Answer:
There are three possible chemical equations for the combustion of sulfur:
2S (s) + O₂ (g) → 2SO (g)S (s) + O₂ (g) → SO₂ (g)2S (s) + 3O₂ (g) → 2SO₃ (g)Explanation:
Combustion is a reaction with oxygen. The products of the reaction are oxides, and energy is released in the form of heat and light.
Sulfur iis a nonmetal, so the oxide formed is a nonmetal oxide.
The most common oxidation numbers of sulfur are -2, + 2, + 4, and + 6.
The combination of sulfur with oxygen may be only with the positive oxidation numbers (+2, + 4, and +6).
Then you have three different equations for sulfur combustion:
1) Oxidation number +2:
S(s) + O₂(g) → SO(g)Which when balanced is: 2S(g) + O₂(g) → 2SO(g)
2) Oxitation number +4:
S(s) + O₂(g) → SO₂(g)That equation is already balanced.
3) Oxidation number +6:
S(s) + O₂(g) → SO₃(g)Which when balanced is: 2S(s) + 3O₂(g) → 2SO₃(g)
The balanced equation for the combustion of sulfur is [tex]\[ \text{S}(s) + \text{O}_2(g) \rightarrow \text{SO}_2(g) \][/tex]
To balance this equation, we need to ensure that the number of atoms of each element is the same on both sides of the equation. Sulfur (S) is present as a diatomic molecule [tex](S_2)[/tex] when it reacts with oxygen [tex](O_2)[/tex] to form sulfur dioxide [tex](SO_2)[/tex]. The balanced equation considering the diatomic nature of sulfur is:
[tex]\[ \text{S}_2(s) + \text{O}_2(g) \rightarrow 2\text{SO}_2(g) \][/tex]
Here's the step-by-step process to balance the equation:
1. Start by writing the unbalanced equation with the correct formulas for the reactants and products:
[tex]\[ \text{S}_2 + \text{O}_2 \rightarrow \text{SO}_2 \][/tex]
2. Count the number of atoms of each element on both sides of the equation:
On the left side, there are 2 sulfur (S) atoms and 2 oxygen (O) atoms.
On the right side, there is 1 sulfur (S) atom and 2 oxygen (O) atoms.
3. To balance the sulfur atoms, we need to have the same number of sulfur atoms on both sides. Since there are 2 sulfur atoms on the left, we need to multiply the sulfur dioxide [tex](SO_2)[/tex] by 2 on the right side:
[tex]\[ \text{S}_2 + \text{O}_2 \rightarrow 2\text{SO}_2 \][/tex]
4. Now, count the number of oxygen atoms again. There are 2 oxygen atoms on the left and 4 on the right (2 molecules of [tex]SO_2[/tex], each with 2 oxygen atoms).
5. To balance the oxygen atoms, we need to have 4 oxygen atoms on the left side as well. Since we already have 2 oxygen atoms in one [tex]O_2[/tex] molecule, we need to add another [tex]O_2[/tex] molecule:
[tex]\[ \text{S}_2 + 2\text{O}_2 \rightarrow 2\text{SO}_2 \][/tex]
6. Finally, count the atoms on both sides to confirm that the equation is balanced:
Left side: 2 S atoms and 4 O atoms.
Right side: 2 S atoms (2 molecules of [tex]SO_2[/tex], each with 1 S atom) and 4 O atoms (2 molecules of [tex]SO_2[/tex], each with 2 O atoms).
The equation is now balanced with 2 sulfur atoms and 4 oxygen atoms on both sides."
In 1909 Fritz Haber discovered the workable conditions under which nitrogen, N2(g), and hydrogen, H2(g), would combine using to produce ammonia. The conditions included medium temperature (~500oC), very high pressure (~351kPa), and an iron catalyst. The reaction is represented by the equation:
N2(g) + 3H2(g) ↔ 2NH3(g)
Assuming a similar process takes place at STP, what volume of ammonia gas will be produced if 2.4L nitrogen are reacted with an excess of hydrogen gas?
A)
1.2L NH3
B)
2.4L NH3
C)
4.8L NH3
D)
9.3g NH3
Answer:
C) 4.8 L NH₃.
Explanation:
The balanced equation for the mentioned reaction is:N₂(g) + 3H₂(g) → 2NH₃(g),
It is clear that 1.0 moles of N₂ react with 3.0 moles of H₂ to produce 2.0 moles of NH₃.
At STP, 2,4 L of N₂ reacts with an excess of hydrogen gas:It is known that at STP: every 1.0 mol of any gas occupies 22.4 L.
using cross multiplication:1.0 mol of N₂ represents → 22.4 L.
??? mol of N₂ represents → 2.4 L.
∴ 2.4 L of N₂ represents = (1.0 mol)(2.4 L)/(22.4 L) = 0.1071 mol.
To find the no. of moles of NH₃ produced:Using cross multiplication:1.0 mol of N₂ produce → 2.0 mol of NH₃, from stichiometry.
0.1071 mol of N₂ produce → ??? mol of NH₃.
∴ The no. of moles of NH₃ = (2.0 mol)(0.1071 mol)/(1.0 mol) = 0.2142 mol.
Again, using cross multiplication:1.0 mol of NH₃ represents → 22.4 L, at STP.
0.2142 mol of NH₃ represents → ??? L.
∴ The no. of liters of NH₃ will be produced = (0.2142 mol)(22.4 L)/(1.0 mol) = 4.789 L ≅ 4.8 L.
So, the right choice is: C) 4.8 L NH₃.
Final answer:
Using Avogadro's law and the stoichiometry of the chemical equation for the production of ammonia, 2.4L of nitrogen gas will produce 4.8L of ammonia gas at standard temperature and pressure (STP).
Explanation:
According to Avogadro's law, equal volumes of gases at the same temperature and pressure contain equal numbers of molecules. Therefore, we can use the balanced chemical equation N2(g) + 3 H2(g) → 2 NH3(g) to determine the volume of ammonia produced by the reaction. The equation tells us that one volume of nitrogen reacts with three volumes of hydrogen to produce two volumes of ammonia. Since we are assuming standard temperature and pressure (STP), we can directly relate the volumes of gases involved in the reaction.
If 2.4L of N2 are reacted with an excess of hydrogen, according to the stoichiometry of the reaction, it would produce twice the volume of NH3 because for every one volume of N2, two volumes of NH3 are produced. Therefore, 2.4L of N2 would produce 4.8L of NH3. Accordingly, the correct answer is C) 4.8L NH3.
Given that G for the reaction below is –957.9 kJ, what is Gf of H2O? 4NH3(g) + 5O2(g) =4NO(g) + 6H2O(g)
Gf,
NH3 = -16.66 kJ/mol
Gf,NO = 86.71 kJ/mol –228.6 kJ/mol –206.4 kJ/mol 46.7 kJ/mol 90.7 kJ/mol
Answer:
- 228.6 kJ/mol.
Explanation:
∵ ΔGrxn = ∑ΔGf, products - ∑ΔGf, reactants
For the reaction:4NH₃(g) + 5O₂(g) → 4NO(g) + 6H₂O,
∴ ΔGrxn = [6(ΔGf, H₂O) + 4(ΔGf, NO)] - [4(ΔGf, NH₃) + 5(ΔGf, O₂)]
ΔGrxn = – 957.9 kJ, ΔGf, H₂O = ??? KJ/mol, ΔGf, NO = 86.71 kJ/mol, ΔGf, NH₃ = - 16.66 kJ/mol, ΔGf, O₂ = 0.0 kJ/mol.
∴ – 957.9 kJ = [6(ΔGf, H₂O) + 4(86.71 kJ/mol)] - [4(- 16.66 kJ/mol) + 5(0.0 kJ/mol)].
– 957.9 kJ = 6(ΔGf, H₂O) + 346.8 kJ/mol + 66.64 kJ/mol
– 957.9 kJ = 6(ΔGf, H₂O) + 413.8 kJ/mol
6(ΔGf, H₂O) = – 957.9 kJ - 413.8 kJ/mol = - 1372 kJ/mol.
∴ ΔGf, H₂O = (- 1372 kJ/mol)/6 = - 228.6 kJ/mol.
Sumit and Rohan were playing in bath tub of water. While playing Sumit accidently dropped his iron key into the bath tub and Rohan dropped a piece of wood.Which among the wood and iron will be easy to find.Explain why,
Answer:
The wood
Explanation:
The block of wood shall float in the water while the iron key would sink due to the weight.
The iron key is easier to find in the bathtub as it will sink due to its density, while the wood floats. This behavior is explained by Archimedes' principle concerning buoyant force and the displacement of water.
Between the iron key and the piece of wood, the iron key would be easier to find because it would sink to the bottom of the bathtub due to its higher density compared to water. Objects denser than water, such as iron, will not float and instead displace a volume of water equal to their own volume as they sink. This concept is explained by Archimedes' principle, which states that the buoyant force on an object submerged in a fluid is equal to the weight of the fluid displaced by the object. Since iron is much denser than water, it displaces a small volume of water before reaching the bottom of the tub. On the other hand, wood is less dense than water and therefore floats on the surface. This is because the wood displaces a volume of water equal to its weight before it is completely submerged, allowing it to float.
In the bathtub experiment mentioned in the question, marbles were dropped into a partially filled bathtub sink to the bottom. While part of their weight is supported by the buoyant force, the downward force on the bottom of the tub increases by exactly the weight of the marbles because the water displaced by the marbles has to go somewhere, exerting an equal force downward.
Nuclear fusion differs from nuclear fission because nuclear fusion reactions- True or False
I think the answer would be True
A car is traveling down a straight road. Which of Newton's laws must be put into effect to cause the car to follow a curve in the road?
Answer:The second law
Answer:
second
Explanation:
Carbon disulfide is prepared by heating sulfur and charcoal. The chemical equation is
Which type of chemical reaction does this word equation exemplify: iron metal plus copper (II) sulfate solution yields iron (II) sulfate solution and copper metal?
Answer:
Synthesis
Explanation:
Answer: Single replacement
[tex]Fe+CuSO_4\rightarrow Cu+FeSO_4[/tex]
Explanation:
Single replacement reaction is a chemical reaction in which more reactive element displaces the less reactive element from its salt solution.
Iron being more reactive than copper would displace copper from its salt solution and thus will generate copper and iron sulphate.
The chemical equation representing iron metal plus copper (II) sulfate solution yields iron (II) sulfate solution and copper metal is:
[tex]Fe+CuSO_4\rightarrow Cu+FeSO_4[/tex]
What is the critical angle for the interface between water and diamond?
33 degrees
90 degrees
57 degrees
0 degrees
98 degrees
Answer:
33 degrees
Explanation:
The critical angle for a light ray moving from a denser medium with refractive index [tex]n_1[/tex] to a second medium with refractive index [tex]n_2[/tex] is given by
[tex]\theta_c = sin^{-1} (\frac{n_2}{n_1})[/tex]
In this case, the critical angle occurs when light moves from diamond to water. The index of refraction of the two materials are:
[tex]n_d = 2.42[/tex] for diamond
[tex]n_w = 1.33[/tex] for water
So the critical angle is
[tex]\theta_c = sin^{-1} (\frac{1.33}{2.42})=sin^{-1}(0.550)=33.3^{\circ}[/tex]
An element of atomic number 88 decays radioactively to anelement of atomic number 82.Which of the following emissions achieve this result?one alpha particle and one beta particlethree alpha particlesone alpha particlesix beta particles
The element initially has an atomic number of 88 and it decays to an atomic number of 82. This is achieved by the emission of three alpha particles in a process known as radioactive decay. No beta particles are emitted in this case.
Explanation:In your question, an element of atomic number 88 decays to an element of atomic number 82. This radioactive decay is a form of alpha decay. In alpha decay, the atomic number decreases by two and the mass number decreases by four, as one alpha particle (consisting of two neutrons and two protons) is emitted from the nucleus.
Therefore, in order to move from an atomic number of 88 to 82, three alpha particles must be emitted. The emission of any beta particles (which transform a neutron into a proton) would have the effect of increasing the atomic number, which is not what happens in this case.
Hence, the correct answer is three alpha particles.
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What is the percent by volume of ethanol (C2H60, or ethyl alcohol) in the final solution when 90 mL of ethanol is diluted to a volume of 550 mL with water?
Answer:
16.0%.
Explanation:
Volume percent of a substance is the ratio of the substance volume to the solution volume multiplied by 100.
V % of ethanol = (volume of ethanol / volume of the solution) x 100.
volume of ethanol = 90.0 mL, volume of the solution = 550.0 mL.
∴ V % of ethanol = (90.0 mL / 550.0 mL) x 100 = 16.36% ≅ 16.0%.
What is the molar mass of Al(OH)^3? Report your answer top the nearest 0.1 g/mol
Answer:
77.98 g/mol ≅ 78.0 g/mol.
Explanation:
The molar mass of any compound can be calculated by the sum of the atomic masses of different atoms in the compound multiplied by its no. in the compound.Molar mass of Al(OH)₃ = (Atomic mass of Al) + 3(Atomic mass of O) + 3(Atomic mass of H)
Atomic mass of Al = 26.98 g/mol. & Atomic mass of O = 16.0 g/mol & Atomic mass of H = 1.0 g/mol.
∴ Molar mass of Al(OH)₃ = (26.98 g/mol) + 3(16.0 g/mol) + 3(1.0 g/mol) = 77.98 g/mol ≅ 78.0 g/mol.
Final answer:
To find the molar mass of Al(OH)3, calculate the total mass of one mole by adding the molar mass of each element: Al, O, and H. The molar mass of Al(OH)3 is approximately 77.0 g/mol.
Explanation:
To find the molar mass of Al(OH)3, we need to calculate the total mass of one mole of Al(OH)3.
First, we calculate the molar mass of each element in Al(OH)3:
Al: 1 mole * 26.98 g/mole = 26.98 g/mole
O: 3 moles * 16.00 g/mole = 48.00 g/mole
H: 3 moles * 1.01 g/mole = 3.03 g/mole
Adding up the masses of each element gives us a total molar mass of Al(OH)3:
26.98 g/mole + 48.00 g/mole + 3.03 g/mole = 77.01 g/mole
Therefore, the molar mass of Al(OH)3 is approximately 77.0 g/mol to the nearest 0.1 g/mol.
How are changes in populations related to the availability of an ecosystem's resources?
A. Population sizes are limited by the amount of resources that are available.
B. Large populations need the same amount of resources as small populations.
C. Changes in population are independent of the availability of an ecosystem's resources.
Answer:
A. Population sizes are limited by the amount of resources that are available.
Explanation:
Think about it, the more people you have, the more food & water you need.
SO the answer is A.
(prove me wrong)
Which of the following hydrocarbons has a double bond in its carbon skeleton?1) C3H82) C2H63) CH44) C2H45) C2H2
Answer:
C₂H₄ (option number 4)Explanation:
A hydrocarbon with a double bond in its carbon skeleton is an alkene and has the general form:
[tex]C_nH_{2n}[/tex].This is, the number of hydrogen atoms is twice the number of carbon atoms.
On the other hand, alkanes have only single bonds, and the compounds with a triple bond in its carbon skeleton are alkynes.
Review each choice:
1) C₃H₈:
In this case, the number of hydrogen atoms is 2×3 + 2 = 6 + 2 = 8, which is corresponds to an alkane, not an alkene.2) C₂H₆
For this, the number of hydrogen atoms is 2 × 2 + 2 = 4 + 2 = 6. Again an alkane, not alkene.3) CH₄
Hydrogen atoms: 1 × 2 + 2 = 4 ⇒ an alkane4) C₂H₄
Hydrogen atoms: 2 × 2 = 4. This is precisely the relation for an alkene, so this is the hydrocarbon that has a double bond in its carbon skeleton.The chemical formula may be writen as CH₂ = CH₂, to show the double bond.So, this is the correct answer.
5) C₂H₂
Hydrogen atoms: 2 × 2 - 2 = 4 - 2 = 2. This relation of carbon and hydrogen atoms corresponds to a compound with triple bond, i.e an alkyne: CH≡CH.The density of NO2 in a 4.50 L tank at 760.0 torr and 25.0 °C is ________ g/l.
A) 1.64.
B) 9.30.
C) 1.68.
D) 1.88.
E) 3.27
The density of NO2 in a 4.50 L tank at 760.0 torr and 25.0 °C is approximately 1.64 g/L.
Explanation:To calculate the density of NO2 in a 4.50 L tank at 760.0 torr and 25.0 °C, we can use the ideal gas law and the molar mass of NO2. The ideal gas law equation is PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature. Rearranging the equation, we have n = PV/RT. First, we need to calculate the number of moles of NO2 in the tank. We can calculate this by dividing the pressure in torr by the ideal gas constant (0.08206 L atm/K mol), multiplied by the temperature in Kelvin. Then we can divide the calculated number of moles by the volume of the tank to get the molar concentration. Finally, we can divide the mass of NO2 by the volume of the tank to get the density. Using this method, the density of NO2 in the 4.50 L tank at 760.0 torr and 25.0 °C is approximately 1.64 g/L (Option A).
Why is it important for scientists to keep testing a hypothesis even after they've found it to be true?
Answer:
as the world is changing we change also
Explanation:
We must always check and recheck are a hypothesis
Answer:
Explanation:
Because sometimes in the details of an experiment there are details hidden away that no one has thought to exploit.
I like to use Cancer as an example. Most cancers have drugs associated with them that are actually poisons (although scientists are getting much, much better in reducing side effects).
But the main purpose until recently is an example of survival of the fittest. Think Darwin. The drug kills off the cancer cells that are most easily killed off. That leaves the slower growing more deadly forms of the cancer behind and they finish the job, because there is nothing to control them, nor is anything competing with them.
Without finding this out, biologists would be at a loss of where to turn. Oncologists repeat the same treatment hundreds of times until the have a feel for how the cancer works. Then they are better equipped to tackle the problem a new.
The mole fraction of nitrogen in the air is 0.7808. this means that 78.08% of the molecules in the air are nitrogen. when the atmospheric pressure is 760 torr, the partial pressure of nitrogen in the air is _______.
Answer:
[tex]p = \boxed{\text{593 torr}}[/tex]
Explanation:
For this question, we must use Dalton's Law of Partial Pressures:
The partial pressure of a gas in a mixture of gases equals its mole fraction times the total pressure:
[tex]p = \chi p_{\text{tot}}[/tex]
Data:
χ = 0.7808
[tex]p_{\text{tot}} = \text{ 760 torr}[/tex]
Calculation:
[tex]p = 0.7808 \times \text{ 760 torr}\\\\p= \boxed{\textbf{593 torr}}[/tex]
The partial pressure of nitrogen in the air, when the atmospheric pressure is 760 torr, is 593.4 torr. This is calculated using the given formula and the mole fraction of nitrogen.
Explanation:The mole fraction of nitrogen (N₂) in the air is 0.7808 or 78.08%. This means that 78.08% of the molecules in the air are nitrogen. When talking about the partial pressure of gases, it means the contribution of that gas to the total pressure of the mixture. The partial pressure of any gas can be calculated using the formula P = (Patm) X (percent content in mixture). In this case, the atmospheric pressure (Patm) is 760 mm Hg, or torr. To find the partial pressure of nitrogen (N₂), multiply the atmospheric pressure by the mole fraction of nitrogen. So, Pₙ₂ = (760 torr) X (0.7808) = 593.4 torr. Therefore, when the atmospheric pressure is 760 torr, the partial pressure of nitrogen in the air is 593.4 torr.
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FIRST GETS BRAINLIEST
calculate the volume of 3.2 x 10^-3 mol CO2 at STP as described by Avogadro's Law assume ideal gas behavior
Answer:
0.07172 L = 7.172 mL.
Explanation:
We can use the general law of ideal gas: PV = nRT.where, P is the pressure of the gas in atm (P = 1.0 atm, Standard P).
V is the volume of the gas in L (V = ??? L).
n is the no. of moles of the gas in mol (n = 3.2 x 10⁻³ mol).
R is the general gas constant (R = 0.0821 L.atm/mol.K),
T is the temperature of the gas in K (T = 273 K, Standard T).
∴ V = nRT/P = (3.2 x 10⁻³ mol)(0.0821 L.atm/mol.K)(273 K)/(1.0 atm) = 0.07172 L = 7.172 mL.
To calculate the volume of 3.2 x 10^-3 mol CO2 at STP, we can use Avogadro's Law. The volume can be calculated by multiplying the number of moles by the molar volume of a gas at STP, which is 22.4 liters/mol.
Explanation:To calculate the volume of gas at STP (Standard Temperature and Pressure), we can use Avogadro's Law. Avogadro's Law states that equal volumes of gases, at the same temperature and pressure, contain the same number of particles (moles).
First, we need to convert the given number of moles of CO2, which is 3.2 x 10^-3 mol, into liters by using the molar volume of a gas at STP, which is 22.4 liters/mol. Multiplying the number of moles by the molar volume gives us the volume:
Volume = 3.2 x 10^-3 mol * 22.4 L/mol = 0.07168 L
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Phosphorus pentachloride decomposes to phosphorus trichloride at high temperatures according to the equation: pcl5(g)→pcl3(g)+cl2(g) at 250° 0.125 m pcl5 is added to the flask. if kc = 1.80, what are the equilibrium concentrations of each gas?
Answer:
[tex]\boxed{\text{[PCl$_{5}$] = 0.0077 mol/L; [PCl$_{3}$] = [Cl$_{2}$] = 0.117 mol/L}}[/tex]
Explanation:
The balanced equation is
PCl₅(g) ⇌ PCl₃(g) + Cl₂(g)
You don't give the volume of the flask, so I assume it is 1 L.
We can set up an ICE table to organize our calculations.
[tex]\begin{array}{lccccc} & \text{PCl}_{5} & \rightleftharpoons & \text{PCl}_{3} & + & \text{Cl}_{2} \\\text{I/mol}\cdot\text{L}^{-1}: & 0.125 & & 0 & & 0 &\\\text{C/mol}\cdot\text{L}^{-1}: & -x & & +x & & +x &\\\text{E/mol}\cdot\text{L}^{-1}:& 0.125-x & & x & & x &\\\end{array}[/tex]
[tex]K_{\text{c}} = \dfrac{\text{[PCl$_3$][Cl$_2$]}}{\text{[PCl$_5$]}} = \dfrac{x^{2}}{0.125-x} = 1.80[/tex]
Check for negligibility
[tex]\dfrac{0.125}{1.80} = 0.0674 < 400.[/tex]
x is not negligible, so we must solve a quadratic.
[tex]x^{2} = 1.80(0.125 - x)\\x^{2} = 0.225 - 1.80x\\x^{2} + 1.80x - 0.225 = 0\\[/tex]
Solve for x.
x = 0.1173
[PCl₅] = 0.125 - x = 0.125 – 0.1173 = 0.0077 mol·L⁻¹
[PCl₃] = x = 0.117 mol·L⁻¹
[Cl₂] = x = 0.117 mol·L⁻¹
[tex]\boxed{\textbf{[PCl$_{5}$] = 0.0077 mol/L; [PCl$_{3}$] = [Cl$_{2}$] = 0.117 mol/L}}[/tex]
Check:
[tex]\dfrac{0.117^{2}}{0.0077} = 1.80\\\\\dfrac{0.0138}{0.0077} = 1.79[/tex]
Close enough. It checks.
In a chemical reaction when the reactants split to form two or more products are called a decomposition reaction. It is generally a breakdown of the reactants to yield products.
The concentrations of [tex]\rm PCl_{5}[/tex] is 0.0077 mol/L, [tex]\rm PCl_{3}[/tex] and [tex]\rm Cl_{2}[/tex] is 0.177 mol/L.
How to calculate the concentration of the gases?The balanced equation given is:
[tex]\rm PCl_{5} (g) \rightleftharpoons \rm PCl_{3} (g) + Cl_{2} (g)[/tex]
Assume the volume of the flask = 1 L[tex]K_{c}[/tex] = 1.80See the ICE table for the equation in the attached image below.
According to the table:
[tex]Kc = \dfrac{[\rm PCl_{3}] [Cl_{2}]}{[\rm PCl_{5}]}[/tex]
[tex]1.80 =\dfrac { x^{2} }{0.125 - x}[/tex]
Check the value for the negligibility:
[tex]\dfrac{0.125 }{1.80} = 0.0674 < 400[/tex]
From above it can be stated that it is not negligible and will be solved by the quadratic equation:
[tex]\begin{aligned}x^{2} &= 1.80 (0.125 - x)\\\\x^{2} &= 0.225 - 1.80x\\\\0 &= x^{2} + 1.80 x - 0.225\end{aligned}[/tex]
Solving further for x:
x = 0.1173
For gases:
[tex]\begin{aligned} \rm [PCl_{5}] &= 0.125 - x \\\\\rm [PCl_{5}] &= 0.125 - 0.1173 \\\\&= 0.0077 \;\rm mol L^{-1}\end{aligned}[/tex]
And,
[tex]\begin{aligned} \rm [PCl_{3}] &= 0.117 \;\rm mol L^{-1}\\\\\rm [Cl_{2}] &= 0.117 \;\rm mol L^{-1} \end{aligned}[/tex]
Therefore, the concentration of each gases are [tex]\rm PCl_{5}[/tex] is 0.0077 mol/L, [tex]\rm PCl_{3}[/tex] and [tex]\rm Cl_{2}[/tex] is 0.177 mol/L.
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Where are metals located on the periodic table?
Finely ground nickel(II) hydroxide is placed in a beaker of water. It sinks to the bottom of the beaker and remains unchanged. An aqueous solution of hydrochloric acid (HCl) is then added to the beaker, and the Ni(OH ) 2 disappears. Which equation best describes what occurred in the beaker? A. Ni(OH ) 2 (s) + HCl(aq) → NiO(aq) + H 2(g) + HCl(aq) B. Ni(OH ) 2 (s) + 2HCl(aq) → NiC l 2 (aq) + 2 H 2 O(l) C. Ni(OH ) 2 (s) + 2 H 2 O(l) → NiC l 2 (aq) + 2 H 2 O(l) D. Ni(OH ) 2 (s) + 2 H 2 O(l) → NiCl 2(aq) + 3H 2O(l) + O 2(g)
Answer:C
Explanation:
The equation which best describes the reaction between Ni(OH)₂ & HCl is Ni(OH)₂(s) + 2HCl(l) → NiCl₂(aq) + 2H₂O(l).
What is neutralization reaction?Those reaction in which acids combine with bases to form water molecule and salt is known as neutralization reaction.
In the given question, nickel hydroxide Ni(OH)₂ is a base and when it reacts with hydrochloric acid it will form water molecule and nickel chloride salt, and chemical reaction for this changes will be represent as follow:
Ni(OH)₂(s) + 2HCl(l) → NiCl₂(aq) + 2H₂O(l)
Reactions except this equation is not correct as in that equations formation of desired products will not takes place.
Hence Ni(OH)₂(s)+2HCl(l)→NiCl₂(aq)+2H₂O(l) best describes the change.
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Which of the following is true about hydropower? It changes the surrounding ecosystem. It does not produce greenhouse gases. It produces harmful radiation. It burns fossil fuels.
Answer:
A
Explanation:
One of the main complaints about hydropower is that it will change the ecosystem. You can read about the history of any dam and you will find that most of them have involved evacuation. That means that farmland was lost and replaced by a lake behind the dam. The energy comes from water cascading over the top of the dam to its bottom.
It does not produce radiation.
It does not burn fossil fuels. It's clean and does not pollute the air.
So there are no greenhouse gases involoved.
Answer:
change the ecosystem
Explanation:
NO
Name this compound according to IUPAC nomenclature rules.
A)
nitrogen oxide
B)
nitrogen oxygen
C)
nitrogen monoxide
D)
mononitrogen monoxide
Answer:
C) nitrogen monoxide
Explanation:
Answer:
c
Explanation:
What are the signs of a chemical reaction?
Bubbling And Fizzing
Answer:
Signs of chemical reactions are, if gas or bubbles are present, if a color changes occurs, or if a precipitate is formed, that could indicate that a chemical reaction has occurred.
Explanation:
Drag each tile to the correct box.
Match the name of each compound to its chemical formula. Use the table to help you.
nitric acid
sulfurous acid
hypochlorous acid
ammonia
sulfuric acid
H2SO3
arrowRight
NH3
arrowRight
HNO3
arrowRight
H2SO4
arrowRight
HClO
arrowRight
Answer:
Here you go buddy. Good Luck
Explanation:
Chemical formula of a compound tells us about the number of atoms of elements that are present in a compound.
For the given options:
1. Nitric acid
This is an acid in which one hydrogen, 1 nitrogen and 3 oxygen atoms are present. The chemical formula for this compound is [tex]HNO_3[/tex]
2. Sulfurous acid
This is an acid in which two hydrogen, 1 sulfur and 3 oxygen atoms are present. The chemical formula for this compound is [tex]H_2SO_3[/tex]
3. Hypochlorous acid
This is an acid in which one hydrogen, 1 chlorine and 1 oxygen atoms are present. The chemical formula for this compound is [tex]HClO[/tex]
4. Ammonia
This is an acid in which three hydrogen and 1 nitrogen atoms are present. The chemical formula for this compound is [tex]NH_3[/tex]
5. Sulfuric acid
This is an acid in which one hydrogen, 1 sulfur and 4 oxygen atoms are present. The chemical formula for this compound is [tex]H_2SO_4[/tex]
PLEASE HELP!!!!!
A certain commercial product used for cleaning ovens must be handled with rubber gloves. The product is slippery and turns litmus paper blue. It probably contains___
a
an acid
b
a base
c
a salt
d
an isotope
Given that the product is slippery and turns litmus paper blue. It probably contains a base (Option B)
What is a base?A base is a substance which dissolves in water to produce hydroxide ion, OH¯
How to test for baseA base has been known to neutralize, producing salt and water.
However, a base can easily be tested for by using litmus paper.
A solution of base will turn red litmus paper blue.
With the above information about base, we can conclude that the product described in the question given above contains a base (option B)
Learn more about base:
https://brainly.com/question/24181314
the acid dissociation constant, ___, is a quantitative measure of acid strength
Answer:
The acid dissociation constant, _Ka__, is a quantitative measure of acid strength
Explanation:
Zn(s) + 2HCl(aq) → ZnCl2(aq) + H2(g) If you have 4 moles of zinc and 4 moles of hydrochloric acid, which of these would be the limiting reactant? A) zinc B) hydrogen gas C) zinc chloride D) hydrochloric acid
Answer:
D) hydrochloric acid.
Explanation:
The balanced equation for the mentioned reaction is:Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g),
It is clear that 1.0 moles of Zn react with 2.0 moles of HCl to produce 1.0 moles of ZnCl₂ and 1.0 mole of H₂.
From stichiometry; Zn reacts with HCl with (1: 2) molar ratio.∴ 2.0 mol of Zn (the remaining 2.0 mol is in excess) react completely with 4.0 mol of HCl with (1: 2) molar ratio.
So,
the limiting reactant is HCl and the excess reactant is Zn.
Thus, the right choice is: D) hydrochloric acid.
Final answer:
Explanation on how to determine the limiting reactant in a chemical reaction involving zinc and hydrochloric acid.
Explanation:
The limiting reactant in a chemical reaction is the reactant that gets consumed completely first, limiting the amount of product formed. To determine the limiting reactant, we compare the moles of each reactant to the stoichiometry of the balanced equation.
In the reaction Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g), if you have 4 moles of zinc and 4 moles of hydrochloric acid, you need to use stoichiometry to see which reactant will be completely consumed first.
Based on the balanced equation, the limiting reactant between zinc and hydrochloric acid is hydrochloric acid as only 2 moles of HCl are needed to react completely with 1 mole of zinc.
When an alpha particle is emitted from an unstable nucleus, the atomic mass numberof the nucleus
9) _______
A) increases by 4.
B) decreases by 2.
C) increases by 2.
D) decreases by 4.
Answer:
The correct option is D.
Explanation:
Radioactive substances usually emit different types of particles when they are decaying. Such particles include alpha particles, beta particles and gamma ray. When an alpha particle is emitted from an unstable radioactive nucleus such nucleus usually lost an atomic mass that correspond to that of helium atom. Note that an alpha particle is made up of two protons and two neutrons, which result in mass number of 4. Thus, a nucleus that emit an alpha particle will have its mass number (atomic mass) reduce by 4 and atomic number that is reduced by 2.
Which of the following occurs when a reaction in a solution is at equilibrium and
more product is added to the solution?
a. Equilibrium shifts to produce more product
b. Equilibrium shifts to produce more reactant
c. No change will occur
d. The reaction will stop
Equilibrium shifts to produce more reactant.
Draw both major organic product(s) that are obtained when 4-chloro-2-methyltoluene is treated with sodium amide followed by treatment with H3O+.
Answer:
I attached the answer as an image. I also drew in the two most acidic hydrogens.
Explanation:
This goes through the 'benzyne' intermediate, meaning it does an E2-looking reaction by expelling a leaving group (chloride) from the adjacent part of the ring using the amide as a strong base. The triple-bonded benzyne has absurd bond angle strain, and is vulnerable to a good nucleophile like an amide ion, and the resultant sp2 anion is then reprotonated by the acid. I didn't draw in the acid-base reaction in step one, or the spectator ion (sodium).
The both major organic products are 3-amino-2-methyltoluene and 4-amino-2-methyltoluene.
The reaction of 4-chloro-2-methyltoluene with sodium amide is an E2 reaction. The abstraction of hydrogen ion by a base and the loss of chloride ion occurs simultaneously leading to the formation of a benzyne intermediate.
This benzyne intermediate is attacked by the amide ion and H3O+ to yield the products; 3-amino-2-methyltoluene and 4-amino-2-methyltoluene. The detailed mechanism of the reaction is shown in the images attached below.
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