What other professions does a fire sprinkler contractor work with? *?

The position vector with magnitude [tex]10 \ m[/tex] points to the right and up. its x-component is  [tex]6.0\ m[/tex] and its y-component is  [tex]8\ m[/tex].

A vector is a physics term for a quantity with both magnitude (size) and direction. Physical quantities including each of these properties are represented by vectors, such as displacement, velocity, force, and acceleration.

The resultant vector is the vector that is created when two or more vectors are added together. It depicts the final result of mixing the various vectors. The vector addition of the various vectors yields the resultant vector.

Given:

Magnitude = [tex]10 \ m[/tex]

x- component = [tex]6\ m[/tex]

The resultant vector is given as:

[tex]r = sqrt(x^2+y^2)\\10 = sqrt(6^2+y^2)\\y^2 = 100-36\\y = 8\ m[/tex]

Hence, the position vector with magnitude  [tex]10 \ m[/tex] points to the right and up. its x-component is [tex]6.0\ m[/tex] and its y-component is [tex]8\ m[/tex].

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The component of the gravitational force parallel to the hill is mg⋅sin(65°). The acceleration of the rollercoaster down the hill is (mg⋅sin(65°))/m.

To determine the value of the component of the gravitational force parallel to the hill, we can use trigonometry. The component of the weight parallel to the hill is given by the equation mg⋅sinθ. In this case, θ is 65 degrees. So the value of the component of the gravitational force parallel to the hill is mg⋅sin(65°).

To find the acceleration of the rollercoaster down the hill, we can use Newton's second law, which states that force equals mass times acceleration. In this case, the force is the component of the gravitational force parallel to the hill, and the mass is given as 300 kg with passengers. So the acceleration is a = F/m = (mg⋅sin(65°))/m.

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Sample Response: If the height of the cylinder increases, the temperature of the water increases, because a greater height means the cylinder has more potential energy that can be converted to thermal energy, increasing the temperature of the water.

Final answer:

To find the cat's speed at the top of the incline, we use the Work-Energy Theorem. The work done moving the cat up the ramp increases her kinetic energy, resulting in a final speed of 5.1 m/s.

Explanation:

To determine the speed of the cat at the top of the incline, we can apply the Work-Energy Theorem. The theorem states that the work done on an object is equal to the change in its kinetic energy. In mathematical terms, Work = ΔKE = KEfinal - KEinitial, where KE is kinetic energy given by ½mv2. The work done on the cat by pushing her up the ramp can be calculated as the force applied (parallel to the ramp) times the distance moved along the ramp, which is Work = Force × Distance = 41.0 N × 2.00 m = 82.0 J.

The initial kinetic energy of the cat can be calculated using her initial speed at the bottom of the ramp, KEinitial = ½ × 8.50 kg × (1.90 m/s)2. Plugging in the values, we get KEinitial = 15.33 J. The final kinetic energy at the top of the incline can be found by adding the work done to the initial kinetic energy: KEfinal = KEinitial + Work = 15.33 J + 82.0 J = 97.33 J. Solving for the final speed, we set KEfinal = ½ × 8.50 kg × v2 equal to 97.33 J and solve for v, finding that the cat's speed at the top of the ramp is 5.1 m/s.

Answer:

The horizontal and vertical velocity of the skier are both 29.4 m/s.

Explanation:

If no forces are acting in the horizontal direction, then the horizontal component of the velocity remains constant in time:

Vx = 29.4 m/s

For the vertical component the gravity acceleration must be considered, and the vertical velocity can be written as:

Vy = g*t

Here the value for g is 9,8 m/s2. Note that the initial vertical velocity is zero.  

Evaluating in the velocity’s expressions for a time of 3 seconds we obtain:

Vx = 29.4 m/s

Vy = 9.8 m/s2 * 3 s = 29.4 m/s

Answer: A, B, C, E

Explanation:

Plastics have a number of properties that make them useful solutions to many complex problems in the world, such as being chemically resistant, durable, non-reactive, and easy to manufacture, which are options A, B, C, and E.

Plastics have a number of properties that make them a popular choice in many industries, such as chemical resistance, which is one of the most important properties of plastics, as they can resist a wide range of chemicals, including acids, bases, and solvents, which makes them ideal for use in chemical processing, pharmaceuticals, and food packaging. Durability is another important property of plastics.

They are resistant to wear and tear, impact, and weathering, which makes them suitable for use in various applications, such as building materials, automotive parts, and toys. Plastics are also non-reactive, which means that they do not react with other materials.

Hence, the correct answers are chemically resistant, durable, non-reactive, and easy to manufacture, which are options A, B, C, and E.

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Answer:

4560m=4.560km

Explanation:

Analysis conceptual

We know that:

1km=1000m

Then, the conversion factor from meters to kilometers is: 1km/1000m

Known data:

4560 m

problem development

We multiply the amount given in m by the conversion factor (1km/1000m ):

[tex]4560 m(\frac{1km}{1000m} )=4.560km[/tex]

4560m=4.560km

In physics, some data points may need to be ignored just before and after a collision. This is done to remove errors and focus on the specific moment of collision.

In physics, it may be necessary to ignore some of the data points just before and just after a collision for various reasons. One reason is to remove outliers or errors in the measurements that could skew the results. For example, if there is a sudden spike or dip in the data due to a measurement error, it would be necessary to exclude those points to ensure accurate analysis.

Another reason is to focus on the specific moment of collision. By excluding the data points surrounding the collision, it allows for a clearer observation and analysis of the collision itself. This is important for understanding the dynamics and effects of the collision.

Therefore, it is not necessary to ignore both sets of data equally, but rather selectively remove data points that may introduce errors or hinder the analysis of the collision.

Answer:

the Answer is D 117 newtons

Explanation:

Final answer:

The magnitude of the acceleration of the larger block across the table is 2.45 m/s², calculated using the gravitational force acting on the hanging mass and applying Newton's second law to the system of both blocks.

Explanation:

To calculate the magnitude of the acceleration of the larger block across the table, we need to apply Newton's second law of motion which states that the force equals the mass times the acceleration (F = ma). In this scenario, only the gravitational force acting on the 10 kg hanging mass needs to be considered for the system of both blocks, as the table is frictionless and there are no other external forces acting on the horizontal block.
We calculate the gravitational force acting on the 10 kg block, which is the weight of the block (W = mg), where m is the mass and g is the gravitational acceleration (approximately 9.8 m/s2). For the 10 kg block, W = 10 kg × 9.8 m/s2 = 98 N. This force is the net force causing both blocks to accelerate, and because the rope is massless and the pulley is frictionless, the tension in the rope is uniform throughout.
The total mass of the system is 30 kg + 10 kg = 40 kg. Using the equation F = ma, rearrange to find acceleration (a = F/m). So the acceleration of the system is a = 98 N / 40 kg = 2.45 m/s2. Therefore, the magnitude of the acceleration of the larger block across the table is 2.45 m/s2.

Answer:

Should be same

Explanation:

An experiment is conducted to test a theory. It is expected that the result of the experiment would match with the theoretical result. Also, if the experiment is repeated by the same or another person, it should give the same result. If not, then either there is error in conduction of experiment or in the theory.

You are facing North. Turn 90 degrees left. W.

Turn 180 degrees right. E.

Reverse direction. W.

Turn 45 degrees left. S.W.

Reverse direction. N.E.

In which direction are you now facing? North East

Using the law of conservation of momentum, which states that initial momentum equals final momentum in a closed system, the initial speed of the truck before it collided with the stationary car is calculated to have been 12 m/s.

This question pertains to the concept of momentum in physics. The law of conservation of momentum states that the total momentum of a system of objects is constant if no external forces are acting on it. In this case, the truck and the car form the system of objects.

The initial momentum of the system before the collision is given by the momentum of the truck, since the car is stationary. The final momentum after the collision is given by the combined mass of the truck and car, multiplied by their common speed.

So, if we denote the initial speed of the truck as V, we have: 3000kg * V (initial momentum of truck) = (3000kg + 1000kg) * 9m/s (final momentum of the system)

Solving for V, we find the initial speed of the truck to have been 12 m/s.

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r1 = 5*10^10 m , r2 = 6*10^12 m

v1 = 9*10^4 m/s

From conservation of energy

K1 +U1 = K2 +U2

0.5mv1^2 - GMm/r1 = 0.5mv2^2 - GMm/r2

0.5v1^2 - GM/r1 = 0.5v2^2 - GM/r2

M is mass of sun = 1.98*10^30 kg

G = 6.67*10^-11 N.m^2/kg^2

0.5*(9*10^4)^2 - (6.67*10^-11*1.98*10^30/(5*10^10)) = 0.5v2^2 - (6.67*10^-11*1.98*10^30/(6*10^12))

v2 = 5.35*10^4 m/s

The speed of a comet in an elliptical orbit around the sun can be calculated using Kepler's second law, which states that a planet sweeps out equal areas in equal amounts of time. This means that when a comet is closer to the sun, it moves faster, and when it is farther away, it moves slower.

The speed of a comet in an elliptical orbit around the sun can be calculated using Kepler's second law, which states that a planet sweeps out equal areas in equal amounts of time. This means that when a comet is closer to the sun, it moves faster, and when it is farther away, it moves slower. To find the speed of the comet when it is 6 x 10^12 m from the sun, we can use the fact that the area swept out by the comet is the same at both points. Using the distances given, we can calculate the speed of the comet when it is 6 x 10^12 m from the sun.

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The data transmission rate of the Eurostar rail service train, London to Paris via Chunnel  is  11516003 bite/second.

Transfer rate is a common metric for gauging how quickly data or information moves from one place to another.

Amount of of data stored in single-side = 8.54-gbyte.

Mass of the one double-layer DVDs= 0.015 g.

Total mass of DVDs = 10⁴ kg.

Total number of DVDs = 10⁴  ÷ 0.015  = 666667

Total amount of data =  666667 × 2 × 8.54 × 1024 × 8 bite

Total time taken = 2 hour 15 min = 2.25 hour = (2.25 × 3600) s = 8100 second

The data transmission rate is = (666667 × 2 × 8.54 × 1024 × 8) ÷ 8100 bite/second

= 11516003 bite/second.

Therefore, the data transmission rate of the Eurostar rail service train, London to Paris via Chunnel is  11516003 bite/second.

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The maximum speed with which this car can round a second unbanked curve is 40 m/s

[tex]\texttt{ }[/tex]

Centripetal Acceleration can be formulated as follows:

[tex]\large {\boxed {a = \frac{ v^2 } { R } }[/tex]

a = Centripetal Acceleration ( m/s² )

v = Tangential Speed of Particle ( m/s )

R = Radius of Circular Motion ( m )

[tex]\texttt{ }[/tex]

Centripetal Force can be formulated as follows:

[tex]\large {\boxed {F = m \frac{ v^2 } { R } }[/tex]

F = Centripetal Force ( m/s² )

m = mass of Particle ( kg )

v = Tangential Speed of Particle ( m/s )

R = Radius of Circular Motion ( m )

Let us now tackle the problem !

[tex]\texttt{ }[/tex]

Given:

initial speed of the car = v₁ = 20 m/s

radius of first curve = R₁ = 80 m

radius of second curve = R₂ = 320 m

Asked:

final speed of the car = v₂ = ?

Solution:

Firstly , we will derive the formula to calculate the maximum speed of the car:

[tex]\Sigma F = ma[/tex]

[tex]f = m \frac{v^2}{R}[/tex]

[tex]\mu N = m \frac{v^2}{R}[/tex]

[tex]\mu m g = m \frac{v^2}{R}[/tex]

[tex]\mu g = \frac{v^2}{R}[/tex]

[tex]v^2 = \mu g R[/tex]

[tex]\boxed {v = \sqrt { \mu g R } }[/tex]

[tex]\texttt{ }[/tex]

Next , we will compare the maximum speed of the car on the first curve and on the second curve:

[tex]v_1 : v_2 = \sqrt { \mu g R_1 } : \sqrt { \mu g R_2 }[/tex]

[tex]v_1 : v_2 = \sqrt { R_1 } : \sqrt { R_2 }[/tex]

[tex]20 : v_2 = \sqrt { 80 } : \sqrt { 320 }[/tex]

[tex]20 : v_2 = 1 : 2[/tex]

[tex]v_2 = 2(20)[/tex]

[tex]\boxed {v_2 = 40 \texttt{ m/s}}[/tex]

[tex]\texttt{ }[/tex]

[tex]\texttt{ }[/tex]

Grade: High School

Subject: Physics

Chapter: Circular Motion