The major product formed when y is heated with Br2 is 1,2-dibromo compound.
Explanation:When y is heated with Br2, the major product formed is 1,2-dibromo compound. This is because Br2 adds across an alkene in an anti-addition manner, resulting in the formation of a vicinal dihalide. The reaction proceeds via a bromonium ion intermediate.
For example, when ethene (y) is heated with Br2, the major product formed is 1,2-dibromoethane. The reaction can be represented by the following equation:
CH2=CH2 + Br2 → CH2BrCH2Br
A sealed container filled with argon gas at 35°C has a pressure of 832 torr. If the volume of the container is decreased by a factor of two, what will happen to the pressure? You may assume the temperature remains at 35°C.
According to Boyle's Law, if the volume of a container filled with gas is halved, keeping temperature constant, the pressure of the gas in the container will double.
Explanation:The science subject in question here relates to the principles of gas laws, specifically Boyle's Law, which falls under the category of physics or chemistry. Highlighting Boyle's law, which states that the pressure of a gas is inversely proportional to its volume provided the temperature remains constant. Hence, if the volume of the sealed container filled with argon gas is reduced by a factor of two, the pressure should be expected to double, given that the temperature remains constant at 35°C.
Learn more about Boyle's Law here:https://brainly.com/question/21184611
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A spherical balloon contains a positively charged object at its center. as the balloon is inflated to a greater volume while the charged object remains at the center, what does the electric potential at the surface of the balloon do?
Final answer:
As a spherical balloon is inflated with a fixed charge at its center, the electric potential at the surface decreases due to the increase in the balloon's radius.
Explanation:
When a spherical balloon with a positively charged object at its center is inflated, the electric potential at the surface of the balloon changes. As the radius of the balloon increases, the electric potential at the surface (V) is defined by the formula V = kQ/r, where k is Coulomb's constant, Q is the charge at the center, and r is the radius of the surface. Therefore, as the balloon's radius expands and r gets larger, the electric potential at the surface decreases because the charge Q remains constant while the distance r increases.
Why should you not heat organic solvents over a bunsen burner flame?
Ca (ClO) 2
Spell out the full name of the compound.
Final answer:
The full name of the compound Ca(ClO)2 is calcium hypochlorite, which follows the naming convention for ionic compounds with polyatomic ions.
Explanation:
The correct full name of the compound Ca(ClO)2 is calcium hypochlorite. When naming ionic compounds, we combine the name of the metal cation and the base name of the nonmetal anion followed by the appropriate suffix. If the nonmetal forms a polyatomic ion with oxygen, often the endings '-ate' or '-ite' are used to distinguish different ions with the same element. In this case, 'hypochlorite' is the name of the ClO anion part of the compound, and since calcium has a characteristic charge of 2+, we do not need to specify its charge in the name.
How many moles of Cl- ions are needed to completely combine with 0.25 moles of Mg+2 ions
How are these equilibrium quantities affected by the initial amount of x(g) placed in the container? assume constant temperature?
Equilibrium quantities of Y and Z are directly affected by initial amount of X placed in container.
Further Explanation:
Le Chatelier’s principle:
According to this principle, if changes are done in pressure, temperature or concentration in any equilibrium reaction, equilibrium shifts to that direction in which effect of altered value is reversed.
Given reaction occurs as follows:
[tex]\text{2X(g)}\rightleftharpoons\text{Y(g)}+\text{Z(g)}[/tex]
From this reaction, it is evident that two moles of X decompose to produce one mole of Y and one mole of Z.
If amount of X used is large, it results in more formation of Y and Z and vice-versa. This implies amount of product formation depends on initial amount of X taken in reaction.
According to Le Chatelier's principle, if amount of X is increased, equilibrium will tend to shift in that direction in which more consumption of X is observed. This is done only if more products are formed. Opposite effects are observed in case less amount of X is taken. Hence formation of Y and Z is dependent on initial amount of X.
Learn more:
1. Sort the solubility of gas will increase or decrease: https://brainly.com/question/2802008
2. Calculation of equilibrium constant of pure water at 25°C: https://brainly.com/question/3467841
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Chemical Equilibrium
Keywords: Le Chatelier’s principle, equilibrium, shift, direction, X, Y, Z, 2X, pressure, temperature, concentration, consumption, increase, decrease, two moles, one mole.
What commercially available compound is used to generate cl2?
Hello!
The commercially available compound that is used to generate Cl₂ is Sodium Hypochlorite
Why?Sodium Hypochlorite is present in commercial bleach. Its chemical formula is NaClO.
Sodium Hypochlorite can react with acids (which can be present in vinegar, glass and window cleaners, drain cleaners or lime, calcium and rust removal products) to form Chlorine gas as shown by the following reaction (for a generic acid HA)
NaClO(aq) + HA(aq) → H₂O(aq) + Cl₂(g) + NaA(aq)
Chlorine gas is very toxic, so bleach should never be mixed with anything but water.
Have a nice day!
Calculate the molarity of na+ ions in 135 ml of a solution containing 5.32 g nacl and 1.20 g na2so4.
Final answer:
The molarity of Na+ ions in a solution containing 5.32 g NaCl and 1.20 g Na2SO4 in 135 mL is 0.8 M. This calculation involves converting the mass of each salt to moles of Na+ ions and then dividing the total moles by the volume of the solution in liters.
After solving , Molarity of Na+ = 0.108 mol Na+ / 0.135 L = 0.8 M
Explanation:
To calculate the molarity of Na+ ions in the solution, we need to determine the total moles of Na+ ions provided by both NaCl and Na2SO4. First, we will convert the masses of NaCl and Na2SO4 to moles using their molar masses (NaCl = 58.44 g/mol and Na2SO4 = 142.04 g/mol). Then we'll account for the fact that each mole of NaCl gives 1 mole of Na+ ions, and each mole of Na2SO4 gives 2 moles of Na+ ions.
NaCl:
5.32 g NaCl × (1 mol NaCl / 58.44 g NaCl) = 0.091 mol Na+
Na2SO4:
1.20 g Na2SO4 × (1 mol Na2SO4 / 142.04 g Na2SO4) × (2 mol Na+ / 1 mol Na2SO4) = 0.0169 mol Na+
Next, we sum the moles of Na+ ions from both compounds: 0.091 mol + 0.0169 mol = 0.108 mol Na+.
Finally, we convert the volume of the solution to liters and calculate the molarity of Na+ ions:
135 mL × (1 L / 1000 mL) = 0.135 L
Molarity of Na+ = Total moles of Na+ / Volume of solution in liters
Molarity of Na+ = 0.108 mol Na+ / 0.135 L = 0.8 M
The molarity of Na⁺ ions in a solution with 5.32 g of NaCl and 1.20 g of Na₂SO₄ in 135 mL is calculated to be approximately 0.800 M.
This involves determining the moles of each compound, the total number of Na⁺ ions, and then using the volume of the solution to find the molarity.
The final concentration of Na⁺ ions is calculated by dividing the total moles of Na⁺ by the volume in liters.
First, we need to determine the moles of both NaCl and Na₂SO₄:
1. Calculating moles of NaCl:
Molar mass of NaCl = 23.0 g/mol Na + 35.5 g/mol Cl = 58.5 g/molNumber of moles of NaCl = 5.32 g / 58.5 g/mol = 0.09094 moles2. Calculating moles of Na₂SO₄:
Molar mass of Na₂SO₄ = 2(23.0 g/mol Na) + 32.1 g/mol S + 4(16.0 g/mol O) = 142.1 g/molNumber of moles of Na₂SO₄ = 1.20 g / 142.1 g/mol = 0.00845 molesEach mole of NaCl provides 1 mole of Na⁺ ions, and each mole of Na₂SO₄ provides 2 moles of Na⁺ ions. Thus, we need to calculate the total moles of Na⁺:Moles of Na⁺ from NaCl = 0.09094 molesMoles of Na⁺ from Na₂SO₄ = 2 * 0.00845 moles = 0.01690 molesTotal moles of Na⁺ = 0.09094 moles + 0.01690 moles = 0.10784 moles3. Calculating the molarity of Na⁺:
Convert the volume of solution from mL to L: 135 mL = 0.135 LMolarity of Na⁺ = Total moles of Na⁺ / Volume of solution in liters = 0.10784 moles / 0.135 L = 0.7996 MThe molarity of Na⁺ ions in the solution is approximately 0.800 M.
Correct question is: Calculate the molarity of Na⁺ ions in 135 ml of a solution containing 5.32 g NaCl and 1.20 g Na₂SO₄ .
at what temperature will you find more potassium nitrate(kno3) in 100 g of H2O . In other words at which temperature will you have a higher solubility: 10c , 20c , 50c , 85c ?
what is 7 2/3=1/5x+2/3-1 1/5x
Abnormal levels of _________ are linked to migraines, seizures, and schizophrenia. A. dopamine B. glutamate C. norepinephrine D. acetycholine
Abnormal levels of glutamate are linked to migraines, seizures and schizophrenia.
As glutamate is a powerful excitatory neurotransmitter which is released by nerve cells present in the brain.
It is mostly responsible for sending signals between nerve cells, and under normal conditions it plays an important role in learning and memory. So this is the correct answer for the abnormal levels which causes neurological disorders.
Answer:
B
Explanation:
Aqueous copper (ii) ion reacts with aqueous iodide ion to yield solid copper (i) iodide and aqueous iodine. write the balanced net ionic equation. express your answer as a net ionic equation. identify all of the phases in your answer.
What is the oxidation state of an individual phosphorus atom in po33−? express the oxidation state numerically (e.g., +1)?
Final answer:
The oxidation state of the phosphorus in PO³₃⁻ is +3, which is determined by considering the oxidation state of oxygen (-2) and the total charge of the ion (3-).
Explanation:
The oxidation state of an individual phosphorus atom in PO³₃⁻ can be determined by using the known oxidation states of oxygen and the overall charge of the ion. Oxygen generally has an oxidation state of -2, and since there are three oxygen atoms, their total contribution is -6. Considering the overall charge of the ion is 3-, we can set up an equation to solve for the oxidation state of phosphorus (x):
3(-2) + x = -3
-6 + x = -3
x = -3 + 6
x = +3
So, the oxidation state of the phosphorus atom in PO₃³⁻ is +3.