List the following numbers in order from least to greatest 2.8,2.8x10^2,2.8x10^-3,2.8x10^4,2.8x10^-5

Brandon can reach a point 300m downstream on the opposite side of the river in a minimum of 60 seconds by swimming diagonally across the river and then running the rest of the way.

In order to determine the minimum amount of time for Brandon to reach a point 300m downstream on the opposite side of a river, we can use the concept of relative velocities.

First, we need to find the velocity of the current. We can use the formula v = d/t, where v is the velocity, d is the distance, and t is the time.

The distance Brandon needs to cross the river is 50m, and he wants to reach a point 300m downstream, so the total distance he needs to travel horizontally is 50m + 300m = 350m.

Since the current is perpendicular to Brandon's swimming direction, it doesn't affect the time it takes for him to swim across the river. Therefore, we only need to consider his running speed.

The time it takes for Brandon to run the remaining distance of 300m is equal to the distance divided by his running speed, which is 300m / 5m/s = 60s.

So, the minimum amount of time for Brandon to reach the point 300m downstream is 60 seconds.

To find the minimum amount of time for Brandon to reach the point across the river, divide the problem into two components: swimming and running. Use the Pythagorean theorem to find the resultant velocity of Brandon's swimming motion. To find the total minimum time, add the swimming time and the running time.

To find the minimum amount of time for Brandon to reach the point across the river, we can use the concept of vector addition. Since the river is flowing downstream, Brandon needs to swim at an angle with respect to the direction of the river current. Let's break down the problem into two components: swimming and running.

Swimming:

Using the Pythagorean theorem, we can find the resultant velocity of Brandon's swimming motion. The width of the river is the base, the downstream distance is the height, and the resultant velocity is the hypotenuse. By substituting the given values, we can find the resultant velocity of Brandon's swimming motion as 5.12 m/s. This is the velocity he will need to swim at an angle to counteract the river current.

Running:

After crossing the river, Brandon needs to run the remaining distance of 300 m at a speed of 5 m/s. The time it takes to run this distance is 300 m / 5 m/s = 60 seconds.

To find the time it takes for Brandon to swim across the river, we can use the formula:

time = distance / velocity

. The distance is 50 m, and the velocity is 5.12 m/s. Therefore, the time it takes for Brandon to swim across the river is 50 m / 5.12 m/s = 9.77 seconds.

Finally, we can add the swimming time and the running time to find the total minimum time it takes for Brandon to reach the point across the river: 9.77 seconds + 60 seconds = 69.77 seconds.

Answer: B

Step-by-step explanation:

on edg

Answer: A. 210

Step-by-step explanation:

We know that the number of combinations of n things taking r at time is given by expression :-

[tex]^nC_r=\dfrac{n!}{r!(n-r)!}[/tex]  (1)

The given expression : [tex]^{10}C_{6}[/tex] which basically gives the number of combinations of 10 things taking 6 at a time.

Using (1) , we have

[tex]^{10}C_{6}=\dfrac{10!}{6!(10-6)!}\\\\=\dfrac{10\times9\times8\times7\times6!}{6!4!}\\\\=\dfrac{10\times9\times8\times7}{4!}\ \ [\text{Cancel }6!\text{ from numerator and denominator}]\\\\=\dfrac{10\times9\times8\times7}{4\times3\times2\times1}\\\\=210[/tex]

Hence, the correct answer is A. 210 .

Answer:

D) Hyperbola.

Step-by-step explanation:

If a right circular cone intersects a plane that passes through one of its nappes, but the plane is not parallel to an edge of the cone, the resulting curve will be one arc of a hyperbola.

Therefore, the answer is Hyperpola.

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Answer:

y=5x - 4.5

Step-by-step explanation:

I took the test

Answer:aAPEX1

Step-by-step explanation:

Answer:

720 is correct

Answer:

0.356

Step-by-step explanation:

Based on the batting averages denoted in the stemplot, the entry of 0.32|9 shows an occurrence of 0.329.

In a stemplot, the numbers that are stems are on the left side and will be the first numbers that should be denoted.

The numbers on the right are leaf numbers and come after the stem. This means that a stemplot showing 0.32|9 is a way of writing 0.329.

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Hence, the value of x is:

[tex]x=\dfrac{1}{3}[/tex]

We have to solve for x i..e we have to find the value of 'x' by solving this equation.

The equation is given as:

[tex]-4(3x-2)=6x+2[/tex]

firstly we will solve the bracket term as:

[tex]-4\times 3x-4\times (-2)=6x+2\\\\-12x+8=6x+2[/tex]

Now we take like terms together i..e the variable term is taken to the right hand side of the equation and the constant term is kept on the left side of the equation as:

[tex]8-2=6x+12x\\\\\\6=18x[/tex]

on dividing both side of the equation by 18, we obtain:

[tex]x=\dfrac{6}{18}\\\\x=\dfrac{1}{3}[/tex]

Hence, the value of x is:

[tex]x=\dfrac{1}{3}[/tex]

Answer:

B

Step-by-step explanation:

To find the reciprocal of 3.6, divide 1 by 3.6.

To find the reciprocal of 3.6, you divide 1 by 3.6. The reciprocal of a number is obtained by flipping the number. So, the reciprocal of 3.6 is

1/3.6

or approximately 0.2778.

A real-world situation that can be modeled by the equation 3 2/3x = 5/6x - 7/8 is when you have a certain amount of money, and you are earning money at a certain rate while also incurring expenses.

To write a real-world situation that could be modeled by the equation 3 2/3x=5/6x-7/8, let's consider a scenario where you have $3.67, and you are earning additional money at a rate of $0.833 per hour. On the other hand, you have expenses of $0.875 per hour. We can represent the money you have earned and the money you have spent using the equation 3 2/3x=5/6x-7/8.

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To write a real-world situation that could be modeled by the equation 3 2/3x=5/6x-7/8, we can consider a scenario where a store is selling two different types of products and the equation represents the difference in the number of sales for the two products.

To write a real-world situation that could be modeled by the equation 3 2/3x=5/6x-7/8, we need to think about a scenario where two quantities are being compared or related. For example, let's consider a situation where a store is selling two different types of products. The equation could represent the difference in the number of sales for the two products over a certain period of time. The left side of the equation represents the number of sales for one product, and the right side represents the number of sales for the other product, with a difference of 7/8 units.

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Using the straight-line depreciation method, the linear equation for the equipment's value over time is y = -175t + 875. After 2 years, the equipment's value is $525. To find when the equipment's value is $200, solve for t and get approximately 3.86 years.

To calculate the depreciation of the equipment using a linear equation, we'll use the straight-line depreciation method. The business purchases the equipment for $875 and it will be worthless after 5 years, so it depreciates $875 over 5 years.

Part A

To write the linear equation representing the value of the equipment y over time t, we need to find the slope (m) of the line which in this case is the annual depreciation. The slope is the change in value divided by the time, thus m = -$175/year. The initial value (intercept) is $875. The equation is:

y = -175t + 875

Part B

Substitute t = 2 into the equation to find the value of the equipment at year 2:

y = -175(2) + 875

y = -350 + 875

y = $525

Part C

We want to find the time t when the value y is $200. Substitute y = $200 into the equation:

200 = -175t + 875

-175t = 200 - 875

-175t = -675

t = [tex]\frac{-675}{-175}[/tex]

The correct answer is the first option: All real numbers.

I just did the quiz and got it right.

For all the non BrainlyPlus members

Final answer:

Using algebra, we set up equations based on the information given: the number of student tickets is three times the number of adult tickets, and the total number of tickets is 376. Solving for the number of adult tickets, we find that 94 adult tickets were sold.

Explanation:

The question asks us to figure out how many adult tickets were sold for the school play when a total of 376 tickets were sold, and student tickets sold were three times the number of adult tickets.

Let's denote the number of adult tickets sold as A and the number of student tickets sold as S. According to the problem, S = 3A. We are also told that the total number of tickets sold is 376, so A + S = 376.

Substituting the first equation into the second one, we get A + 3A = 376. Simplifying this equation, 4A = 376. Dividing both sides by 4, A = 94. Therefore, 94 adult tickets were sold.

Final answer:

As per the values, 94 adult tickets were sold.

Explanation:

The question asks us to determine how many adult tickets were sold for a school play, given a total number of tickets and a ratio of student tickets to adult tickets.

To solve this problem, let's define adult tickets as x and student tickets as 3x, since there are three times as many student tickets as adult tickets.

The total tickets sold is 376, therefore the equation we need to solve is:

x + 3x = 376

Combining like terms, we get:

4x = 376

Dividing both sides by 4, we find that:

x = 94

Therefore, 94 adult tickets were sold.

To maximize profit, derive the profit equation ((120 - 0.1x) * x - (60x + 4000)) and set it to zero to find the critical points. These points will dictate the number of smartphones the company needs to manufacture and sell each day.

The subject of this question is the maximization of profit, which is a concept in economic mathematics. To maximize the profit, you'll need to determine the number of smartphones that the company should produce and sell each day.

The profit is the revenue (the money earned from selling goods) minus the costs. Revenue is given by the equation R = (120 - 0.1x) * x, and the total cost is given by the equation C = 60x + 4000, where x is the number of smartphones produced.

So, the profit P becomes P = R - C = (120 - 0.1x) * x - (60x + 4000). To maximize this profit, we'd take the derivative of P in terms of x and set it equal to zero to find the critical points. After finding the critical points, we then test these values back in the profit equation to find which gives the highest value and hence maximizes the profit.

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Answer:

y=1.32x-0.0022[tex]x^{2}[/tex]

Step-by-step explanation:

Let the standard equation of parabola be y=a[tex]x^{2}[/tex]+bx+c ....... (1)

Let y be the altitude of the ball and x be the distance traveled by the ball.

Now by putting the points one by one, we get the required equation.

first point = (0,0)

golf ball travels a distance of 600 feet  along the ground. Therefore point = (600,0)

At altitude of 200, it travels the distance of 300 feet(mid point) = (300,200)

By putting y=0 and x=0 in (1),

we get c=0,

By putting y=0 and x=600 we get

0 = 360000a+600b ..............(2)

By putting y=200 and x=300, we get

200=90000a+300b ................(3)

Solving (2) and(3) we get, a=-0.0022 and b = 1.32

So the required equation is :

y= =0.0022[tex]x^{2}[/tex]+1.32x

The height of the flagpole is 12 feet.

To determine the height of the flagpole, we can use the Pythagorean theorem.

Using the Pythagorean theorem:

c² = a² + b²

Here, c = 20 feet (length of cable), a = 16 feet (distance from flagpole base to ground point), and h = b (height of the flagpole).

Therefore, we have:

202 = 162 + h²

400 = 256 + h²

To find h, subtract 256 from 400:

400 - 256 = h²

144 = h²

h = √144 = 12.

The denominator of the fraction is -2x.

The correct answer is option (b)

"It is a mathematical statement which consists of equal symbol between two algebraic expressions."

"In a fraction, the value placed above the horizontal line."

"In a fraction, the value placed below the horizontal line."

For given question,

The axis of symmetry for a quadratic equation can be found using the formula [tex]x=-\frac{b}{2a}[/tex]

where a and b are coefficients in the quadratic equation and x represents the values along a vertical line on the coordinate plane.

[tex]\Rightarrow x=\frac{-b}{2a}\\\\ \Rightarrow \frac{a}{x} \times x=\frac{-b}{2a}\times \frac{a}{x}\\\\\Rightarrow a=\frac{b}{-2x}[/tex]

For the fraction [tex]\frac{b}{-2x}[/tex] the numerator is b and denominator is -2x.

Therefore, the denominator of the fraction is -2x.

The correct answer is option (b)

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Learning the proper order in which to read algebraic expressions and solve algebraic equations is important in algebra for understanding the order of operations, developing logical reasoning, and ensuring consistency in mathematical communication.

It is important to learn the proper order in which to read algebraic expressions and solve algebraic equations in algebra for several reasons: