In modern radiotherapy, superconducting wire coils are used to create magnetic fields that focus particle beams in order to deliver the maximum dose of ionizing radiation to a tumor site while minimizing the destruction of healthy tissue. For what type of radiation would this technique NOT be useful?

Answer

given,

acceleration, a = 5 g =  5 x 9.8 = 49 m/s²

speed of sound, v = 331 m/s

speed , v = 3 Mach = 3 x 331 m/s = 993 m/s

time, t = 5.2 s

a) Calculating the time period of black out.

  time required by the aircraft to black out

 using equation of motion

  v = u + a t

 initial velocity = 0 m/s

  993 = 0 + 49 t

   t = 20.26 s

the required time to reach 3 Mach speed is more than the given time hence, pilot will black out.

b) now, calculating the maximum speed it can reach in 5.2 s

 using equation of motion

  v = u + a t

 initial velocity = 0 m/s

  v = 0 + 49 x 5.2

 v = 254.8 m/s

The centripetal acceleration of someone at a latitude of 71.9 degrees on Earth's surface is calculated based on the velocity due to Earth's rotation, adjusted by the cosine of the latitude angle, demonstrating how this acceleration compares to Earth's gravitational pull.

The question asks about the centripetal acceleration of a person standing on Earth's surface at a specific latitude and how this compares to Earth's gravitational acceleration, g. To find the centripetal acceleration (ac) at a latitude of 71.9 degrees, we use the fact that at the equator, where the velocity due to Earth's rotation is maximal, ac is purely in the direction of g and reduces with latitude. The reduction factor is the cosine of the latitude angle because the actual velocity component contributing to centripetal acceleration is the component of the Earth's rotational velocity at the surface that is perpendicular to the axis of rotation, which is maximized at the equator and zero at the poles.

To calculate it: The earth rotates once every 24 hours, giving us a rotational velocity at the equator. We can derive velocity (v) at the equator using the formula v = 2πr / T, where r is Earth's radius (approximately 6380 km) and T is the period of rotation (86400 seconds). The equatorial velocity can then be used to calculate centripetal acceleration at the equator with ac = v² / r, which is found to be a fraction of g, as shown in discussions. At a latitude of 71.9 degrees, this acceleration is reduced by the factor cos(71.9°), illustrating how ac changes with latitude.

Thus, to express the centripetal acceleration at this latitude as a multiple of g, one would calculate the acceleration as derived for the equator and adjust it by the factor cos(71.9°). This allows us to understand the reduced effect of Earth's rotation on the apparent weight of an object as the latitude increases, which is crucial in understanding phenomena such as the variation in gravity and the operation of pendulum clocks at different latitudes.

Answer:

Momentum, p = 720 g-cm/s

Explanation:

The momentum of an object is determined to be,

[tex]p=7.2\times 10^{-3}\ kg-m/s[/tex]

We need to express this quantity in any equivalent units. We know that the conversions are as follows :

1 kg = 1000 g

and 1 m = 100 cm

[tex]p=7.2\times 10^{-3}\ kg-m/s=7.2\times 10^{-3}\times (1000\ g)\times (100\ cm)/s[/tex]

p = 720 g-cm/s

So, the momentum of an object in any equivalent unit is 720 g-cm/s. Hence, this is the required solution.

The momentum of the object is 7.2 × 10^-3 kg·m/s, which is equivalent to 7.2 g·m/s when the mass is converted from kilograms to grams.

The momentum of an object is defined as the product of its mass and velocity. It is a vector quantity, meaning it has both magnitude and direction. The magnitude of the given object's momentum is 7.2 × 10-3 kg·m/s. To express this quantity in equivalent units, we can convert the mass from kilograms to grams by noting that 1 kg equals 1000 grams. Thus, the momentum in grams·m/s can be calculated as (7.2 × 10-3 kg) × (1000 g/kg) = 7.2 g·m/s.

Explanation:

Let's say your mass is M, the ball's mass is m, and the ball's speed is v.  Let's say your final speed is V.

Momentum is conserved.  If you catch the ball, your speed is:

mv = (m + M)V

V = mv / (m + M)

If you deflect the ball, your speed is:

mv = MV + m(-v)

V = 2mv / M

To compare these, we need the common denominator.

If you catch the ball:

V = mMv / (M (m + M))

If you throw the ball:

V = 2m(m + M)v / (M (m + M))

Comparing the numerators, we can see M < 2(m + M), so catching the ball results in a lower speed.

Answer:

3.51724 blocks

2.48275 blocks

Explanation:

L = Length of one block

t = Time taken by both person

[tex]Distance=Speed\times Time[/tex]

[tex]1.2t+1.7t=6L\\\Rightarrow 2.9t=6L\\\Rightarrow t=\dfrac{6}{2.9}L[/tex]

Distance that I walk

[tex]s=1.7t\\\Rightarrow s=1.7\times \dfrac{6}{2.9}L\\\Rightarrow s=3.51724L[/tex]

The Distance that I will walk is 3.51724 blocks

Distance my friend will walk

[tex]s=1.2t\\\Rightarrow s=1.2\times \dfrac{6}{2.9}L\\\Rightarrow s=2.48275L[/tex]

Distance my friend will walk is 2.48275 blocks

To determine the restaurant where you and your friend will arrive at the same instant, we can use the equation distance = speed × time.

To determine the restaurant where you and your friend will arrive at the same instant, we can use the equation distance = speed × time. Let's assume the distance between the buildings is 6 blocks, which is the same for both of you. We'll call the time it takes for both of you to reach the restaurant 't'. For you, the distance covered will be 6 blocks at a speed of 1.7 m/s, so your equation will be 6 = 1.7t. For your friend, the equation will be 6 = 1.2t.

Solving these equations, we find that t = 3.53 seconds for you and t = 5 seconds for your friend. Since you want to arrive at the same instant, you need to use the higher time, which is 5 seconds. Thus, the restaurant where you and your friend can meet at the same instant is located 5 seconds away from both of your buildings.

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Answer:

3.26 m

Explanation:

change in kinetic energy = change in potential energy

[tex]\frac{v^{2}}{2} = gh[/tex]

[tex]h=\frac{v^{2}}{2g}[/tex]

h = (8^2)/ 2*9.81 = 3.26 m

Answer:

[tex]P_2=160\ psia[/tex]

Explanation:

Given that

Pressure ratio ,r= 8

Gauge pressure at inlet = 5.5 psig

Lets take atmospheric pressure = 14.5 lbf/in²

The absolute presure at inlet

P₁ =5.5 + 14.5 psia

P₁= 20 psia

Lets take absolute pressure at the exit =P₂

[tex]r=\dfrac{P_2}{P_1}[/tex]

[tex]P_2=8\times 20\ psia[/tex]

[tex]P_2=160\ psia[/tex]

Therefore the absolute pressure at the exit will be 160 psia.

The incremental development is an effective tool for business software applications while it cannot be applied on real-time systems engineering.

Business software technologies are complex. Business software applications are often upgraded with changes in requirments of business goals and procedures.

Real-time systems engineering require a lot of hardware components that are quite difficult to change easily.

Therefore, the incremental development is an effective tool for business software applications while it cannot be applied on real-time systems engineering.

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Incremental development is effective for business software due to its flexibility, reduced risk, and continuous improvement. However, it is less appropriate for real-time systems engineering because these systems require predictable, precise, and immediate responses that iterative changes can undermine.

Incremental development, often aligned with agile methodologies, is effective for business software systems because it emphasizes flexibility and continuous improvement. This approach allows teams to develop software in small, manageable increments, making it easier to adapt to changing business needs and customer feedback. Regular iterations ensure that the project delivers business value continuously, minimizing risks associated with large-scale overhauls.

Several advantages make incremental development suitable for business software:

Limitations for Real-Time Systems Engineering:

Complete question is: You pull your car into your driveway and stop. The drive shaft of your car engine, initially rotating at 2400 rpm,slows with a constant rotational acceleration of magnitude 30 rad/s². How long does it take for the drive shaft to stop turning?

Answer:

8.37 s

Explanation:

Initial rotational velocity, ω₀ = 2400 rpm = 2400 × 2π/60 = 251.2 rad/s

Final velocity, ω = 0

rotational deceleration, α =- 30 rad/s²

Use the first equation of rotational motion:

[tex] t = \frac{\omega - \omega_o}{\alpha}[/tex]

Substitute the values:

[tex] t = \frac{0 - 251.2}{-30}=8.37 s[/tex]

Answer:

yes. We will have the same displacement.

Explanation:

It's in the definition of a displacement that " displacement is the change in position and if the initial and final position is same then the displacement will be zero". So in the park from starting position if we end up walking at the same position then our displacement will be zero because our initial and final positions are same.

Answer:

The maximum speed of the heart wall during this motion is 0.032 m/s.

Explanation:

Given that,

Amplitude of the simple harmonic motion, A = 1.7 mm = 0.0017 m

Frequency of the fetus's ventricular wall, f = 3 Hz

We need to find the maximum speed of the heart wall during this motion. The maximum speed of the object that is executing SHM is given by :

[tex]v_{max}=A\omega[/tex]

[tex]v_{max}=2\pi f A[/tex]

[tex]v_{max}=2\pi \times 3\times 0.0017[/tex]

[tex]v_{max}=0.032\ m/s[/tex]

So, the maximum speed of the heart wall during this motion is 0.032 m/s. Hence, this is the required solution.

[tex]sp^3[/tex] hybridization and 1 lone pair is exhibited by the nitrogen atom in the following substance pairs are present on the nitrogen.

b. [tex]sp^3[/tex] hybridization and 1 lone pair

Explanation:

The Nitrogen particle is [tex]sp^3[/tex] hybridized with one crossover orbital involved by the solitary pair. Likewise, nitrogen is [tex]sp^3[/tex] hybridized which implies that it has four [tex]sp^3[/tex] half and half orbitals. The sub-atomic structure of water is predictable with a tetrahedral game plan of two solitary sets and two holding sets of electrons. Two of the [tex]sp^3[/tex] hybridized orbitals cover with s orbitals from hydrogens to frame the two N-H sigma bonds.

Nitrogen utilizes [tex]sp^3[/tex] orbitals to accomplish this geometry. Three of the mixtures are utilized to frame bonds to hydrogen and the fourth contains the solitary pair. Whereas lone pairs are the pairs of electron on atoms that don't take an interest in the holding bonding of two atoms. To distinguish solitary matches in a particle, make sense of the number of valence electrons of the molecule and subtract the number of electrons that have partaken in the holding.

Hybridization of nitrogen depends on its bonding context; sp hybridization leads to a linear geometry, whereas sp³ hybridization results in a trigonal pyramidal geometry with one lone pair, as seen in ammonia.

The question is asking about the hybridization of nitrogen in various substances. Hybridization describes the mixing of atomic orbitals to form new hybrid orbitals that can accommodate bonding and lone pairs in molecules. For a nitrogen atom with sp hybridization, the molecule usually has a linear geometry, as in the case of hydrogen cyanide (HCN). Here, nitrogen has one sp hybrid orbital with a lone pair and one with a sigma bond, while the two p orbitals form pi bonds, resulting in a triple bond.

In cases where nitrogen is sp³ hybridized, the nitrogen atom can form three sigma bonds with its sp³ hybrid orbitals and retain one lone pair, giving a trigonal pyramidal geometry. An example of this is in ammonia (NH₃), where the nitrogen atom is bonded to three hydrogen atoms and has one lone pair.

Answer: Did  you get the answers? Im struggling homie.

Explanation:

Answer:

1. 1/9th the original

2. 0.023 N

3. 1.9 x 10^12 electrons

4. 1.62 x 10^-10 C to the right

5. 19.21 N/C

6. 2.17 N/C

7. Not 0.37 N/C

8. 1/4 of what it was

9. 2 electrons must be removed

10. Polarization: when the positive and negative charges in an object are separated

Explanation: Just took the test

In science, a broad idea that has been repeatedly verified so as to give scientists great confidence that it represents reality is called "a theory".

Explanation:

In science, the interpretation of a feature of the organic world that can be tested in repeat manner and analysed by applying agreed tests validation methods, calculation and observation in according to the scientific method, such process is called as a theory in science.

The difference lie between a theory and a hypothesis. Because hypothesis is an "educated guess". Overall it is either a proposed interpretation of an observed phenomenon, or a logical inference of a possible causal association between several phenomena.

Answer: v² = u² + 2as  

2as = v² - u²  

a = (v² - u²) / 2s  

a = (20.0² m²/s² - 6.00² m²/s²) / (2 * 50.0 m)  

a = (400 m²/s² - 36 m²/s²) / (100 m)  

a = (364 m²/s²) / (100 m)  

a = 3.64 m/s²

Explanation:

Answer:1m/s^-2

Explanation:V=u+at where;

V(final velocity)=50m/s

U(Initial velocity)=20m/s

a(acceleration)=?

t(time)=30seconds

Therefore; 50=20+a(30)

Collect like terms

50-20=30a

30=30a

Divide both side by 30

a=1ms^-2

Final answer:

Using the gas law principle and given pressure values, the afternoon temperature of the bicyclist's tires, after an increase in pressure to 422 kPa from 404 kPa, is calculated to be approximately 299 K.

Explanation:

To find the afternoon temperature after the tire pressure increases, we use the gas law principle that describes the relationship between pressure and temperature when the volume and amount of the gas remain constant. Assuming ideal behavior, the relevant equation is the proportionality between pressure and temperature given as P1/T1 = P2/T2.

In this case, the initial pressure (P1) is 404 kPa, the initial temperature (T1) is 286 K, and the final pressure (P2) is 422 kPa. To find the final temperature (T2), we rearrange the formula to T2 = (P2 x T1) / P1.

Plugging in the values:

T2 = (422 kPa x 286 K) / 404 kPa

T2 = 1207962 K kPa / 404 kPa

T2 ≈ 299 K

Therefore, the afternoon temperature when the pressure in the tires has increased to 422 kPa is approximately 299 K.

Answer:

Potential energy is transformed into kinetic energy

friction work decreases kinetic energy

Explanation:

The law of conservation of  the mechanical energy is the sum of kinetic energy plus the different forms of potential energy, this energy is constant throughout the trajectory if the dissipative force (friction) is zero.

Let us apply this to our case, in the upper part of the trajectory almost all the mechanical energy is potential, and a very small part is kinetic, the bicycle goes very slowly, as it descends without pedaling the speed increases so that the kinetic energy it increases and the height decreases therefore the potential energy decreases, but the sum of the two energies remains constant.

Potential energy is transformed into kinetic energy

When the brakes are applied, a dissipative force enters the system that causes part of the energy to be transformed into heat and part into work of this dissipative force against the wheel, two resulting in a net decrease in mechanical energy and therefore a decrease in the speed of the bicycle, the value of this decrease is given by

                  W = DK

Answer:

[tex]KE_2=3.24 \times KE_1[/tex]

Explanation:

given,

Speed of car = v

new speed of car v'= 1.8 v

Kinetic energy of the car

[tex]KE_1 =\dfrac{1}{2}mv^2[/tex]

new Kinetic energy of energy

[tex]KE_2 =\dfrac{1}{2}mv'^2[/tex]

[tex]KE_2=\dfrac{1}{2}m(1.8v)^2[/tex]

[tex]KE_2=3.24 \times \dfrac{1}{2}mv^2[/tex]

[tex]KE_2=3.24 \times KE_1[/tex]

hence, the kinetic energy is increased by the factor of 3.24.

Answer:

18

Explanation:

An isotope an atom of a particular element is another atom having same number of protons or electrons but different number of neutrons.

For example oxygen

element                proton              neutron

O-16                          8                        8

O-17                          8                        9

O-18                          8                        10

Now atomic mass of atom = no. of protons +no. of neutrons

therefore, mass number of Oxygen has 8 protons, 10 neutrons, and 8 electrons. = 8+10 =18.

Answer:

The atomic mass of this isotope is 18.

Explanation:

Given that,

Number of proton = 8

Number of neutron =10

Number of electron = 8

Atomic mass :

Atomic mass is the addition of number of neutron and number of proton or electron.

We need to calculate the atomic mass of this isotope

Using formula of atomic mass

[tex]A=N+P[/tex]

Where, N = number of neutron

P = number of  proton

Put the value into the formula

[tex]A=10+8[/tex]

[tex]A=18[/tex]

Hence, The atomic mass of this isotope is 18.

Answer:

Option (C)

Explanation:

'Pericardiocentesis' is a biological term that is usually defined as a process by which a fluid is removed from the sac that is oriented around the heart. This accumulation of fluid in the heart is commonly known as pericardial effusion. This process is mainly carried out with the help of a needle and a catheter, where the needle is injected into the tissues that are near to the heart.

This fluid that is eliminated from the body is further sent to the laboratories in order to carry out the medical test to determine if a person is affected by infection or cancer.

Thus, the correct answer is option (C).

"The correct answer is C. the removal of fluid from around the heart.

Pericardiocentesis is a procedure where a needle is used to remove fluid from the pericardium, which is the sac-like covering around the heart. This procedure is typically performed when there is an accumulation of fluid in the pericardium (pericardial effusion) that may be causing symptoms such as chest pain or difficulty breathing, or when there is a suspicion of infection or cancer in the pericardial space.

 Let's analyze each option to understand why option C is the correct choice:

 A. Narrowing of the arteries supplying the heart is referred to as atherosclerosis or coronary artery disease, not pericardiocentesis.

 B. Surgical repair of the sac around the heart is known as pericardiectomy or pericardial window, which involves creating an opening in the pericardium to drain fluid or to relieve pressure. This is different from pericardiocentesis, which is a less invasive procedure.

 C. The removal of fluid from around the heart is the definition of pericardiocentesis. It is a minimally invasive procedure that can be both diagnostic, by analyzing the fluid removed, and therapeutic, by relieving the pressure on the heart.

D. A surgical opening made in the heart refers to a procedure such as a thoracotomy or sternotomy, which involves opening the chest cavity to access the heart. This is not related to the removal of fluid from the pericardial sac.

Answer:

a)  two peak in the spectrum , b)  m₁ / m_ c = 100783 , m₂ / m_c = 2.01410, c)  the lighter isotope peak is much higher than the other

Explanation:

A mass spectrometer is a device where an ionized and accelerated sample in a constant electric field enters a magnetic field that deflects it for detection, in vernal the intensity of the magnetic field is controlled.

Newton's second Law gives us

                   [tex]F_{m}[/tex]= m a

The acceleration is centripetal

                   a = v² / r

                   q v B = m v² / r

                   q B = m v / r

                   r = (m / q) v / B

a) with We have two different isotopes must separate only two peak in the spectrum

b) the relative atomic mass is the ratio between the mass of an atom in kg and the weighted mass of carbon that is 12

          m₁ / m_ c = 100783

          m₂ / m_c = 2.01410

It has units for being the relationship between two masses

c) The peak height intensity is proportional to the abundance of each isotope.

       The most used is to calculate the relative abundances is to use the area of ​​each peak

        Therefore the lighter isotope peak is much higher than the other

A) The number of peaks that the mass spectrum will have is; 3 peaks

B) The relative atomic masses of each of the peaks are;

Peak 1H - 1H = 2.01566 amu

Peak 1H - 2H = 3.02193 amu

Peak 2H - 2H = 4.02820 amu

C) The largest and smallest peak will be;

Largest Peak = Peak 2H - 2H

Smallest Peak = Peak 1H - 1H

We are told that the two naturally occurring isotopes of hydrogen are;

atomic mass = 1.00783 ; abundance 99.9885%

atomic mass = 2.01410 ; abundance 0.0115%

A) The mass spectrum will have 3 peaks namely;

B) The relative atomic masses of each of the peaks will be;

Relative atomic mass of Peak 1H - 1H = 1.00783 + 1.00783 = 2.01566 amu

Relative atomic mass of Peak 1H - 2H = 1.00783 + 2.01410 = 3.02193 amu

Relative atomic mass of Peak 2H - 2H = 2.01410 + 2.01410 = 4.02820 amu

C) From B above, we conclude that;

Largest Peak is Peak 2H - 2H

Smallest Peak is Peak 1H - 1H

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Answer:

408.25 Hz.

Explanation:

The fundamental frequency of a stretched string is given as

f' = 1/2L√(T/m') .................... Equation 1

Note: The a steel piano wire is a string

Where f' = fundamental frequency of the wire, L = length of the wire, T = tension on the wire, m' = mass per unit length of the wire.

Given: L = 0.4 m, T = 800 N,

Also,

m' = m/L where m = mass of the steel wire = 3.00 g = 3/1000 = 0.003 kg.

L = 0.4 m

m' = 0.003/0.4 = 0.0075 kg/m.

Substituting into equation 1

f' = 1/(2×0.4)[√(800/0.0075)]

f' = 1/0.8[√(106666.67)]

f' = 326.599/0.8

f' = 408.25 Hz.

Hence the frequency of the fundamental mode of vibration = 408.25 Hz.

To find the frequency of the fundamental mode of vibration, use the equation f₁ = vₓ / 2L, where vₓ is the speed of waves in the string and L is the length of the string. The speed of waves can be calculated using vₓ = √(T/μ), where T is the tension in the string and μ is the linear mass density of the string. Plugging in the given values, the frequency of the fundamental mode is 1886.75 Hz.

In order to find the frequency of the fundamental mode of vibration of the steel piano wire, we need to use the equation:

f1 = vw/2L

Where f1 is the frequency of the fundamental mode, vw is the speed of waves in the string, and L is the length of the string. The speed of waves in the string can be calculated using the equation:

vw = √(T/μ)

Where T is the tension in the string and μ is the linear mass density of the string.

Plugging in the given values, we have:

T = 800 N, L = 0.400 m, and μ = 3.00 g = 0.00300 kg

Converting the linear mass density to kg/m, we have:

μ = 0.00300 kg / 0.400 m = 0.00750 kg/m

Plugging these values into the equation for the speed of waves, we have:

vw = √(800 N / 0.00750 kg/m) = √106666.67 m/s

Finally, plugging the speed of waves and the length of the string into the equation for the frequency of the fundamental mode, we have:

f1 = (√106666.67 m/s) / (2 * 0.400 m)

Calculating this, we get:

f1 = 1886.75 Hz

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To hold the oil drop steady, the electrical force must match its weight. The voltage required to generate this force can be determined, and hence the charge on each plate, using given constants and the weight of the drop. The upper plate should be positive as the drop has excess electrons.

Firstly, we need to find the weight of the oil drop because it will be opposing the electrical force to keep the drop suspended. The mass can be found by converting the micrograms into kilograms (1 microgram = 10^-9 kg). So, the weight (W) of the oil drop will be the mass times gravity. W = 0.025 * 10^-9 *9.8 = 2.45 * 10^-10 N.

The electrical force that will hold the drop steady will exactly equal this weight. Since F = qE where F is the force, q is the charge, and E is the field strength, and E = V/d (where V is potential difference and d is distance), we can put these together to find the voltage that will create this field. V = Fd/q = Wd/q . All that's left is to plug all the given values in: the number of excess electrons in the oil drop times the elementary charge (1.6*10^-19 C), which gives us the total charge on the drop.

As for which plate must be positive, it would be the one opposing the negative charge of the oil drop to suspend it, therefore, the upper plate must be positive.

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Answer:

correct answer is Precipitous vaginal delivery

Explanation:

given data

cervix dilated = 4 cm

effaced = 100%

delivery  = 5 minutes later

solution

correct answer is Precipitous vaginal delivery because precipitous take delivery time less than = 3 hours

A multipara progress at rate 1.5 cm of dilation per hour

and it is progress for 10 cm for the deliver and birth averages approx 20 minute

so here correct answer is Precipitous vaginal delivery

Answer:

Review the task, there should indicate the mass of the player

Explanation:

The speed of the player immediately after stopping the ball is equal to 0.0396 m/s.

The law of conservation of linear momentum can be described as the sum of the momentum before and after the collision must be equal.

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

Where m₁ and m₂ is the mass of the objects, u₁ & u₂ are their initial speed while v₁ & v₂ is the final speed of the collided objects.

The linear momentum can be described as the product of the mass of the object times the velocity of that object. Conservation of momentum can be described as a property held by an object.

Given the initial speed of the ball is u = 21 m/s

The mass of the baseball player, M = 74 Kg

The mass of the given  ball, m = 0.140 Kg

From the law of conservation of momentum, determine the speed of the player (V):

m u + mv = (m + M)  V

0.140 Kg × 21 + 0 = (0.140 + 74) × V

V = 0.0396 m/s

Therefore, the speed of the player is equal to 0.0396 m/s.

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Your question is incomplete, most probably the complete question was,

A 74 Kg baseball player jumps straight up to catch a head-hit ball. If the 140 g ball is moving horizontally at 21 m/s, and the catch is made when the ballplayer is at the highest point of his leap, what is his speed immediately after stopping the ball?

Answer:

ABC is the activity based accounting. It is the costing done for each separate activity which maybe unit level, batch level, product sustaining or facility sustaining.

Explanation:

The basic difference between ABC and traditional costing systems can be explained with the help of the following diagram.

Traditional Costing System

Overhead Cost Accounts (For each individual expense e.g. tax)

First Stage Allocation

N.  Cost Centers ( normally Departments)

Second Stage Allocation ( Direct Labor Or Machine Hours)

Cost Objects ( products, services and customers)

ACTIVITY BASED COSTING SYSTEMS

Overhead Cost Accounts (For each individual expense e.g. tax)

First Stage Allocation ( resource cost drivers)

N. Activity  Cost Centers

Second Stage Allocation ( activity cost drivers)

Cost Objects ( products, services and customers) (Direct Costs)

Four steps are involved in the design of ABC systems.

The first two steps relate to the first stage and final two steps to the second stage of the two - stage allocation process shown above.

Answer:

The correct answer is: b. Channel

Explanation:

The Communication Process Model (CPM) is a model that describes the steps through which effective exchange of information takes place from the  sender of a message to the receiver(s) of the message. (Refer to attached image)

The CPM includes the following steps:

1. Noise- reducing physical/ physiological distractions that can impede clear communication.  

2. Communicator- the person who initiates the communication

3. Message- the information exchanged between the sender and receiver of the message

4. Feedback- How the information from the sender is received by the recipient of the communication

5. Channel- The medium by which the information is delivered from the sender to the receiver.

In this instance, when Aaden decided to have a discussion with his significant other in his home using face-to-face communication, he is deciding on the channel or medium through which the communication will this place. By choosing face-to-face communication at his home, Aaden has determined what he believes is the most appropriate context for the conversation with his significant other, given the sensitive nature of the topic. In this way, Aaden has selected a channel of communication.

Answer: The ratio of f at the higher temperature to f at the lower temperature is 4.736

Explanation:

According to the Arrhenius equation,

[tex]f=A\times e^{\frac{-Ea}{RT}}[/tex]

or,

[tex]\log (\frac{f_2}{f_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}][/tex]

where,

[tex]f_1[/tex] = rate constant at 525K

[tex]K_2[/tex] = rate constant at 545K

[tex]Ea[/tex] = activation energy for the reaction = 185kJ/mol= 185000J/mol   (1kJ=1000J)

R = gas constant = 8.314 J/mole.K

[tex]T_1[/tex] = initial temperature = 525 K

[tex]T_2[/tex] = final temperature = 545 K

Now put all the given values in this formula, we get

[tex]\log (\frac{f_2}{f_1})=\frac{185000J/mol}{2.303\times 8.314J/mole.K}[\frac{1}{525K}-\frac{1}{545K}][/tex]

[tex]\log (\frac{f_2}{f_1})=0.6754[/tex]

[tex](\frac{f_2}{f_1})=4.736[/tex]

Therefore, the ratio of f at the higher temperature to f at the lower temperature is 4.736

The density of the unknown liquid can be calculated by finding the mass of the liquid and dividing it by the volume. The mass of the liquid is 37.13 g and the volume is 48.1 mL. Thus, the density is 0.772 g/mL.

The density of a substance is calculated by dividing its mass by its volume. Here, the mass of the unknown liquid can be calculated by subtracting the weight of the empty graduated cylinder from the weight of it filled with the liquid. That is, mass = 92.39 g - 55.26 g = 37.13 g. The volume of the liquid is given as 48.1 mL. Therefore, the density can be calculated as follows:

Density = mass/volume

= 37.13 g / 48.1 mL = 0.772 g/mL

This means the density of the unknown liquid is 0.772 g/mL.

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Answer:

There should be a total voltage of zero (0)

Explanation:

In bipolar encoding (multilevel binary), there are three voltage levels, positive, negative, and zero. The voltage level for one data element is at zero, while the voltage level for the other element alternates between positive and negative.

However, the primary advantage of a bipolar scheme is that when all the voltages are added together after a long transmission, there should be a total voltage of zero.