The unique characteristic of the amino acid cysteine is _____.
a high level of acidity
its ability to form hydrogen bonds
its ability to form disulfide bridges a second amino group

The correct answer would be B. high concentration of hydroxyl ions, as bleach has a basic pH of about 13.

Hope this helps:)

A solution's hydronium ion concentration must fall as the concentration of hydroxide ions rises. In this instance, [H3O+] [OH-], and the remedy is regarded as basic. A high concentration of hydroxyl ions would expect bleach to have.

The chemical term for the diatomic anion OH is hydroxide. Other names for hydrogen dioxide include hydroxyl, hydroxyl radical, and hydroxide ion. It is made up of an atom of hydrogen and one of oxygen that are joined together by a covalent bond. A negative electric charge is present in the hydrogen.

A diatomic anion with the chemical formula OH is hydrogen oxide. It has a negative electric charge and is made up of two atoms of oxygen and hydrogen that are bound together by a single covalent bond.

A basic solution and a large concentration of hydroxide ions are indicated by a low pOH value.

Thus, option B is correct.

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Answer:

[tex]\boxed{\text{(E) }1.0 \times 10^{-3} \text{ mol/L and pH = 3}}[/tex]

Explanation:

1. Calculate the concentration of hydronium ion

We can use an ICE table to organize the calculations.

                      HA + H₂O ⇌ H₃O⁺ + A⁻

I/mol·L⁻¹:     0.100                  0        0

C/mol·L⁻¹:       -x                    +x      +x

E/mol·L⁻¹:   0.100 - x              x         x

[tex]K_{\text{a}} = \dfrac{\text{[H}_{3}\text{O}^{+}]\text{A}^{-}]} {\text{[HA]}} = 1.0 \times 10^{-5}\\\\\dfrac{x^{2}}{0.100 - x} = 1.0 \times 10^{-5}\\\\\\\text{Check for negligibility of }x\\\\\dfrac{ 0.100 }{1.0 \times 10^{-5}} = 10 000 > 400\\\\\therefore x \ll 0.100\\\\\\x^{2} = 0.100 \times 1.0\times 10^{-5} = 1.00 \times 10^{-6}\\\\x = \sqrt{1.00 \times 10^{-6}} = 1.0\times 10^{-3}\\\\\rm [H$_{3}$O$^{+}$]= x mol$\cdot$L$^{-1}$ = 1.0 $\times$ 10$^{-3}$ mol$\cdot$L$^{-1}$[/tex]

2. Calculate the pH

[tex]\text{pH} = -\log{\rm[H_{3}O^{+}]} = -\log{1.0 \times 10^{-3}} = \boxed{\mathbf{3}}[/tex]

Answer:

4909.486Kj/mol

Explanation:

the heat would be required to change steam at 100°c to water at 100°c then change the water at that temperature to water at 0°c then change water at 0°c to ice at 0°c then ice at 0°c to ice at -15°c

Answer : The heat released is, 319.28 kJ

Solution :

The conversions involved in this process are :

[tex](1):H_2O(g)(100^oC)\rightarrow H_2O(l)(100^oC)\\\\(2):H_2O(l)(100^oC)\rightarrow H_2O(l)(0^oC)\\\\(3):H_2O(l)(0^oC)\rightarrow H_2O(s)(100^oC)\\\\(4):H_2O(s)(0^oC)\rightarrow H_2O(s)(-15^oC)[/tex]

Now we have to calculate the enthalpy change.

[tex]\Delta H=n\times \Delta H_{condensation}+[n\times c_{p,l}\times (T_{final}-T_{initial})]+n\times \Delta H_{freezing}+[n\times c_{p,s}\times (T_{final}-T_{initial})][/tex]

where,

[tex]\Delta H[/tex] = enthalpy change = ?

Mass of water = 105 g

Moles of water = [tex]\frac{\text{Mass of water}}{\text{Molar mass of water}}=\frac{105g}{18g/mole}=5.83mole[/tex]

[tex]c_{p,s}[/tex] = specific heat of solid water = [tex]36.4J/(mol.^oC)[/tex]

[tex]c_{p,l}[/tex] = specific heat of liquid water = [tex]75.4J/(mol.^oC)[/tex]

[tex]\Delta H_{freezing}[/tex] = enthalpy change for freezing = enthalpy change for fusion = - 6.01 KJ/mole = - 6010 J/mole

[tex]\Delta H_{condensation}[/tex] = enthalpy change for condensation = enthalpy change for vaporization = -40.67 KJ/mole = -40670 J/mole

Now put all the given values in the above expression, we get

[tex]\Delta H=5.83mole\times -40670J/mole+[5.83mole\times 75.4J/(mol.^oC)\times (0-100)^oC]+5.83mole\times -6010J/mole+[5.83mole\times 36.4J/(mol.^oC)\times (-15-0)^oC][/tex]

[tex]\Delta H=-319285.78J=-319.28KJ[/tex]     (1 KJ = 1000 J)

Negative sign indicates that the heat is released during the process.

Therefore, the heat released is, 319.28 KJ

Answer : Verbal and non-verbal communication wad used by Investigators in the past when trying to determine if someone was lying.

Explanation: In the Verbal communication information is transferred from one person to other by speaking.

Non-verbal communication includes Facial expressions , eye contact , body language, eyes blinking etc.

If someone is lying he or she will easily dermined by applying above things.

Answer:

[tex]\boxed{\text{112 K}}[/tex]

Explanation:

A) Know

p₁ = Initial pressure;          p₂ = final pressure

V₁ =Initial volume;             V₂ = final pressure

T₁ = Initial temperature

B) Find

T₂ = final temperature

C) Strategy

Use the Combined Gas Laws Equation:

[tex]\dfrac{p_{1}V_{1}}{T_{1}} = \dfrac{p_{2}V_{2}}{T_{2}}[/tex]

It contains symbols for all the knowns and the unknown.

D) Calculations

(i) Data:

p₁ = 3.5 atm; p₂ = 1.5 L

V₁ = 3.2 L;     V₂ = 2.6 L

T₁ = 323 K     T₂ = ?

(ii) Calculation

[tex]\dfrac{3.5\times3.2}{323} = \dfrac{1.5\times 2.6}{T_{2}}\\\\0.0347 = \dfrac{3.90}{T_{2}}\\\\T_{2} = \dfrac{3.90}{0.0347} = \boxed{\textbf{112 K}}[/tex]

Answer:

Mg.

Explanation:

Mg + 1/2O₂ → MgO.

Mg is oxidized to Mg²⁺ in (MgO) (loses 2 electrons). "reducing agent".

O is reduced to O²⁻ in (MgO) (gains 2 electrons). "oxidizing agent".

Answer:

Kelvin

Explanation:

Answer:

[tex]p = \boxed{\text{593 torr}}[/tex]

Explanation:

For this question, we must use Dalton's Law of Partial Pressures:

The partial pressure of a gas in a mixture of gases equals its mole fraction times the total pressure:

[tex]p = \chi p_{\text{tot}}[/tex]

Data:

χ = 0.7808

[tex]p_{\text{tot}} = \text{ 760 torr}[/tex]

Calculation:

[tex]p = 0.7808 \times \text{ 760 torr}\\\\p= \boxed{\textbf{593 torr}}[/tex]

The partial pressure of nitrogen in the air, when the atmospheric pressure is 760 torr, is 593.4 torr. This is calculated using the given formula and the mole fraction of nitrogen.

The mole fraction of nitrogen (N₂) in the air is 0.7808 or 78.08%. This means that 78.08% of the molecules in the air are nitrogen. When talking about the partial pressure of gases, it means the contribution of that gas to the total pressure of the mixture. The partial pressure of any gas can be calculated using the formula P = (Patm) X (percent content in mixture). In this case, the atmospheric pressure (Patm) is 760 mm Hg, or torr. To find the partial pressure of nitrogen (N₂), multiply the atmospheric pressure by the mole fraction of nitrogen. So, Pₙ₂ = (760 torr) X (0.7808) = 593.4 torr. Therefore, when the atmospheric pressure is 760 torr, the partial pressure of nitrogen in the air is 593.4 torr.

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Answer:

[tex]\boxed{\text{[PCl$_{5}$] = 0.0077 mol/L; [PCl$_{3}$] = [Cl$_{2}$] = 0.117 mol/L}}[/tex]

Explanation:

The balanced equation is

PCl₅(g) ⇌ PCl₃(g) + Cl₂(g)

You don't give the volume of the flask, so I assume it is 1 L.

We can set up an ICE table to organize our calculations.

[tex]\begin{array}{lccccc} & \text{PCl}_{5} & \rightleftharpoons & \text{PCl}_{3} & + & \text{Cl}_{2} \\\text{I/mol}\cdot\text{L}^{-1}: & 0.125 & & 0 & & 0 &\\\text{C/mol}\cdot\text{L}^{-1}: & -x & & +x & & +x &\\\text{E/mol}\cdot\text{L}^{-1}:& 0.125-x & & x & & x &\\\end{array}[/tex]

[tex]K_{\text{c}} = \dfrac{\text{[PCl$_3$][Cl$_2$]}}{\text{[PCl$_5$]}} = \dfrac{x^{2}}{0.125-x} = 1.80[/tex]

Check for negligibility

[tex]\dfrac{0.125}{1.80} = 0.0674 < 400.[/tex]

x is not negligible, so we must solve a quadratic.

[tex]x^{2} = 1.80(0.125 - x)\\x^{2} = 0.225 - 1.80x\\x^{2} + 1.80x - 0.225 = 0\\[/tex]

Solve for x.

x = 0.1173

[PCl₅] = 0.125 - x = 0.125 – 0.1173 = 0.0077 mol·L⁻¹

[PCl₃] = x = 0.117 mol·L⁻¹

 [Cl₂] = x = 0.117 mol·L⁻¹

[tex]\boxed{\textbf{[PCl$_{5}$] = 0.0077 mol/L; [PCl$_{3}$] = [Cl$_{2}$] = 0.117 mol/L}}[/tex]

Check:

[tex]\dfrac{0.117^{2}}{0.0077} = 1.80\\\\\dfrac{0.0138}{0.0077} = 1.79[/tex]

Close enough. It checks.

In a chemical reaction when the reactants split to form two or more products are called a decomposition reaction. It is generally a breakdown of the reactants to yield products.

The concentrations of [tex]\rm PCl_{5}[/tex]  is 0.0077 mol/L, [tex]\rm PCl_{3}[/tex] and [tex]\rm Cl_{2}[/tex]  is 0.177 mol/L.

The balanced equation given is:

[tex]\rm PCl_{5} (g) \rightleftharpoons \rm PCl_{3} (g) + Cl_{2} (g)[/tex]

See the ICE table for the equation in the attached image below.

According to the table:

[tex]Kc = \dfrac{[\rm PCl_{3}] [Cl_{2}]}{[\rm PCl_{5}]}[/tex]

[tex]1.80 =\dfrac { x^{2} }{0.125 - x}[/tex]

Check the value for the negligibility:

[tex]\dfrac{0.125 }{1.80} = 0.0674 < 400[/tex]

From above it can be stated that it is not negligible and will be solved by the quadratic equation:

[tex]\begin{aligned}x^{2} &= 1.80 (0.125 - x)\\\\x^{2} &= 0.225 - 1.80x\\\\0 &= x^{2} + 1.80 x - 0.225\end{aligned}[/tex]

Solving further for x:

x = 0.1173

For gases:

[tex]\begin{aligned} \rm [PCl_{5}] &= 0.125 - x \\\\\rm [PCl_{5}] &= 0.125 - 0.1173 \\\\&= 0.0077 \;\rm mol L^{-1}\end{aligned}[/tex]

And,

[tex]\begin{aligned} \rm [PCl_{3}] &= 0.117 \;\rm mol L^{-1}\\\\\rm [Cl_{2}] &= 0.117 \;\rm mol L^{-1} \end{aligned}[/tex]

Therefore, the concentration of each gases are [tex]\rm PCl_{5}[/tex] is 0.0077 mol/L, [tex]\rm PCl_{3}[/tex] and [tex]\rm Cl_{2}[/tex] is 0.177 mol/L.

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Answer:

C. Spectrum of colors emitted by gas

Explanation:

Neils Bohr model of atom suggested that orbital electrons are divided into spherical orbits or energy levels around the central nucleus. In essence, electrons are located at various energy levels round the nucleus. His concept explained the discrete lines in the atomic spectrum of hydrogen. He suggested that electrons can move between different energy levels by simply gaining or losing energy.

The spectrum of colors emitted by a gas provides the evidence for Bohr's theory of atomic orbitals. This is because the spectral patterns match very well with Bohr's predictions of quantized energy levels for electrons.

The evidence that supports Bohr's theory of atomic orbitals comes from the spectrum of colors emitted by a gas when it is excited by heat or electrical charge. This is because Bohr's theory states that electrons live in distinct energy levels, or orbitals, and can absorb energy and 'jump' to a higher energy level. When they fall back down to their original level, they emit energy in the form of light (photons).

The discrete, or quantized, energy levels predicted by Bohr result in the emission of light in very specific wavelengths, creating a unique spectral pattern for each element. Such spectral patterns observed in the lab match very well with Bohr's predictions, providing strong evidence to support his theory.

Options A, B, and D refer to experiments and models that did contribute to the development of atomic theory, but aren't specifically tied to Bohr's model of the atom. For example, the gold foil experiment carried out by Rutherford was important for discovering the nuclear nature of atoms, but doesn't provide evidence for the existence of atomic orbitals.

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Answer:

The acid dissociation constant, _Ka__, is a quantitative measure of acid strength

Explanation:

Answer:

0.875 time.

Explanation:

The length of plastic water bottles are bought in the United States every day = (the no. of plastic water bottles are bought every day)(length of each bottle) = (140.0 million bottle)(0.25 m) = 35.0 million meter.

The length of the equator of the earth = 40.0 million meter.

∴ The times can the Earth's equator be circled by a line of plastic bottles used in the United States every day = (The length of plastic water bottles are bought in the United States every day)/(The length of the equator of the earth) = (35.0 million meter)/(40.0 million meter) = 0.875 times.

Answer:

as the world is changing we change also

Explanation:

We must always check and recheck are a hypothesis

Answer:

Explanation:

Because sometimes in the details of an experiment there are details hidden away that no one has thought to exploit.

I like to use Cancer as an example. Most cancers have drugs associated with them that are actually poisons (although  scientists are getting much, much better in reducing side effects).

But the main purpose until recently is an example of survival of the fittest. Think Darwin.  The drug kills off the cancer cells that are most easily killed off. That leaves the slower growing more deadly forms of the cancer behind and they finish the job, because there is nothing to control them, nor is anything competing with them.

Without finding this out, biologists would be at a loss of where to turn. Oncologists repeat the same treatment hundreds of times until the have a feel for how the cancer works. Then they are better equipped to tackle the problem a new.

Answer: B.22.4 liters

Explanation:

When we attribute to a certain fixed mass of a given gas a fixed number of molecules. Avogadro considered that the mass of 36g of oxygen at any temperature and pressure would have a fixed number of molecules to which he called 1 mol of molecules. So by definition 1 mole of molecules would have a number of molecules equal to that present in 36 g of oxygen. The occupied volume by one mole of molecules at a given temperature and pressure is called molar volume and consists in 22,4 Liters. The molar volume matches the Avogadro Hypothesis (created in 1811 by Amedeo Avogadro), where equal volumes of different gases, at the same temperature and pressure, have even number of moles.

At standard temperature and pressure (STP), 1 mole of any gas will occupy a volume of 22.4 liters. This is a universal truth for all ideal gases.

The volume of 1 mole of any gas at standard temperature and pressure (STP) is defined by Avogadro's law. According to this law, the volume of 1 mole of gas at STP is 22.4 liters. Therefore, the correct answer to your question is B. 22.4 liters. This applies to all ideal gases, assuming that temperature is 0°C and pressure is 1 atmosphere.

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Answer:

Part A: 6HClO₄(aq) + Fe₂O₃(s) → 2Fe(ClO₄)₃(aq) + 3H₂O(l).

Part B: H₂SO₄(aq) + Sr(s) → SrSO₄(s) + H₂(g).

Part C: H₃PO₄(aq) + 3KOH(aq) → K₃PO₄(aq) + 3H₂O(l).

Explanation:

Part A: complete HClO₄(aq) + Fe₂O₃(s)→ Express your answer as a balanced chemical equation. Identify all of the phases in your answer.

6HClO₄(aq) + Fe₂O₃(s) → 2Fe(ClO₄)₃(aq) + 3H₂O(l).

It is clear that 6 mol of HClO₄ (in aqueous phase) react with 1 mol of Fe₂O₃ (in solid phase) to produce 2 mol of Fe(ClO₄)₃ (in aqueous phase) and 3 mol of H₂O (in liquid phase).

Part B: H₂SO₄(aq) + Sr(s) → Express your answer as a balanced chemical equation. Identify all of the phases in your answer.

H₂SO₄(aq) + Sr(s) → SrSO₄(s) + H₂(g).

It is clear that 1 mol of H₂SO₄ (in aqueous phase) reacts with 1 mol of Sr (in solid phase) to produce 1 mol of SrSO₄ (in solid phase) and 1 mol of H₂ (in gas phase).

Part C: H₃PO₄(aq) + KOH(aq) → Express your answer as a balanced chemical equation.

H₃PO₄(aq) + 3KOH(aq) → K₃PO₄(aq) + 3H₂O(l).

It is clear that 1 mol of H₃PO₄ (in aqueous phase) react with 3 mol of KOH (in aqueous phase) to produce 1 mol of K₃PO₄ (in aqueous phase) and 3 mol of H₂O (in liquid phase).

Answer:The second law

Answer:

second

Explanation:

Answer:

[tex]\boxed{\text{B.}}[/tex]

Explanation:

B.

[tex]\rm C$_7$H_{16}$ + 11O$_2$ $\longrightarrow \,$ 7CO$_2$ + 8H$_2$O[/tex]

BALANCED. 7C, 16H, and 22O on each side of equation.

A.

[tex]\rm C$_7$H$_{16}$ + 5O$_2$ $\longrightarrow \,\rm 6CO$_2$ + 4H$_2$O[/tex]

NOT BALANCED. 7C on left and 6C on right.

C.

[tex]\rm C$_7$H$_{16}$ + 14O$_2$ $\longrightarrow \,$ 7CO$_2$ + 5H$_2$O[/tex]

NOT BALANCED. 16H on left and 10H on right.

D.

[tex]\rm C$_7$H$_{16}$ + 22O$_2$ $\longrightarrow \, $ 14CO$_2$ + 16H$_2$O[/tex]

NOT BALANCED. 7C on left and 14C on right.

Answer:

Explanation:

Since, for ideal gases the temperature is in direct relation to the volume and the pressure, you can predict that if the volume is doubled and the pressure is tripled the effect on the temperature will be 3 × 2 = 6 times.

You can prove it using the combined law of gases:

Where the letters P denote absolute pressures, the letters T denote temperature measured in absolute scale, and the letters V denote volume.

The changes given may be written it this way:

Then, you can write T₂ in terms of the other variables:

Cancel the common factors P₁ and V₁

Which proves that the final temperature is 6 times the initial temperature.

By tripling the pressure and doubling the volume, the gas temperature changes by a factor of 6 according to the combined gas law.

To determine by what factor the gas temperature changes if the volume is doubled and the pressure is tripled, we can use the combined gas law, which is a combination of Boyle's, Charles's, and Gay-Lussac's laws. The combined gas law states that for a given amount of gas, the ratio of the product of pressure (P) and volume (V) to the temperature (T) is constant, or:

(P₁ * V₁) / T₁ = (P₂ * V₂) / T₂

Assuming the initial conditions are P₁, V₁, and T₁, and after the changes they are P₂ = 3 * P₁, V₂ = 2 * V₁, and T₂, we can rearrange the equation to solve for T2/T1:

(3 * P₁ * 2 * V₁) / T₂ = (P₁ * V₁) / T₁

(6 * P₁ * V₁) / T₂ =  (P₁ * V₁)/ T₁

T₂ / T₁ = 6 * (P₁ * V₁) / (P₁ * V₁)

T₂ / T₁ = 6

So by tripling the pressure and doubling the volume, the temperature of the gas increases by a factor of 6. This result agrees with our understanding of the behavior of gases when subjected to changes in temperature, volume, and pressure.

Answer:

Explanation:

1) Since the average kinetic energy of a gas is only dependent on its temperature, you conclude that, at the same temperature of 70°C, the average kinetic energy of He atoms is the same that the average kinetic energy of NH₃ molecules: 7.1 × 10⁻²¹ J / molecule.

2) Now, you can use the equation that relates the average kinetic energy with the mean-square speed:

Where:

You need to use the atomic mass of helium to find the mass (average) of one atom of helum:

        m = 4.003 g/ mol / (6.022 × 10²³ atoms/mol)

        m = 6.647 × 10⁻²⁴ g = 6.647 10 ⁻²⁷ kg / atom

3) Solve for v², substitute, and compute:

Note: since He is a monoatomic molecule, kg/atom = kg/molecule.

            = 2.14 × 10⁶ m²/s² ← answer

Answer:

metals as they have free electrons

Answer:

The answer is metals

Explanation:

Metals, for example mercury (Hg), iron (Fe) and copper (Cu), have metallic bonds. In this kind of bond the electrons are deslocalized. That means that electrons moves from one atom to another, by forming a "sea of electrons". Several properties of metals, such as electrical and thermal conductivity, are explained by this model of chemical bond.

Answer:

Here's how I would explain it.

Explanation:

Think of it this way.

When you mix solutions of silver nitrate and sodium chloride, you get an immediate precipitate of silver chloride. The equation is

Ag⁺(aq) + Cl⁻(aq) ⟶ AgCl(s)

Now, take some AgCl and stir it vigorously with water.

You won't see much happening, because the AgCl is has such a low solubility. Not much of it will go into solution. And yet, a small amount of it does dissolve until the solution is saturated.

The concentration of AgCl in the saturated solution is

about 0.000 01 mol·L⁻¹.

I hope you will agree that this is a dilute solution even though it is saturated with AgCl.

Answer: The strongest inter particle force in [tex]MgCl_2[/tex] is electrostatic force of attraction.

Explanation:

Magnesium chloride is an ionic compound which is formed by the combination of magnesium ions and chloride ions.

Ionic compounds are defined as the compounds which are formed by the complete transfer of electrons from one atom to another atom.

In these compounds, oppositely charged ions are attracted towards each other to form a compound.

The attraction between oppositely charged species is very strong and is known as electrostatic force of attraction.

Hence, the strongest inter particle force in [tex]MgCl_2[/tex] is electrostatic force of attraction.

Answer:

At-207 (meaning At with the number on the top left being 207 and the number at the bottom left being 85.

Explanation:

The sum of the mass numbers has to equal on both sides, so we need 211 = 4+a

a=207

The sum of the atomic numbers as to equal on both sides, so 87=2+b

b=85

The element is determined by the mass number.

Answer:

marie curie

Explanation:

It is Marie Curie who is a famous scientist for her research on radioactivity...

Answer:

- 228.6 kJ/mol.

Explanation:

∵ ΔGrxn = ∑ΔGf, products - ∑ΔGf, reactants

4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O,  

∴ ΔGrxn = [6(ΔGf, H₂O) + 4(ΔGf, NO)] - [4(ΔGf, NH₃) + 5(ΔGf, O₂)]

ΔGrxn = – 957.9 kJ, ΔGf, H₂O = ??? KJ/mol, ΔGf, NO = 86.71 kJ/mol, ΔGf, NH₃ = - 16.66 kJ/mol, ΔGf, O₂ = 0.0 kJ/mol.

∴ – 957.9 kJ = [6(ΔGf, H₂O) + 4(86.71 kJ/mol)] - [4(- 16.66 kJ/mol) + 5(0.0 kJ/mol)].

– 957.9 kJ = 6(ΔGf, H₂O) + 346.8 kJ/mol + 66.64 kJ/mol

– 957.9 kJ = 6(ΔGf, H₂O) + 413.8 kJ/mol

6(ΔGf, H₂O) = – 957.9 kJ - 413.8 kJ/mol = - 1372 kJ/mol.

∴ ΔGf, H₂O = (- 1372 kJ/mol)/6 = - 228.6 kJ/mol.

Answer:

Explanation:

1) Data:

a) m = 20. g

b) ΔT = 35°C - 25°C

c) Cs = 0.13 J / g°C

2)  Formula:

3) Solution:

The answer shows two significant figures.

The energy absorbed as heat by 20.0 g of gold when it is heated from 25ºC to 35ºC is 26.0 joules.

To find the amount of energy absorbed as heat by a substance, we can use the formula:

[tex]\[ Q = m \cdot c \cdot \Delta T \][/tex]

where:

- Q is the heat energy absorbed (in joules),

- m is the mass of the substance (in grams),

- c is the specific heat capacity of the substance (in joules per gram per degree Celsius),

- [tex]\( \Delta T \)[/tex] is the change in temperature (in degrees Celsius).

 Given:

- The mass of gold, m = 20.0  g,

- The specific heat capacity of gold, c = 0.13  J/g·ºC,

- The change in temperature,[tex]\( \Delta T[/tex] = 35ºC - 25ºC = 10ºC .

 Plugging these values into the formula, we get:

[tex]\[ Q = 20.0 \text{ g} \cdot 0.13 \text{ J/g.C} \cdot 10.C \] \[ Q = 20.0 \cdot 0.13 \cdot 10 \] \[ Q = 26.0 \text{ J} \][/tex]

Therefore, the energy absorbed as heat = 26.0 joules.

the answer is in the picture

Answer: 2HCL (aq) + ZN(s) ZnCl2(s) = H2(g)

Explanation:

Answer:

Explanation:

A hydrocarbon with a double bond in its carbon skeleton is an alkene and has the general form:

This is, the number of hydrogen atoms is twice the number of carbon atoms.

On the other hand, alkanes have only single bonds, and the compounds with a triple bond in its carbon skeleton are alkynes.

Review each choice:

1) C₃H₈:

2) C₂H₆

3) CH₄

4) C₂H₄

So, this is the correct answer.

5) C₂H₂

Answer:

3) ester

Explanation:

Esterification is the process in which alkanol and alkanoic acids reacts in the presence of a catalyst and heat. The product is usually an ester(alkanoate) and water.

For the reaction between ethanoic acid and 1-butanol, the product is butylethanoate and water as shown below:

               CH₃COOH + C₄H₈OH → CH₃COOC₄H₈ + H₂O