What are two main ways that minerals are classified

It is Shale And Sandstone

The options that give two examples of clastic sedimentary rock are Shale and Sandstone. The correct option is D.

Sedimentary rocks are those rocks that are formed by the accumulation of minerals and organic particles at the surface of the earth. These rocks are made by the heat and pressure of the earth, which convert the organic material and minerals into rocks.

There are different types of sedimentary rocks. These are sandstone, limestone, and shale. They are mainly formed by the accumulation of minerals from rivers.

Clastic sedimentary rock is formed by fragments or pieces of sedimentary rocks. These are formed when the pieces are broken or fragmented by forces and are present in the basin of the earth's surface.

Thus, the correct option is D. Shale and Sandstone.

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Final answer:

The Law of Conservation of Energy states that energy cannot be created or destroyed but can only change form. This law is fundamental to understanding the behavior of energy in various systems.

Explanation:

The question pertains to the basic laws that govern energy behavior in physics. The main law that defines what happens to energy is known as the Law of Conservation of Energy. This pivotal law asserts that energy cannot be created or destroyed, but can only change from one form to another.

For instance, electrical energy can be converted into thermal energy, kinetic energy can be transformed into potential energy, and so forth.

In a physical process, energy may seem to 'disappear' as it changes form, such as when friction converts kinetic energy into heat energy that is dispersed into the environment. However, the total energy before and after the process remains the same, affirming that energy is conserved.

Furthermore, looking at the broader perspective, the energy within a closed system remains constant over time. The only changes that occur are the forms of energy; for example, within an ecosystem, the chemical energy in food is converted into kinetic energy by animals, and ultimately into heat energy when it is used by organisms.

Ultimately, energy might leave the planet in the form of heat radiating into space, but overall, it stays within the Earth-sun system, converting and moving from one place to another.

The question refers to nuclear physics and can be interpreted using the concept of half-life. In the given scenario, three half-lives have passed in the decay of calcium-47 from 4.80 mg to 1.2 mg. Therefore, the time passed is three times the half-life of calcium-47.

This question can be solved using the concept of half-life, which is widely used in nuclear physics and radioactive decay calculations. Since the half-life represents the time taken for half of a substance to decay, you can use the known half-life of Calcium-47, if provided, to figure out the time that has passed. Given we started with 4.80 mg and are left with 1.2 mg of Calcium-47 implies three half-lives have passed (as 4.80 mg to 2.4 mg is one half-life, 2.4 mg to 1.2 mg is a second half-life and finally 1.2 mg to 0.6 mg is the third half-life). Therefore, the time elapsed is equal to three times the half-life.

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Answer:

The answer is Zinc

Explanation:

The number of protons is the atomic number. Looking a periodic table, you can see this atomic number for all elements.

Nickel has twenty-eight protons, so, their atomic number is twenty-eight.

Zinc has as atomic number thirty. so, Zinc has thirty protons. Two more than Nickel.

The answer is AlF3. Hopes this helps.

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Answer:

Figure A depicts dissolution, B and F depict straining. Figure C depicts the use of filter paper. Figure D shows the evaporation process. Figure E shows separation with the help of a magnet.

Explanation:

The techniques mentioned in the images are separation techniques.

Straining is the separation process in which the particles are separated on the basis of size with the help of a filter. The filter will set the cut-off value and the particles are separated.

In Figure B with the help of a strainer, the water from the spaghetti is removed. So figure B possesses straining.

In figure F the tea leaves are separated from the tea with a strainer. Thus Figure F also depicts the straining technique.

The use of filter paper is made to differentiate the particles of very small size. In figure C, filter paper is used to separate the solute in the solution.

The separation of iron is made with the use of a magnet. Magnet has the ability to attract iron towards it.

In figure E, iron nails are being separated with the help of a magnet.

Dissolving is the process of making two solutes miscible in a solution. In figure A, sugar was made to dissolve in water making a miscible solution. Sand is allowed to dissolve in water making an immiscible solution.

Evaporation is the process of converting liquid to vapor form.

Figure D posses the evaporation process in which water is evaporated in the form of vapor, leaving the salt behind.

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A.  The pressure will remain unchanged.

B.  The pressure will increase by 1.5P.

C.  The pressure will decrease by 3P.

D.  The pressure will increase by 3P.

Salt is usually formed during neutralization reactions, that is the reaction of an acid and a base. This is illustrated as follows:

HX + YOH -->  XY + H2O

where XY is the salt

From the given choices, the only pair of acid and base is:

Vinegar and antacids

Answer is: vinegar and antacids.

Neutralizationis is reaction in which an acid (in this example vinegar or acetic acid CH₃COOH)  and a base (in this example antacid, aluminium hydroxide, magnesium hydroxide or some other base) react quantitatively with each other.

Balanced chemical reaction of vinegar and antacid:

2CH₃COOH(aq) + Mg(OH)₂(aq) → (CH₃COO)₂Mg(s) + 2H₂O(l).

Magnesium acetate ((CH₃COO)₂Mg) is a salt.

Answer : No it is not balanced. it has more Cl on the product side than the reactant side.

Explanation :

The given chemical equation is,

[tex]2Na+Cl\rightarrow 2NaCl[/tex]

But the net balanced chemical equation is,

[tex]2Na+Cl_2\rightarrow 2NaCl[/tex]

Law of conservation of matter : In a chemical reaction, the mass of products must be equal to the mass of reactants.

The mass of reactant side, 2Na + [tex]Cl_2[/tex] = 2(23) + 2(35.5) = 117

The mass of product side, 2NaCl = 2(23 + 35.5) = 117

This means, the mass of product is equal to the mass of reactant. The mass remains conserved.

The mass of reactant side, 2Na + Cl = 2(23) + 35.5 = 81.5

The mass of product side, 2NaCl = 2(23 + 35.5) = 117

This means, the mass of product is not equal to the mass of reactant. The mass is not conserved.

C. Homogeneous mixtures These alloys are homogeneous mixtures because they have a uniform composition throughout.

Answer:

Homogeneous Mixture

Explanation:

C : " Neutrons are inside the nucleus of an atom" is the answer because, Rutherford  theorized if the neutrons were in the center and the electrons were orbiting in separate energy levels the protons would be in the nucleus to keep the neutrons from floating. If the nucleus has neutral and positive particles, then it will be positive nucleus. Hope this helps

The discovery that added to Rutherford's discovery of a positive nucleus is neutrons are inside the nucleus of an atom.

Rutherford, through his ground breaking experiment with a thin gold foil was able to show that the nucleus is composed of a positively charged core called the nucleus.

In addition to this discovery, Chadwick in 1932 discovered the neutrons which are neutral particles but are also contained in the nucleus. They contribute to the mass of the atom.

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The electrode potential values of [tex]{\text{L}}{{\text{i}}^ + }[/tex] ,[tex]{\text{N}}{{\text{a}}^ + }[/tex] and [tex]{{\text{K}}^ + }[/tex] are [tex]\boxed{ - 3.045{\text{ V}}}[/tex] , [tex]\boxed{ - {\text{2}}{\text{.714 V}}}[/tex] and [tex]\boxed{ - {\text{2}}{\text{.925 V}}}[/tex]respectively.

Further explanation:

Electrochemical cells are the devices that are used to generate an electric current from the energy released by the spontaneous redox reaction. Redox reactions involve the transfer of electrons between the chemical species by oxidation and reduction process. The oxidation process represents the loss of electrons and reduction process represents the gain of electrons.

In order to determine the standard reduction potential, the electrode is coupled with standard hydrogen electrode as illustrated in the attached image. The SHE acts as anode and the metal electrode acts as the cathode. The value of reduction potential for hydrogen has been assigned as 0.00 V.

The formula to calculate cell potential [tex]\left( {{E_{{\text{cell}}}}} \right)[/tex] of the reaction when the reduction occurs as cathode and oxidation occur at anode is as follows:

 [tex]{E_{{\text{cell}}}} = {E_{{\text{cathode}}}} - {E_{{\text{anode}}}}[/tex]

The expression of Nernst equation that relates the reduction potential of a half or full electrochemical cell reaction to the standard electrode potential is given as,

[tex]{E_{{\text{cell}}}} = E_{{\text{cell}}}^\circ - \dfrac{{2.303RT}}{{nF}}\log \dfrac{{\left[ P \right]}}{{\left[ R \right]}}[/tex]               ……. (1)

Here,

[tex]{E_{{\text{cell}}}}[/tex] is cell potential.

[tex]E_{{\text{cell}}}^\circ[/tex] is standard cell potential.

[tex]R[/tex] is gas constant and is equal to [tex]8.314{\text{ J/K}} \cdot {\text{mol}}[/tex].

[tex]T[/tex] is temperature.

[tex]n[/tex] denotes the number of moles of electrons transferred in the reaction.

[tex]F[/tex] is Faraday constant and is equal to [tex]95484.56{\text{ C/mol}}[/tex] .

[tex]\left[ P \right][/tex] is the concentration of product.

[tex]\left[ R \right][/tex] is the concentration of reactant.

At standard temperature [tex]25\;^\circ {\text{C}}\left( {298{\text{ K}}} \right)[/tex] the value of  [tex]\dfrac{{2.303RT}}{F}[/tex] is equal to [tex]0.0592{\text{ V}}[/tex]. Thus the equation(1) is written as,

[tex]{E_{{\text{cell}}}} = E_{{\text{cell}}}^\circ - \dfrac{{0.0591}}{n}\log \dfrac{{\left[ P \right]}}{{\left[ R \right]}}[/tex]         …… (2)

Knowing the concentration of the electrolyte solutions taken in the cathodic compartment and substituting the values in the Nernst equation gives the reduction potential for the half cell.

The electrode potential values of [tex]{\mathbf{L}}{{\mathbf{i}}^{\mathbf{ + }}}[/tex] ,[tex]{\mathbf{N}}{{\mathbf{a}}^{\mathbf{ + }}}[/tex] and [tex]{{\mathbf{K}}^{\mathbf{ + }}}[/tex] are [tex]{\mathbf{ - 3}}{\mathbf{.045 V}}[/tex],  [tex]{\mathbf{ - 2}}{\mathbf{.714 V}}[/tex] and [tex]{\mathbf{ - 2}}{\mathbf{.925 V}}[/tex] respectively as determined with respect to standard hydrogen electrode at [tex]{\mathbf{298 K}}[/tex].

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Answer details:  

Grade: Senior School

Subject: Chemistry

Chapter: Electrochemistry

Keywords: Electrochemical cells, Redox reactions, Oxidation, reduction, cell potential, half-cell, Nernst equation and Faraday constant.

The reduction potential describes the ease with which electrons are accepted by chemical species.

The term reduction potential is a measure of the ease with which a chemical specie accepts electrons and becomes "reduced". The more negative the reduction potential of a chemical specie, the more difficult it is for that chemical specie to accept electrons and become reduced.

The reduction potentials of  lithium, sodium, and potassium are as follows;

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Answer is: To carry information to cells in the body at different places from where it's released into the blood.

Hormones are chemical messengers that travel through the blood and body fluids to organs and tissues to modify and control functions.

For example, estrogen and testosterone are hormones.

Testosterone is synthesized in several steps from cholesterol and is converted in the liver. It is the male sex hormone and an anabolic steroid.

Estrogen is synthesis in theca interna cells in the ovary, by the synthesis of androstenedione from cholesterol. It is the primary female sex hormone.

solid

extra charecters cuz i need them

Metalloids are those elements which  possess the characters of both metals and non-metals  .

A metalloid is an element that has properties between  metals and nonmetals. Metalloids can also be called semimetals.

Important use of metalloid is -:

Metalloids are useful in the semiconductor industry.

Properties of metalloids are -:

These mentioned properties describes about the properties of metalloids.

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Answer;

C. seafloor spreading

Explanation;

The theory of seafloor spreading states that new ocean crust is continually being formed, and that this crust is slowly carried away from its point of origin over a period of time.

Paleomagnetism helped explain an unusual observation from the 1950s. Magnetic studies revealed that the ocean floor was comprised of parallel bands of crust having alternating magnetic polarity.These magnetic bands were symmetric about the mid-oceanic ridge.