We can show that triangle abc is congruent to triangle a prime b prime c prime by translation of

Answer:

C) 4

Step-by-step explanation:

The given function is

[tex]f(x)=\left \{ {{2x+5,\:-6\:<\:x\le0} \atop {-2x+3,\:0\:<x\le4}} \right.[/tex]

The function is defined on two intervals.

The first interval is

[tex]-6\:<\:x\le0[/tex] and the second interval is [tex]\:0\:<x\le4[/tex].

[tex]-7[/tex] does not belong to any of these intervals.

[tex]-6[/tex] does not also belong to any of these intervals.

[tex]4[/tex] belongs to the interval [tex]\:0\:<x\le4[/tex].

Hence 4 is in the domain of f(x).

[tex]5[/tex] does not also belong to any of the intervals.

Therefore the correct answer is C.

For this case, we use the cylindrical coordinates: 
x² + y² = r² 
dV = r dz dr dθ 

The limits are:
z = 0 to z = 1/(r²)^10 = 1/r^20
r = 1 to ∞ 
θ = 0 to 2π 

Integrating over the limits:
V = ∫ [0 to 2π] ∫ [1 to ∞] ∫ [0 to 1/r^20] r dz dr dθ 
V = ∫ [0 to 2π] ∫ [1 to ∞] rz | [z = 0 to 1/r^20] dr dθ 
V = ∫ [0 to 2π] ∫ [1 to ∞] 1/r^19 dr dθ 
V = ∫ [0 to 2π] −1/(18r^18) |[1 to ∞] dθ 
V = ∫ [0 to 2π] 1/18 dθ 
V = θ/18 |[0 to 2π] 
V = π/9

The volume of the volcano is an illustration of definite integral

The volume of the volcano is: [tex]\mathbf{\frac{1}{9}\pi}[/tex]

The graphs are given as:

[tex]\mathbf{z = 0}[/tex] and [tex]\mathbf{z = \frac{1}{(x^2 + y^2)^{10}}}[/tex]

The cylinder is:

[tex]\mathbf{x + y =1}[/tex]

For cylindrical coordinates, we have:

[tex]\mathbf{r^2 =x^2 + y^2}[/tex]

So, we have:

[tex]\mathbf{z = \frac{1}{(r^2)^{10}}}[/tex]

[tex]\mathbf{z = \frac{1}{r^{20}}}[/tex]

Where:

[tex]\mathbf{r = 1 \to \infty}[/tex]

[tex]\mathbf{\theta = 0 \to 2\pi}[/tex]

So, the integral is:

[tex]\mathbf{V = \int\limits^{2\pi}_0 {\int\limits^{\infty}_1 {\frac{1}{r^{20}}} \, r\ dr } \, d\theta }[/tex]

Cancel out r

[tex]\mathbf{V = \int\limits^{2\pi}_0 {\int\limits^{\infty}_1 {\frac{1}{r^{19}}} \, dr } \, d\theta }[/tex]

Rewrite as:

[tex]\mathbf{V = \int\limits^{2\pi}_0 {\int\limits^{\infty}_1 {r^{-19}} \, dr } \, d\theta }[/tex]

Integrate

[tex]\mathbf{V = \int\limits^{2\pi}_0 {{-\frac{1}{18}r^{-18}}} |\limits^{\infty}_1 \, d\theta }[/tex]

Expand

[tex]\mathbf{V = \int\limits^{2\pi}_0 {{-\frac{1}{18}(\infty^{-18} -1^{-18}) }} , d\theta }[/tex]

[tex]\mathbf{V = \int\limits^{2\pi}_0 {{-\frac{1}{18}(0 -1) }} , d\theta }[/tex]

[tex]\mathbf{V = \int\limits^{2\pi}_0 {{-\frac{1}{18}( -1) }} , d\theta }[/tex]

[tex]\mathbf{V = \int\limits^{2\pi}_0 {{\frac{1}{18} }} , d\theta }[/tex]

Integrate

[tex]\mathbf{V = \frac{1}{18}(\theta)|\limits^{2\pi}_0}[/tex]

Expand

[tex]\mathbf{V = \frac{1}{18}(2\pi - 0)}[/tex]

[tex]\mathbf{V = \frac{1}{18}(2\pi )}[/tex]

Cancel out 2

[tex]\mathbf{V = \frac{1}{9}\pi}[/tex]

Hence, the volume is: [tex]\mathbf{\frac{1}{9}\pi}[/tex]

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Answer: circumference = 308mm

Step-by-step explanation: the formula for the circumference of a circle is given by

C=2πr

Given that r=49mm

Pi=22/4

C=2*22/7*49

C=44*7=308mm

In geometry, the circumference of a circle is the distance around it. That is, the circumference would be the length of the circle if it were opened up and straightened out to a line segment. Since a circle is the edge of a disk, circumference is a special case of perimeter.

Answer: it is  a

Step-by-step explanation: :) :v :B

Answer: H=2

Step-by-step explanation:

we just need to complete the square for the x terms

gropu x terms

x^2-4x

take 1/2 of linear coefient and square it

-4/2=-2, (-2)^2=4

x^2-4x+4

factor

(x-2)^2

h=2

The value of h is 2.

Completing the square for the x terms by grouping x terms

x^2-4x

Taking 1/2 of linear coefficient and squaring it.

-4/2=-2, (-2)^2=4

x^2-4x+4

Factorizing the equation.

(x-2)^2

h=2.

An equation is a mathematical statement this is made of two expressions related with the aid of an identical sign. As instance, 3x – 5 = 16 is an equation. To fix this equation, we get the value of the variable x as x = 7.

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Answer:

6 days

Step-by-step explanation:

Given that one student can paint a wall in 10 minute and another student in 15 minutes.

Since if number of persons increase, painting time decreases, this is a question of inverse proportion

Hence if they work together they can paint in one day

[tex]\frac{1}{10} +\frac{1}{15}[/tex] part of the work

i.e. work completed in 1 day when they work together

=[tex]\frac{1}{10} +\frac{1}{15} \\=\frac{9+6}{90} \\=\frac{1}{6}[/tex]

Hence in 6 days they can together complete the full work

A)$391,000

B)$417,000

C)$404,000

D)$411,000

My answer is D) $411,000 in 2011.

There is an average increase of 4% from the previous budget to arrive at the amount of the current year. 

2009 budget $381,700

381,700 * (1.04)² = 381,700 * 1.0816 = 412,846.72  only Choice D. is nearest to the amount

2000 budget $265,100

265,100 * (1.04)¹¹ = 265,100 * 1.540 = 408,254 only Choice D. is nearest to the amount.

Step 1

Find the slope of the given line

we have

[tex]10x+2y=-2[/tex]

Isolate the variable y

Subtract [tex]10x[/tex] both sides

[tex]2y=-10x-2[/tex]

Divide by [tex]2[/tex] both sides

[tex]y=-5x-1[/tex]

The slope of the given line is

[tex]m=-5[/tex]

Step 2

Find the equation of the line that is parallel to the given line and passes through the point [tex](0, 12)[/tex]

we know that

If two lines are parallel. then their slope are equal

In this problem we have

[tex]m=-5[/tex]

[tex](0, 12)[/tex]

The equation of the line into slope-intercept form is equal to

[tex]y=mx+b[/tex]

substitute the values

[tex]12=-5*0+b[/tex]

[tex]b=12[/tex]

the equation of the line is

[tex]y=-5x+12[/tex]

therefore

the answer is

[tex]y=-5x+12[/tex]

Final answer:

The algebraic expression representing 'two less than twice a number is the same as four times the number' is solved, resulting in the number being -1.

Explanation:

The student's question involves solving a simple algebraic equation. We are given that two less than twice a number is the same as four times the number. To represent this algebraically, let's let the unknown number be n. The phrase 'twice a number' can be written as 2n. 'Two less than' this expression would be 2n - 2. The statement implies this is equal to four times the number, which is 4n. Therefore, the equation we need to solve is 2n - 2 = 4n. To solve this equation, we need to isolate the variable n on one side of the equals sign.

Subtract 2n from both sides: -2 = 2n.

Divide both sides by 2 to find the value of n: n = -1.

In conclusion, the number that satisfies the condition given is -1.

Answer: 113.04 sq. units

To find the upper and lower limits of a 95% confidence interval for the given data, calculate the standard error, use the multiplier of 2, and apply the formula Sample mean ± Multiplier * Standard error.

To calculate the upper and lower limit for a 95% confidence interval, we use the formula: Confidence interval = Sample mean ± Multiplier * Standard error. For this case, the sample mean is $94 and the standard deviation is $10. The standard error is calculated as $10 / √36 = $10 / 6 ≈ $1.67.

With a 95% confidence level, the multiplier is approximately 2. Therefore, the upper limit would be $94 + 2($1.67) = $94 + $3.34 ≈ $97.34, and the lower limit would be $94 - $3.34≈ $90.66.

Final answer:

Correcting for the apparent typo in the question, assuming 'c' refers to an angle and a side length respectively, there can only be one possible triangle formed given the angle and two sides. This is based on geometric principles where a unique triangle can be determined from an angle opposite and its respective side length.

Explanation:

The question presents a probable typo since it mentions two different values for 'c'. Assuming 'c = 85°' refers to an angle, and 'c = 13' refers to the length of a side opposite this angle, the proper interpretation involves finding possible triangles given an angle and two sides. However, the principles of geometry dictate that with one angle and two sides specified, especially in this non-ambiguous manner where one side length and the angle opposite are known, one can determine a unique triangle, assuming the given information leads to a viable geometric figure.

By using the Law of Sines, one might attempt to find the other angles or sides, but since we only have one angle and one side length, we directly know there's no ambiguity - geometrically speaking, there's only one way to construct such a triangle, thus, only one possible triangle can be formed given the corrected assumptions.

Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion.  1.97 is the time taken by the ball to hit the ground.

Distance is a scalar quantity that refers to "how much ground an object has covered" during its motion.

Given that a ball is thrown from a height of 70 feet with an initial downward velocity of 4/fts. The ball's height h (in feet) after t seconds is given by the following.

h=70-4t-16t²

Now we can take h=0

h=-16t²+70-4t

-16t²+70-4t

Divide by 2

-8t²-2t+35

Now apply quadratic formula

a=-8, b=-2, c=35

t=-b±√b²-4ac/2a

t=2±√-2²-4(-8)(35)/2(-8)

t=2±√4+1120/-16

we get t= 1.97 and t= -2.22

You get the numbers to be : 1.97 and -2.22

We do not consider negative values. So the correct answer is 1.97

Hence 1.97 is the time taken by the ball to hit the ground.

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