: 8 / 4 = 2
The common ratio is not the same for all pairs of consecutive terms. Since the common ratio is not constant, the given sequence (-1, 1, 4, 8) is not a geometric sequence.
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The price of milk has been increasing over the last month. Audrey believes there is a positive correlation between the number of predicted storms and the price of milk.
Number of Storms Predicted Milk Price
1 $2.70
3 $2.89
4 $3.50
6 $3.88
7 $3.91
Use the table to determine the average rate of change from 3 to 6 storms.
3
0.98
1.21
0.33
Answer:
0.33
Step-by-step explanation:
Aight so all we do is use the formula, as shown here:
[tex]\frac{\Delta x}{\Delta y}[/tex]
[tex]x[/tex] is this amount it changed, which is 0.99. So we plug that for [tex]\Delta x[/tex]:
[tex]\frac{0.99}{\Delta y}[/tex]
Then, we find the amount of times the storm changed, and we plug that for [tex]\Delta y[/tex]:
[tex]\frac{0.99}{3}[/tex]
So, now that we have utilized the formula, we can now solve!
[tex]\frac{0.99}{3} = 0.33[/tex]
Good luck!
Answer:
0.33
Step-by-step explanation:
If 5 is an element in the domain of f(x)= 8x-21/5, what is the corresponding element in the range?
The corresponding element in the range when 7 is an element in the domain is f(5)=179/5
Step-by-step explanation:
Given that the 5 is an element in the domain of f(x)
The function f is defined by f(x)=8x-21/5
To find the corresponding element in the range:
That is put x=5 in the given function f(x)
Therefore f(x) becomes
f(5) = 8(5)-21/5
=40-21/5
=179/5
Therefore corresponding element in the range when 5 is an element in the domain is f(5)=179/5
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Find the quotient. 22x2y2 ÷ 11x2y2
Quotient = 2
Solution:
Given expression is [tex]22x^2y^2\div11x^2y^2[/tex].
To find the quotient.
[tex]22x^2y^2\div11x^2y^2=\frac{22x^2y^2}{11x^2y^2}[/tex]
In numerator 22 can be written as 2 × 11.
[tex]\frac{22x^2y^2}{11x^2y^2}=\frac{2\times11x^2y^2}{11x^2y^2}[/tex]
Take common term out in the numerator and denominator.
[tex]\frac{22x^2y^2}{11x^2y^2}=\frac{(11x^2y^2)(2)}{11x^2y^2}[/tex]
Common terms in the numerator and denominator will be cancelled.
[tex]\frac{22x^2y^2}{11x^2y^2}=2[/tex]
Hence the quotient is 2.
Answer:
The guy up top is right its 2 with no mistake.
Step-by-step explanation:
30 points
Which expression is equivalent to | a | ≤ 4 ?
1. a ≥ –4 and a ≤ 4
2. a ≤ –4 or a ≥ 4
3. a ≤ –4 and a ≥ 4
4. a ≥ –4 or a ≤ 4
Answer:
1. a ≥ –4 and a ≤ 4
Step-by-step explanation:
Rule : | a | ≤ 4 ⇔ -4 ≤ a ≤ 4
:)
What are the opposites of 6, −3.4, 2.25, and 8 1/ 5 ? Enter the answers in respective order, each separated by comma.
Answer:
Step-by-step explanation:
Answer:
Step-by-step explanation:
6= -6, -3.4=3.4, 2.25=-2.25, 8 1/5=-81/5
How many liters of water must be added to 15 liters of 40 % sugar syrup to obtain 30 % sugar syrup?
Answer:
5 liters of water.
Step-by-step explanation:
Let [tex]y[/tex] be the liters of water that must be added to 15 liters of 40% sugar syrup.
Initially, we have [tex]0.4(15)=6[/tex] liters of sugar syrup, and since adding water does not add any new syrup, the amount of sugar syrup must be the same after the water has been added. After the water has been added, 30% of the solution is sugar syrup, or
[tex]Sugar\:syrup =0.3(15+y)[/tex]
And since this must equal the amount of syrup we had before:
[tex]0.3(15+y)=0.4(15)[/tex]
[tex]4.5+0.3y=6[/tex]
[tex]0.3y=1.5[/tex]
[tex]\boxed{y=5}[/tex]
Thus, 5 liters of water must be added to obtain 30% sugar syrup.
Answer:
5 liters of water
a science test is worth 100 points and has 25 questions. There are multiple-choice questions worth three points each and short essay questions worth 8 points each. How many short essay questions are on the test?
There are 5 short essay questions on test
Solution:
Let "a" be the number of multiple choice questions
Let "b" be the number of short essay questions
Worth of each multiple choice questions = 3 points
Worth of each short essay questions = 8 points
There are 25 questions in total
number of multiple choice questions + number of short essay questions = 25
a + b = 25
a = 25 - b --------- eqn 1
The test is worth 100 points. Theerefore, we frame a equation as:
number of multiple choice questions x Worth of each multiple choice questions + number of short essay questions x Worth of each short essay questions = 100
[tex]a \times 3 + b \times 8=100[/tex]
3a + 8b = 100 --------- eqn 2
Let us solve eqn 1 and eqn 2
Substitute eqn 1 in eqn 2
3(25 - b) + 8b = 100
75 - 3b + 8b = 100
5b = 100 - 75
5b = 25
b = 5
Thus there are 5 short essay questions on test
The number of short essay questions on the test is 5.
Explanation:The science test is worth 100 points and has 25 questions. Let's represent the number of multiple-choice questions as 'x' and the number of short essay questions as 'y'. Each multiple-choice question is worth three points, so the total number of points for the multiple-choice questions is 3x. Each short essay question is worth eight points, so the total number of points for the short essay questions is 8y. We can write two equations to represent the given information:
x + y = 25 (since there are 25 questions in total)
3x + 8y = 100 (since the total points for the test is 100)
To find the number of short essay questions on the test, we need to solve these two equations. By substituting x = 25 - y into the second equation, we can solve for y.
3(25 - y) + 8y = 100
75 - 3y + 8y = 100
5y = 25
y = 5
Therefore, there are 5 short essay questions on the test.
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A rectangle park measures 300 ft by 400 ft. A sidewalk runs diagonally from one comer to the opposite corner. Find the length o
the sidewalk
a 400 ft
c 250 ft
b. 500 ft
d. 650 ft
The length of side walk is 500 feet
Solution:
Given that, A rectangle park measures 300 ft by 400 ft
Length = 300 feet
Width = 400 feet
A sidewalk runs diagonally from one comer to the opposite corner
We have to find the length of side walk
Which means, we have to find the length of diagonal of rectangle
The diagonal of rectangle is given by formula:
[tex]d = \sqrt{w^2+l^2}[/tex]
Where,
d is the length of diagonal
w is the width and l is the length of rectangle
Substituting the values in formula, we get
[tex]d = \sqrt{400^2+300^2}\\\\d = \sqrt{160000+90000}\\\\d = \sqrt{250000}\\\\d = 500[/tex]
Thus length of side walk is 500 feet
which expression is equivalent to 8/9 divided by 3/4
The expression is equivalent to 8/9 divided by 3/4 is 32/27.
What is fraction?The fractional bar is a horizontal bar that divides the numerator and denominator of every fraction into these two halves.
The number of parts into which the whole has been divided is shown by the denominator. It is positioned in the fraction's lower portion, below the fractional bar.How many sections of the fraction are displayed or chosen is shown in the numerator. It is put at the upper half of the fraction above the fractional bar.We have to divide the fraction 8/9 by 3/4.
As, the fraction does not allow division then we will perform the multiplication.
So, 8/9 x 4/3
= 32 / 27
Thus, the required fraction is 32/27.
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A school district has a student population of $6,734 students. If the maximum class size is 25 students. How many more teacher must the district have to supplement their staff of 217 teachers?
Answer:
53 teachers
Step-by-step explanation:
Basically, what we need to do here is to find how many teachers there need to be, first. If there are 6,734 students in the school district and if maximum class size is 25, then the number of teachers needed is:
6,734 / 25 = 269.36
Of course, it's obvious that we can't have a decimal number of teachers, so we need to find integer (269 or 270).
If we take 269 teachers and 25 students per class, we get:
269 • 25 = 6,725 students, which is not enough, since there are 6,734 students.
That means that the number of teachers needed is 270.
It is given that there are already 217 teachers, meaning that 270-217=53 teachers have to be supplemented.
52 more teachers must the district have to supplement their staff of 217 teachers.
Given that,
A school district has a student population of 6,734 students.
If the maximum class size is 25 students.
We have to determine,
How many more teachers must the district have to supplement their staff of 217 teachers?
According to the question,
Total number of students = 6,734
Maximum class size = 25 students
Then,
The number of teachers needed is,
[tex]= \dfrac{6734}{25}\\\\= 269.36[/tex]
Here, 269 teachers are needed for each group of 25 students.
Therefore,
The number of more teacher must the district have to supplement their staff of 217 teachers is,
269 - 217 = 52
Hence, 52 more teachers must the district have to supplement their staff of 217 teachers.
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Roger served 5/8 pound of crackers, which was 2/3 of entire box. What was the weight of crackers originally in box?
Answer:
original weight of the box = 15 / 16 pounds
Step-by-step explanation:
The cost of 5 squash and 2 zucchini is $1.32. 3 squash and 1 zucchini cost $0.75. Find the cost of each vegetable
Multiply the polynomials.
* (x + 4)(x2 - 5x + 3)
O
O
O
A. x2 - 5x2 - 17x+ 12
B. x3 – x2 + 3x + 12
c. x2 - 5x2 + 3x + 12
2 2 17 10
Answer:
x^3-x^2-17x+12
Step-by-step explanation:
(x+4)(x^2-5x+3)
x^3-5x^2+3x+4x^2-20x+12
x^3-5x^2+4x^2+3x-20x+12
x^3-x^2-17x+12
what is the standart dievation of 63 and 37 and what is the standart dievation of 88 and 112 this is a sample not a population
hello that is a hard question but the answer is your face
Answer:
im so sorry about the kid that said that. that was mean
Step-by-step explanation:
What is the algebraic expression for the following word phrase: the quotient of 6 and z?
A. 6+z
B. 6z
C. 6-z
D. 6/z
Answer:
Step-by-step explanation:
the quotient is the result of division
the quotient of 6 and z...
6/z <===
** pay attention to the wording...because if it would have said : the quotient of z and 6, it would have been z/6
Is 15/18 an equivalent ratio
Answer:
no
Step-by-step explanation:
bc
15/18 cant be simplified no matter what
Answer:
No
Step-by-step explanation:
15/18 can not be simplified
Rewrite the following expression using the distributive property and the GCF: 36+48
Answer:
12(3+4)
Step-by-step explanation:
Answer:
Etc: 12 34
Step-by-step explanation:
Camille shaded 18/30 of a model. Write the decimal that represents the unshaded portion of the model
Answer:
The decimal that represents the unshaded portion of the model is 0.4
Step-by-step explanation:
we know that
Camille shaded 18/30 of a model
That means
The total parts of the model is equal to 30
The shaded parts of the model is 18
To find out the unshaded parts of the model subtract the shaded parts from the total parts
[tex]30-18=12[/tex]
To find out the decimal that represents the unshaded portion of the model, divide the unshaded parts of the model by the total parts of the model
so
[tex]\frac{12}{30}=0.4[/tex]
How to you use a unit rate to solve a rate problem for any number of units?
Answer:
Here, we have used the unit rate i.e. speed of 30 mph to get the distance traveled in 5 number of units i.e. 5 hours.
Step-by-step explanation:
We are asked the way to use a unit rate to solve a rate problem for any number of units.
Let, us assume that a car is moving at a unit rate of 30 miles per hour. And we have to calculate the distance it travels in 5 units of time i.e. 5 hours.
Now, the distance traveled in 5 hours will be given by 30 × 5 = 150 miles.
Since [tex]\textrm {Speed} = \frac{\textrm {Distance}}{\textrm {Time}}[/tex] and here, speed is 30 miles per hour and the time is 5 hours. (Answer)
Can you help me on a math problem?
Answer: -3 and +3
Step-by-step explanation:
Find the Lowest Common Multiple of 108 and 120
Answer:
Step-by-step explanation:
108 = 2*2*3*3*3=2² * 3³
120 = 2*2*2*3*5=2³*3*5
LCM = 2³*3³*5 = 8*27*5= 1080
To find the LCM of 108 and 120, first find their prime factorizations and then multiply the highest power of each prime factor.
Explanation:To find the Lowest Common Multiple (LCM) of 108 and 120, we can first find their prime factorizations. The prime factorization of 108 is 2 × 2 × 3 × 3 × 3, while the prime factorization of 120 is 2 × 2 × 2 × 3 × 5. We can then find the LCM by taking the highest power of each prime factor from both numbers. So, the LCM of 108 and 120 is 2 × 2 × 2 × 3 × 3 × 3 × 5 = 2,160.
The Lowest Common Multiple (LCM) of 108 and 120 is 1080. This is found by finding the prime factors of each number, and then multiplying together the highest power of each factor.
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Use the grouping method to factor the polynomial below completely.
3x3 + 9x2 + 5x + 15
O A. (3x2 + 3)(x+5)
O B. (3x2 + 5)(x + 5)
O C. (3x2 + 3)(x+3)
O D. (3x2 + 5)(x + 3)
The correct answer is D. (3x2 + 5)(x + 3). Here’s how you can use the grouping method to factor the polynomial completely:
Group the first two terms and the last two terms: (3x3 + 9x2) + (5x + 15)
Factor out the greatest common factor from each group: 3x2(x + 3) + 5(x + 3)
Factor out the common binomial factor: (3x2 + 5)(x + 3)
So, the polynomial 3x3 + 9x2 + 5x + 15 can be factored completely as (3x2 + 5)(x + 3).
Hope it helps.
Please help!!!!! Math is very confusing and this makes no sense
A running track has the shape of a rectangle capped with a semicircle on each end, as shown below. If the track is 80 feet wide, and the rectangular portion of the track is 90 feet tall, estimate the length around the outside of the track.
The missing figure is attached down
The length around the outside of the track is about 431 feet
Step-by-step explanation:
A running track has the shape of a rectangle capped with a semicircle on each end
The track is 80 feet wideThe rectangular portion of the track is 90 feet tallWe need to estimate the length around the outside of the track
The length of the outside the track is the length of two semi-circle and two straight lengths of the rectangle
∵ The track is 80 feet wide
- From the figure the width of the track is the diameter of the
semi-circles
∴ The diameter of each semi-circle = 80 feet
∵ The radius of a circle is half its diameter
∴ The radius of each semi-circle = [tex]\frac{1}{2}[/tex] × 80 = 40 feet
∵ The length of a circle = 2πr
∴ The length of a semi-circle = πr
∴ The length of two semi-circle = 2 × πr
- Substitute r by 40
∴ The length of two semi-circle = 2 × π(40) = 80π feet
∵ The rectangular portion of the track is 90 feet tall
∴ The length of the rectangle = 90 feet
∴ The two straight parts of the track = 2 × 90 = 180 feet
- Add the length of the two semi-circles and the two straight
parts to find the length of the track
∵ Length of the track = 80π + 180
- Substitute π by 3.141
∴ Length of the track = 80(3.141) + 180
∴ Length of the track = 431.28 ≅ 431 feet
The length around the outside of the track is about 431 feet
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If an employee earns $20.00 per hour plus $1.50 per hour for vacation and you pay $2.00 per hour in tax and $9.00 for every $100.00 in payroll for workers compensation what is the total hourly wage for the employee ?
What is 3x + 4 = x + 8
Answer:
x is equal to 2
Step-by-step explanation:
2x+4=8
2x=4
x=2
Answer:
x = 2
Step-by-step explanation:
First you must subtract x to both sides leaving you with 2x + 4=8 and you subtract 4 to both sides giving you 2x=4 and lastly to get the x by itself you divide both sides by 2 leaving you with x=2
An online store is offering 15% off all items in your order. Before the discount is applied, the items in your cart are: shampoo for $6.35, conditioner for $6.35, granola bars for $12.50, dish soap for $13.40, and toothpaste for $2.50. What is the discounted total price for all the items, assuming no sales tax is added? Report your answer to two decimal places. Do not include the dollar sign, $, in the answer box below.
Answer:
The total discounted price is 34.93
Step-by-step explanation:
The items in the cart are:
Shampoo for $6.35Conditioner for $6.35Granola bars for $12.50Dish soap for $13.40 Toothpaste for $2.50Total cart = $ 41.10
Discount = 41.10 * 0.15 = $ 6.17
Discounted total price = 41.10 - 6.17
Discounted total price = 34.93
Answer:
34.94.
Step-by-step explanation:
First we must find the total price of all the items: =$6.35+$6.35+$12.50+$13.40+$2.50=$41.10.
Next, we can calculate the discount: =(15/100)×$41.10=$6.165.
Therefore, our discounted price is $41.10−$6.165=$34.935≈$34.94.
Please help ASAP!!!!
The simplified answer is [tex]5\frac{2}{9}[/tex].
Option: C.
Step-by-step explanation:
To simply [tex]-3\frac{1}{9} - (-8\frac{1}{3} )[/tex]:
First convert this improper fraction into normal fraction.
[tex]-3\frac{1}{9}[/tex] = [tex]\frac{-28}{9}[/tex].
[tex]-8\frac{1}{3}[/tex] = [tex]\frac{-25}{3}[/tex].
Now we have to simplify [tex]-\frac{28}{9} - (-\frac{25}{3} )[/tex].
= [tex]-\frac{28}{9} + \frac{25}{3}[/tex].
After applying LCM to the denominators, Multiply the second term with 3 in both numerator and denominator.
= [tex]-\frac{28}{9} + \frac{75}{9}[/tex].
=[tex]\frac{-28+75}{9}[/tex].
=[tex]\frac{47}{9}[/tex].
Convert the answer in improper fraction form.
[tex]\frac{47}{9}[/tex] = [tex]5\frac{2}{9}[/tex].
Thus the simplified answer is [tex]5\frac{2}{9}[/tex].
Will make brainliest if answered right
Answer:
d 10x=-3
Step-by-step explanation:
Identify a decimal number between 0.25 and 0.125
Answer: 0.126?
Step-by-step explanation:
A decimal number between 0.25 and 0.125 could be 0.2 or 0.15. These numbers sit within the specified range and comply with the principles of decimal number placement.
Explanation:The task here is to identify a decimal number that lies between 0.25 and 0.125. To achieve this, we can carefully select a decimal value that stands in the middle of these two numbers. An example of a suitable decimal would be 0.2, as it comfortably sits within this specified range. Another example could be 0.15. These are both valid decimal numbers that reside between 0.25 and 0.125, and their selection adheres to the principles of decimal number placement on a number line.
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How would I solve (6r +3)2 and show my work?
Answer:
12r+6
Step-by-step explanation:
2(6r+3)
2(6r)+2(3)
12r+6