When she subtracts 4 from both sides, 1/2x = –1/2x results. What is the value of x?

To find the median of an even-numbered data set, arrange the numbers in order, identify the two middle numbers, add them, and divide by two. The median for the given data set is 23.5.

To find the median of the data set (24, 16, 23, 30, 18, 29), follow these steps:

Applying these steps to the provided data set:

The correct median of this data set is 23.5.

The percent is used to compare the ratios when the wholes are different because it gives simple calculation.

A number or ratio that can be expressed as a fraction of 100 or a relative value indicating hundredth part of any quantity is called percentage.

Given that;

The percent's are used to compare ratios when the wholes are different.

Now,

Let two ratios are,

⇒ 19/25 and 17/20

So, For compare we can find the percent of that ratios and simply by comparison we get the large and small ratio as;

⇒ 19/25 = 0.76 = 76%

⇒ 17/20 = 0.85 = 85%

Thus, The percent of ratio 17/20 is more than the percent of ratio 19/25.

So, The percent's are used to compare ratios when the wholes are different because it gives simple calculation and not to make denominator same.

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Answer:

Hence the number in decimal is:

0.125

Step-by-step explanation:

We are given that:

The top 1/8 of the runners advance to the finals for the track and field competition.

We are asked to find the decimal value of the number i.e. we have to represent 1/8 in the decimal value.

on dividing the number 1 ( which is in numerator) by 8 ( which is in denominator) we obtain:

[tex]\dfrac{1}{8}=0.125[/tex]

Hence the number in decimal is:

0.125

8/3 is the greatest value among 8/3, 2.28, 10/12, and 0.199.

The greatest value to be determined among 8/3, 2.28, 10/12, and 0.199.

Fraction is defined as the number of compositions that constitute the Whole.

Here,
= 8/3, 2.28, 10/12, and 0.199.
= 2.66, 2.28 , 0.62 and 0.199
The greatest among the 2.66, 2.28, 0.62, and 0.199 is 2.66

Thus, 8/3 is the greatest value among 8/3, 2.28, 10/12, and 0.199.

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When does the total spent on your gym membership exceed the amount of your gift card is After 4 months

Given:

Sign-up fee = $20

Monthly fee = $25

Gift card = $120

Now let determine when does the total spent on gym membership exceed the amount gift card

Let x represent the number of months

Hence:

20 + 25x = 120

25x= 120-20

25x= 100

x=100/25

x=4

Inconclusion When does the total spent on your gym membership exceed the amount of your gift card is After 4 months.

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Answer:

1200

Step-by-step explanation:

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Kiersten’s will earn 1200 dollars from his online business  this month.

Given,

Subscription fees received by Kiersten for a month by each subscriber is $10.

Since the number of members is 100 last month, so total earning of Kiersten will be,

[tex]100\times 10=1000[/tex] dollars.

According to the question, this month, 30 new members joined the website, and 10 members cancelled their subscription.

So the number of members increased will be 20.

Hence the kiersten have total 120 members this month, so the total earning of kiersten this month will be,

[tex]120\times 10=1200[/tex] dollars.

Thus kiersten earn 1200 dollars from his online business.

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For any integers m and n, [tex]\(6m^2 + 34n - 18\)[/tex] is always even Integer . One solution is [tex]\(m = 1, n = 2\)[/tex].

To determine if the expression [tex]\(6m^2 + 34n - 18\)[/tex] is an even integer for any integers m and n, let's analyze the terms.

The expression can be factored as [tex]\(2(3m^2 + 17n - 9)\).[/tex] Since 2 is a factor of the expression, it implies that the entire expression is even. Therefore, for any integers m and n, [tex]\(6m^2 + 34n - 18\)[/tex] is an even integer.

Now, to find possible values for m and n that satisfy the condition, consider that [tex]\(3m^2 + 17n - 9\)[/tex] must be an integer. We can choose arbitrary values for m and n and verify that [tex]\(3m^2 + 17n - 9\)[/tex]is an integer. For example, let m = 1 and n = 2:

[tex]\[3(1)^2 + 17(2) - 9 = 3 + 34 - 9 = 28\][/tex]

Since 28 is an integer, m = 1 and n = 2 are valid solutions.

conclusion, any integers m and n will make [tex]\(6m^2 + 34n - 18\)[/tex]an even integer. One such solution is m = 1 and n = 2, and there are infinitely many other possible pairs of integers that satisfy this condition.

Answer:  The correct option is (A)  F   T  →  T.

Step-by-step explanation:  We are given to select the correct illustration of the truth value of the following conditional statement :

"If ice is hot, then rain is wet".

Let p : Ice is hot. This is a false statement.

And

q : rain is wet. This statement is true.

We know that

The statement "if p then q" is written as p ⇒ q.

Since p is false and q is true, so p ⇒ q will be true.

That is,

p      q      p ⇒ q

F      T         T

Thus, the correct illustration is   F    T   →   T.

Option (A) is CORRECT.

Answer:

17:16

Step-by-step explanation:

12 ft = 144 inches, so this is

153 in : 144 in

= 9·17 : 9·16

= 17 : 16

Final answer:

The probability of drawing an even-numbered ball or an odd-numbered ball from the urn is 1.

Explanation:

To find the probability of drawing an even-numbered ball or an odd-numbered ball from an urn containing 6 balls numbered 1 through 6, we need to determine the total number of favorable outcomes and divide it by the total number of possible outcomes.

The total number of possible outcomes is 6, as there are 6 balls in the urn.

The favorable outcomes are the even-numbered balls (2, 4, 6) and the odd-numbered balls (1, 3, 5), which is a total of 6 balls.

Therefore, the probability of drawing an even-numbered ball or an odd-numbered ball is 6/6, which simplifies to 1.

For a given number X, its cube is written as X^3.

Here we want to see if we can find a number that is exactly 3 more than its cube, this means that:

[tex]X = X^3 + 3[/tex]

We will see that yes, there exists a number with this property.

Then we can try to solve this to find the number with that given property.

We can rewrite it as:

[tex]-X^3 + X - 3 = 0[/tex]

Now we can solve this for X, as the question asks about existence and not for the exact number, we can graph this the above function:

[tex]f(X) = -X^3 + X - 3[/tex]

And if it crosses the x-axis, then at some point we have:

[tex]f(X) = 0[/tex]

This would imply that there exists a real number that is 3 more than its cube.

The graph can be seen below, and we can see that it intersects the X-axis, then yes, there is a number that is exactly 3 more than its cube.

And by watching the graph, we can see that the number is:

[tex]X = -1.672[/tex]

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we know that

If the lines u and w are parallel

then

∠g=[tex]105\°[/tex] ------> by alternate exterior angle

therefore

the answer is

∠g=[tex]105\°[/tex]

Answer:

<SRU and <VUW

Step-by-step explanation:

Corresponding angles occur when two lines are cut by a third line (transverse line).

In the problem you can see two lines (QRS) and (TUV) cutting by (PRUW).

Two angles are corresponding if one is on the outside (outside the two lines) and the other is on the inside (between the two lines).

In this graphic some of the corresponding angles are <SRP and <VUP, <PRQ and <RUT, <WUV and <URS.

The equation of the line is [tex]\bold{y = \frac{2}{3}x-2}[/tex]

The correct answer is an option (C)

"It is the change in y coordinate with respect to the change in x coordinate."

"It is the point at which the line intersects the Y-axis."

"y = mx + c, where m is the slope and cis the y-intercept."

For given question,

A line has slope 2/3 and y–intercept -2.

So, m = [tex]\frac{2}{3}[/tex] and c = -2

Substitute these value in the slope-intercept form of line,

[tex]\Rightarrow y = mx + c\\\\\Rightarrow y = \frac{2}{3}x+(-2)\\\\ \Rightarrow y = \frac{2}{3}x-2[/tex]

Therefore, the equation of the line is [tex]\bold{y = \frac{2}{3}x-2}[/tex]

The correct answer is an option (C)

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The vertex of the given function is [tex](3,0)[/tex].

Given:

The given function is [tex]f(x)=2|x-3|[/tex].

To find:

The coordinates of the vertex of the graph of [tex]f(x)[/tex].

Explanation:

The vertex form of an absolute function is:

[tex]f(x)=a|x-h|+k[/tex]         ...(i)

Where, [tex]a[/tex] is a constant and [tex](h,k)[/tex] is the vertex.

We have,

[tex]f(x)=2|x-3|[/tex]          ...(ii)

On comparing (i) and (ii), we get

[tex]h=3[/tex]

[tex]k=0[/tex]

Therefore, the vertex of the given function is [tex](3,0)[/tex].

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Answer:

C (-1, 1/2, -3/5) is INCORRECT and I know it isn’t (1/3, -5/3, -2/5)...... but I’m pretty sure the answer is 1/2, 3, 5

Step-by-step explanation: