Makayla has $8 to buy tickets at the school fair. Each ticket costs $1.50. Which inequality
best represents how many tickets she can buy?
n = number of tickets
-
-
-
A. n<5
B. n< 6
C. n<8​

Answer:

y = 2x + 1

Step-by-step explanation:

This line goes through the points (-2, 0) (the x-intercept) and (0, 1) (the y-intercept).

As we move from -2 to 0, x increases by 2, and at the same time y increases from 0 to 1, that is, by 1.  Thus, the slope of this line is m  = rise / run = 2/1 = 2.

Starting with the slope-intercept formula for a straight line:

y = mx + b becomes y = 2x + 1.    (We had already found b.)

The equation of line is x - 2y + 2 = 0.

Equations are mathematical statements containing two algebraic expressions on both sides of an 'equal to (=)' sign.

Here, x-intercept = -2

         y- intercept = 1

Now, equation of line

             x/a + y/b = 1

              x/-2 + y/1 = 1

              (x - 2y)/-2 = 1

               x - 2y = -2

               x - 2y + 2 = 0

Thus, the equation of line is x - 2y + 2 = 0.

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To solve the inequality, you need to isolate/get x by itself:

171 > -6x    Divide -6 on both sides [dividing/multiplying a negative number on

-28.5 < x      [dividing/multiplying a negative number in an inequality causes the sign (<, >, ≤, ≥) to flip]

-28.5 < x    [x is a number greater than -28.5]

So your graph should have an open circle at -28.5 (the first small line next to -28), and the arrow pointing to the right since x is greater than -28.5 (increasing)      The 1st option is your answer

[use the o---> and put it at -28.5]

Answer:

pift^2(or your third option) is the area of a circle with a radius of 1.

Answer:

Step-by-step explanation:

Look at the picture.

We have the triangle 30° - 60° - 90°. The sides are in ratio 1 : √3 : 2.

We have:

[tex]a\sqrt3=5\sqrt3[/tex]          divide both sides by √3

[tex]a=5[/tex]

It's a right triangle.

Answer:

2x^(10)y^(12)

Hope This Helps!   Have A Nice Day!!

Answer:

The correct answer is 2X¹⁰Y¹²

Step-by-step explanation:

Points to remember

identities

Xᵃ * Xᵇ = X⁽ᵃ⁺ᵇ⁾

Xᵃ/Xᵇ = X⁽ᵃ⁻ᵇ⁾

To find the equivalent to given expression

It is given that,

60X²⁰Y²⁴/30X¹⁰Y¹²

Using identities we can write,

60X²⁰Y²⁴/30X¹⁰Y¹² = (60/30) * (X²⁰/X¹⁰) * (Y²⁴/y¹²)

  = 2 * X⁽²⁰ ⁻ ¹⁰⁾ * Y⁽²⁴ ⁻ ¹²⁾

  = 2 * X¹⁰ * Y¹²

  = 2X¹⁰Y¹²

The correct answer is 2X¹⁰Y¹²

Answer:

see explanation

Step-by-step explanation:

Using the rules of exponents

• [tex]a^{\frac{m}{n} }[/tex] ⇔ [tex]\sqrt[n]{a^{m} }[/tex]

• [tex]a^{-m}[/tex] ⇔ [tex]\frac{1}{a^{m} }[/tex]

(a)

[tex]27^{\frac{1}{3} }[/tex] = [tex]\sqrt[3]{27}[/tex] = 3

(b)

[tex]25^{-\frac{1}{2} }[/tex]

= [tex]\frac{1}{25^{\frac{1}{2} } }[/tex] = [tex]\frac{1}{\sqrt{25} }[/tex] = [tex]\frac{1}{5}[/tex]

Answer: Sqrt(36/16)

sqrt(36/16)=6/4=3/2 rational

Answer:

0.42% Chance Of The Counters Being Red

Step-by-step explanation:

1.00

-0.58

=0.42% Probability

The probability that a randomly picked counter from a bag containing only red and blue counters is red, given that the probability the counter is blue is 0.58, is 0.42.

The subject here is

probability

, which in

mathematics

is a measure of the likelihood that a particular event will occur. The problem states that the

probability

that a counter is blue is 0.58. Since we only have red and blue counters in the bag, and the probabilities of all possible outcomes must add up to 1, the

probability

that a counter picked at random is red is 1 - the

probability

that the counter is blue. So, to find the

probability

that the counter is red, subtract 0.58 from 1. The resulting

probability

that a randomly picked counter is red is therefore 0.42.

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Answer:

C. Directrix and Focus

Step-by-step explanation:

Given choices are :

A. Locus and Directrix

B. Axis and vertex

C. Directrix and Focus or

D. Vertex and Locus

Now we need to find about which of the above choices are the exact same distance from a parabola.

By definition of parabola, vertex lies at equal distance from directrix and focus.

Hence choice  C. Directrix and Focus  is correct.

Answer:

C.Directix and Focus

Step-by-step explanation:

The directrix and the focus are both parts of the parabola that are the exact same distance form the vertex ot he parabola, the only difference is that they are in opposite directions, the focus of the parabola is always found inside of the parabola and in the axis of symmetry, on the same axis of symmetry both on the outside of the parabola, the same distance from the vertex than the focus you can find the directrix, which is a straight line that is perpendicular to the axis of symmetry.

Answer:

the measure of the obtuse base angle of the trepezoid is 111.

Step-by-step explanation:

An isosceles triangle has one vertex angle and two congruent base angles. Also, we know that the sum of all angles in a triangle must equal 180 degrees. So we can say that:

Vertex Angle + Base Angle + Base Angle = 180.

Vertex Angle + 2 x (Base Angle) = 180.

2 x (Base Angle) = 180 - Vertex Angle

2 x (Base Angle) = 180 - 42

2 x (Base Angle) = 138

Base Angle = 69

Also, we know that angles on one side of a straight line always add to 180 degrees.

So we can say that:

Base Angle + ? = 180

? = 180 - Base Angle

? = 180 - 69

? = 111

So, the measure of the obtuse base angle of the trepezoid is 111.

________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________________

Answer:

C. a value close to the mean

Step-by-step explanation:

The positive skewness of distribution could be caused by a value close to the mean. Thus, option C is correct.

The normal distribution is somewhat similar where the main observation (mean or its surrounding) occurs frequently and as we go far from the mean, its chances decrease.

Normal distribution of proportion: The sampling distribution of the proportion we're talking about should be normally distributed.

A skewed distribution is a distribution having bias on one of the two sides (either left or right).

The positive skewness of distribution could be caused by a value close to the mean.

Thus, option C is correct.

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It is B

-2 =3(-1) + 1

Answer:

See attachment.

Step-by-step explanation:

The parent function is [tex]f(x)=|x|[/tex]

When this function is translated 2 units to the right, the new equation becomes; [tex]g(x)=|x-2|[/tex].

Another translation of 2 units up gives  [tex]h(x)=|x-2|+2[/tex].

A final dilation by a factor of [tex]\frac{1}{3}[/tex] gives  [tex]i(x)=\frac{1}{3}|x-2|+2[/tex].

The graph of this function is shown in the attachment.

Answer:

Its C

Step-by-step explanation:

On Edge

The simplified expression for cos x csc x tan x is 1 .

Sure, let's simplify the expression step by step:

Given expression:[tex]\( \cos(x) \csc(x) \tan(x) \)[/tex]

We know that:

[tex]- \( \csc(x) = \frac{1}{\sin(x)} \)[/tex]

[tex]- \( \tan(x) = \frac{\sin(x)}{\cos(x)} \)[/tex]

So, we substitute these into the expression:

[tex]\( \cos(x) \cdot \frac{1}{\sin(x)} \cdot \frac{\sin(x)}{\cos(x)} \)[/tex]

Now, we cancel out the common terms:

[tex]\( \frac{\cos(x) \cdot \sin(x)}{\sin(x) \cdot \cos(x)} \)[/tex]

Now, we can see that the numerator and the denominator cancel each other out:

[tex]\( \frac{1}{1} = \boxed{1} \)[/tex]

In conclusion, the simplified expression is ( 1 ).

We start by using the trigonometric identities to express [tex]\( \csc(x) \) and \( \tan(x) \) in terms of \( \sin(x) \) and \( \cos(x) \)[/tex]. Then, we substitute these expressions into the given expression. Next, we cancel out the common terms in the numerator and denominator, resulting in a simplified expression of 1. This simplification demonstrates the relationship between the trigonometric functions and highlights their interconnectedness through fundamental trigonometric identities.

Complete question:

Simplify the expression cos x csc x tan x

Answer:

8 - 6x

Step-by-step explanation:

just trust me the other guy's wrong

Both terms [tex]a^8b^4[/tex] and [tex]a^2b^2[/tex] contain some powers of a and b. So, we can factor the occurrences with the smallest exponent:

[tex]a^8b^4+a^2b^2 = a^2b^2(a^6b^2+1)[/tex]

The complete factored form of the polynomial [tex]a^{8}b^{4} +a^{2}b^{2}[/tex]  is  [tex]a^{2}b^{2} (a^{6}b^{2} + 1 )[/tex] .

A complete factored form of expression is the result expression of the polynomial which is expressed as the product of its smallest factor format. We always get a simplified expression of the polynomial in the complete factored form.

The given expression is -  [tex]a^{8}b^{4} +a^{2}b^{2}[/tex]

Taking the term [tex]a^{2}b^{2}[/tex]  common to express the polynomial in factored form,

[tex]a^{8}b^{4} +a^{2}b^{2}[/tex]  =  [tex]a^{2}b^{2} (a^{6}b^{2} + 1 )[/tex]

Thus, the complete factored form of the polynomial [tex]a^{8}b^{4} +a^{2}b^{2}[/tex]  is  [tex]a^{2}b^{2} (a^{6}b^{2} + 1 )[/tex] .

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Answer:

a

Step-by-step explanation:

Option: A is the correct answer.

The appropriate domain for the function is:

            A. All non-negative integers

We know that a domain of a function is the set of all the value of the independent variable  at which the function is defined.

Here  x represents the number of cars sold and F(x) represents their net profits (in dollars)

As we know that the profit will be zero when none of the car will be sold and also the car will be sold as a whole.Also, the profit is calculated when some cars are sold.

Hence, the x-value will be the set of all the positive integers.

           Hence, the correct answer is:

              Option: A

Answer: 5. 24.04

6. 30

7. 49.45

Step-by-step explanation:

use the law of sines for 5 and 6,

law of cosine for 7

5-6= opp/hyp.

7= adj/hyp

5. Let x be the missing angle.

We have the hypotenuse of the given right angle triangle to be 27 units.

The opposite side to the missing angle is 11 units.

We use the sine ratio to obtain:

[tex]\sin x=\frac{Opposite}{Hyppotenuse}[/tex]

[tex]\sin x=\frac{11}{27}[/tex]

[tex]x=\sin^{-1}(\frac{11}{27})[/tex]

[tex]x=24.04\degree[/tex] to the nearest hundredth.

6. Let y represent the missing angle.

We have the hypotenuse of the given right angle triangle to be 24 units.

The opposite side to the missing angle is 12 units.

We use the sine ratio to obtain:

[tex]\sin y=\frac{Opposite}{Hyppotenuse}[/tex]

[tex]\sin y=\frac{12}{24}[/tex]

[tex]y=\sin^{-1}(\frac{1}{2})[/tex]

[tex]y=30\degree[/tex].

7. Let the missing angle be z.

This time we have the adjacent side to be 13 units and the hypotenuse is 20 units.

We use the cosine ratio to obtain:

[tex]\cos z=\frac{Adjacent}{Hypotenuse}[/tex]

This implies that:

[tex]\cos z=\frac{13}{20}[/tex]

[tex]z=\cos ^{-1}(\frac{13}{20})[/tex]

[tex]z=49.46\degree[/tex] to the nearest hundredth

Answer:I believe the answer is 12 because it takes 4, 1/4 unit cube to make 1 cubic unit so to make 3 cubic units you need 12, 1/4 unit cubes if that makes any sense. :) Please make Brainliest if this helped.

Answer:

The correct answer option is A. [tex]\frac{1}{16}[/tex].

Step-by-step explanation:

We are given the following geometric sequence and we are to find its 8th term:

[tex]1024, 256,64,...[/tex]

Here [tex]a_1=1024[/tex] and common ratio [tex](r) = \frac{64}{256} =0.25[/tex].

The formula we will use to find the 8th term is:

nth term = [tex]a_1 \times r^{(n-1)}[/tex]

Substituting the values in the formula to get:

8th term = [tex]1024 \times 0.25^{(8-1)}[/tex]

8th term = [tex] \frac { 1 } { 1 6 } [/tex]

Answer:

This is a right triangle, so we know that:

h² = b' · c'

which is this case can be specificly written as:

BD² = AD · CD

BD² = 7 · 3 = 21

BD = √21

Now that we can also notice that ΔADB is also a right triangle, therefore we can apply the pythagorean theorem:

AD² + BD² = AB²

7² + (√21)² = x²

x²               = 49 + 21 = 70

x                 = √70

Answer:

see explanation

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

y - 3 = - 9(x + 4) ← is in point- slope form

with slope m = - 9

Given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{-9}[/tex] = [tex]\frac{1}{9}[/tex]

The point (a, b) = (4, - 3), hence

y + 3 = [tex]\frac{1}{9}[/tex] (x - 4) ← equation of perpendicular line

Answer:

11.77

Step-by-step explanation:

Volume of sphere = [tex]\frac{4}{3}[/tex] × π × r²

580 mm³ =  [tex]\frac{4}{3}[/tex] × π × r²

( Divide both sides by  [tex]\frac{4}{3}[/tex] )

435 mm³ = π × r²

( Divide both sides by π )

138.4648005 = r²

( Square root both sides )

11.76710672 = r

Answer:

y = 1

x = 4

{x,y} = {4,1}

Step-by-step explanation:

[2]

x - 3y = 1

 + 3y       +3y

x = 3y + 1

[1]

x + 3y = 7

(3y + 1) + 3y = 7

      - 1            - 1

(3y) + 3y = 6

6y = 6

6      6

y = 1

--------------------------------

x = 3y + 1

y = 1

x = 3(1) + 1

x = 4

y = 1

x = 4

{x,y} = {4,1}

Answer:

105

Step-by-step explanation:

15 x 4 = 60

9 x 5 = 45

45 + 60 = 105

Answer:

105

Step-by-step explanation:

4x15=60

5x9=45

45=60=105

Answer:

r = 17/10

Step-by-step explanation:

Let the common ratio be r.  Then 5r = 8.5, and r = 17/10.

Answer:

1.7

Step-by-step explanation:

Answer:

[tex]\dfrac{21}{32}=0.65625[/tex]

Step-by-step explanation:

If the probability of success is 50%, then p=0.5 and q=1-0.5=0.5.

At least three successes in six trials of a binomial experiment means that favorable are 3 successes, 4 successes, 5 successes and 6 successes.

1. 3 successes:

[tex]Pr_1=C^3_6p^3q^{6-3}=\dfrac{6!}{3!(6-3)!}\cdot (0.5)^3\cdot (0.5)^3=20\cdot \dfrac{1}{2^6}=\dfrac{5}{16}[/tex]

2. 4 successes:

[tex]Pr_2=C^4_6p^4q^{6-4}=\dfrac{6!}{4!(6-4)!}\cdot (0.5)^4\cdot (0.5)^2=15\cdot \dfrac{1}{2^6}=\dfrac{15}{64}[/tex]

3. 5 successes:

[tex]Pr_3=C^5_6p^5q^{6-5}=\dfrac{6!}{5!(6-5)!}\cdot (0.5)^5\cdot (0.5)^1=6\cdot \dfrac{1}{2^6}=\dfrac{3}{32}[/tex]

4. 6 successes:

[tex]Pr_4=C^6_6p^6q^{6-6}=\dfrac{6!}{6!(6-6)!}\cdot (0.5)^6\cdot (0.5)^1=1\cdot \dfrac{1}{2^6}=\dfrac{1}{64}[/tex]

Now, the probability of at least three successes in six trials of a binomial experiment is

[tex]Pr=Pr_1+Pr_2+Pr_3+Pr_4=\dfrac{5}{16}+\dfrac{15}{64}+\dfrac{3}{32}+\dfrac{1}{64}=\dfrac{20+15+6+1}{64}=\dfrac{42}{64}=\dfrac{21}{32}=0.65625[/tex]

To find the probability of at least three successes in six trials of a binomial experiment where the success rate is 50%, we'll need to consider the complement of this event, which is easier to calculate in this situation. The complement consists of the probability of either 0, 1, or 2 successes in the six trials. By finding the sum of these probabilities, we can subtract it from 1 to find the probability of the original event (3 or more successes).

First, let's recall the formula for the binomial distribution:

P(X = k) = C(n, k) * p^k * (1 - p)^(n - k)

where:
- P(X = k) is the probability of k successes in n trials,
- C(n, k) is the number of combinations of n items taken k at a time, it can be calculated using the formula C(n, k) = n! / (k! * (n - k)!),
- p is the probability of success for each trial,
- (1 - p) is the probability of failure for each trial,
- n is the number of trials, and
- k is the number of successes.

Since the success probability is 50%, or 0.5, and the complement includes the probability of 0, 1, or 2 successes, we can calculate each of these probabilities.

For k = 0 (zero successes):
P(X = 0) = C(6, 0) * (0.5)^0 * (0.5)^(6 - 0)
P(X = 0) = (6! / (0! * 6!)) * 1 * (0.5)^6
P(X = 0) = 1 * (0.5)^6
P(X = 0) = (1/64)

For k = 1 (one success):
P(X = 1) = C(6, 1) * (0.5)^1 * (0.5)^(6 - 1)
P(X = 1) = (6! / (1! * 5!)) * (0.5) * (0.5)^5
P(X = 1) = 6 * (0.5) * (0.5)^5
P(X = 1) = 6 * (1/64)

For k = 2 (two successes):
P(X = 2) = C(6, 2) * (0.5)^2 * (0.5)^(6 - 2)
P(X = 2) = (6! / (2! * 4!)) * (0.5)^2 * (0.5)^4
P(X = 2) = (15) * (0.25) * (0.0625)
P(X = 2) = 15 * (1/64)

Now we sum up these probabilities to get the complement:
P(X < 3) = P(X = 0) + P(X = 1) + P(X = 2)
P(X < 3) = (1/64) + 6*(1/64) + 15*(1/64)
P(X < 3) = (1 + 6 + 15) / 64
P(X < 3) = 22 / 64
P(X < 3) = 11 / 32

Now to find the probability of at least three successes (P(X >= 3)), we subtract the complement from 1:
P(X ≥ 3) = 1 - P(X < 3)
P(X ≥ 3) = 1 - (11 / 32)
P(X ≥ 3) = (32 / 32) - (11 / 32)
P(X ≥ 3) = 21 / 32

Converting this to a percentage and rounding to the nearest tenth of a percent:
P(X ≥ 3) ≈ (21 / 32) * 100
P(X ≥ 3) ≈ 65.625%

Rounded to the nearest tenth of a percent, the probability is 65.6%.

Answer:

[tex]\large\boxed{A=25\pi}[/tex]

Step-by-step explanation:

The formula of an area of a circle:

[tex]A=\pi r^2[/tex]

r - radius

We have the center A(-3, 3) and the point on the circle B(1, 6).

The radius is equal to the distance between the center and the any point on the circle.

The formula of a distance between two points:

[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Substitute:

[tex]r=\sqrt{(1-(-3))^2+(6-3)^2}=\sqrt{4^2+3^2}=\sqrt{16+9}=\sqrt{25}=5[/tex]

[tex]A=\pi(5^2)=25\pi[/tex]

The area of the circle centered at A(-3, 3) and passing through B(1, 6) is 25π square units.

The subject of this problem is geometry, specifically about the area of a circle.To find the area of a circle, we need to know the radius. Since B is on the circle, AB is the radius. The area (A) of a circle is found using the formula A = πr², where r represents the radius of the circle. Here, the radius of the circle can be determined by finding the distance between the center A(-3, 3) and a point on the circle B(1, 6).

The formula for distance between two points in a plane is √[(x₂ - x₁)² + (y₂ - y₁)²]. Substituting values, we get r = √[(1 - -3)² + (6 - 3)²] = √[(4)² + (3)²] = √[16 + 9] = √25 = 5. Therefore, the radius is 5.

Substitute r = 5 in the area formula: A = π * (5)² = 25π square units.

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Answer:

[tex]y=-8.08[/tex] -------> [tex]y+8=3(x+2)^{2}[/tex]

[tex]y=14.25[/tex] -------> [tex]y-14=-(x-3)^{2}[/tex]

[tex]y=-7.625[/tex] -----> [tex]y+7.5=2(x+2.5)^{2}[/tex]

[tex]y=17.25[/tex] -------> [tex]y-17=-(x-3)^{2}[/tex]

[tex]y=-7.25[/tex] -------> [tex]y+7=(x-4)^{2}[/tex]

[tex]y=6.25[/tex] -------> [tex]y-6=-(x-1)^{2}[/tex]

Step-by-step explanation:  

we know that

The standard form of a vertical parabola is equal to

[tex](x-h)^{2}=4p(y- k)[/tex]

where

(h,k) is the vertex

the focus is (h, k + p)

and

the directrix is y = k - p

Part 1) we have

[tex]y+8=3(x+2)^{2}[/tex]

Convert to standard form

[tex](x+2)^{2}=(1/3)(y+8)[/tex]

The vertex is the point [tex](-2,-8)[/tex]

[tex]h=-2,k=-8[/tex]

[tex]4p=1/3[/tex]

[tex]p=1/12[/tex]

the directrix is equal to

[tex]y = k-p[/tex] -----> [tex]y=-8-(1/12)=-8.08[/tex]

Part 2) we have

[tex]y-14=-(x-3)^{2}[/tex]

Convert to standard form

[tex](x-3)^{2}=-(y-14)[/tex]

The vertex is the point [tex](3,14)[/tex]

[tex]h=3,k=14[/tex]

[tex]4p=-1[/tex]

[tex]p=-1/4[/tex]

the directrix is equal to

[tex]y = k-p[/tex] -----> [tex]y = 14-(-1/4)=14.25[/tex]

Part 3) we have

[tex]y+7.5=2(x+2.5)^{2}[/tex]

Convert to standard form

[tex](x+2.5)^{2}=(1/2)(y+7.5)[/tex]

The vertex is the point [tex](-2.5,-7.5)[/tex]

[tex]h=-2.5,k=-7.5[/tex]

[tex]4p=1/2[/tex]

[tex]p=1/8[/tex]

the directrix is equal to

[tex]y = k-p[/tex] -----> [tex]y=-7.5-(1/8)=-7.625[/tex]

Part 4) we have

[tex]y-17=-(x-3)^{2}[/tex]

Convert to standard form

[tex](x-3)^{2}=-(y-17)[/tex]

The vertex is the point [tex](3,17)[/tex]

[tex]h=3,k=17[/tex]

[tex]4p=-1[/tex]

[tex]p=-1/4[/tex]

the directrix is equal to

[tex]y = k-p[/tex] -----> [tex]y = 17-(-1/4)=17.25[/tex]

Part 5) we have

[tex]y+7=(x-4)^{2}[/tex]

Convert to standard form

[tex](x-4)^{2}=(y+7)[/tex]

The vertex is the point [tex](4,-7)[/tex]

[tex]h=4,k=-7[/tex]

[tex]4p=1[/tex]

[tex]p=1/4[/tex]

the directrix is equal to

[tex]y = k-p[/tex] -----> [tex]y=-7-(1/4)=-7.25[/tex]

Part 6) we have

[tex]y-6=-(x-1)^{2}[/tex]

Convert to standard form

[tex](x-1)^{2}=-(y-6)[/tex]

The vertex is the point [tex](1,6)[/tex]

[tex]h=1,k=6[/tex]

[tex]4p=-1[/tex]

[tex]p=-1/4[/tex]

the directrix is equal to

[tex]y = k-p[/tex] -----> [tex]y=6-(-1/4)=6.25[/tex]

The parabolas represented by y + 8 = 3(x+2)², y - 14 = -(x-3)², y - 17 = -(x-3)², and y - 6 = -(x-1)² match with the directrixes y = -7.25, y = 14.25, y = 17.25, and y = 6.25 respectively.

To match the equations representing parabolas with their directrixes, we need to use the fact that the equation of a parabola is given by y - k = a(x-h)², where (h,k) is the vertex of the parabola and the directrix is given by y = k - 1/4a.

Given this, we can match the equations as follows:
1. y + 8 = 3(x+2)² matches with y = -7.25
2. y - 14 = -(x-3)² matches with y = 14.25
3. y + 7.5 = 2(x+2.5)² there isn't a match in column B
4. y - 17 = -(x-3)² matches with y = 17.25
5. y + 7 = (x-4)² there isn't a match in column B
6. y - 6 = -(x-1)² matches with y = 6.25.

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The complete question here:

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used

match the equations representing parabolas with their directrixes

Column A.

y+8=3(x+2)^2

y-14=-(x-3)^2

y+7.5=2(x+2.5)^2

y-17=-(x-3)^2

y+7=(x-4)^2

y-6=-(x-1)^2

Column B.

y=-7.25

y=6.25

y=17.25

y=14.25