How many regions would a net for a three-dimensional solid like the one shown have?

Answer

A

Step-by-step explanation:

Answer:

a. 4.85

Step-by-step explanation:

im right

? = a+b

a = 3

(3+b)/3=3/b

b= -4.85 or 1.85

it cant be negive.

so ? = 3+1.85 = 4.85

Area is determined by using the formula A=lw  Area= Length x  Width

A= 1 1/4 x 3   convert to an improper fraction

A= 5/4 x 3/1  multiply

A=15/4   divide

A=3 3/4 square feet

Answer: [tex]A=3\dfrac{3}{4}\ ft^2[/tex]

Step-by-step explanation:

Given: The dimensions of the wrapping paper :

[tex]1\text{ and}\dfrac{1}{4}\text{ feet }\text{ by 3 feet}\\\\\text{i.e }1+\dfrac{1}{4}\text{ feet }\text{ by 3 feet}\\\\\text{i.e }\dfrac{5}{4}\text{ feet }\text{ by 3 feet}[/tex]

Now, we know that the area of a rectangle is given by :-

[tex]A=length*width[/tex]

Now, the area of the wrapping paper is given by :-

[tex]A=\dfrac{5}{4}\times3=\dfrac{15}{4}=3\dfrac{3}{4}\ ft^2[/tex]

Answer:

Step-by-step explanation:

1600

Discriminant = b^2 - 4ac

a = 4

b = 16

c = 16

16^2 - 4(4 x 16)

256 - (4x64)

256 - 256 = 0

Therefore it only has one root

Answer:

The baker made 36 batches of muffins.

Step-by-step explanation:

Let the total amount of flour be x

We know he used 2/5 of the flour for bread, we also know he used 16 pounds for bread.

We can write this as :

[tex]\frac{2}{5}\times x=16[/tex]

Solving this we get;

[tex]2x=80[/tex]

So, x = 40

Means total amount of flour was 40 pounds and he used 16 pounds for bread, so the remaining is for batches of muffins, which is [tex]40-16=24[/tex] pounds

As each batch of muffin uses 2/3 pounds, so 24 pounds of flour will be used to bake :

[tex]\frac{24}{\frac{2}{3} }[/tex]

= [tex]\frac{24\times3}{2} =36[/tex]

Hence, the baker made 36 batches of muffins.

Answer:

Step-by-step explanation:

6/8

Answer:

The resulting equation after the first step is 2v+4=8

d is the correct option

Step-by-step explanation:

We have been given the equation v + 4 + v = 8. In order to solve it for v, we'' perform the below mentioned steps.

Hence, in the first step, we can group the like terms and combine. In the left hand side v and v are like terms and hence, we can add them

On adding v and v we get 2v

Thus, we have

[tex]v+v+4=8\\2v+4=8[/tex]

Thus, the resulting equation after the first step is 2v+4=8

the answer is A my good sir/madam

The method in which rigid transformations used to justify the SAS congruence theorem is given.

A rigid transformation (also called an isometry) is a transformation of the plane that preserves length. In a rigid transformation the pre-image and image are congruent (have the same shape and sizes).

We are given that;

Theorem is SAS

Now,

The SAS congruence theorem states that if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then the triangles are congruent. To prove this theorem using rigid transformations, we can start with two distinct triangles that have a pair of corresponding congruent sides and a corresponding congruent included angle23. Then we can use a translation to move one triangle so that its congruent side matches the other triangle’s congruent side. Next, we can use a rotation to align the congruent angles of both triangles. Finally, we can use another translation to move the second congruent side of one triangle to match the second congruent side of the other triangle. By doing these rigid transformations, we have shown that one triangle can be mapped onto the other triangle exactly, which means they are congruent

Therefore, by the transformations the answer will be given above.

Learn more about rigid transformations;

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Answer:

Here is the answer and proof :)

Step-by-step explanation:

Answer:

  x ≈ 4.1 cm

Step-by-step explanation:

The side (z) opposite the 42° triangle can be found from the relation ...

  z/(3.6 cm) = tan(42°)

  z = (3.6 cm)·tan(42°) ≈ 3.2415 cm

The relationship between z and x is ...

  z/x = cos(38°)

  x = z/cos(38°) ≈ 4.1135 cm

  x ≈ 4.1 cm

The fraction 30/6 can be rewritten as the whole number 5 after performing the division operation 30 ÷ 6.

The problem asks to rewrite 30/6 as a whole number. In mathematics, this implies using the operation of division. Division is one of the four basic operations in math, along with addition, subtraction, and multiplication.

To solve this problem, you need to divide 30 by 6. Perform the division operation as follows: 30 ÷ 6. The result of this operation is 5.

Therefore, the fraction 30/6 can be rewritten as the whole number 5.

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The statement is true for linear functions, but not in general for all functions.

The statement is true if f(x) is a linear function.

However, it is not true in general for all functions, so the statement is false.

An example of a linear function where the statement is true would be f(x) = 2x.

If we substitute s + t into the function, we get f(s + t) = 2(s + t) = 2s + 2t.

On the other hand, if we substitute f(s) + f(t) into the function, we get f(s) + f(t) = 2s + 2t.

Therefore, the equality holds and the statement is true for linear functions.