Answer:
The rate of formation of CO2 = 1.43 mol L-1s-1.
The rate of formation of H2O = 1.43 mol L-1s-1.
The rate of reaction of O2 = 1.43 mol L-1s-1.
Explanation:
2C6H14(g) + 19O2(g) -------> 12CO2(g) + 14H2O(g)
The rate of reaction of C6H14 is 1.43 mol L-1s-1.
The rate of reaction is theoretically defined as the speed of a chemical reaction. It is how fast or how slow the reactants are being used up or products are being formed.
It is the rate of change of concentration, amount etc., of any of the reactant or any of the product with time. The rate of reaction is the same and uniform for any of the products and reactants.
For a chemical reaction, A + 2B -----> 2C
r = -(dA/dt) = -(dB/dt) = (dC/dt)
Hence, the rate of reaction = rate of disappearance of C6H14 = rate of formation of CO2 = rate of formation of H2O = rate of reaction of O2 = 1.43 mol L-1s-1.
Hope this Helps!!!
How much HCl is produced from the reaction of an excess of HSbCl4 with 3 moles H2S in the following reaction? HSbCl4 + H2S → Sb2S3 + HCl (Remember to balance the equation.)
Answer:
We will produce 8.0 moles of HCl , this is 291.7 grams HCl
Explanation:
Step 1: Data given
Number moles of H2S = 3.0 moles
Step 2: The balanced equation
2HSbCl4 + 3H2S → Sb2S3 + 8HCl
Step 3: Calculate moles HCl
For 2 moles HSbCl4 we need 3 moles H2S to produce 1mol Sb2S3 and 8 moles HCl
For 3.0 moles H2S we'll have 8.0 moles HCl
Step 4: Calculate mass HCl
Mass HCl = moles HCl * molar mass HCl
Mass HCl = 8.0 moles * 36.46 g/mol
Mass HCl = 291.7 grams
We will produce 8.0 moles of HCl , this is 291.7 grams HCl
From the balanced equation, it is determined that 2 moles of HCl are produced from 1 mole of HSbCl4. Therefore, 6 moles of HCl will be produced from the reaction of an excess of HSbCl4 with 3 moles of H2S.
Explanation:The balanced equation for the reaction is:
HSbCl4 + H2S → Sb2S3 + 2HCl
The mole ratio between HSbCl4 and HCl is 1:2, which means that for every 1 mole of HSbCl4, 2 moles of HCl are produced.
Since there is an excess of HSbCl4, we can assume that all 3 moles of H2S will react.
Therefore, the number of moles of HCl produced will be:
(3 moles H2S) x (2 moles HCl/1 mole HSbCl4) = 6 moles HCl
You are troubleshooting an older laptop with a thin-film-transistor liquid-crystal display (LCD TFT) screen that is very dim and flickering. You have determined that the LCD graphics adapter is installed and is functioning properly. What is most likely the problem?
Answer:
the inverter has failed
Explanation:
Based on the information provided within the question it can be said that the most likely problem with the LCD screen in this scenario is that the inverter has failed. The inverter is a component used in LCD displays which prepares the power connection so that is provides the correct power to the screens back-light lamp. If there is a problem with the inverter then it would fail to provide enough power which will cause the light and screen to flicker. Such as in this scenario.
Systematic or Random Error? -This type of error affects overall accuracy but does not necessarily affect precision. This type of error affects precision but does not necessarily affect overall accuracy. This type of error occurs if you use a buret that was calibrated incorrectly when it was made. You can minimize this type of error by taking repeated measurements.
Answer:
This type of error affects overall accuracy but does not necessarily affect precision. - Systematic error
This type of error affects precision but does not necessarily affect overall accuracy. - Random error
This type of error occurs if you use a buret that was calibrated incorrectly when it was made. - Systematic error
You can minimize this type of error by taking repeated measurements. - Random error
Explanation:
Systematic errors are errors that are attributable to instrument being used during measurement or consistent incorrect measurement during a research. They are consistently and repeatedly committed during measurements and therefore affect the overall accuracy of measurements. A person committing systematic error can have precise repeated measurement but will be far from being accurate.
Random errors on the other hand has no pattern and are usually unavoidable because they cannot be predicted. When sufficient replicate measurements are made, such errors are reduced to the barest minimum and usually do not affect the overall accuracy of measurements.
What is the concentration of NOBr, if the concentration of NO was measured to be 0.89 M, Br2 was measured to be 0.562 M, and the equilibrium constant, K, is 1.3 × 10-2?
Answer:
0.076M = [NOBr]
Explanation:
For the reaction:
2NO + Br₂ ⇄ 2 NOBr
The equilibirum constant, K, is defined as:
[tex]K = \frac{[NOBr]^2}{[NO]^2[Br_2]}[/tex](1)
Replacing the concentrations and the equilibrium value in (1):
[tex]1.3x10^{-2} = \frac{[NOBr]^2}{[0.89]^2[0.562]}[/tex]
5.79x10⁻³ = [NOBr]²
0.076M = [NOBr]
I hope it helps!
An industrial chemist studying bleaching and sterilizing prepares several hypochlorite buffers. Find the pH of 0.200 M HClO and 0.200 M NaClO. (Ka for HClO = 2.9 × 10−8)
Answer:
The pH is 7.54
Explanation:
The Henderson - Hasselbalch equation states that for a buffer solution which consists of a weak acid and its conjugate base, the buffer pH is given by:
pH [tex]=pk_{a} +log(\frac{[conjugate base]}{[weakacid]})[/tex]
pkₐ is for the acid
In this case, the buffer hypochlorous acid HClO is a weak acid, and its conjugate base is the hypochlorite anion ClO⁻ is delivered to the solution via sodium hypochlorite NaClO .
NaCIO = 0.200 M
HCIO = 0.200 M
pkₐ = -log₁₀ kₐ = -log₁₀ (2.9 × 10⁻⁸) = 7.54
∴pH = [tex]=7.54 +log\frac{0.2}{0.2}[/tex] = 7.54
Which step in the process of protein synthesis occurs directly after mrna is assembled?
Answer:
Translation
Explanation:
Protein synthesis is the process of production of proteins in in the cells of living organisms. Transcription and Translation are the two main steps in the protein synthesis. The first step is completed in nucleus where mRNA is made using DNA as template. The second step i.e. translation occurs in the cytoplasm with the help of Ribosomes. The mRNA synthesized during transcription is pre-mRNA. After the processing it is assembled as mature RNA. After getting assembled the second step of protein synthesis viz. Translation begins in the cytoplasm.
Evidence for the existence of neutrons did not come until many years after the discoveries of the electron and the proton. Give a possible explanation.
As there was no electric charge on neutrons, and they did not get affected by electromagnetic fields.
Explanation:
The functions of the neutron in atoms is:
To hold the nuclei with coulombic repulsion between the protons.
The neutron has no charge on it and hence were not discovered.
Its mass is slightly less than the proton.
It provides stability to the atom.
Lord Chadwick is credited to prove the existence and discovery of neutron.
He proved that the nucleus of the atom has its mass in the centre as neutron+ proton.
He bombarded beryllium with alpha particles, and found high energy radiation.
The neutron was discovered later than the electron and proton due to the difficulty in detecting uncharged particles. It filled a crucial gap in explaining the atomic nucleus's mass and the existence of isotopes, which differ in neutron count but are chemically identical.
Explanation:The discovery of the neutron was a pivotal moment in the history of subatomic physics. Before the neutron's existence was proven, it was known that the nucleus contained most of an atom's mass, but the mass from protons alone was insufficient to account for it entirely. The detection of neutrons, which are uncharged particles, proved to be much more difficult than that of charged particles like electrons and protons. It was only in 1932 that James Chadwick provided evidence of the neutron, which not only filled the mass discrepancy in the atomic nucleus but also explained the existence of isotopes, which are chemically identical but differ in their number of neutrons.
Proposals to explain this discrepancy included particles hidden within the nucleus. An early hypothesis suggested that neutrons might be a composite of a proton and an electron, which would explain its neutral charge. However, deeper investigation into properties such as the neutron's magnetic moment and mass raised questions that ultimately required a new fundamental particle's acknowledgment.
Suppose paper pulp mills are permitted to emit harmful pollutants, free of charge, into the air. How will the price and output of paper in a competitive market compare with their values under conditions of ideal economic efficiency
Answer:
The price will be too low, and the output will be too large.
Explanation:
"13.136 A pharmaceutical preparation made with ethanol (C2H5OH) is contaminated with methanol (CH3OH). A sample of vapor above the liquid mixture contains a 97/1 mass ratio of C2H5OH to CH3OH. What is the mass ratio of these alcohols in the liquid mixture
Answer:
Mass ratio of ethanol to methanol in the liquid mixture = 202:1
Explanation:
Starting with a basis of 98.0 g
Amount of ethanol vapour in mass = 97 g
Amount of methanol vapour In mass = 1 g
Number of moles = (mass)/(molar mass)
Molar mass of ethanol = 46.07 g/mol
Molar mass of methanol = 32.04 g/mol
Number of moles of ethanol in the vapour = 97/(46.07) = 2.105 moles
Number of moles of methanol in the vapour = 1/(32.04) = 0.0312 mole
But we do know that
(Number of moles in gaseous form) = (number of moles in liquid state) × (Partial pressure).
Partial Pressure of ethanol = 60.5 torr
Partial pressure of methanol = 126.0 torr
(2.105) = (Number of moles of ethanol in the liquid state) × 60.5
number of moles of ethanol in the liquid state = 2.105/60.5 = 0.0348 moles/torr
(0.0312) = (Number of moles of methanol in the liquid state) × 126
number of moles of methanol in the liquid state = 0.0312/126 = 0.000248 moles/torr
We then convert these new number of moles in liquid state into masses
Mass = (Number of moles) × (molar mass)
(Mass of ethanol in the liquid state) = 0.0348 × 46.07 = 1.603 g/torr
(Mass of methanol in the liquid state) = 0.000248 × 32.04 = 0.00795 g/torr
Mass ratio of ethanol to methanol = (1.603/0.00795) = 201.7: 1 ≈ 202:1
The student's question pertains to finding the mass ratio of ethanol and methanol in a liquid mixture based on the mass ratio in the vapor phase using Raoult's law and the known vapor pressures of the alcohols. To answer accurately, additional data on mass or mole fractions is needed.
Explanation:The student's question deals with the calculation of the mass ratio of alcohols, ethanol (C2H5OH) and methanol (CH3OH), in a liquid mixture based on the mass ratio in the vapor phase. To solve this problem, Raoult's law and the given vapor pressures of both alcohols must be used. Raoult's law states that the vapor pressure of a component in a mixture is equal to the mole fraction of the component in the liquid phase times the vapor pressure of the pure component.
With this information, and knowing the vapor pressure of ethanol is 44 torr and that of methanol is 94 torr at the same temperature, we could use the given vapor mass ratio (97/1) to calculate the mole fraction of each component in the vapor phase. Then, apply Raoult's law in reverse to find the mole fractions in the liquid phase, and finally, convert the mole fractions back into a mass ratio. The molecular weight of ethanol (46.07 g/mol) and methanol (32.04 g/mol) are used for this final step.
To proceed with the solution, more data regarding the mass or mole fractions in the liquid or vapor phase would be necessary. Without such data, we cannot fully determine the exact mass ratio in the liquid mixture.