workout 3(-a + 2a - 4)= -5

Answer:

5+4p ≥ 32

No

Step-by-step explanation:

I promise this is the answer

Answer:

[tex]\huge\boxed{\boxed{\tt{65\::)}}}[/tex]

Step-by-step explanation:

Hello.

First, add 10+3.

The sum is 13.

Now, multiply that by 5.

13×5=65

And we're done!

I hope it helps & have an outstanding day! :)

~ST2710 :)

The given equation is

   [tex]\rightarrow 9r+16=\frac{\pi}{5}[/tex]

The value of π is 3.14 or [tex]\frac{22}{7}[/tex] that is a fixed Value.

   [tex]\rightarrow 9r +16=\frac{3.14}{5}\\\\9r+16=0.628\\\\9r=0.628-16\\\\9r=-15.372\\\\r=\frac{-15.372}{9}\\\\r=-1.708[/tex]

So, the given equation is Literal ,because variable value is Known.

A literal equation is an equation that has at least one letter or one unknown variable.

[tex]9r + 16= \frac \pi 5[/tex] is a literal equation because it has letter r

Given that:

[tex]9r + 16= \frac \pi 5[/tex]

By analyzing the equation, we have:

[tex]9, 16, 5 \to[/tex] number

[tex]r \to[/tex] letter

[tex]\pi \to[/tex] constant

Because r is a letter, then the equation is a literal equation

Read more about literal equations at:

https://brainly.com/question/9603210

Answer:

There are 1000 millimeters in a meter.

Starting from lower scale that is, centimeter, decimeter and then meter

1 cm = 10 mm

1 dm = 10 cm

And 1 meter = 10 dm

So, when you go up to mm from meter, we will do [tex]10^{3}[/tex] to get the relation between meter and mm.

Hence, 1 meter = [tex]10\times10\times10=1000[/tex] millimeters.

To find g(x+1) for the function g(x)=x^2, you substitute x+1 into the function to get (x+1)^2, which expands to x^2 + 2x + 1.

The function given is g(x) = x^2. To find g(x + 1), you just need to substitute x + 1 into the function where x is. So, g(x + 1) = (x + 1)^2. If we expand this, it becomes x^2 + 2x + 1.

Therefore, the expression that is equal to g(x + 1) is x^2 + 2x + 1.

https://brainly.com/question/35064274

#SPJ2

Answer:

[tex]x=\frac{w}{2h-11}[/tex]

Step-by-step explanation:

Given equation,

w = 2hx - 11x,

⇒ 2hx - 11x = w

The steps for solving this equation for x are as follows,

Step 1 : By the converse of distributive property,

x(2h-11) = w

Step 2 : Isolate x in the left side of the equation by dividing both sides by 2h - 11 ( Division property of equality )

[tex]x=\frac{w}{2h-11}[/tex]

Heather can type the fastest. Comparing the two rates, we can see that Heather's rate of 68 words per minute is higher than Carrie's rate of 65.5833 words per minute.

To determine who can type the fastest, we need to calculate the typing rate in words per minute for both Carrie and Heather.

First, let's calculate Carrie's typing rate:

Carrie can type 787 words in 12 minutes. To find out how many words she can type per minute, we divide the number of words by the number of minutes.

[tex]\[ \text{Carrie's rate} = \frac{787 \text{ words}}{12 \text{ minutes}} \] \[ \text{Carrie's rate} = 65.5833 \text{ words per minute} \][/tex]

Next, let's calculate Heather's typing rate:

Heather can type 1020 words in 15 minutes. Similarly, we divide the number of words by the number of minutes to find her rate.

[tex]\[ \text{Heather's rate} = \frac{1020 \text{ words}}{15 \text{ minutes}} \] \[ \text{Heather's rate} = 68 \text{ words per minute} \][/tex]

Therefore, Heather can type the fastest.

Denise should plan to spend around 4.2 hours walking back after running. This is calculated using the concept of time = distance / speed and sum of the times, with the total time, running speed and walking speed given as 6 hours, 7 mph, and 3 mph, respectively.

To answer the question 'How long should Denise plan to spend walking back?' we can start by finding the time she spends running. We know that Denise has 6 hours to spend training for an upcoming race. We also know that she runs at a speed of 7mph and walks back at a speed of 3mph.

The total time spent running and walking is 6 hours. To find the running time, we should know that time = distance / speed. However, we don't have the distance. But since the distance ran is equal to the distance walked back, we can use the concept of time = distance / speed and sum of times to solve it.

We can denote the distance by D, thus the time spent running is D/7 and the time walking back is D/3. Adding these times should equal 6 hours.

Putting this into an equation: D/7 + D/3 = 6.

We solve this equation to find D, and find the time spent walking back by substituting D back into D/3. Which gives us about 4.2 hours. So, Denise should plan to spend about 4.2 hours walking back after her run.

https://brainly.com/question/35323330

#SPJ2

The decimal form of 'five thousands and eighty-five thousandths' is 5000.085. Therefore, your answer choice C) 5000.085 is correct.

The decimal number 5000.085 can be understood as a combination of two distinct parts: the whole number component, 5000, signifies 'five thousands,' representing a quantity in the thousands place, and the fractional part, 0.085, signifies 'eighty-five thousandths,' indicating a value less than one but greater than zero. When these two components are integrated, the number 5000.085 emerges, illustrating a precise quantity with both an integral and fractional significance. This understanding showcases the inherent nature of decimal notation, where whole numbers and fractional values harmoniously coexist, providing a comprehensive representation of numerical quantities.

https://brainly.com/question/35871564

#SPJ2

Answer: 7/100

Step-by-step explanation:

Count with yo Hands fool

Answer:

lets

h =# of hens in the filed and c = # of cows in

the field

hens and cows have 50 heads

h + c = 50 (1)

hens and cows have 180 legs (hen has 2

legs and cow has 4 legs)

2h+4c180 (2)

From equation (1) h + c = 50 ----> h = 50 - c

substitute h = 50 c into 2h + 4c = 180 (

-

2h+4c 180

2(50-c) + 4c = 180

1002c+ 4c = 180

2c 180-100

2c=80

C = 40

2h + 4(40) = 180

2h+160 180

2h = 20

h = 10

answer

hens = 10 and cows = 40

double check:

heads: 10 hens + 40 cows = 50 total legs:10(2) + 40(4) = 20 + 160 = 180

The work required to lift the barbell to a height of 2 m is 1,700 J.

To calculate the work required to lift the barbell to a height of 2 m, we need to consider the gravitational potential energy. The work done is equal to the change in potential energy.

The initial potential energy of the barbell is equal to its weight multiplied by the initial height, which is 1,700 N * 1 m = 1,700 J.

The final potential energy of the barbell is equal to its weight multiplied by the final height, which is 1,700 N * 2 m = 3,400 J.

Therefore, the work required to lift the barbell to a height of 2 m is 3,400 J - 1,700 J = 1,700 J.

https://brainly.com/question/16987255

#SPJ12