Answer: the correct option is B ( on the half of the road that the vehicle is traveling).
Explanation: according to Georgia Code About Pedestrians; The driver must stop and remain stopped to let a pedestrian cross at a crosswalk when the pedestrian is
on the half of the road that the vehicle is traveling.
Answer:
B
Explanation:
The driver must stop and remain stopped to let a pedestrian cross at a crosswalk when the pedestrian is _____________.
A. on the half of the road with traffic going in the opposite direction
B. on the half of the road that the vehicle is traveling
C. anywhere on a two-way street
According to the law regrading pedestrian, the pedestrian has the right of way immediately she is crossing on the crosswalk and is half of the road that the vehicle is travelling.
These rules are there for the safety of the driver, pedestrians and other road users
One long wire lies along an x axis and carries a current of 43 A in the positive x direction. A second long wire is perpendicular to the xy plane, passes through the point (0, 5.9 m, 0), and carries a current of 41 A in the positive z direction. What is the magnitude of the resulting magnetic field at the point (0, 1.7 m, 0)?
Answer:
Bnet=1.006*10^-6T
Explanation:
One long wire lies along an x axis and carries a current of 43 A in the positive x direction. A second long wire is perpendicular to the xy plane, passes through the point (0, 5.9 m, 0), and carries a current of 41 A in the positive z direction. What is the magnitude of the resulting magnetic field at the point (0, 1.7 m, 0)?
the magnetic field Bnet=[tex]\sqrt{b1^2+b2^2}[/tex]
the magnetic field due this long wire is given by
B1=∨I1/[tex](2\pi *R1)[/tex]..............................1
B2=∨I2/[tex](2\pi *R2)[/tex]............................2
Bnet=[tex]\sqrt{(vI1/2*pi*R1)^2+(vI2/2*pi*R2)^2}[/tex].......................3
Bnet=v/2*pi[tex]\sqrt{(I1/R1)^2+(i2/R2)^2}[/tex]
Bnet=4*pi*10^-7/(2[tex]\pi[/tex])[tex]\sqrt{(43/1.7)^2+(41/29.5)^2}[/tex]
Bnet=0.0000002*(641.72)^.5
Bnet=1.006*10^-6T
A mass m is oscillating with amplitude A at the end of a vertical spring of spring constant k. The mass is increased by a factor of four.1. What is true about the period? (period does what factor)2. The mass is increased by a factor of four, keeping A and k constant. What is true about the total mechanical energy?3. The mass is increased by a factor of four, keeping A and k constant. What is true about the maximum speed?4. The amplitude is doubled, keeping mass and k constant. What is true about the period?5. The amplitude is doubled, keeping mass and k constant. What is true about the total mechanical energy? Choose the best answer.6. The amplitude is doubled, keeping mass and k constant. What is true about the maximum speed?
Answer:
1. The period doubles
2. The mechanical energy is unchanged
3. The speed is halved
4. The period is unchanged
5. The energy is quadrupled
6. The maximum is speed doubled
Explanation:
1. From Hooke's law we have [tex]T\propto\sqrt{\frac{m}{k} }[/tex]
where T is period, m is mass and k is the spring constant
So If the mass is increased by a factor of 4 then period doubles while k constant
2 According to law of conservation of energy, the energy remains unchanged so therefore the total mechanical energy remain unchanged.
3. From the [tex]w = \sqrt{\frac{k}{m} }[/tex]
where m is mass and w is speed
so we see that mass and speed is inversely proportional therefore if we increase mass speed decreases.
4. The period is independent of amplitude
5. [tex]E=A^{2} [/tex]
where E is energy and A is amplitude
So if the amplitude is doubled the energy is quadrupled.
6. we have the relation
[tex]v_{max}=A [/tex]
where [tex]v_{max}[/tex] is maximum speed and A is amplitude
From the formular we can see they are directly proportional, so if we double amplitude then [tex]v_{max}[/tex] doubles also.
The period would double when the mass of the spring is increased by a factor of four (4).
How to calculate the period.Since all springs obey Hooke’s law, the period is given by this formula:
[tex]T\alpha \sqrt{\frac{m}{k}}\\\\T = 2\pi \sqrt{\frac{m}{k} }[/tex]
Where:
k is the spring constant.m is the mass.We can deduce that, the period is directly proportional to mass of the spring. Thus, the period would double when the mass of the spring is increased by a factor of four (4).
In accordance with the law of conservation of energy, the total mechanical energy of the spring would remain the same because energy can neither be created nor destroyed.
How to calculate the maximum speed.The speed of a spring in simple harmonic motion is an angular speed and it is given by this formula:
[tex]\omega = \sqrt{\frac{k}{m} }[/tex]
We can deduce that, the angular speed is inversely proportional to mass of the spring. Thus, the angular speed would decrease when the mass of the spring is increased by a factor of four (4).
In simple harmonic motion, the period of a spring is independent of its amplitude.
How to calculate the total mechanical energy.Mathematically, the the total mechanical energy of a spring is given by this formula:
[tex]E=A^2[/tex]
We can deduce that, the total mechanical energy is directly proportional to the square of amplitude of the spring. Thus, the total mechanical energy would quadruple when the amplitude of the spring is doubled.
Also, the maximum speed is directly proportional to the amplitude of the spring. Thus, the maximum speed would also double when the amplitude of the spring is doubled.
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Professionals in careers in the exercise and sport sciences need to provide quality programs in specialized settings to prove that a higher degree of competence is needed to fulfill the responsibilities of these careers than may currently be the case.
Answer:
True
Explanation:
It is true that professionals in exercises and sport science need to provide quality specialized settings to prove that a higher degree of competence is needed to fulfill the responsibility of the careers.
A bullet with mass 4.53 g is fired horizontally into a 1.953-kg block attached to a horizontal spring. The spring has a constant 5.73 102 N/m and reaches a maximum compression of 6.20 cm. Find the initial speed of the bullet-block system.
Answer:
The initial speed of the bullet-block system is 113 m/s
Explanation:
Hi there!
Let´s apply the theorem of conservation of energy. If we neglect friction, all the kinetic energy of the bullet-block system is used to compress the spring. In other words, the kinetic energy is converted into elastic potential energy. Then, the initial kinetic (KE) energy of the bullet-block system will be equal to the final elastic potential energy (EPE) of the spring:
KE = EPE
1/2 · m · v² = 1/2 · k · x²
Where:
m = mass of the bullet-block system.
v = initial speed of the bullet-block system.
k = spring constant.
x = compression of the spring
Then, solving for v:
v² = k · x² / m
v² = 5.73 × 10² N/m · (0.620 m)² / 1.957 kg
v = 113 m/s
The Bernoulli effect can have important consequences for the design of buildings. For example, wind can blow around a skyscraper at remarkably high speed, creating low pres- sure. The higher atmospheric pressure in the still air inside the buildings can cause windows to pop out. As originally constructed, the John Hancock Building in Boston popped windowpanes that fell many stories to the sidewalk below. (a) Suppose a horizontal wind blows with a speed of 11.2 m/s outside a large pane of plate glass with dimensions 4.00 m 3 1.50 m. Assume the density of the air to be constant at 1.20 kg/m3. The air inside the building is at atmospheric pressure. What is the total force exerted by air on the win- dowpane?
Answer:
9483.26399 N
Explanation:
[tex]\rho[/tex] = Density of air = 1.2 kg/m³
v = Velocity of wind = 11.2 m/s
A = Area = [tex]4\times 31.5\ m^2[/tex]
The force on the pane is
[tex]F=\dfrac{1}{2}\rho v^2A\\\Rightarrow F=\dfrac{1}{2}\times 1.2\times 11.2^2\times 4\times 31.5\\\Rightarrow F=9483.26399\ N[/tex]
The force on the pane of glass is 9483.26399 N
Water has a density of 1.0 g/cm3. What is the mass of 10.0 cm3 of water?
Answer:
The mass of 10 cm³ of water, is 10 grams
Explanation:
Density of water = 1 g/cm³
Density = Mass / volume
Volume of water = 10 cm³
1 g/cm³ = Mass of water / 10 cm³
10 g = mass of water
The mass of 10.0 cm3 of water, given the density is 1.0 g/cm3, is found by multiplying the volume by the density, which gives us 10.0 g.
Explanation:The question is asking for the mass of a certain volume of water. Given that the density of water is 1.0 g/cm3, and you have 10.0 cm3 of water, the mass can be found by multiplying the volume by the density. So, it's simply 1.0 g/cm3 * 10.0 cm3 = 10.0 g. Therefore, the mass of 10.0 cm3 of water is 10.0 g.
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Anti-lock brakes (ABS) __________
A. prevent skidding and allows drivers to steer during an emergency braking situation.
B. sense a skid and automatically apply the brakes.
C. stop the vehicle faster than normal brakes.
D. all of the above
Answer:
A. prevent skidding and allows drivers to steer during an emergency braking situation.
Explanation:
In an urgent stopping case, anti-lock brakes avoid skidding and allow drivers to steer. ABS can also help improve automobile balance (evitating spinouts), steering (that is directing the vehicle where the driver needs it to go) and braking (distance needed to stop the vehicle). Hence, the correct answer is A.
Anti-lock brakes (ABS) primarily prevent skidding and allow drivers to steer during an emergency braking situation. They do not necessarily stop the vehicle faster. The main benefit of ABS is that it enables steering while braking.
Explanation:The correct answer to your question is A. Anti-lock brakes (ABS) primarily prevent skidding and allow drivers to maintain steering control during an emergency braking situation. When the system senses a wheel is about to lock up and skid, it automatically modulates brake pressure to that wheel. This process repeats rapidly, often several times per second.
Note that ABS does not necessarily stop the vehicle faster. In fact, in certain conditions like gravel or snow, stopping distances can be longer. However, the crucial advantage is that ABS allows you to steer while braking, potentially avoiding a collision.
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A certain chemical reaction experiences a 7.50 x 10-7 kilogram loss in mass. If this mass were to be totally converted to energy, what would be the magnitude of that energy.
Answer:
E=6.75×10¹⁰J
Explanation:
Given data
Mass (m)=7.50×10⁻⁷kg
To find
Energy (E) = ?
Solution
From Albert Einstein’s theory of special relativity
E = mc²........eq(1)
Where
E is energy
m is mass
c is speed of light which 3.0×10⁸m/s
put values in eq(1) we get
E=(7.50×10⁻⁷kg)×( 3.0×10⁸m/s)²
E=6.75×10¹⁰J
A mass is attached to an ideal spring. At time t = 0 the spring is at its natural length and the mass is given an initial velocity; the period of the ensuing (one-dimensional) simple harmonic motion is T . At what time is the power delivered to the mass by the spring first a maximum?
SHM in a mass-spring system involves a restoring force proportional to displacement, with power being maximal at extreme positions.
Simple Harmonic Motion (SHM) is a type of periodic motion defined by a restoring force proportional to displacement. In the context of a mass attached to a spring, the period of SHM can be calculated using the mass and force constant of the spring.
The power delivered to the mass by the spring is first a maximum when the restoring force is at its maximum, which occurs when the mass achieves its greatest displacement. This typically happens when the mass is at the equilibrium point after being displaced.
The time at which the power delivered by the spring is first a maximum aligns with the moments when the mass reaches its extreme positions during the oscillatory motion, typically when it's at the maximum displacement from equilibrium.
When a mass is attached to an ideal spring and set into simple harmonic motion (SHM) with an initial velocity from its natural length, the power delivered by the spring to the mass is first maximized when the mass passes through the equilibrium position at maximum speed. Since the period T is the time it takes for one complete cycle of the motion, the mass reaches its maximum velocity at equilibrium position at one quarter of the period. Therefore, the power delivered to the mass by the spring is first a maximum at t = T/4, where T is the period of the simple harmonic motion
dante is leading a parade across the main street in front of city hall. Starting at city hall, he marches the parade 4 blocks east, then 3 blocks south. From there, the parade marches 1 block west and 9 blocks north and finally stops. What is the vector displacement and direction of the the parade, starting from the city hall and the stopping point? (1 point)
Displacement: 6.71 m, Direction: 63.4 degrees north of east
Displacement: 8.01 m, Direction: 21.9 degrees north of east
Displacement: 2.56 m, Direction: 39.7 degrees north of east
Displacement: 4.31 m, Direction: 88.1 degrees north of east
Answer:
The correct option is A)
Displacement: 6.71 m, Direction: 63.4 degrees north of east
Explanation:
Given that Dante is leading a parade across the main street in front of city hall.
Let, Initial location of parade is 0i+0j
One block of city is one units on the XY- graph
Statement 1: Parade marches the parade 4 blocks east, then 3 blocks south
New location of parade is 4i-3j
Statement 2: The parade marches 1 block west and 9 blocks north and finally stops.
Final location of parade is (4i-3j)+(-1i+9j)=3i+6j
Displacement is given by
Displacement = (Final destination)-(Initial destination)
Displacement = (3i+6j)-(0i+0j)=3i+6j
Thus,
Magnitude of displacement = [tex]\sqrt{3^{2}+6^{2}}[/tex]
= 6.71 m
Direction of displacement = [tex]tan^{-1}(\frac{Y}{X} )[/tex]
= [tex]tan^{-1}(\frac{6}{3} )[/tex]
= 63.43 NE
Therefore, the correct option is A) Displacement: 6.71 m, Direction: 63.4 degrees north of east
A coin is placed 32 cm from the center of a horizontal turntable, initially at rest. The turntable then begins to rotate. When the speed of the coin is 110 cm/s (rotating at a constant rate), the coin just begins to slip. The acceleration of gravity is 980 cm/s^2 . What is the coefficient of static friction between the coin and the turntable?
Answer:
0.39
Explanation:
distance from the center (r) = 32 cm = 0.32 m
speed of the coin (v) = 110 cm/s = 1.1 m/s
acceleration due to gravity (g) = 980 m/s^{2} = 9.8 m/s^{2}
find the coefficient of static friction (k) between the coin and the turn table
frictional force = kmg
before the table begins to move, the frictional force balances the centripetal force ([tex]\frac{mv^{2} }{r}[/tex])
therefore
frictional force = centripetal force
kmg = [tex]\frac{mv^{2} }{r}[/tex]
kg = [tex]\frac{v^{2} }{r}[/tex]
k = [tex]\frac{v^{2} }{r}[/tex] ÷ g
k = [tex]\frac{1.1^{2} }{0.32}[/tex] ÷ 9.8 = 0.39
Which of the following types of light cannot be studied with telescopes on the ground?a. Visible light b. X-rays c. Radio waves d. All of the above
Answer:
Which of the following types of light cannot be studied with telescopes on the ground?
The Answer is X-rays
Explanation:
Earth’s atmosphere blocks most of the radiation from space preventing some electromagnetic spectrum from reaching the Earth because they are absorbed or reflected by the Earth's atmosphere. Visible light and radio waves get through to telescopes on the ground, while X-rays are absorbed by most molecules in the Earth’s atmosphere making it visible only from above the atmosphere.
Some Terms Explained:
Telescope: is an optical instrument that makes distant objects appear magnified. The purposes of a telescope are to gather light using either a lens or a mirror and resolve detail. There are two basic types of telescopes, refractors and reflectors.
Visible light: covers the range of wavelengths from 400–700 nanometers.
X-rays: range in wavelength from 0.001–10 nanometers. They are shorter in wavelength than Ultraviolet rays and longer than gamma rays. They will pass through most substances, and this makes them useful to see inside things.
Radio waves: the longest waves, longer than 1 meter they have the lowest energy. It is used for long distance communication.
Final answer:
X-rays cannot be studied with telescopes on the ground due to Earth's atmosphere blocking them. Space telescopes are needed for such observations.
Explanation:
The type of light that cannot be studied with telescopes on the ground is X-rays. Ground-based telescopes can effectively observe visible light and radio waves, but X-rays are mostly blocked by Earth's atmosphere. To study X-ray emissions, astronomers use space telescopes. Other ranges of the electromagnetic spectrum, such as ultraviolet and gamma rays, are similarly studied using telescopes positioned in space to bypass atmospheric interference.
As part of your daily workout, you lie on your back and push with your feet against a platform attached to two stiff springs arranged side by side so that they are parallel to each other. When you push the platform, you compress the springs. You do an amount of work of 85.0 J when you compress the springs a distance of 0.250 m from their uncompressed length. What magnitude of force must you apply to hold the platform in this position? How much additional work must you do to move the platform a distance 0.220 m farther? What maximum force must you apply to move the platform a distance 0.220 m farther?
Answer:
a) F = 680 N, b) W = 215 .4 J , c) F = 1278.4 N
Explanation:
a) Hooke's law is
F = k x
To find the displacement (x) let's use the elastic energy equation
[tex]K_{e}[/tex] = ½ k x²
k = 2 [tex]K_{e}[/tex] / x²
k = 2 85.0 / 0.250²
k = 2720 N / m
We replace and look for elastic force
F = 2720 0.250
F = 680 N
b) The definition of work is
W = ΔEm
W = [tex]K_{ef}[/tex] - [tex]K_{eo}[/tex]
W = ½ k ( [tex]x_{f}[/tex]² - x₀²)
The final distance
[tex]x_{f}[/tex] = 0.250 +0.220
[tex]x_{f}[/tex] = 0.4750 m
We calculate the work
W = ½ 2720 (0.47² - 0.25²)
W = 215 .4 J
We calculate the strength
F = k [tex]x_{f}[/tex]
F = 2720 0.470
F = 1278.4 N
Marcie wants to work as a freelance editor. She purchases a desk, computer, widescreen monitor, and ergonomic keyboard. What kind of resources are these?
Answer:Capital Resources
Explanation:
Desk, computer, widescreen monitor, and ergonomic keyboard are an example of capital resources.
Capital resources are goods produced and used for the production of other goods and services. Basic items in capital goods are tools, machinery, and building. However, any good being utilized by a business to produce other good and services are under the category of capital goods.
Here Desk, computer and other items help Marcie to design her artwork as freelancer.
The geologic time scale originally ordered earth’s rocks by
The geologic time scale originally ordered Earth’s rocks by relative age.
Explanation:
Geologic time scale is the measure of events occurred in year wise from the starting of universe. Mostly dating of rocks and fossil fuels are doing the trends still now. In order to measure the age of rocks, geological time scale have preferred relative age mode.
In this system, the age of rocks are measured and compared layer by layer. So the lowest layer of rock will be having the maximum age. As we don’t know the starting time of universe, so this method of comparison between the layers to order the rocks is best. So, depending upon the position of the rocks, the age can be determined.
In one case, a sports car, its engine running, is driven up a hill at a constant speed. In another case, a truck approaches a hill, and its driver turns off the engine at the bottom of the hill. The truck then coasts up the hill. Which vehicle is obeying the principle of conservation of mechanical energy? Ignore friction and air resistance.
The truck coasting up the hill with its engine turned off is obeying the principle of conservation of mechanical energy because the kinetic energy is converted into gravitational potential energy without external work, while the sports car with the running engine is not conserving mechanical energy since it is adding energy to the system.
Explanation:The principle of conservation of mechanical energy states that the total mechanical energy in a system remains constant if only conservative forces are doing work. When friction and air resistance are ignored, as requested, the truck that coasts up the hill with the engine turned off obeys this principle because its initial kinetic energy is converted into gravitational potential energy without any external work being done on or by the system. On the other hand, the sports car with its engine running is continually adding energy to the system to maintain a constant speed up the hill, which means it is not conserving mechanical energy as in the first case.
Which of the following supports the claim that the atom is like a solid positive cookie with negative electrons embedded within it? (This model is known as the Plum Pudding Model of the atom, and is illustrated to the right).
a. Law of Constant Composition, Law of Multiple Proportions, Law of Conservation of Mass Alpha particles are scattered at a variety of angles (over 90 degrees) when bombarded at gold foil.
b. When light from hydrogen emissions passes through a diffracting grating, there are distinct bands of color.
c. The Cathode Ray Tube experiment, in which the ray was attracted to the south pole of the magnet.
Answer:
a. Law of Constant Composition, Law of Multiple Proportions, Law of Conservation of Mass Alpha particles are scattered at a variety of angles (over 90 degrees) when bombarded at gold foil.
Explanation:
Which of the following supports the claim that the atom is like a solid positive cookie with negative electrons embedded within it? (This model is known as the Plum Pudding Model of the atom, and is illustrated to the right).
a. Law of Constant Composition, Law of Multiple Proportions, Law of Conservation of Mass Alpha particles are scattered at a variety of angles (over 90 degrees) when bombarded at gold foil.
b. When light from hydrogen emissions passes through a diffracting grating, there are distinct bands of color.
c. The Cathode Ray Tube experiment, in which the ray was attracted to the south pole of the magnet.
the plumbudding model of the atom was postulated by JJ Thompson and plum pudding model. . ... Thomson had discovered that atoms are composite objects, made of pieces with positive and negative charge, and that the negatively charged electrons within the atom were very small compared to the entire atom.
so a. correctly typifies the thompson model of the atom
Final answer:
Option c, the Cathode Ray Tube experiment, supports the claim that the atom is like a solid positive cookie with negative electrons embedded within it.
Explanation:
The correct option that supports the claim that the atom is like a solid positive cookie with negative electrons embedded within it is option c. The Cathode Ray Tube experiment, in which the ray was attracted to the south pole of the magnet, is consistent with the Plum Pudding Model of the atom. This model describes atoms as having a diffuse positive charge with embedded electrons.
Which is a correct statement of what occurs at a turbine during electricity production?
Answer:
The turbine is rotated and rotates the generator to produce electricity.
Explanation:
Within a turbine enters the superheated steam which is at high pressure and high temperature, this steam is previously formed in the boiler when the steam enters the turbine hits each one of the blades of the turbine making it rotate at a given speed, the turbine shaft is coupled to the shaft of an electric generator and thus generates electricity.
It is also important to say that when the steam comes out of the turbine comes out at low pressure, this way the internal operating process is carried out within the turbine.
A satellite with an orbital period of exactly 24.0 h is always positioned over the same spot on Earth.This is known as a geosynchronous orbit. Television, communication, and weather satellites use geosynchronous orbits. At what distance would a satellite have to orbit Earth in order to have a geosynchronous orbit?
Answer:
35870474.30504 m
Explanation:
r = Distance from the surface
T = Time period = 24 h
G = Gravitational constant = 6.67 × 10⁻¹¹ m³/kgs²
m = Mass of the Earth = 5.98 × 10²⁴ kg
Radius of Earth = [tex]6.38\times 10^6\ m[/tex]
From Kepler's law we have relation
[tex]T^2=\dfrac{4\pi^2r^3}{GM}\\\Rightarrow r^3=\dfrac{T^2GM}{4\pi^2}\\\Rightarrow r=\left(\dfrac{(24\times 3600)^2\times 6.67\times 10^{-11}\times 5.98\times 10^{24}}{4\pi^2}\right)^{\dfrac{1}{3}}\\\Rightarrow r=42250474.30504\ m[/tex]
Distance from the center of the Earth would be
[tex]42250474.30504-6.38\times 10^6=\mathbf{35870474.30504\ m}[/tex]
35870474.30504 m
A satellite in geosynchronous orbit remains over the same point on Earth, requiring an altitude of approximately 35,793 kilometers. This is calculated using the orbital mechanics involving the gravitational constant and Earth's mass and radius.
A geosynchronous orbit means that the satellite has an orbital period of [tex]24[/tex] hours, remaining over the same point on Earth as it rotates. To find the distance at which a satellite must orbit to achieve this, we use the universal law of gravitation and centripetal force.
We know:
Orbital period [tex]T = 86400 \text{ seconds}[/tex]
Gravitational constant [tex]G = 6.67430 \times 10^{-11} \, \text{N} \left( \text{m/kg} \right)^2[/tex]
Mass of Earth [tex]M = 5.972 \times 10^{24} \, \text{kg}[/tex]
Radius of Earth [tex]R = 6.371 \times 10^{6} \, \text{meters}[/tex]
The formula for the geostationary orbit (orbital radius r) is given by:
[tex]r^3 = \frac{GMT^2}{4\pi^2}[/tex]
Substituting the values, we get:
[tex]GM T^2 = 6.67430 \times 10^{-11} \times 5.972 \times 10^{24} \times (86400)^2\\\\GM T^2 = 6.67430 \times 10^{-11} \times 5.972 \times 10^{24} \times 7464960000\\\\GM T^2 = 2.963 \times 10^{14}\\\\r^3 \approx \frac{2.963 \times 10^{14}}{4 \times 9.8696}\\\\r^3 \approx 7.507 \times 10^{12} \, \text{m}^3\\\\r \approx \sqrt[3]{7.507 \times 10^{12}}\\\\r \approx 42164 \, \text{km}\\\\[/tex]
To find the altitude (h) above Earth’s surface:
[tex]h = r - \text{Earth's radius} = 42164 \, \text{km} - 6371 \, \text{km} \approx 35793 \, \text{km}[/tex]
Thus, a satellite needs to orbit at an altitude of approximately [tex]35,793 km[/tex] to maintain a geosynchronous orbit.
A 10 kilogram object suspended from the end of a vertically hanging spring stretches the spring 9.8 centimeters. At time t=0, the resulting mass-spring system is disturbed from its rest state by the force F(t)=140cos(8t). The force F(t) is expressed in Newtons and is positive in the downward direction, and time is measured in seconds.
Answer:
K= 1000 N-m
Explanation:
It is assumed that we asked to find the spring constant k of the spring
We know that under equilibrium condition
weight of the object = force applied by the spring
given m =10 Kg
x= extension in the spring = 9.8 cm
mg=kx
[tex]10\times9.8=k\times9.8\times10^(-2)[/tex]
K= 1000 N-m
The spring constant, k of the vertically suspended spring measured in Newton meter is 1000 N/m
Given the Parameters :
Acceleration due to gravity, g = 9.8 m/s²Mass of object, m = 10 kg Extension, e = 9.8 centimetersUsing the Relation :
F = ke ; k = spring constant Force, F = mass × acceleration due to gravityThe expression can be written thus :
mg = ke
Converting, extension to meters = (9.8/100) = 0.098 m
(10 × 9.8) = 0.098k
98 = 0.098k
k = 98/0.098
k = 1000 N/m
Therefore, the spring constant is 1000 N/m
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Here are the names of some substances: Sulphur, copper, oxygen, iron, water, magnesium, mercury Which substance: Is at gas room temperature? Is a liquid metal? Is a solid non-metal? is a chemical compound?
Answer:
Gas at room temperature: Oxygen
Liquid metal: Mercury
Solid non-metal: Sulphur, Copper
Chemical compound: Water
Explanation:
Oxygen(O): atomic no.-8It is highly reactive non-metal and third most abundant element in the universe after hydrogen and helium. Diatomic oxygen(O₂) constitutes 20.8% of earth atmosphere that used in respiration in living organisms.
Mercury(Hg): atomic no.-80It is shiny, silvery and only metal which is found in liquid state at normal room temperature. Most common use of mercury is in thermometer, barometer, sphygmomanometer etc.
Sulphur(S): atomic no.-16It is bright yellow crystalline solid non-metal at room temperature in elemental form. Combined sulphur exists in sulphates and sulphides i.e. CaSO₄.2H₂o, MgSO₄.7H₂O, PbS, ZnS etc. Abundance in earth crust is only 0.03-0.1%.
Copper(Co): atomic no.-29It is pinkish-orange, malleable and ductile metal found in solid state at room temperature. It is commonly used in making wire, alloy etc.
Water(H₂O):Water covers 71% of earth surface. A molecule contains one oxygen and two hydrogen atoms connected by covalent bonds. It is crucial for all forms of life.
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What is the significance of Le Châtelier's principle when used in industrial fields?
1) Scientists know that reactions at chemical equilibrium will have consistent reaction rates if the intensity of external factors is steadily increased, so scientists can use external factors to manipulate these chemical reactions into producing specific results.
2) Scientists know that reactions at chemical equilibrium will shift to regain equilibrium if left in the same external conditions long enough, so scientists can stabilize these chemical reactions' environments in order to produce specific results.
3) Scientists know that reactions at chemical equilibrium will have consistent reaction rates despite any change in external conditions, so scientists can depend on these chemical reactions to always produce the same specific results.
4) Scientists know that reactions at chemical equilibrium will shift to regain equilibrium when affected by external factors, so scientists can use external factors to manipulate these chemical reactions into producing specific results.
scientists can prove the answer of the chemical reaction and in every case
Answer:
4) Scientists know that reactions at chemical equilibrium will shift to regain equilibrium when affected by external factors, so scientists can use external factors to manipulate these chemical reactions into producing specific results.
Explanation:
Le Châtelier's principle states that changes in the temperature, pressure, volume, or concentration of a system will result in predictable and opposing changes in the system in order to achieve a new equilibrium state. Le Châtelier's principle doesn't say anything about reaction rates.
The idea of an industrial process is to obtain an specific product. So, you can apply changes into a system in equilibrium to produce more desirable product. A simple example is to decrease the concentration of products by removing them or increasing the concentration of reactants by adding them, so that, more product is produced and more reactant is used, and the equilibrium is reached again.
When you throw a ball up in the air, it travels up and then stops instantaneously before falling back down. At the point where it stops and changes directions to fall back down is
Answer:
The ball stops instantaneously at the topmost point of the motion.
Explanation:
Assume we have thrown a ball up in the air. For that we have given a force on the ball and it acquires an initial velocity in the upward direction.
The forces that resist the motion of the ball in the upward direction are the force of gravity and air resistance. The ball will instantaneously come to rest when the velocity of the ball reduces to zero.
The two forces acting in the downward direction reduces its speed continuously and it becomes zero at the topmost point.
Final answer:
The highest point of a ball's upward trajectory is when its velocity is zero, and it momentarily stops before falling back to Earth under the influence of gravity. This is the point where the ball has its maximum potential energy and is the peak of the trajectory.
Explanation:
When you throw a ball up in the air, it travels upwards and slows down under the influence of gravity. At the highest point of its trajectory, the ball's velocity momentarily becomes zero before it reverses direction and falls back to the ground. This moment is known as the peak or the apex of the ball's trajectory. The ball's vertical velocity increases in the downward direction as it descends due to the acceleration caused by gravity. At the peak, not only does the velocity become zero, but this is also the point where the ball has its maximum potential energy.
When calculating the time it takes for the ball to reach its highest point or how high it goes, you can use the initial velocity and the acceleration due to gravity. For example, if a ball is thrown upwards with a velocity of 10 m/s, you can calculate the maximum height using the formula for the displacement under constant acceleration, considering that the final velocity at the highest point is zero and the acceleration due to gravity is -9.8 m/s² (negative as it is in the opposite direction to the ball's initial motion).
Suppose a yo-yo has a center shaft that has a 0.250 cm radius and that its string is being pulled.
(a) If the string is stationary and the yo-yo accelerates away from it at a rate of 1.50 m/s2, what is the angular acceleration of the yo-yo?
(b) What is the angular velocity after 0.750 s if it starts from rest?
(c) The outside radius of the yo-yo is 3.50 cm. What is the tangential acceleration of a point on its edge? Ans:
(a) 600 rad/s2,
(b) 450 rad/s,
(c) 21.0 m/s
Answer:
600 rad/s²
450 rad/s
21 m/s²
Explanation:
r = Radius
[tex]\omega_f[/tex] = Final angular velocity
[tex]\omega_i[/tex] = Initial angular velocity
[tex]\alpha[/tex] = Angular acceleration
t = Time taken
Linear acceleration is given by
[tex]a=r\alpha\\\Rightarrow \alpha=\dfrac{a}{r}\\\Rightarrow \alpha=\dfrac{1.5}{0.25\times 10^{-2}}\\\Rightarrow \alpha=600\ rad/s^2[/tex]
Angular acceleration of the yo-yo is 600 rad/s²
[tex]\omega_f=\omega_i+\alpha t\\\Rightarrow \omega_f=0+600\times 0.75\\\Rightarrow \omega_f=450\ rad/s[/tex]
angular velocity of the yo-yo is 450 rad/s
[tex]a=r\alpha\\\Rightarrow a=3.5\times 10^{-2}\times 600\\\Rightarrow a=21\ m/s^2[/tex]
Tangential acceleration of a point on its edge is 21 m/s²
The angular acceleration, angular velocity and tangential acceleration are;
A) 600 rad/s²
B) 450 rad/s,
C) 21 m/s²
What is the angular velocity and acceleration?A) We are given;
Radius; r = 0.25 cm = 0.0025 m
Linear acceleration; a = 1.5 m/s²
Formula for Angular Acceleration is;
α = a/r
Thus; α = 1.5/0.0025
α = 600 rad/s²
B) We are given;
time; t = 0.75 s
final angular velocity is gotten from;
ω_f = ω_i + αt
ω_f = 0 + (600 * 0.75)
ω_f = 450 rad/s
C) We are given;
Radius; r = 3.5 cm = 0.035 m
Formula for tangential acceleration is;
α_t = rα
α = 0.035 * 600
α = 21 m/s²
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. A 2.00 kg ball is attached to a ceiling by a string. The distance from the ceiling to the center of the ball is 1.00 m, and the height of the room is 3.00 m. What is the gravitational potential energy associated with the ball relative to each of the following? (a) the ceiling (b) the floor (c) a point at the same elevation as the ball
Explanation:
Mass of ball, m = 2 kg
Acceleration due to gravity, g = 9.81 m/s²
Height of ball from ground = 3 - 1 = 2 m
Potential energy, PE = mgh
Potential energy of ball, PE = 2 x 9.81 x 2 = 39.24 J
a) Potential energy of ball at ceiling = 2 x 9.81 x 3 = 58.86 J
Potential energy of ball relative to ceiling = 58.86 - 39.24 = 19.62 J
b) Potential energy of ball at floor = 2 x 9.81 x 0 = 0 J
Potential energy of ball relative to floor = 39.24 - 0 = 39.24 J
c) Potential energy of ball at same elevation = 2 x 9.81 x 2 = 39.24 J
Potential energy of ball relative to same elevation = 39.24 - 39.24 = 0 J
The gravitational potential energy of the ball relative to the ceiling and a point at the same elevation as the ball is 0 Joules because they are at the same height. The gravitational potential energy of the ball relative to the floor is 39.24 Joules.
Explanation:The gravitational potential energy of an object, in this case, the 2.00 kg ball, can be calculated using the formula: PE = mgh, where m is the mass of the object in kg, g is acceleration due to gravity (on Earth, it's about 9.81 m/s²), and h is the height in meters.
(a) the ceiling: The distance from the ceiling to the center of the ball is 1.00m, thus the potential energy relative to the ceiling is PE = 2.00 kg * 9.81 m/s² * 0 m = 0 J, since the ball is at the same level as the ceiling.
(b) the floor: The height of the ball from the floor can be calculated as the height of the room minus the distance from the ceiling to the center of the ball, which is 3.00 m - 1.00 m = 2.00 m. Thus, the potential energy relative to the floor is PE = 2.00 kg * 9.81 m/s² * 2.00 m = 39.24 J.
(c) a point at the same elevation as the ball: Since the point is at the same elevation as the ball, therefore, the potential energy would be PE = 2.00 kg * 9.81 m/s² * 0 m = 0 J.
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physical science!!!!!!helpppp
Answer:
Option B
10.36 m/s
Explanation:
Using the first given equation, then velocity=distance/time
Since distance is provided as 200 m and time, t is 19.3 seconds then substituting these figures yields
v=200/19.3=10.3626943
Rounding off to 2 decimal places, then
v=10.36 m/s
An ice-skater is moving at a constant velocity across an icy pond, The skater throws a snowball directly ahead.
Which of the following correctly describes the velocity of the center of mass of the skater-snowball system immediately after the snowball is thrown?
Assume friction and air resistance are negligible.
(A) It is equal to the velocity of the snowball.
(B) It is equal to the new velocity of the skater.
(C) It is equal to half the original velocity of the skater.
(D) It is equal to the original velocity of the skater.
Answer:
(D) It is equal to the original velocity of the skater.
Explanation:
The velocity of the center of mass of a system is
[tex]\vec{v}_{cm} = \frac{m1\vec{v}_1 + m_2\vec{v}_2}{m_1 + m_2}[/tex]
The velocity of the center of mass is constant if there is no external force, because the total momentum of the whole system is conserved.
So, before the snowball is thrown, the velocity of the center of mass is equal to that of the skater. This velocity will always be equal to the velocity of the center of mass of the system.
Immediately after the snowball is thrown, the velocity of the center of mass is equal to that of the skater. Option D is correct.
Velocity of the center of mass:
It is defined as the ratio of the sum of the momentum of the masses and total mass.
The velocity of the center of mass of a system given as
[tex]\bold {V_c_m = \dfrac {p_1 + p_2 } {m_1+m_2}}[/tex]
Where,
p1 - momentum of the first mass
p2 - momentum of the second mass
m1 + m1 - total mass of the system
If there is no external force, the velocity of the center of mass is constant because the total momentum of the whole system is conserved.
Therefore, immediately after the snowball is thrown, the velocity of the center of mass is equal to that of the skater.
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An 880 kg cannon at rest fires a 12.4 kg cannonball forward at 540 m/s. What is the recoil velocity of the cannon
Answer:
The recoil velocity of the cannon is 7.61 m/s in the opposite direction of the cannonball
Explanation:
Linear Momentum
The principle of conservation of the linear momentum establishes that the sum of the linear momentums of every object in an isolated system (no external forces) is constant, regardless of the interactions between them.
Let's think we have two objects with masses [tex]m_1[/tex] and [tex]m_2[/tex], moving at speeds [tex]v_1[/tex] and [tex]v_2[/tex]. If they collide and change their speeds to [tex]v_1'[/tex] and [tex]v_2'[/tex], then
[tex]m_1v_1+m_2v_2=m_1v_1'+m_2v_2'[/tex]
In our problem, the 880 kg cannon is initially at rest and has the cannonball of 12.4 Kg inside of it. As the initial speed of both joined objects is zero, the initial total momentum is zero. After the ball is fired, the ball moves at v_2=540 m/s. We need to find the recoil velocity of the cannon [tex]v_1'[/tex]
[tex]m_1v_1'+m_2v_2'=0[/tex]
[tex]\displaystyle m_1v_1'=-m_2v_2'[/tex]
[tex]\displaystyle v_1'=-\frac{m_2v_2'}{m_1}[/tex]
[tex]\displaystyle v_1'=-\frac{12.4(540)}{880}=-7.61\ m/s[/tex]
The recoil velocity of the cannon is 7.61 m/s in the opposite direction of the cannonball
Electrically charged sunspot gases which escape the sun's chromosphere and enter the earth's atmosphere near the magnetic north pole cause the _______.
Answer:
Northern Lights ( Aurora Borealis)
Explanation:
When the electricaly charged sunspot gases (they are named a solar wind) escape the sun's chromosphere and penetrates from the earth magnetic sheild which is called earth's magnetosphere then upon there interaction with atoms and molecules of our atmosphere there are little bursts of photons in the form of light which made up these northern lights.
A mxiture of n2 and H2 has mole fraction of 0.4 and 0.6 respectively. Determine the density of the mixture at one bar and 0 c.
Answer:
The density of the mixture is 0.55kg/m^3
Explanation:
P = 1bar = 100kN/m^2, T = 0°C = 273K, n = 0.4+0.6 = 1mole
PV = nRT
V = nRT/P = 1×8.314×273/100 = 22.70m^3
Mass of N2 = 0.4×28 = 11.2kg
Mass of H2 = 0.6×2 = 1.2kg
Mass of mixture = 11.2 + 1.2 = 12.4kg
Density of mixture = mass/volume = 12.4/22.7 = 0.55kg/m^3