Nuclear fusion differs from nuclear fission because nuclear fusion reactions- True or False

Answers

Answer 1

I think the answer would be True


Related Questions

Which of the following provides evidence to support Bohr's theory of atomic orbitals?
A. Gold foil experiment
B. Plum pudding model
C. Spectrum of colors emitted by gas
D. Radiation produced when beryllium is bombarded with alpha particles

Answers

Answer:

C. Spectrum of colors emitted by gas

Explanation:

Neils Bohr model of atom suggested that orbital electrons are divided into spherical orbits or energy levels around the central nucleus. In essence, electrons are located at various energy levels round the nucleus. His concept explained the discrete lines in the atomic spectrum of hydrogen. He suggested that electrons can move between different energy levels by simply gaining or losing energy.

Final answer:

The spectrum of colors emitted by a gas provides the evidence for Bohr's theory of atomic orbitals. This is because the spectral patterns match very well with Bohr's predictions of quantized energy levels for electrons.

Explanation:

The evidence that supports Bohr's theory of atomic orbitals comes from the spectrum of colors emitted by a gas when it is excited by heat or electrical charge. This is because Bohr's theory states that electrons live in distinct energy levels, or orbitals, and can absorb energy and 'jump' to a higher energy level. When they fall back down to their original level, they emit energy in the form of light (photons).

The discrete, or quantized, energy levels predicted by Bohr result in the emission of light in very specific wavelengths, creating a unique spectral pattern for each element. Such spectral patterns observed in the lab match very well with Bohr's predictions, providing strong evidence to support his theory.

Options A, B, and D refer to experiments and models that did contribute to the development of atomic theory, but aren't specifically tied to Bohr's model of the atom. For example, the gold foil experiment carried out by Rutherford was important for discovering the nuclear nature of atoms, but doesn't provide evidence for the existence of atomic orbitals.

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Urgent 25 points!!!
Consider this gas law problem: if I have 3.2 L of gas at a pressure of 3.5 atm and a temperature of 323 K, what will be the temperature of the gas if I decrease the volume of the gas to 2.6 L and decrease the pressure to 1.5

Answer all parts below for full credit:
A) What are the knows in this problem
B) What is the problem asking you to find
C) Which gas law is the best law for finding the answer to this problem?
D) Use the gas law that you indicated in part C above and find the unknown value(be sure to show all of your work)

Answers

Answer:

[tex]\boxed{\text{112 K}}[/tex]

Explanation:

A) Know

p₁ = Initial pressure;          p₂ = final pressure

V₁ =Initial volume;             V₂ = final pressure

T₁ = Initial temperature

B) Find

T₂ = final temperature

C) Strategy

Use the Combined Gas Laws Equation:

[tex]\dfrac{p_{1}V_{1}}{T_{1}} = \dfrac{p_{2}V_{2}}{T_{2}}[/tex]

It contains symbols for all the knowns and the unknown.

D) Calculations

(i) Data:

p₁ = 3.5 atm; p₂ = 1.5 L

V₁ = 3.2 L;     V₂ = 2.6 L

T₁ = 323 K     T₂ = ?

(ii) Calculation

[tex]\dfrac{3.5\times3.2}{323} = \dfrac{1.5\times 2.6}{T_{2}}\\\\0.0347 = \dfrac{3.90}{T_{2}}\\\\T_{2} = \dfrac{3.90}{0.0347} = \boxed{\textbf{112 K}}[/tex]

How do you do this question?

Answers

Answer:

[tex]\boxed{\text{(E) }1.0 \times 10^{-3} \text{ mol/L and pH = 3}}[/tex]

Explanation:

1. Calculate the concentration of hydronium ion

We can use an ICE table to organize the calculations.

                      HA + H₂O ⇌ H₃O⁺ + A⁻

I/mol·L⁻¹:     0.100                  0        0

C/mol·L⁻¹:       -x                    +x      +x

E/mol·L⁻¹:   0.100 - x              x         x

[tex]K_{\text{a}} = \dfrac{\text{[H}_{3}\text{O}^{+}]\text{A}^{-}]} {\text{[HA]}} = 1.0 \times 10^{-5}\\\\\dfrac{x^{2}}{0.100 - x} = 1.0 \times 10^{-5}\\\\\\\text{Check for negligibility of }x\\\\\dfrac{ 0.100 }{1.0 \times 10^{-5}} = 10 000 > 400\\\\\therefore x \ll 0.100\\\\\\x^{2} = 0.100 \times 1.0\times 10^{-5} = 1.00 \times 10^{-6}\\\\x = \sqrt{1.00 \times 10^{-6}} = 1.0\times 10^{-3}\\\\\rm [H$_{3}$O$^{+}$]= x mol$\cdot$L$^{-1}$ = 1.0 $\times$ 10$^{-3}$ mol$\cdot$L$^{-1}$[/tex]

2. Calculate the pH

[tex]\text{pH} = -\log{\rm[H_{3}O^{+}]} = -\log{1.0 \times 10^{-3}} = \boxed{\mathbf{3}}[/tex]

Balance and state of the reactions are precipitation, acid/base, or oxidation/reduction reactions.

A) Fe + O2 -> Fe2O3

B) Br2 + Fe(NO3)2 + KNO3 -> KBr + Fe(NO3)3

C) Ba(OH)2 + HNO3 -> H2O + Ba(NO3)2

D) NaF + Mg(NO3)2 -> MgF + NaNO3

Answers

The answers are in the photo.

By what factor does the gas temperature change if the volume is doubled and the pressure is tripled?

Answers

Answer:

If the volume is doubled and the pressure is tripled, the temperature changes by a factor of 6.

Explanation:

Since, for ideal gases the temperature is in direct relation to the volume and the pressure, you can predict that if the volume is doubled and the pressure is tripled the effect on the temperature will be 3 × 2 = 6 times.

You can prove it using the combined law of gases:

P₁ V₁ /T₁ = P₂ V₂ / T₂

Where the letters P denote absolute pressures, the letters T denote temperature measured in absolute scale, and the letters V denote volume.

The changes given may be written it this way:

V₂ = 2 × V₁ = 2V₁P₂ = 3 × P₁ = 3P₁

Then, you can write T₂ in terms of the other variables:

T₂ = (P₂ V₂  T₂) / (P₁ V₁) = 3P₁ 2V₁ T₂ / (P₁V₁)

Cancel the common factors P₁ and V₁

T₂ = 6 T₁

Which proves that the final temperature is 6 times the initial temperature.

By tripling the pressure and doubling the volume, the gas temperature changes by a factor of 6 according to the combined gas law.

To determine by what factor the gas temperature changes if the volume is doubled and the pressure is tripled, we can use the combined gas law, which is a combination of Boyle's, Charles's, and Gay-Lussac's laws. The combined gas law states that for a given amount of gas, the ratio of the product of pressure (P) and volume (V) to the temperature (T) is constant, or:

(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂

Assuming the initial conditions are P₁, V₁, and T₁, and after the changes they are P₂ = 3 * P₁, V₂ = 2 * V₁, and T₂, we can rearrange the equation to solve for T2/T1:

(3 * P₁ * 2 * V₁) / T₂ = (P₁ * V₁) / T₁

(6 * P₁ * V₁) / T₂ =  (P₁ * V₁)/ T₁

T₂ / T₁ = 6 * (P₁ * V₁) / (P₁ * V₁)

T₂ / T₁ = 6

So by tripling the pressure and doubling the volume, the temperature of the gas increases by a factor of 6. This result agrees with our understanding of the behavior of gases when subjected to changes in temperature, volume, and pressure.

Predict the products of each reaction: Part A Part complete HClO4(aq)+Fe2O3(s)→ Express your answer as a balanced chemical equation. Identify all of the phases in your answer. 6HClO4(aq)+Fe2O3(s)→2Fe(ClO4)3(aq)+3H2O(l) Previous Answers Correct Part B H2SO4(aq)+Sr(s)→ Express your answer as a balanced chemical equation. Identify all of the phases in your answer. Request Answer Part C H3PO4(aq)+KOH(aq)→ Express your answer as a balanced chemical equation. Identify all of the phases in your answer. nothing Request Answer Provide Feedback Correct. No additional followup.

Answers

Answer:

Part A: 6HClO₄(aq) + Fe₂O₃(s) → 2Fe(ClO₄)₃(aq) + 3H₂O(l).

Part B: H₂SO₄(aq) + Sr(s) → SrSO₄(s) + H₂(g).

Part C: H₃PO₄(aq) + 3KOH(aq) → K₃PO₄(aq) + 3H₂O(l).

Explanation:

Part A: complete HClO₄(aq) + Fe₂O₃(s)→ Express your answer as a balanced chemical equation. Identify all of the phases in your answer.

The balanced chemical equation is:

6HClO₄(aq) + Fe₂O₃(s) → 2Fe(ClO₄)₃(aq) + 3H₂O(l).

It is clear that 6 mol of HClO₄ (in aqueous phase) react with 1 mol of Fe₂O₃ (in solid phase) to produce 2 mol of Fe(ClO₄)₃ (in aqueous phase) and 3 mol of H₂O (in liquid phase).

Part B: H₂SO₄(aq) + Sr(s) → Express your answer as a balanced chemical equation. Identify all of the phases in your answer.

The balanced chemical equation is:

H₂SO₄(aq) + Sr(s) → SrSO₄(s) + H₂(g).

It is clear that 1 mol of H₂SO₄ (in aqueous phase) reacts with 1 mol of Sr (in solid phase) to produce 1 mol of SrSO₄ (in solid phase) and 1 mol of H₂ (in gas phase).

Part C: H₃PO₄(aq) + KOH(aq) → Express your answer as a balanced chemical equation.

The balanced chemical equation is:

H₃PO₄(aq) + 3KOH(aq) → K₃PO₄(aq) + 3H₂O(l).

It is clear that 1 mol of H₃PO₄ (in aqueous phase) react with 3 mol of KOH (in aqueous phase) to produce 1 mol of K₃PO₄ (in aqueous phase) and 3 mol of H₂O (in liquid phase).

For chemistry purposes we will always measure delta Ts (temperature changes) with which scale?


SELECT AN ANSWER


Reichter



Kelvin



Fahrenheit



Celcius

Answers

Answer:

Kelvin

Explanation:

How much heat is released when 105g of steam at 100.0C is cooled to ice at -15C? Enthalpy of vaporization of water is 40.67kj/mol, the enthalpy of fusion of water is 6.01kj/mol, the molar heat capacity of water is 75.4J/(mol.C) and the molar heat capacity of ice is 36.4J/(mol.C)

Answers

Answer:

4909.486Kj/mol

Explanation:

the heat would be required to change steam at 100°c to water at 100°c then change the water at that temperature to water at 0°c then change water at 0°c to ice at 0°c then ice at 0°c to ice at -15°c

Answer : The heat released is, 319.28 kJ

Solution :

The conversions involved in this process are :

[tex](1):H_2O(g)(100^oC)\rightarrow H_2O(l)(100^oC)\\\\(2):H_2O(l)(100^oC)\rightarrow H_2O(l)(0^oC)\\\\(3):H_2O(l)(0^oC)\rightarrow H_2O(s)(100^oC)\\\\(4):H_2O(s)(0^oC)\rightarrow H_2O(s)(-15^oC)[/tex]

Now we have to calculate the enthalpy change.

[tex]\Delta H=n\times \Delta H_{condensation}+[n\times c_{p,l}\times (T_{final}-T_{initial})]+n\times \Delta H_{freezing}+[n\times c_{p,s}\times (T_{final}-T_{initial})][/tex]

where,

[tex]\Delta H[/tex] = enthalpy change = ?

Mass of water = 105 g

Moles of water = [tex]\frac{\text{Mass of water}}{\text{Molar mass of water}}=\frac{105g}{18g/mole}=5.83mole[/tex]

[tex]c_{p,s}[/tex] = specific heat of solid water = [tex]36.4J/(mol.^oC)[/tex]

[tex]c_{p,l}[/tex] = specific heat of liquid water = [tex]75.4J/(mol.^oC)[/tex]

[tex]\Delta H_{freezing}[/tex] = enthalpy change for freezing = enthalpy change for fusion = - 6.01 KJ/mole = - 6010 J/mole

[tex]\Delta H_{condensation}[/tex] = enthalpy change for condensation = enthalpy change for vaporization = -40.67 KJ/mole = -40670 J/mole

Now put all the given values in the above expression, we get

[tex]\Delta H=5.83mole\times -40670J/mole+[5.83mole\times 75.4J/(mol.^oC)\times (0-100)^oC]+5.83mole\times -6010J/mole+[5.83mole\times 36.4J/(mol.^oC)\times (-15-0)^oC][/tex]

[tex]\Delta H=-319285.78J=-319.28KJ[/tex]     (1 KJ = 1000 J)

Negative sign indicates that the heat is released during the process.

Therefore, the heat released is, 319.28 KJ

Ethanoic acid and 1-butanol can react to produce water and a compound classified as an 1) aldehyde 2) amine 3) ester 4) halide

Answers

Answer:

3) ester

Explanation:

Esterification is the process in which alkanol and alkanoic acids reacts in the presence of a catalyst and heat. The product is usually an ester(alkanoate) and water.

For the reaction between ethanoic acid and 1-butanol, the product is butylethanoate and water as shown below:

               CH₃COOH + C₄H₈OH → CH₃COOC₄H₈ + H₂O

How much energy is absorbed as heat by 20. G of gold when it is heated from 25ºc to 35ºc? The specific heat of gold is 0.13 j/g·ºc.

Answers

Answer:

26. J

Explanation:

1) Data:

a) m = 20. g

b) ΔT = 35°C - 25°C

c) Cs = 0.13 J / g°C

2)  Formula:

Heat absorbed, Q = m × Cs × ΔT

3) Solution:

Q = 20. g × (35°C - 20°C) × 0.13 J/ g°C = 20. g × 10°C × 0.13 J/g°C = 26. J ← answer

The answer shows two significant figures.

The energy absorbed as heat by 20.0 g of gold when it is heated from 25ºC to 35ºC is 26.0 joules.

To find the amount of energy absorbed as heat by a substance, we can use the formula:

[tex]\[ Q = m \cdot c \cdot \Delta T \][/tex]

where:

- Q is the heat energy absorbed (in joules),

- m is the mass of the substance (in grams),

- c is the specific heat capacity of the substance (in joules per gram per degree Celsius),

- [tex]\( \Delta T \)[/tex] is the change in temperature (in degrees Celsius).

 Given:

- The mass of gold, m = 20.0  g,

- The specific heat capacity of gold, c = 0.13  J/g·ºC,

- The change in temperature,[tex]\( \Delta T[/tex] = 35ºC - 25ºC = 10ºC .

 Plugging these values into the formula, we get:

[tex]\[ Q = 20.0 \text{ g} \cdot 0.13 \text{ J/g.C} \cdot 10.C \] \[ Q = 20.0 \cdot 0.13 \cdot 10 \] \[ Q = 26.0 \text{ J} \][/tex]

Therefore, the energy absorbed as heat = 26.0 joules.

A mixture of nitrogen and hydrogen gases, at a temperature of 500


K, was put into an evacuated

vessel of volume 6.0


dm3. The vessel was then sealed.


N2(g) + 3H2(g) 2NH3(g)


The mixture was allowed to reach equilibrium. It was found that 7.2


mol of N2 and 12.0


mol of H2 were present in the equilibrium mixture. The value of the equilibrium constant, Kc, for this equilibrium is 6.0 × 10–2 at 500

K.


What is the concentration of ammonia present in the equilibrium mixture at 500


K?

answer is B, I don't know why. Please help

Answers

Answer:

0.7589 mol/L ≅ 0.76 mol/L.

Explanation:

For the equilibrium mixture:

N₂(g) + 3H₂(g) ⇄ 2NH₃(g),

Kc = [NH₃]²/[N₂][H₂]³

At 500 K, V = 6.0 dm³ = 6.0 L:

Kc = 6.0 x 10⁻²,

[N₂] = (7.2 mol)/(6.0 L) = 1.2 mol/L, [H₂] = (12.0 mol)/(6.0 L) = 2.0 mol/L.

∴ [NH₃]² = (Kc)[N₂][H₂]³ = (6.0 x 10⁻²)(1.2 mol/L)(2.0 mol/L)³ = 0.576.

∴ [NH₃] = √(0.576) = 0.7589 mol/L ≅ 0.76 mol/L.

Which type of substances have chemical bonds that are not directional and valence electrons that move freely between the atoms?

Answers

Answer:

metals as they have free electrons

Answer:

The answer is metals

Explanation:

Metals, for example mercury (Hg), iron (Fe) and copper (Cu), have metallic bonds. In this kind of bond the electrons are deslocalized. That means that electrons moves from one atom to another, by forming a "sea of electrons". Several properties of metals, such as electrical and thermal conductivity, are explained by this model of chemical bond.

What does this mean: A saturated solution may be quite dilute because some substances have a very low solubility. I don't understand what this is saying.

Answers

Answer:

Here's how I would explain it.

Explanation:

Think of it this way.

When you mix solutions of silver nitrate and sodium chloride, you get an immediate precipitate of silver chloride. The equation is

Ag⁺(aq) + Cl⁻(aq) ⟶ AgCl(s)

Now, take some AgCl and stir it vigorously with water.

You won't see much happening, because the AgCl is has such a low solubility. Not much of it will go into solution. And yet, a small amount of it does dissolve until the solution is saturated.

The concentration of AgCl in the saturated solution is

about 0.000 01 mol·L⁻¹.

I hope you will agree that this is a dilute solution even though it is saturated with AgCl.

Which of these, if dissolved in 1.0 l of pure water, would produce a buffer solution? which of these, if dissolved in 1.0 l of pure water, would produce a buffer solution? 0.1 mol nah2po4 + 0.1 mol na2hpo4 0.1 mol h3o+ + 0.1 mol cl- 0.1 mol hcl + 0.1 mol naoh 0.1 mol h3o+ + 0.1 oh- 0.1 mol nacl + 0.1 mol kcl?

Answers

Answer:

(0.1 mol NaH₂PO₄ + 0.1 mol Na₂HPO₄)

Explanation:

A buffer solution is an aqueous solution consisting of a mixture of a weak acid and its conjugate base, or weak base and its conjugate acid.

Also, a buffer solution is a solution which resists changes in pH when acid or alkali is added to it.

(0.1 mol NaH₂PO₄ + 0.1 mol Na₂HPO₄) when dissolved in 1 L H₂O will produce a buffer because NaH₂PO₄ is considered as weak acid while Na₂HPO₄ is its conjugate base. 2.(0.1 mol H₃O⁺ + 0.1 mol Cl⁻) is not a mixture of a weak acid and its conjugate base, or weak base and its conjugate acid.(0.1 mol HCl + 0.1 mol NaoH) HCL is a strong acid and NaOH is a strong base so it will not form a buffer when dissolved in water. (0.1 mol H₃O⁺ + 0.1 OH⁻) is not a mixture of a weak acid and its conjugate base, or weak base and its conjugate acid(0.1 mol NaCl+ 0.1 mol KCl) NaCL and KCL are salts so it will not form a buffer when dissolved in water.

So the right choice is

(0.1 mol NaH₂PO₄ + 0.1 mol Na₂HPO₄)

Final answer:

A combination of 0.1 mol NaH2PO4 and 0.1 mol Na2HPO4 would produce a buffer solution.

Explanation:

A buffer solution is a solution that resists changes in pH when small amounts of acid or base are added. To form a buffer solution, we need a weak acid and its conjugate base (or a weak base and its conjugate acid) in roughly equal amounts.

Out of the given options, the combination of 0.1 mol NaH2PO4 and 0.1 mol Na2HPO4 would produce a buffer solution. NaH2PO4 is a weak acid and Na2HPO4 is its conjugate base. Together, they can maintain the pH of the solution.

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How is plant photosynthesis and human respiration a example of zero waste world

Answers

Photosynthesis will produce oxygen gas that will be taken up by humans for respiration. Respiration will produce carbon dioxide that will be taken up by plants for photosynthesis. So both waste products will be recycled and reused so therefore an example of zero waste world

Answer:

On the one hand the human being when breathing consume oxygen and returns carbon dioxide to the environment, which for human respiration would be waste, instead the absorbent plant said carbon dioxide to transform it into nutrients through photosynthesis and as a danger releases oxygen, the which as we said before is used by the human being in his breathing. This concludes a sustainability cycle with zero waste.

Explanation:

Photosynthesis is a process that develops in two stages:

Light reactions: it is a light-dependent process (clear stage), it requires light energy to manufacture ATP and NADPH reduced energy carrier molecules, to be used in the second stage.

Calvin-Benson cycle: it is the independent stage of light (dark stage), the products of the first stage plus CO2 are used to form the C-C bonds of carbohydrates. Dark stage reactions usually occur in the dark if energy transporters from the light stage are present. Recent evidence suggests that the most important enzyme of the dark stage is indirectly stimulated by light, if so the term would not be correct to call it "dark stage". The light stage occurs in the grana and the dark one in the stroma of the chloroplasts.

Human breathing

In breathing, a vital process for life, the oxygen from the inhaled air enters the blood, and carbon dioxide - a waste gas from the metabolism of nutrients - is exhaled into the atmosphere.

The exchange of these gases takes place when the air reaches the pulmonary alveoli. These small sacs are surrounded by blood capillaries. The air diffuses through these cells to reach the interior of the blood capillaries, which transport oxygen-rich air to the heart to be distributed throughout the body. At the same time, in the alveoli the gaseous carbon dioxide diffuses from the blood into the lung and is exhaled.

Why does grinding solid crystals increase the rate of dissolving for a solid solute in water? smaller crystals are more polar. smaller crystals are more nonpolar. smaller crystals have more energy. smaller crystals have more surface area. none of the above?

Answers

Answer:

The answer is...

Explanation:

Smaller crystals have more surface area.

How many moles of co2 are there in a 50.0 dm3 sample of the gas at a pressure of 100.0 kpa and a temperature of 50°c?

Answers

Answer:

1.86 moles

Explanation:

The equation you need to use is PV = nRT, where n is the value you are searching for.

P = 100.0 kPA

V = 50.0 dm^3

n = ?

R = 8.314

T = 50 celsius converted to kelvin (323 k)

Multiply the pressure times the volume (100*50) and divide it by the constant (R) by the temperature (8.314*323).

(100*50) / (8.314*323) = 5000 / 2685.422  = 1.86 moles

There are 1.19 moles of CO2 in the given sample.

To determine the number of moles of CO2 in the sample, we can use the ideal gas law, which is given by:

[tex]\[ PV = nRT \][/tex]

where:

- [tex]P[/tex] is the pressure of the gas,

- [tex]V[/tex] is the volume of the gas,

- [tex]n[/tex] is the number of moles of the gas,

- [tex]R[/tex] is the ideal gas constant, and

- [tex]T[/tex] is the temperature of the gas in Kelvin.

 First, we need to convert the temperature from degrees Celsius to Kelvin:

[tex]\[ T(K) = T(°C) + 273.15 \][/tex]

[tex]\[ T(K) = 50°C + 273.15 = 323.15 K \][/tex]

Next, we need to ensure that the volume is in cubic meters [tex](m^3)[/tex] since the standard units for the ideal gas constant [tex]R[/tex] are [tex]J/(mol*K)[/tex]when pressure is in pascals [tex]Pa[/tex] and volume is in cubic meters. Note that 1 [tex]dm^3[/tex] is equivalent to 0.001 m³:

[tex]\[ V = 50.0 \text{ dm}^3 \times \frac{0.001 \text{ m}^3}{1 \text{ dm}^3} = 0.0500 \text{ m}^3 \][/tex]

 Now we can plug in the values into the ideal gas law equation:

[tex]\[ n = \frac{PV}{RT} \][/tex]

[tex]\[ n = \frac{(100.0 \text{ kPa} \times \frac{1000 \text{ Pa}}{1 \text{ kPa}})(0.0500 \text{ m}^3)}{(8.314 \text{ J/(mol·K)})(323.15 \text{ K})} \][/tex]

[tex]\[ n = \frac{(100,000 \text{ Pa})(0.0500 \text{ m}^3)}{(8.314 \text{ J/(mol·K)})(323.15 \text{ K})} \][/tex]

[tex]\[ n = \frac{5000 \text{ J}}{2684.8695 \text{ J/(mol)}} \][/tex]

[tex]\[ n \approx 1.19 \text{ moles} \][/tex].

 Therefore, there are approximately 1.19 moles of CO2 in the 50.0 dm³ sample at a pressure of 100.0 kPa and a temperature of 50°C.

What is the name of the scientist famous for their pioneering research on radioactivity?

Percy L. Julian

Max Planck

Albert Einstein

Marie Curie

Answers

Answer:

marie curie

Explanation:

It is Marie Curie who is a famous scientist for her research on radioactivity...

At standard temperature and pressure, 1 mole of gas has what volume? A. 2.4 liters B. 22.4 liters C. 42.4 liters D. 76.6 liters

Answers

Answer: B.22.4 liters

Explanation:

When we attribute to a certain fixed mass of a given gas a fixed number of molecules. Avogadro considered that the mass of 36g of oxygen at any temperature and pressure would have a fixed number of molecules to which he called 1 mol of molecules. So by definition 1 mole of molecules would have a number of molecules equal to that present in 36 g of oxygen. The occupied volume by one mole of molecules at a given temperature and pressure is called molar volume and consists in 22,4 Liters. The molar volume matches the Avogadro Hypothesis (created in 1811 by Amedeo Avogadro), where equal volumes of different gases, at the same temperature and pressure, have even number of moles.

Final answer:

At standard temperature and pressure (STP), 1 mole of any gas will occupy a volume of 22.4 liters. This is a universal truth for all ideal gases.

Explanation:

The volume of 1 mole of any gas at standard temperature and pressure (STP) is defined by Avogadro's law. According to this law, the volume of 1 mole of gas at STP is 22.4 liters. Therefore, the correct answer to your question is B. 22.4 liters. This applies to all ideal gases, assuming that temperature is 0°C and pressure is 1 atmosphere.

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Which would expect bleach to have?

A high concentration of hydronium ions

A high concentration of hydroxyl ions

A high concentration of hydrogen ion

A low concentration of all kinds of ions

Answers

The correct answer would be B. high concentration of hydroxyl ions, as bleach has a basic pH of about 13.

Hope this helps:)

A solution's hydronium ion concentration must fall as the concentration of hydroxide ions rises. In this instance, [H3O+] [OH-], and the remedy is regarded as basic. A high concentration of hydroxyl ions would expect bleach to have.

What is hydroxyl ion ?

The chemical term for the diatomic anion OH is hydroxide. Other names for hydrogen dioxide include hydroxyl, hydroxyl radical, and hydroxide ion. It is made up of an atom of hydrogen and one of oxygen that are joined together by a covalent bond. A negative electric charge is present in the hydrogen.

A diatomic anion with the chemical formula OH is hydrogen oxide. It has a negative electric charge and is made up of two atoms of oxygen and hydrogen that are bound together by a single covalent bond.

A basic solution and a large concentration of hydroxide ions are indicated by a low pOH value.

Thus, option B is correct.

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What is the strongest interparticle force in a sample of solid mgcl2?

Answers

Answer: The strongest inter particle force in [tex]MgCl_2[/tex] is electrostatic force of attraction.

Explanation:

Magnesium chloride is an ionic compound which is formed by the combination of magnesium ions and chloride ions.

Ionic compounds are defined as the compounds which are formed by the complete transfer of electrons from one atom to another atom.

In these compounds, oppositely charged ions are attracted towards each other to form a compound.

The attraction between oppositely charged species is very strong and is known as electrostatic force of attraction.

Hence, the strongest inter particle force in [tex]MgCl_2[/tex] is electrostatic force of attraction.

PLEASE HELP, CHEMISTRY!!! 20 POINTS!!!

Balance the following redox equation using the oxidation-number-change method. Describe each step you use to balance the reaction.

HCl(aq) + Zn(s) ZnCl2(s) + H2(g)

Answers

the answer is in the picture

Answer: 2HCL (aq) + ZN(s) ZnCl2(s) = H2(g)

Explanation:

In the reaction of magnesium with oxygen, explain which atom is the reducing agent.

Show ALL steps.

Answers

Answer:

Mg.

Explanation:

The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).An oxidizing agent, or oxidant, gains electrons and is reduced in a chemical reaction. Also known as the electron acceptor, the oxidizing agent is normally in one of its higher possible oxidation states because it will gain electrons and be reduced.A reducing agent (also called a reductant or reducer) is an element (such as calcium) or compound that loses (or "donates") an electron to another chemical species in a redox chemical reaction.For the reaction:

Mg + 1/2O₂ → MgO.

Mg is oxidized to Mg²⁺ in (MgO) (loses 2 electrons). "reducing agent".

O is reduced to O²⁻ in (MgO) (gains 2 electrons). "oxidizing agent".

Which is a balanced chemical equation? A. C7H16 + 5O2 6CO2 + 4H2O B. C7H16 + 11O2 7CO2 + 8H2O C. C7H16 + 14O2 7CO2 +5H2O D. C7H16 + 22O2 14CO2 + 16H2O

Answers

Answer:

[tex]\boxed{\text{B.}}[/tex]

Explanation:

B.

[tex]\rm C$_7$H_{16}$ + 11O$_2$ $\longrightarrow \,$ 7CO$_2$ + 8H$_2$O[/tex]

BALANCED. 7C, 16H, and 22O on each side of equation.

A.

[tex]\rm C$_7$H$_{16}$ + 5O$_2$ $\longrightarrow \,\rm 6CO$_2$ + 4H$_2$O[/tex]

NOT BALANCED. 7C on left and 6C on right.

C.

[tex]\rm C$_7$H$_{16}$ + 14O$_2$ $\longrightarrow \,$ 7CO$_2$ + 5H$_2$O[/tex]

NOT BALANCED. 16H on left and 10H on right.

D.

[tex]\rm C$_7$H$_{16}$ + 22O$_2$ $\longrightarrow \, $ 14CO$_2$ + 16H$_2$O[/tex]

NOT BALANCED. 7C on left and 14C on right.

Can anybody check my answer?
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A given mass of air has a volume of 10.00L at 100kPa. What volume will it occupy at 50kPa if the temperature does not change?

Five moles of a gas occupies 20L of space with a pressure of 101.3kPa. What is the temperature of the gas?

Answers

Answer:

[tex]\boxed{\text{25. 20 L; 26. 49 K}}[/tex]

Explanation:

25. Boyle's Law

The temperature and amount of gas are constant, so we can use Boyle’s Law.

[tex]p_{1}V_{1} = p_{2}V_{2}[/tex]

Data:

[tex]\begin{array}{rcrrcl}p_{1}& =& \text{100 kPa}\qquad & V_{1} &= & \text{10.00 L} \\p_{2}& =& \text{50 kPa}\qquad & V_{2} &= & ?\\\end{array}[/tex]

Calculations:

[tex]\begin{array}{rcl}100 \times 10.00 & =& 50V_{2}\\1000 & = & 50V_{2}\\V_{2} & = &\textbf{20 L}\\\end{array}\\\text{The new volume will be } \boxed{\textbf{20 L}}[/tex]

26. Ideal Gas Law

We have p, V and n, so we can use the Ideal Gas Law to calculate the volume.

pV = nRT

Data:  

p = 101.3 kPa

V = 20 L

n = 5 mol

R = 8.314 kPa·L·K⁻¹mol⁻¹

Calculation:

101.3 × 20 = 5 ×  8.314 × T

2026 = 41.57T

[tex]T = \dfrac{2026}{41.57} = \textbf{49 K}\\\\\text{The Kelvin temperature is }\boxed{\textbf{49 K}}[/tex]

Two vessels are labeled A and B. Vessel A contains NH3 gas at 70°C, and vessel B contains He gas at the same temperature. If the average kinetic energy of NH3 is 7.1x10^(-21) J/molecule, calculate the mean-square speed of He atoms in m^2/s^2.

Answers

Answer:

v² = 2.14 × 10⁶ m²/s²

Explanation:

1) Since the average kinetic energy of a gas is only dependent on its temperature, you conclude that, at the same temperature of 70°C, the average kinetic energy of He atoms is the same that the average kinetic energy of NH₃ molecules: 7.1 × 10⁻²¹ J / molecule.

2) Now, you can use the equation that relates the average kinetic energy with the mean-square speed:

KE avg = (1/2)mv²

Where:

Ke avg is the average kinetic energy,m is the mass, andv² is the mean-square speed.

You need to use the atomic mass of helium to find the mass (average) of one atom of helum:

Atomic mass of helium: 4.003 g / molaverage mass of 1 atom:

        m = 4.003 g/ mol / (6.022 × 10²³ atoms/mol)

        m = 6.647 × 10⁻²⁴ g = 6.647 10 ⁻²⁷ kg / atom

3) Solve for v², substitute, and compute:

Note: since He is a monoatomic molecule, kg/atom = kg/molecule.

KE avg = (1/2)mv² ⇒ v² = 2KE avg / m

v² = 2 × 7.1 × 10⁻²¹ J/ molecule /  (6.647 × 10 ⁻²⁷ kg / molecule)

            = 2.14 × 10⁶ m²/s² ← answer

In the past, investigators would look at which two types of cues when trying to determine if someone was lying?


Biased and unbiased


Verbal and non-verbal


Quiet and loud


Simple and complex

Answers

Verbal and nonverbal.

They would look for shakiness of the voice (verbal) or darting eyes (nonverbal), and other things to that same effect.

Answer : Verbal and non-verbal communication wad used by Investigators in the past when trying to determine if someone was lying.

Explanation: In the Verbal communication information is transferred from one person to other by speaking.

Non-verbal communication includes Facial expressions , eye contact , body language, eyes blinking etc.

If someone is lying he or she will easily dermined by applying above things.

Every day, about 1 4 0 , 0 0 0 , 0 0 0 140,000,000140, comma, 000, comma, 000 plastic water bottles are bought in the United States. Each bottle is about 0 . 2 5 0.250, point, 25 meters long, and the equator of the Earth is about 4 0 , 0 0 0 , 0 0 0 40,000,00040, comma, 000, comma, 000 meters around. How many times can the Earth's equator be circled by a line of plastic bottles used in the United States every day?

Answers

Answer:

0.875 time.

Explanation:

The length of plastic water bottles are bought in the United States every day = (the no. of plastic water bottles are bought every day)(length of each bottle) = (140.0 million bottle)(0.25 m) = 35.0 million meter.

The length of the equator of the earth = 40.0 million meter.

∴ The times can the Earth's equator be circled by a line of plastic bottles used in the United States every day = (The length of plastic water bottles are bought in the United States every day)/(The length of the equator of the earth) = (35.0 million meter)/(40.0 million meter) = 0.875 times.

Which of the following best represents the reaction between sulfuric acid and calcium hydroxide? f H2SO4 + 2Ca(OH)2 → 2CaSO4 + 3H2O g H2SO4 + Ca(OH)2 → CaSO4 + 2H2O h HSO4 + CaOH → CaSO4 + H2O j H2SO4 + Ca(OH)2 → CaSO4 + H2O

Answers

Answer:

g. H₂SO₄ + Ca(OH)₂ → CaSO₄ + 2H₂O.

Explanation:

Sulfuric acid is represented as H₂SO₄ and calcium hydroxide is represented as Ca(OH)₂.

To balance a chemical reaction. we should apply the law of conservation of mass that the no. of different atoms in both sides (reactants and products).

The only choice that represent the reactants correctly and apply the law of conversation of mass is:

g. H₂SO₄ + Ca(OH)₂ → CaSO₄ + 2H₂O.

f. H₂SO₄ + 2Ca(OH)₂ → 2CaSO₄ + 3H₂O

is not correct that the no. of S, and O is not equal in both reaction sides.

S in reactants (1) while in products (2).

O in reactants (8) while in products (11).

h. HSO₄ + CaOH → CaSO₄ + H₂O

The reactants is represented in a wrong way.

j. H₂SO₄+ Ca(OH)₂ → CaSO₄ + H₂O

is not correct that the no. of H and O is not equal in both reaction sides.

H in reactants (4) while in products (2).

O in reactants (6) while in products (5).

So, the right choice is: g. H₂SO₄ + Ca(OH)₂ → CaSO₄ + 2H₂O.

The correct balanced equation for the reaction between sulfuric acid  and calcium hydroxide is: H₂SO₄ + 2Ca(OH)₂ → CaSO₄ + 2H₂O

This equation represents a neutralization reaction between an acid (sulfuric acid) and a base (calcium hydroxide). In this reaction, sulfuric acid reacts with calcium hydroxide to produce calcium sulfate and water.

The stoichiometric coefficients in front of each compound indicate the balanced ratio of reactants and products.

According to the equation, for every 1 molecule of sulfuric acid, 2 molecules of calcium hydroxide. This is because sulfuric acid is a diacid, meaning it can donate two hydrogen ions (H+) per molecule.

To learn more about the balanced equation, follow the link:

https://brainly.com/question/7181548

#SPJ6

Determine the identity of X in the following alpha decay equation (please help)

Answers

Answer:

At-207 (meaning At with the number on the top left being 207 and the number at the bottom left being 85.

Explanation:

The sum of the mass numbers has to equal on both sides, so we need 211 = 4+a

a=207

The sum of the atomic numbers as to equal on both sides, so 87=2+b

b=85

The element is determined by the mass number.

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