Please help!!!!!!!!!!

answer for this question is (d)3x2-x+6

This is the answer:)

The last ones answer is six

Answer:

Explanation:

To solve log (−5.6x + 1.3) = −1 − x graphycally, you must graph this system of equations on the same coordinate plane:

1) To graph the equation 1 you can use these features of logarithmfunctions:

        log ( -5.6x + 1.3) = 0 ⇒ -5.6x + 1.3 = 1 ⇒x = 0.3/5.6 ≈ 0.054

       x = 0 ⇒ log (0 + 1.3) = log (1.3) ≈ 0.11

        x            log (-5.6x + 1.3)

        -1           0.8

        -2           1.1

        -3           1.3

2) Graphing the equation 2 is easier because it is a line: y = - 1 - x

3) The solution or solutions of the equations are the intersection points of the two graphs. So, now the graph method just requires that you read the x coordinates of the intersection points. From the least to the greatest, rounded to the nearest tenth, they are:

Answer:

x = -2.1

& .2

Step-by-step explanation:

Answer:

D

Step-by-step explanation:

Substitute x = g(x) into f(x)

f(2x + 3) = (2x + 3)² ← expand factors

f(g(x)) = (2x)² + 6x + 6x + 3² = 4x² + 12x + 9 → D

Do what? I can't see a question

repost and let me know once it’s up because I can’t see the picture

Good luck,

:)

ANSWER

D. 13

EXPLANATION

The given function is:

[tex]f(x) = \frac{2x + 1}{x -4} [/tex]

Let

[tex]y = \frac{2x + 1}{x -4} [/tex]

Interchange x and y.

[tex]x= \frac{2y + 1}{y-4} [/tex]

Solve for y.

[tex]x(y - 4)=2y + 1[/tex]

[tex]xy - 4x=2y + 1[/tex]

[tex]xy - 2y = 1 + 4x[/tex]

[tex](x - 2)y = 1 + 4x[/tex]

[tex]y = \frac{1 + 4x}{x - 2} [/tex]

[tex] {f}^{ - 1}(x) = \frac{1 + 4x}{x - 2} [/tex]

We put x=3,

[tex]{f}^{ - 1}(3) = \frac{1 + 4 \times 3}{3- 2}[/tex]

[tex]{f}^{ - 1}(3) = \frac{13}{1} = 13[/tex]

Answer:

the person above me is correct

Step-by-step explanation:

by the way its 8 because 24 words divided by 4 weeks is 8.

The unit rate describing Alan's vocabulary acquisition is 6 words per week.

The unit rate that describes the situation where Alan learned 24 new vocabulary words in 4 weeks is 6 words per week.

To find the unit rate, divide the total number of words learned by the total number of weeks. In this case, 24 words / 4 weeks = 6 words per week.

Answer:

4a + 2b + 1/4 c.

Step-by-step explanation:

1/4(16a+8b+c)

= 1/4 * 16a + 1/4 * 8b + 1/4 * c

= 4a + 2b + 1/4 c.

Final answer:

To apply the distributive property to the expression 1/4(16a+8b+c), we distribute the 1/4 to each term inside the parentheses and simplify the expression.

Explanation:

To apply the distributive property to the expression 1/4(16a+8b+c), we distribute the 1/4 to each term inside the parentheses. This means multiplying 1/4 by 16a, 1/4 by 8b, and 1/4 by c. The distributive property states that a (b + c) = ab + ac. So, the expression becomes:

1/4(16a) + 1/4(8b) + 1/4(c)

Since 1/4 times any number equals the number divided by 4, we can simplify further:

(16a/4) + (8b/4) + (c/4)

Which simplifies to:

4a + 2b + c/4

Answer:

Hello cheaters lol jk, Answer is B.  

Step-by-step explanation:

more interest equals more money, if you divide the amount of the house by 6% and do the same for the other by 5, the amount for B is greater.  

The House A is more worth than House B .

Compound interest is an interest accumulated on the principal and interest together over a given time period. The interest accumulated on a principal over a period of time is also accounted under the principal.

Formula of Compound interest :

[tex]A = P (1+\frac{r}{100} )^{n}[/tex]

Where,

A = Final amount

P = initial principal

r = rate per annum

n = Time in years

According to the question

House A:

Principal = 125260

Rate = 5%

Time in years = 2

Applying Formula of Compound interest for final amount

[tex]A = P (1+\frac{r}{100} )^{n}[/tex]

[tex]A = 125260 (1+\frac{5}{100} )^{2}[/tex]

[tex]A = 125260 (1.05)^{2}[/tex]

A = 138,099.15

House B:

Principal = 120160

Rate = 6%

Time in years = 2

Applying Formula of Compound interest for final amount

[tex]A = P (1+\frac{r}{100} )^{n}[/tex]

[tex]A = 120160 (1+\frac{6}{100} )^{2}[/tex]

[tex]A = 120160(1.06)^{2}[/tex]

A = 135,011.776

Hence , House A is more worth than House B .

To know more about Compound interest  here:

https://brainly.com/question/14295570

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Answer:

im pretty sure its the first one

Answer with explanation:

When the size of Preimage is greater than size of Image than dilation factor will be less than 1 and greater than zero.

And, when Size of preimage is greater than Size of Image than dilation factor will be greater than 1.

In the given diagram

Size of Preimage > Size of Image

Dilation Factor=0 <Dilation factor <1

Option A: It has a scale factor between zero and one and is a reduction.

Answer:

Domain = Range =  All real numbers

Step-by-step explanation:

To quickly solve this problem, we can use a graphing tool or a calculator to plot the equation.

Please see the attached image below, to find more information about the graph

The equation is:

f(x)=2x+cos x

From the plot, we can see the answer is

Option a.

Domain = Range = (-∞,∞)

Answer: a

Step-by-step explanation:

right on edg

The value of ∑n=14[100(−4)n−1] is -5368709100

The sequence is given as:

∑n=14[100(−4)n−1]

The above sequence is a geometric sequence, with the following properties

The sum of n terms of a geometric series is:

[tex]S_n = \frac{a* (r^n - 1)}{r - 1}[/tex]

So, we have:

[tex]S_n = \frac{100* ((-4)^{14} - 1)}{-4 - 1}[/tex]

Evaluate

[tex]S_{14} = -5368709100[/tex]

Hence, the value of ∑n=14[100(−4)n−1] is -5368709100

Read more about geometric series at:

https://brainly.com/question/24643676

The sum [tex]\(\sum_{n=1}^4 [100(-4)^{n-1}]\)[/tex] is [tex]\[\boxed{-5100}\][/tex]

To find the sum [tex]\(\sum_{n=1}^4 [100(-4)^{n-1}]\),[/tex] we will calculate the individual terms of the sequence and then sum them up.

The general term of the sequence is [tex]\(100(-4)^{n-1}\)[/tex]. Let's compute the terms from [tex]\(n = 1\) to \(n = 4\):[/tex]

1. For [tex]\(n = 1\):[/tex]

[tex]\[ 100(-4)^{1-1} = 100(-4)^0 = 100 \cdot 1 = 100 \][/tex]

2. For [tex]\(n = 2\):[/tex]

[tex]\[ 100(-4)^{2-1} = 100(-4)^1 = 100 \cdot (-4) = -400 \][/tex]

3. For [tex]\(n = 3\):[/tex]

[tex]\[ 100(-4)^{3-1} = 100(-4)^2 = 100 \cdot 16 = 1600 \][/tex]

4. For [tex]\(n = 4\):[/tex]

[tex]\[ 100(-4)^{4-1} = 100(-4)^3 = 100 \cdot (-64) = -6400 \][/tex]

Now, let's sum these terms:

[tex]\[100 + (-400) + 1600 + (-6400)\][/tex]

Perform the calculations step-by-step:

1. [tex]\(100 - 400 = -300\)[/tex]

2. [tex]\(-300 + 1600 = 1300\)[/tex]

3. [tex]\(1300 - 6400 = -5100\)[/tex]

Answer:

option B

Step-by-step explanation:

Step 1

A + B = C

[tex]A=\left[\begin{array}{ccc}8&-3\\3&y+2\end{array}\right][/tex][tex]+B=\left[\begin{array}{ccc}3x&z+4\\w&1/2y\end{array}\right][/tex]

=

[tex]C=\left[\begin{array}{ccc}x&2z\\4&y\end{array}\right][/tex]

Step 2

[tex]\left[\begin{array}{ccc}8+3x&-3+z+4\\3+w&y+2+y/2\end{array}\right][/tex][tex]=\left[\begin{array}{ccc}x&2z\\4&y\end{array}\right][/tex]

Step 3

4 equations are form

Equation 1

8 + 3x = x

8 = -2x

x = -4

Equation 2

-3 + z + 4 = 2z

1 + z = 2z

1 = z

z = 1

Equation 3

3 + w = 4

w = 1

Equation 4

y + 2 + y/2 = y

2 + y/2 = 0

4 + y = 0

y = -4

Step 4

[tex]\left[\begin{array}{ccc}3(-4)&1+4\\1&1(-4)/2\end{array}\right][/tex]

[tex]\left[\begin{array}{ccc}-12&5\\1&-2\end{array}\right][/tex]

Answer:

B

Step-by-step explanation:

I got 100% on EDGE 2020 Unit test

4x➕6(503-x)=2296

Distribute the 6 into the parentheses

Let x represent the students

503-x will represent the non-students

4x➕3018➖6x=2296

Then combine like terms

-2x➕3018=2296

Now since you move your constant your sign has to change as well,

-2x=2296➖3018

Then subtract

-2x=-722

Then divide both sides by -2

You are left with x=361

This represents the students

503➖361= 142 which equal the non-students

Therefore your answer is:

361=students

142=non-students

Hope this helps! :3

Answer:

361 students and 503-361=142 non students

Step-by-step explanation:

Let x = number of students. And 503-x = the number of non students. Therefore, 4x+6(503-x)=2296

Answer:

  B) x^2/12 +y^2/16 = 1

Step-by-step explanation:

The distance from focus to covertex is the same as the distance from the center to the vertex: 4. So, the Pythagorean theorem tells you ...

  a^2 + 2^2 = b^2

  a^2 +4 = 4^2 = 16

  a^2 = 16 -4 = 12

So, the standard-form equation ...

  x^2/a^2 +y^2/b^2 = 1

looks like this when the values are filled in:

  x^2/12 +y^2/16 = 1

Answer:

Option A

Option C

Step-by-step explanation:

A relationship is defined as a function if and only if each element of the "domain" set is assigned only one element of the "range" set. That is, there is only one output value y assigned to each input value x.

The relation x = 3 is not a function because there are infinite output values y, assigned to the same input element x.

(3, 2), (3, 5) (3, 9) (3,10000)

Then the option A is true

Option C is also true, the equation of the line shown is

[tex]x = 3[/tex]

The rest of the options are false because x = 3 is not a function

Answer:

983497

step-by-step explanation:

The sum formula of arithmetic sequence is given by:

[tex]S_n = \frac{n}{2}(2a_1 +(n - 1)d[/tex]

a_1 is the first term, n is the nth term and d is the common difference

From the given information

[tex]d = - 1 -( - 5) = - 1 + 5 = 4[/tex]

[tex]a_1 = - 5 \: and \: n = 703[/tex]

By substitution we obtain:

[tex]S_{703}= \frac{703}{2}(2( - 5) +(703- 1)4)[/tex]

[tex]S_{703}= \frac{703}{2}( - 10 + 2808)[/tex]

[tex]S_{703}= \frac{703}{2}(2798)[/tex]

[tex]S_{703}=98397[/tex]

Answer:

S = 983,497

Step-by-step explanation:

We are given the following sequence and we are to find the sum of the first 703 terms of this sequence:

[tex]-5, -1, 3, 7, ...[/tex]

Finding the common difference [tex]d[/tex] = [tex]-1-(-5)[/tex] = [tex]4[/tex]

[tex]a_1=-5[/tex]

[tex]a_n=?[/tex]

[tex]a_n=a_1+(n-1)d[/tex]

[tex] a_n = - 5 + ( 7 0 3 - 1 ) 4 [/tex]

[tex] a _ n = 2803 [/tex]

Finding the sum using the formula [tex]S_n = \frac{n}{2}(a_1+a_n)[/tex].

[tex]S_n = \frac{703}{2}(-5+2803)[/tex]

S = 983,497

Answer:

slope=-1/4

Step-by-step explanation:

point 1: -4,-1

point 2: 0,-2

y1-y2/x1-x2

1/-4

-1/4

That is 99 degrees if you have the triangle facing the other way

the measure of angle KJL is [tex]\( 40^\circ \)[/tex].

Given information

[tex]\( m(KP) = 2 \cdot m(IP) \)\\\( m(IVK) = 120^\circ \)[/tex]

Using the fact that the sum of angles in a circle is [tex]\( 360^\circ \)[/tex], we have:

[tex]\[ m(KP) + m(IP) + m(IVK) = 360^\circ \][/tex]

Substituting the given values:

[tex]\[ 2 \cdot m(IP) + m(IP) + 120^\circ = 360^\circ \][/tex]

Solving for [tex]\( m(IP) \)[/tex]:

[tex]\[ 3 \cdot m(IP) = 360^\circ - 120^\circ \]\[ 3 \cdot m(IP) = 240^\circ \]\[ m(IP) = \frac{240^\circ}{3} \]\[ m(IP) = 80^\circ \][/tex]

Finding [tex]\( m(KP) \)[/tex]:

[tex]\[ m(KP) = 2 \cdot m(IP) = 2 \cdot 80^\circ = 160^\circ \][/tex]

Using the angle formed by a tangent and a secant theorem, we can find [tex]\( m(\angle KJL) \)[/tex]:

[tex]\[ m(\angle KJL) = \frac{1}{2} (m(KP) - m(IP)) \][/tex]

Substituting the known values:

[tex]\[ m(\angle KJL) = \frac{1}{2} (160^\circ - 80^\circ) \]\[ m(\angle KJL) = \frac{1}{2} (80^\circ) \]\[ m(\angle KJL) = 40^\circ \][/tex]

Therefore, the measure of angle KJL is [tex]\( 40^\circ \)[/tex].

The complete question is:

given:  [tex]\( m(KP) = 2 \cdot m(IP) \)\\[/tex] and [tex]\( m(IVK) = 120^\circ \)[/tex]

find: m∠KJL.

Answer:

The answer is -8.

Step-by-step explanation:

C. If a<0, then the parabola opens down

Answer:

c. 1 and 3

Step-by-step explanation:

To quickly solve this problem, we can use a graphing tool or a calculator to plot each equation.

Please see the attached image below, to find more information about the graph s

The equations are:

1) y = sin (3x + π/6)

2) y = cos (3x - π/6)

3) y = cos (3x - π/3)

Looking at the graphs, we can see that the identical ones

are equations one and three

Correct option:

c. 1 and 3

The correct option is:

             option: c     c.   1 and 3

The first trignometric function is given by:

     [tex]y=\sin (3x+\dfrac{\pi}{6})[/tex]

and also we know that:

[tex]\sin \theta=\cos(\dfrac{\pi}{2}-\theta)[/tex]

This means that:

[tex]\sin (3x+\dfrac{\pi}{6})=\cos (\dfrac{\pi}{2}-(3x+\dfrac{\pi}{6})\\\\\\\sin (3x+\dfrac{\pi}{6})=\cos (\dfrac{\pi}{2}-3x-\dfrac{\pi}{6})\\\\\\\sin (3x+\dfrac{\pi}{6})=\cos (\dfrac{\pi}{2}-\dfrac{\pi}{6}-3x)\\\\\\\sin (3x+\dfrac{\pi}{6})=\cos (\dfrac{2\pi}{6}-3x)\\\\\\\sin (3x+\dfrac{\pi}{6})=\cos (\dfrac{\pi}{3}-3x)\\\\\\\sin (3x+\dfrac{\pi}{6})=cos (-(3x-\dfrac{\pi}{3}))[/tex]

As we know that:

[tex]\cos (-\theta)=cos(\theta)[/tex]

Hence, we have:

[tex]\sin (3x+\dfrac{\pi}{6})=\cos (3x-\dfrac{\pi}{3})[/tex]

Also,  by the graph we may see that the graph of 1 and 2 function do not match.

Hence, they are not equivalent.

A function assigns the values. The temperature that will model most accurately predict the time spent cooling will be 300.

A function assigns the value of each element of one set to the other specific element of another set.

For the given function [tex]f(t)=349.2 (0.98)^t[/tex], the value of t which will lie within the given function range will be the value function that will model most accurately predict the time spent on cooling. Therefore, let's substitute the values and check,

A.) t = 0

[tex]f(t)=349.2 (0.98)^t\\\\0=349.2 (0.98)^t[/tex]

As the value of t will lie at infinite, therefore, this will not give an accurate prediction of the model.

B.) f(t) = 100

When the value of the function will be 100 then the value of t will be 61.6, therefore, this can not be the most accurate prediction.

C.) f(t) =300

When the value of the function will be 300 then the value of t will be 7.5, therefore, this is the most accurate prediction.

D) f(t) = 400

When the value of the function will be 400 then the value of t will be -6.724, therefore, this can not be the most accurate prediction.

Thus, the temperature that will model most accurately predict the time spent cooling will be 300.

Learn more about Function:

https://brainly.com/question/5245372

Answer:

[tex]4w^4-7z^4+6w^2z^2[/tex]

Step-by-step explanation:

We can reformat this equation so we can vertically add.

Then, we can just add down.

Since all the degrees and the variables are the same, we only have to worry about the coefficients.

5 - 1 = 4 --> [tex]4w^4[/tex]

-7 + 13 = 6 --> [tex]6w^2z^2[/tex]

-3 - 4 = -7 --> [tex]-7z^4[/tex]

Now let's rewrite this.

[tex]4w^4-7z^4+6w^2z^2[/tex]

Translations, rotations, and reflections are all rigid transformations.

Answer: 47+B(.85) = A

Step-by-step explanation:

One bagel = $0.85

Sold 47 today

One bagel(.85) = profit

A = profit

B = additional bagels

47+B(.85) = A

Answer:

[tex]f(x)=3^x[/tex]

Step-by-step explanation:

Given that the function is represented by the graph below, which  begins in the second quadrant near the x−axis and increases slowly while crossing the ordered pair 0, 1. When the graph enters the first quadrant, it begins to increase quickly throughout the graph

Because it passes through (0,1) it is of the form

[tex]y=a^x[/tex]

Also for negative x large it is very near x axis, So a must be positive then only it increases faster in the I quadrant.  Range is only posiitve real numbers

So the function is

[tex]f(x) =3^x[/tex]

Answer:

[tex]3,726\ m^{2}[/tex]

Step-by-step explanation:

step 1

Find the scale factor

we know that

If two figures are similar, then the ratio of its corresponding sides is equal to the scale factor

Let

z----> the scale factor

x----> corresponding side of the larger trapezoid

y----> corresponding side of the smaller trapezoid

[tex]z=\frac{x}{y}[/tex]

we have

[tex]x=64\ m[/tex]

[tex]y=12\ m[/tex]

substitute

[tex]z=\frac{64}{12}[/tex]

step 2

Find the area of the larger trapezoid

we know that

If two figures are similar, then the ratio of its areas is equal to the scale factor squared

Let

z----> the scale factor

x----> area of the larger trapezoid

y----> area of the smaller trapezoid

[tex]z^{2}=\frac{x}{y}[/tex]

we have

[tex]z=\frac{64}{12}[/tex]

[tex]y=131\ m^{2}[/tex]

substitute

[tex](\frac{64}{12})^{2}=\frac{x}{131}[/tex]

[tex]x=(\frac{4,096}{144})(131)[/tex]

[tex]x=3,726\ m^{2}[/tex]

Answer:

The measure of angle BCD is [tex]68.5\°[/tex]

Step-by-step explanation:

step 1

Find the value of x

In this problem

[tex]m<ABD+m<BCD+m<EDF=180\°[/tex] -----> is a straight line

substitute the values

[tex](3x+4)+(6x-8)+(7x-20)=180\°[/tex]

[tex](16x-24)=180\°[/tex]

[tex]16x=180\°+24\°[/tex]

[tex]x=12.75\°[/tex]

step 2

Find the measure of angle BCD

[tex]m<BCD+=(6x-8)\°[/tex]

substitute the value of x

[tex]m<BCD+=(6(12.75)-8)=68.5\°[/tex]

Answer:

[tex]\$17,500[/tex]

Step-by-step explanation:

Let

x----> that month's sales

y----> October earnings

we know that

[tex]8\%=8/100=0.08[/tex]

[tex]y=0.08x+1,400[/tex] -----> equation A

[tex]y=2,800[/tex] -----> equation B

Equate equation A and equation B and solve for x

[tex]2,800=0.08x+1,400[/tex]

[tex]0.08x=2,800-1,400[/tex]

[tex]x=1,400/0.08[/tex]

[tex]x=\$17,500[/tex]

Final answer:

The salesperson needs to earn an additional $1,400 on top of the base salary to meet the goal, which means they need to sell $17,500 worth of merchandise with an 8% commission rate.

Explanation:

To calculate the amount of merchandise the salesperson must sell to meet the goal of $2,800, we need first to understand how much more money is needed beyond the base salary. The salesperson receives a base salary of $1,400. Since the goal is $2,800, the additional amount needed from commission is $2,800 - $1,400 = $1,400.

With an 8% commission rate, we can set up an equation where the amount of merchandise sold (let's call it x) times the commission rate (0.08) equals the additional amount needed ($1,400). The equation is: 0.08x = $1,400. To find x, divide both sides by 0.08, therefore x = $1,400 / 0.08, which equals $17,500.

So, the salesperson will need to sell $17,500 worth of merchandise to meet the goal of earning $2,800 in October.