Write two numbers, neither of which is 8, whose GCF is 8.

Answers

Answer 1
128 and 16 GCF is 8
Answer 2
Final answer:

To find two numbers whose GCF is 8 but neither is 8, choose multiples of 8 that are not equal to 8 itself.

Explanation:

To find two numbers whose GCF is 8 and neither of which is 8, we need to find two numbers that have 8 as their largest common factor.

The easiest way to do this is to select a number that is a multiple of 8, such as 16, and then choose another number that is also a multiple of 8, but not equal to 8 itself, such as 24.

So, the two numbers whose GCF is 8 and neither of which is 8 are 16 and 24.

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Related Questions

The intelligence quotient (iq) test scores are normally distributed with a mean of 100 and a standard deviation of 15. what is the probability that a person would score 130 or more on the test?

Answers

                                                        x - 100
Calculate the relevant z-score = ----------------
                                                             15
                            130-100              30
Here, this is z = ----------------- = ----------- = 2
                                     15               15

130 would be 2 std. dev. above the mean here.  

Your job would be to calculate the area under the std. normal curve to the right of z = 2.  Using my TI-83 Plus calculator's built-in normalcdf( function, I found that this probability is 1.00 - 0.977    =    0.023.

which of the fallowing functions has a slope 3/2 and contains the midpoint segment between (6, 3) and (-2, 11)?

Answers

well, we know the slope is 3/2, what's the midpoint of those anyway?

[tex]\bf \textit{middle point of 2 points }\\ \quad \\ \begin{array}{lllll} &x_1&y_1&x_2&y_2\\ % (a,b) &({{ 6}}\quad ,&{{ 3}})\quad % (c,d) &({{ -2}}\quad ,&{{ 11}}) \end{array}\qquad % coordinates of midpoint \left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right) \\\\\\ \left( \cfrac{-2+6}{2}~~,~~\cfrac{11+3}{2} \right)\implies (2,7)[/tex]

so, what's the equation of a line whose slope is 3/2 and runs through 2,7?

[tex]\bf \begin{array}{lllll} &x_1&y_1\\ % (a,b) &({{ 2}}\quad ,&{{ 7}}) \end{array} \\\\\\ % slope = m slope = {{ m}}= \cfrac{rise}{run} \implies \cfrac{3}{2} \\\\\\ % point-slope intercept \stackrel{\textit{point-slope form}}{y-{{ y_1}}={{ m}}(x-{{ x_1}})}\implies y-7=\cfrac{3}{2}(x-2) \\\\\\ y-7=\cfrac{3}{2}x-3\implies y=\cfrac{3}{2}x+4[/tex]

Find the minimum value of the function

Answers

[tex]\bf \textit{ vertex of a vertical parabola, using coefficients}\\\\ \begin{array}{lccclll} g(x) = &{{ 2}}x^2&{{ +4}}x&{{ -5}}\\ &\uparrow &\uparrow &\uparrow \\ &a&b&c \end{array}\qquad \left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad {{ c}}-\cfrac{{{ b}}^2}{4{{ a}}}\right) \\\\\\ \left(-\cfrac{{{ b}}}{2{{ a}}}\quad ,\quad \stackrel{minimum}{-5-\cfrac{4^2}{4(2)}}\right)[/tex]

please please answer these two (16-17) questions

Answers

This would be C and B

Out of 6 women would consider themselves baseball​ fans, with a standard deviation of

Answers

For example 35% of women consider themselves fans of proffesional baseball You randonly selected six women and ask each if she considers herself a fan of proffesional baseball. Construct a binomial distribution using n = 6 and p = .35 P(x = 0) = 0.65^6 P(x = 1) = 6*0.35*0.65^5 P(x = 2) = 6C2*0.35^2*0.65^4 P(x = 3) = 6C3*0.35^3*0.65^3 etc.

225/400 in simplest form

Answers

The simplified expression of 225/400 is 9/16

How to simplify the expression

From the question, we have the following parameters that can be used in our computation:

225/400

Divide 225 and 400 by 25

so, we have the following representation

225/400 = 9/16

This cannot be further simplified

Hence, the simplified expression is 9/16

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Sets A and B, shown in the Venn diagram, are such that the total number of elements in set A is twice the total number of elements in set B. Altogether, there are 3011 elements in the union of A and B, and their intersection has 1000 elements. What is the total number of elements in set A?

Answers

Hi there,
Let's solve your problem step by step. First off, we need to assign variables to each set. Here's how you do that:

Let a represent set A and let b represent set B.

Now that we have that down, we can move on. Our next step is to translate our given information to numbers. We are given that set A has twice the total number of elements than in set B. This is what we get after the translation:

[tex]a=2b[/tex]

We are also given that there are 1000 elements in the two sets' intersection. Hence, we get:
[tex]a-1000[/tex] and [tex]b-1000[/tex]
The total number of elements combined in set A and set B can be represented as: 
[tex](a-1000)+(b-1000)+1000[/tex]
The question gives us that there are 3011 total elements in the union of A and B, so we can equate the expression above to 3011. This is our resulting product:
[tex](a-1000)+(b-1000)+1000 = 3011[/tex]
We can simplify this equation to [tex]a+b=4011[/tex]. In the beginning, we found that a = 2b, or b = 1/2a, so we can substitute that into the equation. Here is the process:
[tex]a+b=4011[/tex]
[tex]a+ \frac{1}{2}a=4011[/tex]
[tex] \frac{3}{2} a=4011[/tex]
[tex]a=2674[/tex]
Therefore, the total number of elements in set a is 2674.

An investment grows by 5% per year for 20 years. By what percent does it increase over the 20-year period?

Answers

Final answer:

An investment that grows by 5% per year for 20 years will increase by approximately 165.33% over the 20-year period. This calculation is based on the principle of compound interest.

Explanation:

In the given scenario, the growth of the investment is calculated using the principle of

compound interest

- a concept in Mathematics. Compound interest takes into account the phenomenon that, over time, your investment will grow not only from the initial amount invested but also from any interest or earnings that have been accumulated. Therefore, the 5% growth rate per year is being applied to an increasingly larger amount because the interest is being compounded, i.e., you're earning 'interest on interest'.

To calculate the overall percent increase after 20 years, we use the formula for compound interest: A = P(1 + r/n)^(nt), where:

A is the final amount of money in the accountP is the principal amount (the starting amount)r is the annual interest rate (decimal)n is the number of times interest applied per time periodt is the number of time periods the money is invested for

In this case, we can assume that P = 1 (representing 100% of the initial investment), r = 0.05 (5% growth per year), n = 1 (interest is compounded once per year), and t = 20 years. Substituting these values in, we get A = 1(1 + 0.05/1)^(1*20) = 2.6533 approximately. Therefore, the investment increased by about 165.33% over the 20-year period.

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Find the total length of the curve with parametric equations x = sin(t), y = sin(2t), z = sin(3t)

Answers

sin=12(3)=76(tk87) hope this helped you have a nice day

The total length of the curve with parametric equations give is 23.5 units.

What are parametric equations?

A parametric equation defines a group of quantities as functions of one or more independent variables called parameters.

Given that, a parametric equation, x = sin(t), y = sin(2t), z = sin(3t),

Finding the first derivative,

x' = cost

y' = 2cos2t

z' = 3cos3t

The parametric integral for length =

L = [tex]\int\limits^{t_2}_{t_1} \sqrt{ {x'^2+y'^2+z'^2} \, dx[/tex]

t₁ = 0, t₂ = 2π

T = [tex]\int\limits^{2\pi}_{0} \sqrt{ {(cost)^2+(2cos2t)^2+(3cos3t)^2} \, dt[/tex]

We will solve the integral by trapezoidal rule,

[tex]\int\limits^a_bf ({x}) \, dx = \frac{f(a)+f(b)}{2} (b-a)[/tex]

Therefore,

[tex]\int\limits^{2\pi}_{0} \sqrt{ {(cost)^2+(2cos2t)^2+(3cos3t)^2} \, dt[/tex]

= [tex]\frac{\sqrt{(cos2\pi)^2+(2cos2\pi)^2+(3+cos3\pi)^2} +\sqrt{(cos0)^2+(2cos0)^2+(3+cos0)^2}}2} (2\pi)[/tex]

= 23.5

Hence, the total length of the curve with parametric equations give is 23.5 units.

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Use either the ratio test or the root test as appropriate to determine

Answers

ratio becuse thats cool right

The series ∑∞ n=1 an with terms [tex]a_n = (1 * 8 * 15 * ... * (7n-6)) / (7^n * n!)[/tex]diverges. Hence the correct option is 2.

Ratio Test:

For the series ∑∞ n=1 an with terms an, let:

lim n->∞ |an+1 / an| = L

If L < 1, the series converges.

If L > 1, the series diverges.

If L = 1 or the limit diverges, the test is inconclusive.

Applying the Ratio Test:

Here, [tex]a_n = (1 * 8 * 15 * ... * (7n-6)) / (7^n * n!)[/tex]

Let's analyze the limit as n approaches infinity for the ratio of successive terms:

Simplifying the numerator and denominator, we get:

[tex]lim n- > ∞ | 7^(^n^+^1^) * (n+1)! / (7^n * n!) | = lim n- > ∞ | 7 * (n+1) |[/tex]

As n approaches infinity, the constant term 7 becomes insignificant. Therefore:

lim n->∞ |an+1 / an| = lim n->∞ |n+1|

Since the limit approaches positive infinity as n approaches infinity, L > 1.

Conclusion:

Based on the ratio test, the series ∑∞ n=1 an with terms [tex]a_n = (1 * 8 * 15 * ... * (7n-6)) / (7^n * n!)[/tex]diverges. Hence the correct option is 2.

Complete question:

Use either the ratio test or the root test as appropriate to determine whether the series ∑∞, n=1 an with given terms an converges, or state if the test is inconclusive. an= 1⋅8⋅15⋯(7n−6)/7^n n!

The series converges.

The series diverges.

The test is inconclusive.

A rectangular storage container with an open top is to have a volume of 10 m3. the length of this base is twice the width. material for the base costs $10 per square meter. material for the sides costs $6 per square meter. find the cost of materials for the cheapest such container. (round your answer to the nearest cent.)

Answers

Refer to the diagram shown below.

The volume of the container is 10 m³, therefore
x*2x*h = 10
2x²h = 10
h = 5/x²        (1)

The base area is 2x² m².
The cost is $10 per m², therefore the cost of the base is
(2x²)*($10) = 20x²

The area of the sides is
2hx + 2(2xh) = 6hx = 6x*(5/x²) = 30/x m²
The cost is $6 per m², therefore the cost of the sides is
(30/x)*($6) = 180/x

The total cost is
C = 20x² + 180/x

The minimum cost is determined by C' = 0.
That is,
40x - 180/x² = 0
x³ = 180/40 = 4.5
x = 1.651
The second derivative of C is
C'' = 40 + 360/x³
C''(1.651) = 120 >0, so x = 1.651 m yields the minimum cost.

The total cost is
C = 20(1.651)² + 180/1.651 = $163.54

Answer: $163.54

Use the Social Security tax rate of 6.2% and Medicare tax rate of 1.45% to determine the total deduction.

Gross Pay: $6223

Answers

$6223 *  .062 = 385.826 Social Security
$6223 *  .0145= 90.2335 Medicare

$6223 - 385.826 - 90.902335 = 5746.271665 or $5,746.25 
Total deductions = 
294.923665

11<15+v
Solve the inequality for v

Answers

V is greater than -4

Ms. Rios buys 453 grams of strawberries she has 23 grams left after making smoothies how many grams of strawberries did she use

Answers

453 - 23 = 420 grams left
Final answer:

Ms. Rios used 430 grams of strawberries to make her smoothies. This is calculated by subtracting the amount left (23 grams) from the total amount purchased (453 grams).

Explanation:

To determine how many grams of strawberries Ms. Rios used for making smoothies, we can subtract the quantity of strawberries left unprocessed from the total quantity she originally purchased. In this case, Ms. Rios bought 453 grams of strawberries and had 23 grams left after making smoothies.

The formula to determine the solution would be: Total amassed quantity - Remaining quantity = Used quantity

By filling the above formula with our values, the solution will be as follows: 453 grams (total) - 23 grams (remaining) = 430 grams (used).

Thus, Ms. Rios used 430 grams of strawberries for making smoothies.

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Sixth-grade students at Cramon Junior High are not to have more than 12 hours of homework per week. They take one math course and two science courses in sixth grade. The amount of time required to do homework for a math course is x hours, and the time required to do homework for a science course is y hours.
How would this problem be represented in the form of an inequality?

Answers

I think the answer is x + 2y or 5(x + 2y) with 5 being the number of days in a school week

Answer:

X+2y=12

Step-by-step explanation:


Explain the solution to |4w + 9| = –7.

Answers

Actually, Abby, this problem has NO SOLUTION.  WHY?  because no absolute value is ever less than zero (0).


Suppose there is a strong positive correlation between v and w. Which of the following must be true?

Answers

The truth is when V increases, W tends to increase. Positive correlation between two variables in which both variables move in tandem. Positive correlation exists when one variable decreases as the other also decreases or one variable increases while others increase too.

The graph below indicates the distance that the cat (red line) and mouse (green line) have run as a function of the time since the chase began. How far did the mouse run before the cat caught it ?

a. 1 foot c. 22 feet
b. 11 feet d. 6 feet

Answers

The mouse ran a distance of 11 feets before being caught by the cat

How to use the graph for our solution

Using the information on the graph ;

Y - axis = Distance covered by the mouse and cat

X - axis = Time taken to cover Distance

The intersection point of the two lines is the point at which the mouse was caught .

Tracing the point to the y-axis , we get the required Distance value

Hence, from the graph, the distance is 11 feets

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Before being caught by the cat, the mouse sprinted 11 feet.

How can we apply the graph to our solution?

Using the data from the graph;

The distance traveled by the mouse and cat is represented by the Y axis.

X axis = Distance traveled in time

The spot where the two lines connect is where the mouse was trapped.

We get the requisite Distance value by tracing the point to the y-axis.

As a result of the graph, the distance is 11 feet.

The length of a rectangle is twice its width. The perimeter is 60 ft. Find its area.

Answers

Answer:

200 feet squared

Step-by-step explanation:

W=Width

2W=Length

Perimeter = 2*Length + 2*Width

Now use substitution for the Length

60 = 2(2W) + 2(W)

60=4W + 2W = 6W divide both sides by 6

60/6 = 6W/6

10 = W

Width = 10 and Length is twice as long so it is 20. 10+10+20+20=60

The area is Length * Width = 20*10=200

Amy has 1/4 hour to do 5 chores. She plans to spend the same fraction of an hour on each chore. She wants to use the number line to help her determine what fraction of an hour she can spend on each chore. What is the correct number label for point A?

Answers

i think it would take her 1/20 of an hour to do each chore and i dont know what point a is .

the correct number label for point A on the number line is [tex]\( \frac{1}{20} \).[/tex]

Let's break this down step by step:

1. Determine the time available for each chore: Amy has 1/4 hour to do 5 chores. To find out how much time she can spend on each chore, divide the total time available (1/4 hour) by the number of chores (5).

[tex]\( \frac{1}{4} \div 5 = \frac{1}{4} \times \frac{1}{5} = \frac{1}{20} \)[/tex]  hour per chore.

2. Representing the fraction of an hour on a number line:The number line represents the whole hour. Since Amy has 1/20 hour per chore, each point on the number line represents 1/20 hour.

  - Let's label point A as [tex]\( \frac{1}{20} \).[/tex]

So, the correct number label for point A on the number line is [tex]\( \frac{1}{20} \).[/tex]

Amy has 1/4 hour to complete 5 chores. To find out how much time she can spend on each chore, we divide 1/4 by 5, which gives us 1/20 hour per chore. On the number line representing an hour, each point represents 1/20 hour, so point A is labeled as 1/20. This means that Amy can spend 1/20 hour on each chore to complete all five chores within the 1/4 hour time frame she has.

complete question

Amy has 1/4 hour to do 5 chores. She plans to spend the same fraction of an hour on each chore. She wants to use the number line to help her determine what fraction of an hour she can spend on each chore. What is the correct number label for point A?

The spread of data set X is greater than the spread of data set Y, and the data sets are normally distributed. Which statement is true? The mean of data set X is greater than the mean of data set Y. The median of data set X is less than the median of data set Y. The standard deviation of data set X is greater than the standard deviation of data set Y. The range of data set X is less than the range of data set Y. The mode of data set X is greater than the mode of data set Y.

Answers

The standard deviation is a measure of how far dispersed around the mean the individual parts of a distribution are. Therefore, because data set X has a greater spread, its standard deviation is going to be greater than that of data set Y. Items such as the mean, median, or mode are measures of central tendency and do not impact the standard deviation.

Answer:

The answer is option C on plato :)

Step-by-step explanation:


Beyond Euclidean Geometry.


Many airlines use maps to show the travel paths of all their flights, which are called route maps. For instance, K12Air has a route map that describes all the possible routes to and from Samsville, Shiloh, Camden, Chelsea, Jamestown, and Lorretta.

You have been provided a route map for K12Air. Write a question about this map that involves Hamiltonian or Euler circuits or paths.

Help me come up with a question?

Answers

An Euler path is a path that traverses every edge (line) exactly once.
In the given graph, each edge (line) represents a given flight for the aircraft.  The pilot has to figure out a path to ensure each given flight is fulfilled (without repetition). 
An Euler circuit, is an Euler path that returns to the original position.  For this graph, there is no such circuit, but an Euler path exists.
The return flight will be another path in the opposite direction.

A Hamiltonian path is a path that touches on each node (city) exactly once, edges may be skipped or repeated.  This way, the pilot makes a stop at each city exactly once (without repetition of the city).
A Hamiltonian circuit is a path that touches on each intermediate city exactly once, but returns to the original city.
There are possible Hamiltonian paths and Hamiltonian circuits in this graph.

The above explanations should give you a clear idea on what questions to ask.

A suitable question to ask about the K12Air route map in the context of Hamiltonian or Euler circuits or paths could be:

Is it possible to find a Hamiltonian circuit on the K12Air route map that allows a plane to travel through each city exactly once before returning to the starting city?

To formulate a question involving Hamiltonian or Euler circuits or paths, one must understand the difference between these concepts:

- A Hamiltonian path is a path in an undirected or directed graph that visits each vertex exactly once. If this path returns to the starting vertex, it is called a Hamiltonian circuit.

- An Euler path is a path in a graph that visits every edge exactly once. If this path starts and ends at the same vertex, it is called an Euler circuit.

Given the context of the K12Air route map, which describes all the possible routes to and from various cities, the question should focus on whether it's possible to traverse the graph representing the route map in a way that satisfies the conditions of either a Hamiltonian or an Euler circuit/

For the Hamiltonian circuit, the question is whether there exists a sequence of flights that allows a plane to start at one city, visit every other city exactly once, and return to the starting city without repeating any city. This would require the route map to have a Hamiltonian circuit, which is a more stringent condition than an Euler circuit because it involves visiting all vertices exactly once.

For an Euler circuit, the question would be whether there exists a sequence of flights that allows a plane to traverse every possible route exactly once before returning to the starting point. This would require the route map to have an Euler circuit, meaning every edge (route) is used exactly once.

In the case of K12Air, the question about the Hamiltonian circuit is particularly interesting because it tests the connectivity of the route map and the possibility of a round trip that covers all cities without repetition. This could be relevant for planning efficient travel itineraries or for optimizing the use of airline resources. If the route map does not allow for a Hamiltonian circuit, one might then ask if a Hamiltonian path exists, which would not require returning to the starting city.

To answer such a question, one would need to analyze the connectivity of the graph represented by the route map, possibly using theorems related to Hamiltonian graphs, such as Dirac's theorem or Ore's theorem, which provide sufficient conditions for a graph to contain a Hamiltonian circuit.

Evaluate the integral i = z s f ds when f(x, y, z) = z 2 + 3xy and s is the portion of the plane x + 2y + 2z = 0 above the unit disk x 2 + y 2 ≤ 1 in the xy-plan

Answers

Final answer:

To solve the surface integral of a scalar field as given, parametrize the surface S, compute the gradient of the scalar field f, and setup the integral related to the given plane equation and limits of the unit disk. Details of the setup and a specific numerical solution are not provided.

Explanation:

The problem you've asked about, i.e., evaluating the integral i = z s f ds when f(x, y, z) = z 2 + 3xy and s is the portion of the plane x + 2y + 2z = 0 above the unit disk x 2 + y 2 ≤ 1 in the xy-plan, falls under the subject of vectors and calculus, particularly triple integrals. It includes a surface integral of a scalar field.

In general, to evaluate a surface integral of a scalar field, first, you should parametrize the surface S with vector function r(u, v). Then you calculate the cross product of partial derivatives of r with respect to u and v to find the surface element dS. In other words, you compute the gradient of the scalar field f.

In this case, you would need to set up the integral with f(x, y, z) and ds related to the given plane equation x + 2y + 2z = 0 and the limits to the unit disk. Solve this integral by any standard method (like substitution or by parts) as needed depending on the complexity of f.

Note: Since the specific setup and solution to this integral could be complex and calculation heavy, a detailed step by step solution is not provided in this formatted answer.

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on the blueprint of the house 44 millimeters represents 8 meters. the length of the living room is 33 millimeters on the blueprint. what is the actual length of the living room?

Answers

So if 44=8 and 33=x, solve for x. 
The problem would look like this : 44mm = 8m
                                                      33mm =  x
You would cross multiply giving you this : 44x = 264
Then divide 264 by 44 to isolate x, then you should get this : x = 6
6m will be your answer.

The actual length of the living room is 6 meters.

What is unit conversion?

Conversion of units is the conversion between different units of measurement for the same quantity, typically through multiplicative conversion factors.

Here the unit of lengths, millimeter is converted to meter based on the given scale

For the given situation,

In blue print the house is represented as follows,

44 millimeters =  8 meters

⇒ [tex]1 millimeter = \frac{8}{44} meters[/tex]

⇒ [tex]1 millimeter = 0.18 meters[/tex]

The length of the living room = 33 millimeters

The actual length of the living room in meters = [tex]33(0.18)[/tex]

⇒ [tex]5.94[/tex] ≈ [tex]6 meters[/tex]

Hence we can conclude that the actual length of the living room is           6 meters.

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Find the unit rate by using WKU. David drove 135 miles in 3 hours.

Answers

divide 135 by 3 and the unit rate will be 45

estimate the difference between 206 and 167

Answers

206 - 167 estimation is 38
correct answer is 39

a company announced that 40% of those enrolled in its training to program will be sent to a new plant. if there are 60 people enrolled in the training program, how many will be sent to the new plant

Answers

24 people will be sent to the new plant.

Use cross-multiplication to find 40% of 60

 40       x
 __  =  __
100     60

40(60) = 100x
2400 = 100x
Divide by 100.
x = 24

There are 60 people enrolled in the program, then 24 people will be sent to the new plant.

What is the percentage?

The percentage is defined as a ratio expressed as a fraction of 100.

To find the number of people sent to the new plant, we can multiply the percentage of people sent to the new plant by the total number of people enrolled in the training program. The percentage is given as a decimal by dividing the percentage by 100, so 40% is equal to 0.40.

The result is then multiplied by the number of people enrolled in the training program, which is 60.

40% of those enrolled in the training program will be sent to the new plant, which is 40/100 x 60 people = 24 people.

The final result is 24 people.

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[tex]F(x)=(6 \sqrt{x} -2)(5 \sqrt{x} +7)[/tex]

Answers

[tex]\bf f(x)=(6\sqrt{x}-2)(5\sqrt{x}+7) \\\\\\ \cfrac{dy}{dx}=\stackrel{product~rule}{\left( 6\cdot \frac{1}{2}x^{-\frac{1}{2}} \right)(5x^{\frac{1}{2}}+7)~~+~~(6x^{\frac{1}{2}}-2)\left(5\cdot \frac{1}{2}x^{-\frac{1}{2}} \right)} \\\\\\ \cfrac{dy}{dx}=\left(\cfrac{6}{2}\cdot \cfrac{1}{\sqrt{x}} \right)(5x^{\frac{1}{2}}+7)~~+~~2(3x^{\frac{1}{2}}-1)\left(\cfrac{5}{2}x^{-\frac{1}{2}} \right)[/tex]

[tex]\bf \cfrac{dy}{dx}=\left(3\cdot \cfrac{1}{\sqrt{x}} \right)(5x^{\frac{1}{2}}+7)~~+~~2\cdot \cfrac{5}{2}(3x^{\frac{1}{2}}-1)\left(\cfrac{1}{\sqrt{x}} \right) \\\\\\ \cfrac{dy}{dx}=\cfrac{3(5\sqrt{x}+7)}{\sqrt{x}}~~+~~\cfrac{5(3\sqrt{x}-1)}{\sqrt{x}}\\\\\\ \cfrac{dy}{dx}=\cfrac{15\sqrt{x}+21~~+~~15\sqrt{x}-5}{\sqrt{x}} \\\\\\ \cfrac{dy}{dx}=\cfrac{30\sqrt{x}+16}{\sqrt{x}}[/tex]

Which number is one million times larger than 8.7 x 104 ? A) 8.7 x 107 B) 8.7 x 108 C) 8.7 x 109 D) 8.7 x 1010

Answers

Assuming the numbers after 10 are exponents:

1 million is equal to 10^6. Let's multiply this by the original expression.
8.7*10^4*10^6

Add exponents when multiplying with the same base
10^4*10^6= 10^10

Final answer: 8.7*10^10, or D

Answer:

D) [tex]8.7 * 10^{10}[/tex]

Step-by-step explanation:

The question is correctly written as below:

Which number is one million times larger than [tex]8.7 * 10^{4}[/tex]?

A) [tex]8.7 * 10^{7}[/tex]

B) [tex]8.7 * 10^{8}[/tex]

C) [tex]8.7 * 10^{9}[/tex]

D) [tex]8.7 * 10^{10}[/tex]

Consider [tex]8.7 x 10^{4}[/tex] to be number A and number B is one million times ([tex]10^{6}[/tex]) greater than number A

[tex]B = A * 10^{6}[/tex]

[tex]B = 8.7 * 10^{4} * 10^{6}[/tex]

[tex]B = 8.7 * 10^{4+6}[/tex]

[tex]B = 8.7 * 10^{10}[/tex]

D) [tex]8.7 * 10^{10}[/tex]

The length of a rectangle is 4 meters less than twice the width. If the area of the rectangle is 286 square​ meters, find the dimensions.

Answers

essentially, you have A=bw for a rectangle.
286=x(2x-4), let width be x.
solve
286=2x^2-4x for x

The dimensions of the rectangle are length = 22 meters and width = 13 meters

What is area of rectangle?

[tex]A=l\times w[/tex], where 'l' is the length and 'w' is the width of the rectangle.

For given question,

Suppose 'l' is the length and 'w' is the width of the rectangle.

The length of a rectangle is 4 meters less than twice the width.

So, we get an equation,

⇒ l = 2w - 4

The area of the rectangle is 286 square​ meters.

⇒ A = 286 sq. m.

Using the formula for the area of the rectangle,

[tex]\Rightarrow A=l\times w\\\\\Rightarrow 286=(2w-4)\times w\\\\\Rightarrow 286=2w^2-4w\\\\\Rightarrow 2w^2-4w-286=0[/tex]

Now, we solve the quadratic equation [tex]2w^2-4w-286=0[/tex]

[tex]\Rightarrow 2w^2-4w-286=0\\\\\Rightarrow w^2-2w-143=0\\\\\Rightarrow (w-13)(w+11)=0\\\\\Rightarrow w-13=0~~~or~~~w+11=0\\\\\Rightarrow w=13~~~or~~~w=-11[/tex]

w = -11 is not possible.

So, the width of the rectangle is 13 meters.

And the length of the rectangle would be,

[tex]\Rightarrow l \\= 2w - 4\\=(2\times 13)-4\\=22[/tex]

Therefore, the dimensions of the rectangle are length = 22 meters and width = 13 meters

Learn more about the area of the rectangle here:

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