f(x) = x +4 and g(x) = 12x -6 what is f(3) + g (-1)

(A) 22

(B) 33

(C) -11

(D) 11

I am having a brain fart can someone explain how I get the answer to this?

Answer:

B. 2x – 1 = 13 and x = 7

Step-by-step explanation:

We are given 4 equations and a solution for each. We have to tell which of the given solution satisfies the given equation.

Option A.

2x -1 = 13 and x = 6

Using this value in the equation, we get:

2(6) -1 = 13

12 - 1 = 13

11 = 13, which is not true. Hence this option is not valid

Option B.

2x - 1 = 13 and x = 7

Using the value in the equation, we get:

2(7) - 1 =13

14 - 1 =13

13 = 13, which is true. Hence this option is valid.

Option C.

2x + 1 =13 and x = 7

Using the value in the equation, we get:

2(7) + 1 = 13

15 = 13, which is not true. So this option is not valid

Option D.

2x - 1 = 13 and x = 11

Using this value in the equation, we get:

2(11) - 1 = 13

21 = 13, which is not true. Hence this option is not valid.

Answer:

C:12

Step-by-step explanation:

should be 13.5

The first quartile (Q1) is defined as the middle number between the smallest number and the median of the data set.

so the middle number of 10,11,12,15,17,19 is 13.5   since 12+15=27/2=13.5

the closest answer choice is C! Hope this helped!

Answer:

The correct option is C.

Step-by-step explanation:

The given data set is

10, 11, 12, 15, 17, 19, 22, 24, 29, 33, 38

Divide the data in two equal parts.

(10, 11, 12, 15, 17), 19, (22, 24, 29, 33, 38)

Divide each parenthesis in two equal parts.

(10, 11), 12, (15, 17), 19, (22, 24), 29, (33, 38)

The first quartile is 12, second quartile or median is 19 and third quartile is 29.

Since the first quartile of the data set is 12 Therefore, the correct option is C.

Answer:

The vale of 6 is 'Thousands'

Answer:

Place value of 6 is thousand and tens.

Step-by-step explanation:

6560   is the number where 6 has 2 place value

(1) at thousands

(2) at tens .

6,560 = 6000+500+60

          = 6x1000 +5x100+6x10

              Here we can see that 6 is at two places

              thousand and tens

Answer:

  75 + 22.50d = 300

Step-by-step explanation:

The equation sums the amount Kyle currently has (75) with the amount he saves in d days (22.50d). It sets that total to 300, since Kyle hopes to save a total of $300 in d days.

Answer:

-5 2/3 points per minute

Step-by-step explanation:

change / time = (-85 points)/(15 minutes) = -17/3 points/minute = -5 2/3 points/minute

I guess you mean

[tex]\sec^6x(\sec x\tan x)-\sec^4x(\sec x\tan x)=\sec^5x\tan^3x[/tex]

On the left side, we have a common factor of [tex]\sec^4x(\sec x\tan x)=\sec^5x\tan x[/tex], so that

[tex]\sec^6x(\sec x\tan x)-\sec^4x(\sec x\tan x)=\sec^5x\tan x(\sec^2x-1)[/tex]

Recall that

[tex]\sec^2x=1+\tan^2x[/tex]

from which it follows that

[tex]\sec^5x\tan x(\sec^2x-1)=\sec^5x\tan x\tan^2x=\sec^5x\tan^3x[/tex]

Answer:

4 units

Step-by-step explanation:

The distance from x=-5 to x=-1 on the line y=4 is -1-(-5) = -1+5 = 4 units.

_____

It might help to plot the points on a graph and count the grid squares between them.

Answer:

4 units

Step-by-step explanation:

on edge

Answer: [tex](x+10)^2+(y+6)^2=121[/tex]

Step-by-step explanation:

The equation of a circle in the general form is:

 [tex]ax^{2}+by^2+cx+dy+e=0[/tex]

The equaton of  a circle in standard form is:

[tex](x-h)^2+(y-k)^2=r^2[/tex]

Where the center is at (h, k) and r is the radius

To write the equation of a circle from general form to standard form, you must complete the squaare, as you can see below:

1- Given the equation in general form:

[tex]x^{2}+y^2+20x+12y+15=0[/tex]

2- Complete the square:

-Group the like terms and move the constant to the other side.

- Complete the square on the left side of the equation.

- Add the same value to the other side.

Then you obtain:

[tex](x^{2}+20x)+(y^2+12y)=-15\\(x^2+20x+(\frac{20}{2})^2)+(y^2+12y+(\frac{12}{2})^2)=-15+(\frac{20}{2})^2+(\frac{12}{2})^2\\\\(x+10)^2+(y+6)^2=-15+100+36\\(x+10)^2+(y+6)^2=121[/tex]

So just say the piece of land is in the shape of a rectangle and a triangle put together. To find the length (perimeter) add each sides up and subtract the line where the two shapes meet. To find the acreage (area) find the area of the rectangle (length*width) and add the area of the triangle (1/2*base*height)

Answer with explanation:

1.→Answer Written by Jack is Incorrect.

[tex]m^n=\text{exponent}\\\\\frac{x^a}{x^b}=x^{a-b}\\\\x^a \times x^b=x^{a+b}[/tex]

Error:Instead of subtracting powers,jack has added powers of same exponent.

Correct Solution:

    [tex]=\frac{54\times x^9 \times y^8}{6\times x^3 \times y^4}\\\\ \text{Here ,correct answer should be}=9\times x^{9-3} \times y^{8-4}\\\\=9 x^6 y^4[/tex]

2.Initial Amount, a=78,000

Rate =3 %=0.03

Error: Rate percent should be divided by 100, to get the value of b.

So, b= 0.03

Correct Solution:

Exponential growth is given by

  [tex]y=a\times b^x\\\\y=78,000\times (0.03)^x[/tex]

3.The Expression is

[tex]m^2-13 m -30\\\\a=1, b= -13,c= -30\\\\ac=-30\\\\b=-13= -15 +2,as -15 \times 2 = -30\\\\\text{Equivalent expression}=(m-15)(m+2)[/tex]

Option A: (m-15)(m+2)  

[tex]4.\rightarrow x^n=(x^3) \times (x^{-17})\\\\=\text{using law of indices},x^a\times x^b=x^{a+b}\\\\x^n=x^{3-17}\\\\x^n=x^{-14}\\\\n=-14[/tex]  

The equivalent of an expression is the other form of the expression.

The equivalent expression is: [tex]\mathbf{x^{-14}}[/tex]

The expression is given as:

[tex]\mathbf{(x^3)(x^{-17})}[/tex]

Remove brackets

[tex]\mathbf{(x^3)(x^{-17}) = x^3 \times x^{-17}}[/tex]

Apply law of indices

[tex]\mathbf{(x^3)(x^{-17}) = x^{3-17}}[/tex]

[tex]\mathbf{(x^3)(x^{-17}) = x^{-14}}[/tex]

Hence, the equivalent expression is: [tex]\mathbf{x^{-14}}[/tex]

Read more about equivalent expressions at:

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all are corespondent to each lateral line

Hey there!

The correct answer is D. Nine Hundred Thousand

This is the place it’s in => 900,000

Hope this helps you!

God bless ❤️

Brainliest would be appreciated!

xXxGolferGirlxXx

put it on negative three

Answer:

Draw an open circle at -4 and shade in the line to the left of -4.

Step-by-step explanation:

x < -4 means that the number is to the left of -4 on the number line.

To graph the inequality, draw an open circle at -4 to show that the number cannot be -4.

However, the number can be anywhere to the left of -4, so you shade in that part of the line.

Answer:

28.8 ft

Step-by-step explanation:

SOH CAH TOA reminds you that ...

Tan = Opposite/Adjacent

The height to the top of the antenna is opposite the angle of elevation, and the distance to the building is adjacent. So, we have ...

tan(58°) = (160 ft +antenna height)/(118 ft)

(118 ft)·tan(58°) = 160 ft + antenna height . . . . . . . multiply by 118 ft

188.8 ft - 160 ft = antenna height = 28.8 ft . . . . . . subtract 160 ft, evaluate

The height of the antenna is 28.8 ft above the top of the building. (The total height of building + antenna is 188.8 ft.)

The problem can be solved using trigonometry. The tangent of the angle of elevation equals the total height (building plus antenna) divided by the distance from the point to the base of the building. Subtract the building's height from the total height to get the antenna's height.

To find the height of the antenna, we need to solve a right triangle problem using trigonometry. We know that the building is 160 Ft tall, and the angle of elevation to the top of the antenna is 58 degrees from a point 118 Ft from the base of the building. This forms a right triangle, with the building's height as one side, the horizontal distance of 118 Ft as another, and the antenna height as the hypotenuse. We can use the tangent of the angle to calculate the height of the antenna:

tangent(58) = opposite/adjacent

Here, 'opposite' represents the antenna's total height above the ground and 'adjacent' the distance from the point to the base of the building. So:

tangent(58) = total height / 118

To find the total height, we rearrange the formula:

total height = tangent(58) * 118

But remember the total height includes the building's height, so we subtract that to get the antenna's height:

antenna's height = total height - height of the building

Which, after substituting the known values, gives us the antenna's height.

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Answer: 2.3

Step-by-step explanation:

 The triangle shown in the image attached is a right triangle.

Therefore, you can calculate the missing lenght of the triangle (x), by applying the proccedure shown below:

- Apply [tex]tan\alpha=\frac{opposite}{adjacent}[/tex]

- Substitute values.

- Solve for the missing side x.

Therefore, you obtain the following result:

[tex]tan\alpha=\frac{opposite}{adjacent}\\tan(25)=\frac{x}{5}\\x=5*tan(25)\\x=2.3[/tex]

Answer:

The value of x = 2.3 units to the nearest tenth

Step-by-step explanation:

* The triangle is right angle triangle

- We can use one of the trigonometry functions to find the value of x

∵ The measure of the one of the acute angle is 25°

∵ The length of the adjacent side of the angle is 5 units

∵ The length of the opposite side of the angle is x

- because we have opposite and adjacent of the given angle

∴ We will use the tan function

∵ tanФ = opposite to Ф/adjacent to Ф

∴ tan25 = x/5 ⇒ by using cross-multiplication

∴ x = 5 × tan25 = 2.33 ≅ 2.3

∴ The value of x = 2.3 units to the nearest tenth

Answer:

A''(7, 5)

Step-by-step explanation:

Reflection over the line x=L is the transformation ...

(x, y) ⇒ (2L-x, y)

For L=-5, this is ...

(x, y) ⇒ (-10 -x, y)

Then, translation over the line x=2 gives ...

(x, y) ⇒ (2·2 -(-10 -x), y) = (14+x, y)

So, the point (-7, 5) is translated to (14-7, 5) = (7, 5).

Given a markup of 80% and a selling price of $100.80, the cost price is approximately $56. Subtracting this from the selling price yields a cost to store of $44.80.

To find the cost to store, we need to first calculate the cost price using the selling price and the markup percentage.

Given:

- Markup percentage: 80%

- Selling price: $100.80

Step 1: Calculate the cost price using the formula:

[tex]\[ \text{Cost Price} = \frac{\text{Selling Price}}{1 + \frac{\text{Markup Percentage}}{100}} \][/tex]

Substitute the given values:

[tex]\[ \text{Cost Price} = \frac{100.80}{1 + \frac{80}{100}} \][/tex]

[tex]\[ \text{Cost Price} = \frac{100.80}{1 + 0.80} \][/tex]

[tex]\[ \text{Cost Price} = \frac{100.80}{1.80} \][/tex]

[tex]\[ \text{Cost Price} ≈ 56 \][/tex]

Step 2: Calculate the cost to store by subtracting the cost price from the selling price:

[tex]\[ \text{Cost to store} = \text{Selling Price} - \text{Cost Price} \][/tex]

[tex]\[ \text{Cost to store} = 100.80 - 56 \][/tex]

[tex]\[ \text{Cost to store} = 44.80 \][/tex]

So, the cost to store is $44.80.

Answer:

s + 10

Step-by-step explanation:

Ruben has s number of shoes. Then, 10 more shoes that Ruben has is

s + 10

Final answer:

To write an expression for 'ten more shoes than Ruben,' define a variable for Ruben's shoes, for example, R, and then add 10. The expression is R + 10.

Explanation:

If you want to write an expression for "ten more shoes than Ruben," you need to start by defining a variable for the number of shoes that Ruben has. Let's say that R represents the number of shoes Ruben has. Then, to express "ten more shoes than Ruben," you simply add 10 to that variable. Therefore, the expression would be R + 10. This straightforward notation clarifies the relationship between Ruben's shoe count and the additional ten pairs. By employing variables and simple arithmetic operations, such as addition, this expression succinctly conveys the concept of having ten more shoes than Ruben, facilitating mathematical communication and problem-solving.

Answer:

y-5=3x+2

Step-by-step explanation:

1) to make up the equation through the given two points:

[tex]\frac{x+8}{-6+8}= \frac{y+1}{5+1}; \ => \ y=3x+24[/tex]

2) to change that equation according to the condition:

y-5=3x+24-5; ⇔ y-5=3x+19.

P.S. the way suggested above is not the shortest one.

Answer:

Step-by-step explanation:

With the variables defined as above, the total amount spent is ...

  x + y = 56 . . . . . the amount spent on accessories and clothes

When the amount spent on accessories is subtracted from the amount spent on clothes, the result is $18, so we can write another equation that says this:

  y - x = 18

Both equations can be rearranged to put y alone on the left. In the first case, we add -x to both sides of the equation. In the second case, we add x to both sides of the equation.

the next number can be 34 as the sequence goes in difference of 1,2,3,4,5,6,5,2,1,1so I think it will continue with sequence 1

The value of the next number is 34

A sequence is defined as an arrangement of numbers in a particular order. On the other hand, a series is defined as the sum of the elements of a sequence.

There are two types of sequence, the arithmetic sequence and geometry sequence.

Example of arithmetic sequence is 2,4,6 ,8, 10... and we get the next number by adding 2. Also

Example of geometry sequence is 2,4,8,16,32... we get the next number by multiplying 2.

From the sequence above the next number will be 34 because the last three number has a common difference of 1.

learn more about sequence from

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Answer:

  D. A table of values represents points that lie on the graph of a linear function.

Step-by-step explanation:

A table of values can represent any relation, not necessarily a linear function. Statement D is not always true.

Statement D, 'A table of values represents points that lie on the graph of a linear function,' is not always true. A table of values could represent various types of functions or data sets. All other statements are correct for a linear function.

Let's analyze each of the given statements to identify which one is not always true:

Therefore, the correct answer is D. A table of values represents points that lie on the graph of a linear function.

Answer:

7

Step-by-step explanation:

Add them and hen divide by how many numbers there are

Answer:

B.) (x+3, y-7)

Step-by-step explanation:

x-coordinates increase farther to the right of the y-axis. Increasing the x-coordinate of a point by 3 will move the point 3 units to the right.

y-coordinates increase farther above the x-axis. Decreasing the y-coordinate of a point by 7 will move the point 7 units down.

To translate a point (x, y) 3 units right and 7 units down, the new coordinates need to be ....

(x +3, y-7) . . . . . . . . matches selection B

Answer:  [tex]sin\ 2x=-\dfrac{240}{289}\qquad cos\ 2x=\dfrac{161}{289}\qquad tan\ 2x=-\dfrac{240}{161}[/tex]

Step-by-step explanation:

[tex]cos\ x=\dfrac{15}{17}\quad and\quad csc\ x<0\implies sin\ x=-\dfrac{8}{17}\ and\ tan\ 2x=-\dfrac{8}{15}\\\\sin\ 2x=2(sin\ x\cdot cos\ x)\\\\.\qquad =2\bigg(\dfrac{-8}{17}\cdot \dfrac{15}{17}\bigg)\\\\\\.\qquad =2\bigg(\dfrac{-120}{289}\bigg)\\\\\\.\qquad=\large\boxed{-\dfrac{240}{289}}[/tex]

[tex]cos\ 2x=cos^2\ x-sin^2\ x\\\\.\qquad=\bigg(\dfrac{15}{17}\bigg)^2-\bigg(\dfrac{-8}{17}\bigg)^2\\\\\\.\qquad=\dfrac{225}{289}-\dfrac{64}{289}\\\\\\.\qquad=\large\boxed{\dfrac{161}{289}}[/tex]

[tex]tan\ 2x=\dfrac{sin\ 2x}{cos\ 2x}\\\\\\.\qquad=\large\boxed{-\dfrac{240}{161}}[/tex]

The trigonometry values are:[tex]\mathbf{sin(2x) = -\frac{240}{289}}[/tex], [tex]\mathbf{cos(2x) =\frac{161}{289}}[/tex] and [tex]\mathbf{tan(2x)= -\frac{240}{161}}\\[/tex]

The given parameter is:

[tex]\mathbf{cos(x) = \frac{15}{17}}[/tex]

If csc(x) is less than 0, then sin(x) is less than 0.

Using the following trigonometry ratio,

[tex]\mathbf{sin^2(x) +cos^2(x) = 1}[/tex]

Substitute [tex]\mathbf{cos(x) = \frac{15}{17}}[/tex]

[tex]\mathbf{sin^2(x) +(\frac{15}{17})^2 = 1}[/tex]

Expand

[tex]\mathbf{sin^2(x) +\frac{225}{289} = 1}[/tex]

Collect like terms

[tex]\mathbf{sin^2(x) = 1 -\frac{225}{289}}[/tex]

Take LCM

[tex]\mathbf{sin^2(x) = \frac{289-225}{289}}[/tex]

[tex]\mathbf{sin^2(x) = \frac{64}{289}}[/tex]

Take square roots

[tex]\mathbf{sin(x) = \pm\frac{8}{17}}[/tex]

Recall that, the sine of the angles is negative.

So, we have:

[tex]\mathbf{sin(x) = -\frac{8}{17}}[/tex]

sin(2x) is then calculated as:

[tex]\mathbf{sin(2x) = 2sin(x)cos(x)}[/tex]

This gives

[tex]\mathbf{sin(2x) = 2 \times \frac{-8}{17} \times \frac{15}{17}}[/tex]

[tex]\mathbf{sin(2x) = -\frac{240}{289}}[/tex]

cos(2x) is then calculated as:

[tex]\mathbf{cos(2x) =cos^2(x) - sin^2(x)}[/tex]

This gives

[tex]\mathbf{cos(2x) =(\frac{15}{17})^2 - \frac{64}{289}}[/tex]

[tex]\mathbf{cos(2x) =\frac{225}{289} - \frac{64}{289}}[/tex]

Take LCM

[tex]\mathbf{cos(2x) =\frac{225 - 64}{289}}[/tex]

[tex]\mathbf{cos(2x) =\frac{161}{289}}[/tex]

Lastly, tan(2x) is calculated using:

[tex]\mathbf{tan(2x)= \frac{sin(2x)}{cos(2x)}}[/tex]

So, we have:

[tex]\mathbf{tan(2x)= \frac{-240/289}{161/289}}[/tex]

[tex]\mathbf{tan(2x)= -\frac{240}{161}}\\[/tex]

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Answer:

[tex]f^{-1}(x)=(+/-)\sqrt{4-x}[/tex]

Step-by-step explanation:

we have

[tex]f(x)=4-x^{2}[/tex]

Let

y=f(x)

[tex]y=4-x^{2}[/tex]

Exchange the variables x for y and y for x

[tex]x=4-y^{2}[/tex]

Isolate the variable y

[tex]y^{2}=4-x[/tex]

square root both sides

[tex]y=(+/-)\sqrt{4-x}[/tex]

Let

[tex]f^{-1}(x)=y[/tex]

[tex]f^{-1}(x)=(+/-)\sqrt{4-x}[/tex] -----> inverse function

Answer:

f⁻¹(x) = ±√x-4

Step-by-step explanation:

We have given  a function.

f(x) = 4-x²

We have to find the inverse of given function.

Putting y = f(x) in given equation, we have

y  = 4-x²

Adding -4 to both sides of equation, we have

y-4 = 4-x²-4

y-4 = -x²

x² = 4-y

Taking square root to both sides of above equation, we have

x = ±√4-y

Putting x = f⁻¹(y) , we have

f⁻¹(y) = ±√4-y

Replacing y by x, we have

f⁻¹(x) = ±√x-4 which is the answer.

Answer:

x=2y^2 -24y + 69

Step-by-step explanation: Move the expression to the right side and change its sign.

Answer:

$43.00

Step-by-step explanation:

final price = marked price + tax

= marked price + (tax rate) · (marked price)

= (marked pric) · (1 + tax rate)

= $40.00 · 1.075

= $43.00

Answer: Darren’s range is 20 points.

Step-by-step explanation: A range is the difference between the highest score and the lowest score. With the lowest score being 280 and the highest score being 300, the difference is 20 points for the range.

Negative exponents work like this: you have to consider the multiplicative inverse of the positive exponent.

So you have

[tex] y={-3} = \dfrac{1}{y^3},\quad x^{-5} = \dfrac{1}{x^5}[/tex]

The third expression already contains positive exponents only, you don't have to do anything.