Which linear function has the same y-intercept as the one that is represented by the graph?

Which Linear Function Has The Same Y-intercept As The One That Is Represented By The Graph?

Answers

Answer 1
The answer would be C because the y-intercept is when x is equal to 0
Answer 2
y-intercept when x = 0
on the graph x = 0 , y = 3

function
y = 2x + 3 when x = 0
y = 3

answer
C. y = 2x + 3

Related Questions

Amanda, Bryce, and Corey enter a race in which they have to run, swim, and cycle over a marked course. Their average speeds are given in the table. Corey finishes first with a total time of 2 hr 32 min. Amanda comes in second with a time of 3 hr 33 min. Bryce finishes last with a time of 4 hr 14 min. Find the distance (in mi) for each part of the race.

Answers

How far is the course? Can you provide the table the question say is included?

Find the least common multiple (LCM) of 54 and 72. A) 9 B) 27 C) 108 D) 216

Answers

the lowest common multiple is 216 (D)
LCM (54,72):
54, 108, 162, 216...
72, 144, 216...
Answer: 
D) 216

We are conducting a test of the hypotheses h0: p = 0.2 ha: p ≠ 0.2 we find a test statistic of z = -1.11. what is the corresponding p-value? give your answer as a proportion between 0 and 1 to 4 decimal places.

Answers

we have to find the p value from the z table and multiply by 2 for two tailed hypothesis at 5% level of significance. The P-Value is 0.266999.

Discuss the differences between parametric and non-parametric tests?

Answers

Nonparametric tests are also called distribution-free tests because they don't assume that your data follow a specific distribution. You may have heard that you should use nonparametric tests when your data don't meet the assumptions of the parametric test, especially the assumption about normally distributed data.

Which equation is equivalent to 1 5/6 - 2/6 = 1 3/6

Answers

11/6-1/3 = 9/6 should be equivalent

The weight of football players is normally distributed with a mean of 200 pounds and a standard deviation of 25 pounds. the probability of a player weighing more than 241.25 pounds is

Answers

Final answer:

To find the probability of a football player weighing more than 241.25 pounds, calculate the z-score and use the standard normal distribution table.

Explanation:

To find the probability of a football player weighing more than 241.25 pounds, we need to calculate the z-score and then use the standard normal distribution table.

The formula for calculating the z-score is: z = (x - μ) / σ where x is the player's weight, μ is the mean weight, and σ is the standard deviation.

Plugging in the values, we get: z = (241.25 - 200) / 25 = 1.65

Using the standard normal distribution table, we can find that the probability of a value being greater than 1.65 is approximately 0.0495.

Your football team gained 4 yards on first down and 2 yards on second down during its last possession. Which number is the additive inverse of the yards gained?
A) −2
B) −6
C) 4
D) 6

Answers

gained 4 yards, then gained 2 yards....so they gained a total of 6 yds

the additive inverse is the number when added to ur number (-6) equals 0. So the additive inverse is basically the opposite number....another words, it is the same number, with the opposite sign.

so the additive inverse of 6 is -6 <==

Answer:

-6

Step-by-step explanation:

Because if you add up all of the events you'll get 6 . Then, after that it asks for the additive inverse so you put an negative sign behind the #6.

Your mid-morning break begins at 10:30 A.M. and lasts for 15 minutes. You work 2 hours and 50 minutes until your lunch break. What time does your lunch break begin?

Answers

1. You start by adding 15 minutes to 10:30
because the break takes 15 minutes Which equals 10:45.

2. You then add another 2 hours and 50 minutes of work until your lunch break which makes it 1:35.

3. Your lunch break starts at 1:35

Final answer:

The lunch break begins at 1:20 P.M. after working for 2 hours and 50 minutes from the mid-morning break at 10:30 A.M.

Explanation:

The mid-morning break begins at 10:30 A.M. and lasts for 15 minutes.

You work 2 hours and 50 minutes from 10:30 A.M.

To find the start time of your lunch break, add 2 hours and 50 minutes to 10:30 A.M.

Lunch break begins at 1:20 P.M.

Vail Ski Shop received a $1,201 invoice dated July 8 with 2/10, 1/15, n/60 terms. On July 22, Vail sent a $485 partial payment. (If more than one discount, assume date of last discount)



a. What credit should Vail receive?

b. What is Vail’s outstanding balance?

Answers

A)
100%-1%=99%=0.99
485/0.99=489.9
489.9 is the amount of payment to be credited

B)
1,201−489.9=711.1 is the balance outstanding

Final answer:

Vail Ski Shop won't receive any credit because the payment did exceed the discount period. Vail's outstanding balance is $716, calculated by subtracting the partial payment from the original invoice.

Explanation:

The $1,201 invoice dated July 8 with 2/10, 1/15, n/60 terms means that Vail Ski Shop receives a discount  if paid within certain time periods, specifically a 2% discount if paid within 10 days, a 1% discount if paid within 15 days, and full payment is required within 60 days. However, since Vail made a partial payment of $485 on July 22, the days had already exceeded both the 10 and 15-day discount periods. This implies that Vail should not receive any credit.

To calculate Vail's outstanding balance, we would subtract the amount Vail has paid partially from the original invoice. So, the calculation would be $1,201 - $485 which equals $716. Therefore, Vail's outstanding balance would be $716.

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a number is less than 200 and greater than 100 the ones digit is 5 less than 10.the tens digit is 2 more than the ones digit.what is the number

Answers

It's between 101 and 199.

5 less than 10 is 5.
2 more than 5 is 7

My guess is 157

The correct number is between 100 and 200 would be 175.

Used the concept of number system which states that,

A writing system used to express numbers is known as a number system. It is the mathematical notation used to consistently express the numbers in a particular set using digits or other symbols.

Given that,

A number is less than 200 and greater than 100.

Here, the one's digit is 5 less than 10, and the tens digit is 2 more than the one digit.

Since the one's digit is 5 less than 10.

So, the number in one's place is,

10 - 5 = 5

And, the tens digit is 2 more than the one digit.

5 + 2 = 7

Since the number is between 100 and 200.

So, the possible value of a number with the value in one's place 5 and the value in tens place 7 would be,

175

Clearly, the number 175 is between 100 and 200.

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solve the equation for x.

ax+bx=c

Answers

ax+bx = c
abx = c
abx/ab = c/ab
x = c/ab

Answer: x = c/a + b

Step-by-step explanation: I have put the variable x in purple in the image that I have made so you can see it better.

Notice that the variable we are solving for in

this problem appears in 2 separate terms.

In this situation, we must factor the x out

of both terms to get x(a + b) = c.

Think about it as the reverse of the distributive property.

In other words, if we take our second step and distribute the x

through the parentheses, we end up back at our first step.

The beauty of factoring is that the two x's in this problem

have now been combined into one x and we can get x

by itself by dividing both sides by a + b.

This gives us x = c/a + b.

Solve for Z. Z−4/9−1/3=5/9 Enter your answer in the box. Z=

NEED HELP FAST WILL GIVE BRAINLIEST 15 POINTS

Answers

z-4/9-1/3=5/9
z -4/9 + 4/9 - 1/3 = 5/9 + 4/9 = 1
z - 1/3 + 1/3 = 1 + 1/3
z= 1 1/3

Answer:

The answer correct answer is, 4/3

Step-by-step explanation:

I am reveiwing this quiz right now!

You have 3/8 of a cake. You divide the remaining cake into six equal pieces. What fraction of the original cake is each piece?

Answers

Just divide 3/8 (of a cake) by 6.  That comes out to    3
                                                                                   ------ = 1/16 of the original
                                                                                    8(6)      cake.

all quadrilaterals are polygons

Answers

True.
Polygons are figures with straight edges, and any number of sides/vertices.
Quadrilaterals are figures with straight edges, with 4 sides and 4 vertices.
true (sorry for this but my text cant be less than 20 characters)

Suppose 4 mg of a drug is injected into a person's bloodstream. As the drug is metabolized, the quantity diminishes at the continuous rate of 3% per hour?

Answers

Let Q(t) = the mass (mg) remaining after t hours.
We are told that Q diminishes by 3% every hour.

When t = 0, Q = 4 mg
When t = 1,  Q = 4*0.97 mg
When t = 2, Q = 4*(0.97)² mg

By induction,
[tex]Q(t) = 4 (0.97)^{t} \, mg[/tex]

Q'(t) = 0.97Q
Therefore the rate of decrease is 3% per hour.

The person receives an additional dosage when Q falls to 0.50 mg. This happens when
[tex]4(0.97)^{t}=0.5 \\0.97^{t} = 0.125 \\ t \,ln(0.97) = ln(0.125) \\ t = \frac{ln(0.125)}{ln(0.97)} =68.27 \, hrs[/tex]

After the second injection, the mass is now 4.5 mg. Therefore
[tex]Q(t)=4.5(0.97)^{t}[/tex]

When the mass again reaches 0.50 mg, then
[tex]4.5(0.97)^{t}=0.5 \\ 0.97^{t}=0.1111 \\ t \, ln(0.97) = ln(0.1111) \\ t = 72.14 \, hrs[/tex]

Answers: 
(a) [tex]Q(t) = 4(0.97)^{t}[/tex]
(b) 3% per hour
(c) 68.3 hours
(d) 72.1 hours

what 87,628 divided by 931

Answers

The answer is 94.12

Do you want me to be more into detail
94.12 is the answer
Hope it helped!

Jacob used 1/7 of a liter of water to fill 1/9 of the fish aquarium. How many liters r needed to fill the aquarium?

Answers

Since 1/7 L of water fills 1/9 of the aquarium, 9 times 1/7 will fill the aquarium:

9(1/7) = 9/7 = 1 2/7 L of water will fill the aquarium.

we know that 1/7 of a liter filled up 1/9 of the aquarium, well, a "whole" will be 9/9.

how many liters will it be to fill up the 9/9 of the aquarium?

[tex]\bf \begin{array}{ccll} \stackrel{liters}{water}&\stackrel{fish}{aquarium}\\ \text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\ \frac{1}{7}&\frac{1}{9}\\\\ w&\frac{9}{9} \end{array}\implies \cfrac{\frac{1}{7}}{w}=\cfrac{\frac{1}{9}}{\frac{9}{9}}\implies \cfrac{\frac{1}{7}}{\frac{w}{1}}=\cfrac{\frac{1}{9}}{\frac{9}{9}}\implies \cfrac{1}{7}\cdot \cfrac{1}{w}=\cfrac{1}{9}\cdot \cfrac{9}{9} \\\\\\ \cfrac{1}{7w}=\cfrac{1}{9}\implies 9=7w\implies \cfrac{9}{7}=w[/tex]

Write this in Interval Notation:

4x - 6 ≥ 6x - 20

Answers

4x - 6 ≥ 6x - 20 = 6x-20,∞ 

Jim Abbott purchased a $58,000 recreational vehicle (RV) with a 45 percent markup on selling price. a. What was the amount of the dealer’s markup? Markup amount $ b. What was the dealer’s original cost? Original cost $

Answers

Final answer:

The dealer's markup amount is $26,100 and the original cost of the RV is $31,900.

Explanation:

To determine the dealer's markup, we need to find 45% of the selling price of the RV. We can set up the following equation:

Markup amount = Selling price × Markup percentage

Let's plug in the given values: $58,000 × 45% = $26,100

The dealer's original cost can be found by subtracting the markup amount from the selling price:

Original cost = Selling price - Markup amount

Let's calculate it: $58,000 - $26,100 = $31,900

You have a photo that measures 1 in. wide by 3 in. tall. If you want to enlarge the photo so that the height is 18 in., what will the width of the photo be?

A. 98 in.
B. 4 in.
C. 6 in.
D. 108 in.

Answers

C. 6in is the answer
18/3= 6

6(1)= 6

The answer is C.

Hope this helps!

How do I multiply 8.354 by 11.81?

Answers

well you can do it manually or use a calculator.

Answer is  98.66074

a box of cereal contains 23.4 ounces. It cost $5.49. What is the cost,to the nearest cent, of the cereal per ounce.

Answers

Do 5.49 / 23.4
This equals $0.23

The answer is $0.23

is 1 1/3 a unit rate

Answers

No it is not a unit rate unless 11/3 is your numerator for a quantity of one. For example, "he finishes 11/3 of his homework every hour"
No, a unit rate always has a denominator of 1. For example, 5 miles an hour is 5/1.

The table below shows the typical hours worked by employees at a company. A salaried employee makes $67,000 per year. Hourly employees get paid $25 per hour, but get $37.50 per hour for each hour over 40 hours. Sun. Mon. Tues. Wed. Thurs. Fri. Sat. 0 10 8 8 7 6.5 4.5 Which of the payment options would you recommend to a new employee? a. Either one. Hourly and salaried employees earn the same amount per week. b. Hourly pay. Hourly employees make more per week than salaried employees. c. Salaried pay. Salaried employees make more per week than hourly employees. d. There is not enough information given to compare weekly earnings.

Answers

First, we must calculate the weekly pay of an employee that is paid a fixed amount. Given that there are 52 weeks in a year, the weekly pay for a regularly paid employee is: 67,000 / 52 = $1,288.46 Now, we calculate the number of hours an employee that is paid hourly works per week: 0 + 10 + 8 + 8 + 7 + 6.5 + 4.5 = 44 So this employee is paid: 25 x 40 + 37.5 x 4 = $1,150 Therefore, it is recommended that a new employee goes for the salaried pay since the weekly earnings are greater in this option. The answer is C.

Answer:

C should be the correct option

Step-by-step explanation:

Tell me if im wrong :)

Jade spent 37.60 on groceries. 4/5 of that total was spent on vegetables. How much was spent on other items

Answers

total amount=4/5(total amount)+unknown amount
37.6=4/5(37.6)+x
(1/5)(37.6)=x
x=37.6/5

pls help i have a math question and I can`t figure out the answer

Answers

Final answer:

The student's questions relate to high school-level mathematics, such as using a graphing calculator for probability distribution calculations, the practice of mental arithmetic, and understanding significant figures and rounding. Some problems also touch on algebraic thinking and the application of mathematics in real-world contexts.

Explanation:

The student is asking several questions that pertain to solving mathematical problems and making calculations, which fall within the subject of Mathematics. It's apparent that the questions involve using a graphing calculator, understanding probability distributions, mental arithmetic, and solving equations. This level of mathematics typically corresponds to High School curriculum.



For instance, the student mentions using a graphing calculator to find a probability with a binomial distribution (binompdf), which indicates a familiarity with statistical functions and probability theory. The second part of the series includes an arithmetic puzzle meant to encourage mental math skills by breaking down a problem into more manageable parts. Another problem gives insight into significant figures and decimal places, suggesting the topic of precision and rounding in measurements or calculated results.



Additional parts of the problems focus on making estimates and using ratios for time calculations, implying topics potentially from an algebra or pre-calculus course, with a touch on the real-world application of mathematics and the flexibility and multiple methods within the mathematical process.

Computer upgrades have a nominal time of 80 minutes. samples of five observations each have been taken, and the results are as listed. sample 1 2 3 4 5 6 79.2 80.5 79.6 78.9 80.5 79.7 78.8 78.7 79.6 79.4 79.6 80.6 80.0 81.0 80.4 79.7 80.4 80.5 78.4 80.4 80.3 79.4 80.8 80.0 81.0 80.1 80.8 80.6 78.8 81.1 factors for three-sigma control limits for formula179.mml and r charts factors for r charts number of observations in subgroup, n factor for formula180.mml chart, a2 lower control limit, d3 upper control limit, d4 2 1.88 0 3.27 3 1.02 0 2.57 4 0.73 0 2.28 5 0.58 0 2.11 6 0.48 0 2.00 7 0.42 0.08 1.92 8 0.37 0.14 1.86 9 0.34 0.18 1.82 10 0.31 0.22 1.78 11 0.29 0.26 1.74 12 0.27 0.28 1.72 13 0.25 0.31 1.69 14 0.24 0.33 1.67 15 0.22 0.35 1.65 16 0.21 0.36 1.64 17 0.20 0.38 1.62 18 0.19 0.39 1.61 19 0.19 0.40 1.60 20 0.18 0.41 1.59
a. using factors from above table, determine upper and lower control limits for mean and range charts. (round your intermediate calculations and final answers to 2 decimal places. leave no cells blank - be certain to enter "0" wherever required.) mean chart range chart ucl 81.06 4.01 lcl 78.86 0.00 g

Answers

Final answer:

The UCL and LCL for the mean and range charts are calculated based on the average and range of the data sets. The table provided in the question provides respective factors for various subgroup sizes. For n=5, the factors are A2=0.58, D3=0 and D4=2.11. Using these we compute UCL and LCL for both charts. Round off to two decimal places and fill '0' in any empty cells.

Explanation:

To find the Upper Control Limit (UCL) and Lower Control Limit (LCL) for the mean and range charts, we have to use the r and formula179.mml charts that are provided in your question. We will take the observations in groups of five as mentioned in the question.

Firstly, calculate the average (X-bar) for each of these groups and find the overall average (M) of these five averages.Please find the range (R) for each subgroup and then the average of these ranges (meanR).Referring to the table given in your question, for n=5, the factors are A2=0.58, D3=0 and D4=2.11.The UCL and LCL for the mean chart can be calculated using UCL=M+A2*meanR and LCL=M-A2*meanR, whereas, for the range chart, they are UCL=D4*meanR and LCL=D3*meanR

Using these steps, you can find the upper and lower control limits for both the mean and range charts. Always remember to round off your answers to two decimal places and also, to avoid leaving any cells blank in the excel sheet. If required, fill in  '0' in those empty cells. This way, meaningful interpretation of the control charts can be made.

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The upper and lower control limits for the mean chart are 81.06 and 78.86, respectively, while the upper control limit for the range chart is 8.45 and the lower control limit is 0.

To determine the upper and lower control limits for the mean and range charts, we can use the factors provided in the table.

For the mean chart:

- The upper control limit (UCL) is calculated by adding the product of the factor for the mean chart (A2) and the average range (R-bar) to the overall average (X-double-bar). In this case, the A2 factor is 0.73 and the R-bar is 4.01, so the UCL for the mean chart is: 81.06 (rounded to 2 decimal places).

- The lower control limit (LCL) is calculated by subtracting the product of the factor for the mean chart (A2) and the average range (R-bar) from the overall average (X-double-bar). Using the same values, the LCL for the mean chart is: 78.86 (rounded to 2 decimal places).

For the range chart:

- The UCL for the range chart is calculated by multiplying the factor for the range chart (D4) by the average range (R-bar). In this case, the D4 factor is 2.11 and the R-bar is 4.01, so the UCL for the range chart is: 8.45 (rounded to 2 decimal places).

- The LCL for the range chart is always 0 since range values cannot be negative.

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12.917 rounded to the nearest ones

Answers

I am pretty sure the answer is 13
To round to the nearest ones, round to the nearest digit for the number 2. Since 9 rounds up, then the answer is 13.

To graph the inequality t > 5, you would put an open circle on 5 and shade to the right. true or false

Answers

true, open since t>5 and to the right since all values greater than 5 satisy
Since the sign is simply "greater than", not "greater than or equal to", you do use an open circle.
All numbers greater than 5 are to the right of 5, so you shade to the right of 5.
The statement is true.

a car travels 150 miles at a certain speed if the speed had been 5 miles faster the trip would have been in one hour less time find the speed

Answers

30 i wanna say was their speed i divided 150 by 5. 

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