pls.. help me with this i really need it.. pls. A gas in a cylinder expands from a volume of 0.110 m3 to 0.320 m3. Heat flows into the gas just rapidly enough to keep the pressure constant at 1.65 x 105 Pa during the expansion. The total heat added is 1.15 x 105 J. (a) Find the work done by the gas. (b) Find the change in internal energy of the gas. (c) Does it matter whether the gas is ideal? Why or why not?

Correct answer choice is :

C) The freezing and melting temperatures of a substance are the same.

Explanation:

Fluids have a particular temperature at which they convert into solids, identified as their freezing point. In theory, the melting point of a solid should be the same as the freezing point of the liquid. In practice, small variations among these measures can be seen. The freezing point of a matter is the same as that substance's melting point. At this distinct temperature, the substance can exist as either a solid or a liquid. At temperatures below the freezing/ melting point, the substance is a solid.

Answer: The correct answer is "The freezing and melting temperatures of a substance are the same".

Explanation:

Freezing temperature: It is the temperature at which the liquid becomes the solid.

Melting temperature: It is the temperature at which the solid starts converted into liquid.

The freezing point of a substance is the same as the melting point of the substance. During melting and freezing of the substance, the temperature remains same as the energy is spent in changing the phase of the substance not in changing the temperature.

Latent heat is there. It is a hidden heat. It is required to change phase of the substance without showing temperature on thermometer.

Boiling temperature: It is the temperature at which liquid gets converted into vapors. At this temperature, vapor pressure of the liquid equals to the pressure surrounding the liquid.

To find the speed of the bicycle, we can consider the gearing ratio between the sprocket assemblies and the wheel. The speed in feet per second can be calculated using the cyclist's pedalling rate and the circumference of the wheel. We can use conversion factors to convert the speed to miles per hour.

In order to find the speed of the bicycle, we need to consider the gearing ratio between the sprocket assemblies and the wheel. The ratio of the radii of the sprocket assemblies and the wheel can be used to determine the wheel's rotational speed.

Let's say the cyclist is pedaling at a rate of 1 revolution per second on the sprocket assembly with a radius of 4 inches. The sprocket assembly is connected to another sprocket assembly with a radius of 2 inches, which is then connected to the wheel with a radius of 14 inches.

The ratio of the radii between the sprocket assembly and the wheel is 14/2 = 7.

Therefore, the speed of the bicycle in feet per second can be calculated by multiplying the cyclist's pedalling rate by the circumference of the wheel:

Speed (feet per second) = 1 revolution/second x 2π x 14 inches = 28π inches/second = 28π/12 feet/second

To find the speed of the bicycle in miles per hour, we can convert the speed from feet per second to miles per hour:

1 mile = 5280 feet and 1 hour = 3600 seconds, so:

Speed (miles per hour) = (28π/12 feet/second) x (5280 feet/1 mile) x (1 hour/3600 seconds)

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Answer:

The object has larger mass. Examples would be like-cars of a different build driving at the same mph, or animals that typically run at the same speed but have different weights.

Explanation:

The more inertia that an object has, the more mass that it has.

Answer: option 4: circuit one will have more current.

Explanation:

Ohm's law states that the current in a circuit is proportional to voltage.

[tex]I \propto V \\ \Rightarrow I=\frac{V}{R}[/tex]

Let the current in the first circuit be I, voltage be V and resistance be R, the,

[tex]I_1=\frac{V_1}{R_1}[/tex]

The voltage in the second circuit is

[tex]V_2=\frac{V_1}{2}[/tex]

The resistance in the second circuit is:

[tex]R_2=2R_1[/tex]

[tex]\Rightarrow I_2=\frac{V_2}{R_2}=\frac{V_1/2}{2R_1}=\frac{I_1}{4}[/tex]

Hence, circuit one has 4 times more current than circuit two.

Answer:

B

Explanation:

The VW Beetle takes 25.53 seconds to reach a speed of 60.0 mi/h with an acceleration of 2.35 m/s². The top-fuel dragster has an acceleration of 22.36 m/s² to go from 0 to 30 mi/h in 0.600 seconds.

To calculate the time it takes for the VW Beetle to reach a speed of 60.0 mi/h, we need to use the equation v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken. Rearranging the equation to solve for t, we have t = (v - u) / a. Plugging in the values, we get t = (60.0 mi/h - 0) / 2.35 m/s² = 25.53 s.

To find the acceleration of the top-fuel dragster, we use the equation a = (v - u) / t, where a is the acceleration, v is the final velocity, u is the initial velocity, and t is the time taken. Rearranging the equation to solve for a, we have a = (v - u) / t. Plugging in the values, we get a = (30 mi/h - 0) / 0.600 s = 50 mi/h/s = 22.36 m/s².

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The hydraulic pressure on sample is [tex]3.35*10^{7} N/m^{2}[/tex].

Hydraulic pressure is the force imparted per unit area of a liquid on the surfaces which it has contact.

The magnitude of force acting on the small cylinder is equal to [tex]F_{N}[/tex].

In static equilibrium, all the torques should add up to zero:[tex]F_{N}l - 270(2l)= 0\\F_{N} = 270(2)\\F_{N} = 540 N[/tex]

The pressure applied to the fluid (through the small cylinder):

[tex]P= \frac{540}{\pi (\frac{2*10^{-2} }{2} )^2}[/tex]

[tex]P = 1.71*10^{6} Pa[/tex]

The force of fluid on the large cylinder:

[tex]F= P\pi R^{3} \\F= 1.71*10^{6} \pi (0.05^{2} )\\F= 1.34*10^{4} N[/tex]

The pressure on the sample:

[tex]P_{S} =\frac{F}{A} \\P_{S}= \frac{1.34*10^{4} }{4*10^{-4} } \\P_{S}= 3.35*10^{7} N/m^{2}[/tex]

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Answer:

Speed is the distance an object travels within a specific unit of time, whereas acceleration is the rate at which the speed or direction of an object is changing.

(Apex) Pretest

The option that best describes the difference between speed and acceleration is : ( B ) Speed is the distance an object travels within a specific unit of time, whereas acceleration is the rate at which the speed or direction of an object is changing.

Acceleration is the rate of change of velocity with time while speed is the rate of change distance with time.

Acceleration is a vector quantity because it has magnitude and direction while speed is a scalar quantity.

Hence we conclude that Speed is the distance an object travels within a specific unit of time, whereas acceleration is the rate at which the speed or direction of an object is changing.

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The velocity of the toy car is 2m/s.

HOW TO CALCULATE VELOCITY:

Velocity (m/s) = Distance (m) ÷ time (s)

Velocity = 8m ÷ 4s

Velocity = 2m/s.

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Answer: elastic potential energy

Explanation:

The form of energy stored in the string of the bow is elastic potential energy. Elastic potential energy is the energy stored in an elastic object (such as the string of a bow) when the object is compressed/stretched by a certain amount x with respect to its natural length. The elastic potential energy stored in the object is given by

[tex]U=\frac{1}{2}kx^2[/tex]

where k is the spring constant of the elastic string, and x is the compression/stretching.

To find the range, maximum height, and speed at impact of a projectile fired with an initial speed of 500m/s and angle of elevation 30 degrees, we can use the equations of projectile motion.

To find the range, maximum height, and speed at impact of a projectile fired with an initial speed of 500m/s and angle of elevation 30 degrees, we can use the equations of projectile motion.

Range: The horizontal distance covered by the projectile is the range. In this case, we can use the formula:

R = (V02 * sin(2θ)) / g

where R is the range, V0 is the initial speed, θ is the angle of elevation, and g is the acceleration due to gravity.

Substituting the given values into the formula, we have:

R = (5002 * sin(2 * 30)) / 9.8

R = (250000 * sin(60)) / 9.8

R ≈ 1450.83 meters

Maximum Height: The maximum height reached by the projectile can be found using the formula:

H = (V02 * sin2(θ)) / (2 * g)

Substituting the given values into the formula:

H = (5002 * sin2(30)) / (2 * 9.8)

H ≈ 3060.45 meters

Speed at Impact: The speed at impact is the magnitude of the velocity of the projectile when it hits the ground. Since the projectile is fired at an angle and lands at a lower height than its initial position, the speed at impact will be lower than the initial speed. However, we need more information to calculate the exact speed at impact.

Answer: accelration=changespeed/changetime

changetime=8

changespeed=45-5=40

40/8=5

5m/s^2 is acceleration

Explanation:

Answer:

There are not enough neutrons to overcome the electrical repulsion of the protons.

Explanation:

Neutrons help stabilize a nucleus by attracting other nucleons (protons and neutrons). Although protons also attract other nucleons using the strong nuclear force, they repel other protons with the electrical force.

Hope this helps!

Answer:

If the racetrack’s length is 36 inches and is set to a height of 8 inches, 16 inches and 24 inches and each roll of the toy car is 7.8 seconds, 7.3 seconds and 6.6 seconds respectively, then, it only shows that the higher the racetrack, the faster the toy car will roll down because velocity, which measures how fast something is moving, is affected by gravity. Motion, as shown in this kind of scenario, is a kind of concept that depicts movement or change in position under given circumstances or factors over a period of time.

Explanation:

So,a)It will hit ground at 4.52seconds.b)At 145 ft/s fast is it going at the time of impact

An object is dropped from a 400-ft tower:

a) When does it hit the ground? Using the formula: time = [tex]\sqrt[1]{2*height/g}[/tex], where g is the acceleration due to gravity (32 ft/s²), the time taken to hit the ground is approximately 4.52 seconds.

b) How fast is it going at the time of impact? The velocity of the object when it hits the ground can be calculated as velocity = g * time, which gives a velocity of about 145 ft/s.

Answer: [tex]a=5 m/s^2[/tex]

Explanation:

The acceleration of an object can be calculated by using Newton's second law:

[tex]F=ma[/tex]

where

F is the net force applied on the object

m is the mass of the object

a is its acceleration

In this problem, we have F=125 N and m=25.0 kg, so we can rearrange the equation to calculate the acceleration:

[tex]a=\frac{F}{m}=\frac{125 N}{25.0 kg}=5 m/s^2[/tex]

Answer:

C). W = 50 J

Explanation:

As we know that the work done is the product of force and displacement

so here it is given that the net force on the stack of books is 25 N

[tex]F = 25 N[/tex]

also the displacement of the stack of books is 2m as it is lifted upwards

so we have

[tex]d = 2 m[/tex]

now by the formula of work done we know

[tex]W = F.d[/tex]

now plug in all values in it

[tex]W = (25)(2)[/tex]

[tex]W = 50 J[/tex]

On Mars, your mass would be 26.6 kg.

On Mars, the weight of an object is calculated by multiplying its mass by the acceleration due to gravity on Mars, which is approximately 0.38 times the acceleration due to gravity on Earth. Since your mass remains the same at 70 kg, the weight on Mars would be 70 kg multiplied by 0.38, which equals 26.6 kg. Therefore, statement A, which says that your mass would be 26.6 kg on Mars, is true.

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The correct answer is

C. reduce the friction between its moving parts

In fact, by reducing the friction between the moving parts of the machine, it is possible to reduce the energy wasted due to this friction; therefore, more input energy is converted into useful work, and this will improve the efficiency of the machine.

Answer: We can reasonably improve a machines ability to do work by reducing the friction between the moving parts of machine. The correct answer is C.

Explanation:

According to the law of conservation of energy, the energy can neither be created nor destroyed. The energy can be converted from one form to another.

The energy is wasted due to the friction. It reduces the efficiency of the machines to do the work. There will be energy loss due to the friction. By reducing the friction, More energy can be converted into the work.

Therefore, we can reasonably improve a machines ability to do work by reducing the friction between the moving parts of machine.

The magnitude of the skydiver's acceleration when the upward force of air resistance is half of his weight is 4.9 m/s² downward. This is found using Newton's Second Law and the skydiver's weight calculated from his mass and the acceleration due to gravity.

When the upward force of air resistance is equal to one-half of the skydiver's weight, the net force on the skydiver is only half of his weight acting downward. The skydiver's weight (W) can be calculated using the equation W = mg, where m is the mass and g is the acceleration due to gravity. For a mass (m) of 105 kg and assuming the acceleration due to gravity (g) is approximately 9.8 m/s2, the skydiver's weight would be 105 kg × 9.8 m/s2 = 1029 N. Half of this weight is 1029 N / 2 = 514.5 N.

According to Newton's Second Law (F = ma), the net force is equal to the mass multiplied by the acceleration. In this case, the net force is also the unbalanced force acting on the skydiver, which is half the skydiver's weight. Therefore, we have F = ma, which means 514.5 N = 105 kg × a. Solving for a, the acceleration, we get a = 514.5 N / 105 kg which is approximately 4.9 m/s2. Therefore, the magnitude of the skydiver's acceleration in this case is 4.9 m/s2 downward.